The volume of a colloidal particle `V_C` as compared to the volume of a solute particle in a true solution `V_S` could be

The volume of a colloidal particle `V_C` as compared to the volume of a solute particle in a true solution `V_S` could be
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The volume of a colloidal particle `V_C` as compared to the volume of a solute particle in a true solution `V_S` could ... `~ 10^(-3)` D. `~ 10^(3)`
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A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure becomes 2.9 kPa at 298 K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K -Chemistry

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Last Answer : Mass by mass percentage = 20% Mass of solution= 550gram Mass of solute/mass of solution multipled by 100 Therefore, 20/100 = 1/5 Hence, Mass of solute=Mass of solution/5 = 550gram/5 = 110Gram Therefore, The mass of solute is 110gm

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Description : What is a solution that contains as much solute as it can hold at a given temperature?

Last Answer : This is called a saturated solution.