At 2 atm pressure the value of `(x)/(m)` will be : (log 2 = 0.3010)

At 2 atm pressure the value of `(x)/(m)` will be : (log 2 = 0.3010)
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At 2 atm pressure the value of `(x)/(m)` will be : (log 2 = 0.3010)
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