What is the number of Cr 's in the compound K2 Cr2 O7 ?

1 Answer

Answer :

Suppose the oxidation number of Cr is x. Now , the oxidation number of K₂Cr₂O7 = 0 (1.2) + (2.x) + (-2) .7 = 0 2x-12 = 0 2x = 12 x = 6 Cr + 6.

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