Which term is defined as scientists working alone?

Which term is defined as scientists working alone?
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individual endeavor
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Description : Spandex while working out - alone or with undies underneath?

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Description : Can a dad get in trouble for leaving 11 and 12 yr old boys alone while working during the day?

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Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between the number of days taken by Ram and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Description : Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between ... and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Last Answer : Let the time taken by Ram, Suresh and Shilpa to finish the work alone be A, B and C respectively Therefore, 1/A + 1/B + 1/C = 1 Also it is given that, A = B/3 and C =B/2 3/B + 1/B + ... between the number of days taken by Ram and Shilpa, each working alone, to complete the work = 3-2 = 1 Answer: a)

The hypothesis underlying team teaching is Options: A) Teachers feel bore while working alone B) Teachers are not competent C) The best teachers in schools are shared by more students D) The single teacher cannot control the class

Description : The hypothesis underlying team teaching is Options: A) Teachers feel bore while working alone B) Teachers are not competent C) The best teachers in schools are shared by more students D) The single teacher cannot control the class

Last Answer : C) The best teachers in schools are shared by more students 

Prabu and balaji are two workers. Working together they can complete the whole work in 20 hours. If the Prabu worked for 5 hours and balaji worked for 17 hours, still there was half of the work to be done. In how many hours Prabu working alone, can complete the whole work? a) 17 hours b) 23 hours c) 34 hours d) 37 hours

Description : Prabu and balaji are two workers. Working together they can complete the whole work in 20 hours. If the Prabu worked for 5 hours and balaji worked for 17 hours, still there was half of the work to be done ... working alone, can complete the whole work? a) 17 hours b) 23 hours c) 34 hours d) 37 hours

Last Answer : C Efficiency of Prabu and balaji = 5% Prabu worked for 5 hours and balaji worked separately 17 hours. Which means it can be considered that Prabu and balaji worked together for 5 hours and balaji worked alone for ... (5-2.08) = 2.92% Thus, prabu require . = 34 hours to complete the work alone.

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Description : Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Last Answer : A Let sai's 1 day work = x Ram's 1 day work = y Then x+y = 1/10 ===>1 and 2x +2y /3 = 1/6 (6x+2y )/3 = 1/6 6x + 2y =1/2 ====>2 Multiply 1 by 6 =>6x+6y = 6/10 2 = ... /10 - 1/40 = 4-1/10 =3/40 Sai's 1 day work = 3/40 So sai alone could complete the work in 40/3 days.

Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Description : Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Last Answer : D Work done by pranesh in 4 days = 1/60 *4 =1/15 Remaining work = 1-1/15 =(15 - 1)/15 =14/15 Now 14/15 work done by sarvesh in 28 days Whole work will be done by sarvesh in(28*15 /14) = 2* 15 =30 ... 's work = 1/60 + 1/30 = (1+2) /60 = 3/60 =1/20 Hence both will finish the work in 20 days

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60

Description : P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each ... finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60 

Last Answer : B Time taken by (P + Q) to finish the job = 24days. (P + Q)'s 1 day's job = 1/24 Time taken by (Q +R) to finish the job = 30days. (Q + R)'s 1 day's job = 1/30 Time taken by (R + P) to finish the ... - {(P + Q)'s 1 day's job } = (1/20 -1/24)=1/120 Hence, R alone can finish the job in 120 days.

3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Description :  3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Last Answer : C  Part filled in 4 hrs = 4/12 = 1/3 Remaining part = 2/3 (P+Q)’s 14 hrs work = 2/3 (P+Q)’s 1 hr work = 2/ 3 *14 = 1/21 R’s 1 hr work = (P+Q+R)’s 1 hr work – (P+Q)’s 1 hr work = 1/12 – 1/21 = 7-4/84 = 3/84 = 1/28 R alone can fill the tank in 28 hrs.

Three tubes A, B and C can fill a tank in 12hours. After working at it together for 4 hours, C is closed and A and B can fill the remaining part in 12 hours. The number of hours taken by C alone to fill the tank is A) 32hrs B) 30hrs C) 38hrs D) 36hrs

Description : Three tubes A, B and C can fill a tank in 12hours. After working at it together for 4 hours, C is closed and A and B can fill the remaining part in 12 hours. The number of hours taken by C alone to fill the tank is A) 32hrs B) 30hrs C) 38hrs D) 36hrs

Last Answer : D A+B+C in 1h = 1/12 A+B+C in 4h = 4/12 = 1/3 Remaining = 1-1/3 = 2/3 A+B in 12hrs = 2/3 A+B in 1hr = 2/36=1/18 C alone to fill the tank= 1/12– 1/18 = 3-2/36= 1/36=36hrs

Three taps P,Q,R can fill a bunker in 3 hrs. After working at it together for 1 hr, R is closed and P,Q can fill the remaining part in 3 hrs. The number of hrs taken by R alone to fill the bunker. A) 9hrs B) 7hrs C) 11hrs D) 5hrs

Description : Three taps P,Q,R can fill a bunker in 3 hrs. After working at it together for 1 hr, R is closed and P,Q can fill the remaining part in 3 hrs. The number of hrs taken by R alone to fill the bunker. A) 9hrs B) 7hrs C) 11hrs D) 5hrs

Last Answer : A  Part filled in 1 hr = 1/3  Remaining part = 1 – 1/3 = 2/3  (P + Q)’s 3 hours work = 2/3  (P+Q)’s 1 hour work = 2/9  R’s 1 hr work = [(P+Q+R)’s 1 hr work – (P+Q)’s 1 hr work]  = 1/3 – 2/9 = 3-2/9 = 1/9  R alone can fill the tank in 9 hours.

Which of the following is defined as the difference between current assets and current liabilities? A. Venture Capital B. Working Capital C. Equitable Mortgage D. None of the Above

Description : Which of the following is defined as the difference between current assets and current liabilities? A. Venture Capital B. Working Capital C. Equitable Mortgage D. None of the Above

Last Answer : B. Working Capital Explanation: The capital of a business which is used in its day-to-day trading operations, calculated as the current assets minus the current liabilities.

Indicate the false statement. Noise figure is defined as A. the ratio of the S/N power supplied at the input terminal of a receiver or amplifier to the S/N power supplied to the output or load resistor B. noise factor expressed in decibels C. an unwanted form of energy tending to interfere with the proper and easy reception and reproduction of wanted signal D. S/N of an ideal system divided by S/N at the output of the receiver or amplifier under test, both working at the same temperature over the same bandwidth and fed from the same source

Description : Indicate the false statement. Noise figure is defined as A. the ratio of the S/N power supplied at the input terminal of a receiver or amplifier to the S/N power supplied to the output or ... under test, both working at the same temperature over the same bandwidth and fed from the same source

Last Answer : C. an unwanted form of energy tending to interfere with the proper and easy reception and reproduction of wanted signals

Having defined working capital as current assets, it can be further classified according to . A. financing method and time B. rate of return and financing method C. time and rate of return D. components & time

Description : Having defined working capital as current assets, it can be further classified according to  . A. financing method and time B. rate of return and financing method C. time and rate of return D. components & time

Last Answer : D. components & time

Prohibition of sexual harassment of working women defined in __of CCS Conduct rules a) Sec 3-A b) Sec 3-B c) Sec 3-C d) Sec 3-D

Description : Prohibition of sexual harassment of working women defined in __of CCS Conduct rules a) Sec 3-A b) Sec 3-B c) Sec 3-C d) Sec 3-D

Last Answer : c) Sec 3-C

Factor of safety in machine design is defined as the ratio of ultimate stress to __________ stress. (A) Working (B) Bearing (C) Yield (D) None of these

Description : Factor of safety in machine design is defined as the ratio of ultimate stress to __________ stress. (A) Working (B) Bearing (C) Yield (D) None of these

Last Answer : Option A

What is meant by the term 'stand alone computer?

Description : What is meant by the term 'stand alone computer?

Last Answer : It means that it works on its own, without interaction withother computers - or, if any such interaction occurs, it is notrelevant to the problem being considered.