What is 72 divided by to get 8?

What is 72 divided by to get 8?
by

1 Answer

Answer :

9
by

Related questions

What is 192 divided by 72?

Description : What is 192 divided by 72?

Last Answer : 2.6667

What is 3.56 divided by 0.72 4.94 or 0.04?

Description : What is 3.56 divided by 0.72 4.94 or 0.04?

Last Answer : 4.94

What is 4968 divided by 72?

Description : What is 4968 divided by 72?

Last Answer : 69

What is 4968 divided into 72?

Description : What is 4968 divided into 72?

Last Answer : 69

What is 72 divided by 4968?

Description : What is 72 divided by 4968?

Last Answer : 0.0145

What is 72 divided by something equals 6?

Description : What is 72 divided by something equals 6?

Last Answer : 12

What is the difference between 72 846 divided by twice of three and seventy-five multiplied twice?

Description : What is the difference between 72 846 divided by twice of three and seventy-five multiplied twice?

Last Answer : Need answer

What is 72 divided by 4968?

Description : What is 72 divided by 4968?

Last Answer : 0.0145

72 tens divided by 9 tens?

Description : 72 tens divided by 9 tens?

Last Answer : 8

The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

What is the LCM of 8 72 and 216?

Description : What is the LCM of 8 72 and 216?

Last Answer : It is 216

What is next in sequence 7 21 8 72 9?

Description : What is next in sequence 7 21 8 72 9?

Last Answer : According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. ... )/6 where n = 1, 2, 3, ...and, accordingly, the next term is -693.

What day is 72 hours from Tuesday at 8 PM?

Description : What day is 72 hours from Tuesday at 8 PM?

Last Answer : Friday 8pm

X Ltd. forfeited 20 shares of Rs. 10 each on which Rs. 6 per share were paid. If out of these shares, 8 shares were reissued to Ram as fully paid up on payment of Rs. 5•50 per share, the amount that will remain standing to the credit of Share Forfeited A/c will be– (A) Rs. 48 (B) Rs. 72 (C) Rs. 84 (D) Rs. 120

Description : X Ltd. forfeited 20 shares of Rs. 10 each on which Rs. 6 per share were paid. If out of these shares, 8 shares were reissued to Ram as fully paid up on payment of Rs. 5 50 per share, the amount that will remain standing ... Share Forfeited A/c will be- (A) Rs. 48 (B) Rs. 72 (C) Rs. 84 (D) Rs. 120

Last Answer : Answer: Rs. 120

A ball moving with uniform velocity comes to rest in a distance of 72 m in 6 s. Its initial velocity and retardation are (a) 12 m/s and 2 m/s2 (b) 12 m/s and 4 m/s2 (c) 24 m/s and 8 m/s2 (d) 24 m/s and 4 m/s2

Description : A ball moving with uniform velocity comes to rest in a distance of 72 m in 6 s. Its initial velocity and retardation are (a) 12 m/s and 2 m/s2 (b) 12 m/s and 4 m/s2 (c) 24 m/s and 8 m/s2 (d) 24 m/s and 4 m/s2

Last Answer : Ans:(d)

Sumati did some preliminary experiment with the lenses and found out that the magnification of the eyepiece (L 2 ) is 3. If in her experiment with L 2 she found an image at 24 cm from the lens, at what distance did she put the object? (a) 72 cm (b) 12 cm (c) 8 cm (d) 6 cm

Description : Sumati did some preliminary experiment with the lenses and found out that the magnification of the eyepiece (L 2 ) is 3. If in her experiment with L 2 she found an image at 24 cm from the lens, at what distance did she put the object? (a) 72 cm (b) 12 cm (c) 8 cm (d) 6 cm

Last Answer : (c) 8 cm

Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10 8 m/s(in 10 -8 order) a) 0.5 b) 72 c) 4 d) 3

Description : Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10 8 m/s(in 10 -8 order) a) 0.5 b) 72 c) 4 d) 3

Last Answer : c) 4

The population of a city in 2000 is 50,000. The average increase in population over last 8 decades is 7500 and average incremental increase during 8 decades is 750. The population of the city based on incremental method, in the year 2020 will be (A) 55,000 (B) 60,500 (C) 66,500 (D) 72,500

Description : The population of a city in 2000 is 50,000. The average increase in population over last 8 decades is  7500 and average incremental increase during 8 decades is 750. The population of the city based  on incremental method, in ... (A) 55,000  (B) 60,500  (C) 66,500  (D) 72,500 

Last Answer : (C) 66,500

24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Description : 24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Last Answer : 72÷48×8+14 = (72/48) × 8 + 14 = (3/2) × 8 + 14 = 12 +14 = 26 24 + (72 ÷ 48 × 8 + 14) ×36 ÷ (3 × 4) + 36 ÷ 3 × 4 = 24 + 26 × 36÷12 + 36 ÷ 3 × 4 = 24 + 26 × 3 + 12 × 4 = 24 + 78 + 48 = 150 Answer: e)

A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Description : A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Last Answer : c) 8 Let first two digit no. and second two digit no. be x and y respectively. x = y × 40/100 +16 x - 2y/5 = 16....(i) x + y = 72...(ii) From equation (i) and (ii) x = 32, y = 40 Difference = 8 Answer: c)

The energy consumption and production patterns in a chemical plant over a 9 month period is provided in the table below; Month 1 2 3 4 5 6 7 8 9 Production in Tonnes / month 493 297 381 479 585 440 234 239 239 Energy Consumption MWh /month 78.2 75.7 76.3 76.1 78.1 70.7 73.7 64.4 72.1 Estimate the cumulative energy savings at end of the 9th month and give your inference on the result ? ( consider 9 month data for evaluation for predicted energy consumption)

Description : The energy consumption and production patterns in a chemical plant over a 9 month period is provided in  the table below; Month 1 2 3 4 5 6 7 8 9 Production in Tonnes / month 493 ... and give your inference on the  result ? ( consider 9 month data for evaluation for predicted energy consumption)

Last Answer : It is required to use the equations Y= mX + C and  nC + mΣX = ΣY  cΣX + mΣX2 = ΣXY Month X =  Production in  Tonnes /  month Y =Energy  Consumption MWh  /month  X 2 XY 1 493 78.2 ... 73.7 54756 17240.63 8 239 64.4 57121 15402.96 9 239 72.1 57121 17228.98 3387 665.3 1410683 253221

Track structure for CC+8 t+ 2 t loaded trains is:- (a) 52 Kg 90 UTS;PSC 1540 sleepers/ Km.; 250 mm ballast. (b) 60 Kg 90 UTS;PSC 1660 sleepers/ Km.; 300 mm ballast.* (c) 52 Kg 72 UTS;PSC 1540 sleepers/ Km.; 300 mm ballast. (d) 90 R;PSC 1340 sleepers/ Km.; 250 mm ballast.

Description : Track structure for CC+8 t+ 2 t loaded trains is:- (a) 52 Kg 90 UTS;PSC 1540 sleepers/ Km.; 250 mm ballast. (b) 60 Kg 90 UTS;PSC 1660 sleepers/ Km.; 300 mm ballast.* (c) 52 Kg 72 UTS;PSC 1540 sleepers/ Km.; 300 mm ballast. (d) 90 R;PSC 1340 sleepers/ Km.; 250 mm ballast.

Last Answer : b) 60 Kg 90 UTS;PSC 1660 sleepers/ Km.; 300 mm ballast.*

An antenna has a radiation resistance of 72 Ω a loss resistance of 8 Ω and a power gain of 16. Find efficiency and directivity.

Description : An antenna has a radiation resistance of 72 Ω a loss resistance of 8 Ω and a power gain of 16. Find efficiency and directivity.

Last Answer : An antenna has a radiation resistance of 72 Ω a loss resistance of 8 Ω and a power gain of 16. Find efficiency and directivity.

Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Description :  Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Last Answer : C Total time taken = 4 hours; Time of stoppage = 1 hour, that is, actual time taken = 4 hours - 1 hours = 3 hours Speed = Distance/Time = 216/3 = 72 km/hr Average speed = Total Distance/ Total Time = 216/4 = 54 km/hr

P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another Rs 18 lakh few years. At the end of 10 years profit Of R is equal to sum of profit of P and Q. Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11

Description : P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another ... Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11 

Last Answer : Answer: C) Ratio of their profit P, Q, R is 54*4+36*6:72*6+90*4:108*x+126*(10-x) =12:22:35 - 0.5x Profit of R=profit of P +profit of Q 35-0.5x=12+22 X=2 year The number of years for R invests Rs 126 lakh =10-2=8years

How many kg of dal at Rs.8.40 per kg be mixed with32 kg of dall at Rs10.20 per kg to get a mixture worth Rs.9.60 per kg? a) 23 b) 49 c) 43 d) 72 e) 16

Description : How many kg of dal at Rs.8.40 per kg be mixed with32 kg of dall at Rs10.20 per kg to get a mixture worth Rs.9.60 per kg? a) 23 b) 49 c) 43 d) 72 e) 16

Last Answer : E By the rule of allegation ,we have Quantity of 1st kind dall : Quantity of 2nd kind dall = 60 : 120  => Quantity of 1st kind dall:32 = 1:2  Quantity of 1st kind dall =32 *1/2 = 16