What is 3.56 divided by 0.72 4.94 or 0.04?

What is 3.56 divided by 0.72 4.94 or 0.04?
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4.94
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A pure drug is administered as a sphere and as a cube. The amount of drug is the same in the two tablets. Assuming that the shape and size do not influence the mass transfer, the ratio of rate of dissolution in water at t = 0for the cubic to spherical tablet is: (A) 0.54 (B) 1.04 (C) 1.24 (D) 1.94

Description : A pure drug is administered as a sphere and as a cube. The amount of drug is the same in the two tablets. Assuming that the shape and size do not influence the mass transfer, the ratio of rate of dissolution in water at t ... tablet is: (A) 0.54 (B) 1.04 (C) 1.24 (D) 1.94

Last Answer : (C) 1.24

A wall of the firebrick has an inside temperature of 313ºF and an outside temperature of 73ºF. What is the difference in the surface temperature in Rankin?  a. 70  b. 68  c. 72  d. 94 ºR = ºF + 460

Description : A wall of the firebrick has an inside temperature of 313ºF and an outside temperature of 73ºF. What is the difference in the surface temperature in Rankin?  a. 70  b. 68  c. 72  d. 94 ºR = ºF + 460

Last Answer : 70

In an competitive examination, the average was found to be 72 marks. After detecting the errors the marks of 94 candidates had to be charged from 90 to 66 each, and the average is reduced to 64 marks. Find the total number of candidates who took the exam. A) 282 B) 382 C) 828 D) 200

Description : In an competitive examination, the average was found to be 72 marks. After detecting the errors the marks of 94 candidates had to be charged from 90 to 66 each, and the average is reduced to 64 marks. Find the total number of candidates who took the exam. A) 282 B) 382 C) 828 D) 200 

Last Answer :  A)  let the number of candidates be A total marks of candidates = 72A after detecting error the change of marks for one candidate = 90 - 66 = 24 marks change of marks for 94 candidates = 94*24 = ... after detecting error of N candidates = 64A then, 72A- 2256= 64A , 8A=2256 A=282

How can 11-04-47, 11-11-72, 09-23-75 and 09-16-79 all fall on the same day of the week?

Description : How can 11-04-47, 11-11-72, 09-23-75 and 09-16-79 all fall on the same day of the week?

Last Answer : Need Answer

On Ashok marg, three consecutive traffic lights change after 36, 42 and 72 seconds respectively. If the lights are switched on at 9.00 A.M sharp, at what time will they change simultaneously? a) 9 :08 :44 b) 9:08:24 c) 9:08:04 d) 9:08:34

Description : On Ashok marg, three consecutive traffic lights change after 36, 42 and 72 seconds respectively. If the lights are switched on at 9.00 A.M sharp, at what time will they change simultaneously? a) 9 :08 :44 b) 9:08:24 c) 9:08:04 d) 9:08:34

Last Answer : b) 9:08:24

A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6.26, CO : 1.56, O2 : 3.91, H2O :15.66, N2 : 72.60 (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02 (C) CO2 : 6.39, CO : 1.60, O2 : 3.99, H2O:25.96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02

The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Description : The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Last Answer : (D) 72,000

53 × 47 + 64 × 56 -72 × 68 = ? a) 1221 b) 1403 c) 1249 d) 1337 e) 1179

Description : 53 × 47 + 64 × 56 -72 × 68 = ? a) 1221 b) 1403 c) 1249 d) 1337 e) 1179

Last Answer : Answer: e)

?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Description : ?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Last Answer : ?% × 725 +14 × 21=700 =>?% × 725 +294 =700 => ?% × 725 =406 =>?=406/725 × 100 =56 Answer: d)

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of the replacement of A and now the average weight is 72 kg. Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Description : The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of ... . Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Last Answer : 3) 56 kg

A circular pipe is subjected to maximum shear force of 60 kN. What is the diameter of the pipe if maximum allowable shear stress is 5 Mpa? a. 27.311 mm b. 75.56 mm c. 142.72 mm d. 692.10 mm

Description : A circular pipe is subjected to maximum shear force of 60 kN. What is the diameter of the pipe if maximum allowable shear stress is 5 Mpa? a. 27.311 mm b. 75.56 mm c. 142.72 mm d. 692.10 mm

Last Answer : c. 142.72 mm

Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Description : Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Last Answer : (C) 72

A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the certain place. What is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Description : A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the ... is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Last Answer : B Let speed of the jeep =x kmph Then, speed of the bus =(100+25)x/100 =125x/100 =5x/4 kmph Time taken by the jeep to travel from P to Q =225/x hours Time taken by the bus to travel from p to Q =225/(5x/4) + ... 225/x=900/5x+37.5/60 225/x=180/x+37.5/60 45/x =37.5/60 37.5x=45*60 X=72 km/hr

A students maks were wrongly entered as 72 instead of 52. Due to that the average marks for the class got increased by half. The number of students in the class is. A) 50 B) 56 C) 46 D) 40

Description : A students maks were wrongly entered as 72 instead of 52. Due to that the average marks for the class got increased by half. The number of students in the class is. A) 50 B) 56 C) 46 D) 40

Last Answer : D)  Let there be y students in the class Total increase in marks = y *1/2 = y/2 Therefore y/2 = (72 – 52) y/2 = 20 y = 40

If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241

Description :  If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241

Last Answer : Answer: A Fraction is x/y (x + 400/100 x ) / (y + 300/100 y) = 18/35 (500/100) x(35) = (400/100)y (18) (5x) × 35 = 18 × 4 y 175 x = 72 y x/y = 72/175

What is 860 divided by 0.04?

Description : What is 860 divided by 0.04?

Last Answer : 21500

What is the answered to 0.04 divided by 680?

Description : What is the answered to 0.04 divided by 680?

Last Answer : 0.0001

What is 860 divided by 0.04?

Description : What is 860 divided by 0.04?

Last Answer : 21500

What is 14.36 divided by 0.04?

Description : What is 14.36 divided by 0.04?

Last Answer : 359

What is 94.3 divided by 8.2?

Description : What is 94.3 divided by 8.2?

Last Answer : 11.5

What is 94 divided by 47?

Description : What is 94 divided by 47?

Last Answer : 2

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

what is 6500 divided by 56 not the calculater answer?

Description : what is 6500 divided by 56 not the calculater answer?

Last Answer : 116, 56s goes into 6500.

What is 56.48 divided by 3 equal?

Description : What is 56.48 divided by 3 equal?

Last Answer : 18.8267

What is the quotient of the whole number 56 divided by the fraction 18?

Description : What is the quotient of the whole number 56 divided by the fraction 18?

Last Answer : 3.1111

4 divided by 56?

Description : 4 divided by 56?

Last Answer : 0.0714

Dhivya, Dinesh and Deepi enter into a partnership and their shares are in the ratio 1/3 :1/4 :1/5. After 2 months, dhivya withdraws half of her capital and after 10 months, a profit of Rs. 462 is divided among them, what is Deepi’s share? A) 123.56 B) 165.45 C) 143.3 D) 146.43

Description : Dhivya, Dinesh and Deepi enter into a partnership and their shares are in the ratio 1/3 :1/4 :1/5. After 2 months, dhivya withdraws half of her capital and after 10 months, a profit of Rs. 462 is divided among them, what is Deepi’s share? A) 123.56 B) 165.45 C) 143.3 D) 146.43

Last Answer : Answer: C) Ratio of initial investments = 1/3 : 1/4 : 1/5 = 20 :15 :12 Let their initial investments be 20x, 15x and 12x respectively Dhivya: Dinesh :Deepi = (20x *2 +10x *10) : (15x *12) : (12x*12) =140x : ... 70:90:72 = 35 : 45 :36 Deepi s share = Rs.462 * 36/116 = Rs(16632/116) =Rs.143.3

What is 72 divided by to get 8?

Description : What is 72 divided by to get 8?

Last Answer : 9

What is 192 divided by 72?

Description : What is 192 divided by 72?

Last Answer : 2.6667

What is 4968 divided by 72?

Description : What is 4968 divided by 72?

Last Answer : 69

What is 4968 divided into 72?

Description : What is 4968 divided into 72?

Last Answer : 69

What is 72 divided by 4968?

Description : What is 72 divided by 4968?

Last Answer : 0.0145

What is 72 divided by something equals 6?

Description : What is 72 divided by something equals 6?

Last Answer : 12

What is the difference between 72 846 divided by twice of three and seventy-five multiplied twice?

Description : What is the difference between 72 846 divided by twice of three and seventy-five multiplied twice?

Last Answer : Need answer

What is 72 divided by 4968?

Description : What is 72 divided by 4968?

Last Answer : 0.0145

72 tens divided by 9 tens?

Description : 72 tens divided by 9 tens?

Last Answer : 8

The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Description : What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Last Answer : c. 78.94 mts/sec2

Using the following thermochemical data. `C(S)+O_(2)(g)rarr CO_(2)(g), Delta H=94.0` Kcal `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l), Delta H=-68.0` Kcal `C

Description : Using the following thermochemical data. `C(S)+O_(2)(g)rarr CO_(2)(g), Delta H=94.0` Kcal `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l), Delta H=-68.0` Kcal `C

Last Answer : Using the following thermochemical data. `C(S)+O_(2)(g)rarr CO_(2)(g), Delta H=94.0` Kcal `H_(2)(g)+1// ... .0` Kcal C. `-114.0` Kcal D. `+114.0` Kcal

`C(s)+O_(2)(g)rarr CO_(2)(g)+94.0` K cal. `CO(g)+(1)/(2)O_(2)(g)rarr CO_(2)(g), Delta H=-67.7` K cal. From the above reactions find how much heat (Kca

Description : `C(s)+O_(2)(g)rarr CO_(2)(g)+94.0` K cal. `CO(g)+(1)/(2)O_(2)(g)rarr CO_(2)(g), Delta H=-67.7` K cal. From the above reactions find how much heat (Kca

Last Answer : `C(s)+O_(2)(g)rarr CO_(2)(g)+94.0` K cal. `CO(g)+(1)/(2)O_(2)(g)rarr CO_(2)(g), Delta H=-67.7` K cal. ... g)` A. `20.6` B. `26.3` C. `44.2` D. `161.6`

The heat of combustion of `CH_(4(g)), C_((g))` and `H_(2(g))` at `25^(@)C` are `-212.4` K cal, -94.0 K cal and -68.4 K cal respectively, the heat of f

Description : The heat of combustion of `CH_(4(g)), C_((g))` and `H_(2(g))` at `25^(@)C` are `-212.4` K cal, -94.0 K cal and -68.4 K cal respectively, the heat of f

Last Answer : The heat of combustion of `CH_(4(g)), C_((g))` and `H_(2(g))` at `25^(@)C` are `-212.4` K cal, -94.0 ... .4` K cal C. `-375.2` K cal D. `+212.8` K cal

What is 0.194 (94 repeating) as a fraction?

Description : What is 0.194 (94 repeating) as a fraction?

Last Answer : It is 193/990.

What is 0.94 rounded to the nearest 10th?

Description : What is 0.94 rounded to the nearest 10th?

Last Answer : 0.9

Hydrated density of HD lipoproteins is (A) 0.94 gm/ml (B) 0.94–1.006 gm/ml (C) 1.006–1.063 gm/ml (D) 1.063–1.21 gm/ml

Description : Hydrated density of HD lipoproteins is (A) 0.94 gm/ml (B) 0.94–1.006 gm/ml (C) 1.006–1.063 gm/ml (D) 1.063–1.21 gm/ml

Last Answer : Answer : D

Hydrated density of (HD) lipoproteins is (A) 0.94 gm/ml (B) 0.94-1.006 gm/ml (C) 1.006-1.063 gm/ml (D) 1.063-1.21 gm/l

Description : Hydrated density of (HD) lipoproteins is (A) 0.94 gm/ml (B) 0.94-1.006 gm/ml (C) 1.006-1.063 gm/ml (D) 1.063-1.21 gm/l

Last Answer : Answer : B

The percentage of Nitrogen in Air is - (1) 0.94 (2) 0.03 (3) 78.03 (4) 85.02

Description : The percentage of Nitrogen in Air is - (1) 0.94 (2) 0.03 (3) 78.03 (4) 85.02

Last Answer : (3) 78.03 Explanation: By volume, thy air contains 78.09% nitrogen, 20.95% oxygen, 0.93% argon, 0.039% carbon dioxide, and small amounts of other gases. Air also contains a variable amount of water vapor, on average around 1%.

If D is the diameter of a circular sewer and D’ is the top horizontal diameter of an equivalent egg shaped section, the relationship which holds good, is A. D’ = 0.64 D B. D’ = 0.74 D C. D’ = 0.84 D D. D’ = 0.94 D

Description : If D is the diameter of a circular sewer and D’ is the top horizontal diameter of an equivalent egg shaped section, the relationship which holds good, is A. D’ = 0.64 D B. D’ = 0.74 D C. D’ = 0.84 D D. D’ = 0.94 D

Last Answer : ANS: C

Calculated the noise figure of the amplifier whose Req equals 2518Ω (RT=600Ω) if its driven by a generator whose output impedance is 50Ω. A. 39.4 B. 3.94 C. 394 D. 0.394

Description : Calculated the noise figure of the amplifier whose Req equals 2518Ω (RT=600Ω) if its driven by a generator whose output impedance is 50Ω. A. 39.4 B. 3.94 C. 394 D. 0.394

Last Answer : A. 39.4