Is this statement true or falseThe incenter of a triangle is equidistant from the sides of the triangle?

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Description : what- A city is planning to have music in the park. The locations of the food, music, and parking form a triangle, as shown. Planners would like the recycling bins to be located equidistant from the places.Where will the recycling bins be located?

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Description : The statement --- if forces acting on a point can be represented in magnitude and direction by the sides of a polygon taken in order then their resultant will be represented in magnitude and direction by the closing ... 's law of forces c.Law of polygon of forces d.D'Alembert's rule e.Lami's theorem

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Description : Twelve flags stand equidistant along the track at the stadium. The runners start at the first flag. A runner reaches the eighth flag 8 seconds after he starts. If he runs at an even speed, how many seconds does he need altogether to reach the twelfth flag? -Riddles

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Description : Point on Y-axis is equidistant from 5,4 and - 2,3 is -Maths 9th

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Description : Point on Y-axis is equidistant from 5,4 and - 2,3 is -Maths 9th

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Description : The locus of a point in rhombus ABCD which is equidistant from A and C is -Maths 9th

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Description : If the points (2, 1) and (1, – 2) are equidistant from the point (x, y), show that x + 3y = 0. -Maths 9th

Last Answer : (a) The distance d between any two points say P(x1, y1) and Q(x2, y2) is given by:d = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)⇒ d2 = (x2 - x1)2 + (y2 - y1)2 ⇒ d = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)( ... distance of a point P(x1, y1) form the origin= \(\sqrt{(x_2-0)^2+(y_2-0)^2}\) = \(\sqrt{x^2_1+y^2_1}\)

Description : The point whose abscissa is equal to its ordinate and which is equidistant from A(–1, 0) and B(0, 5) is -Maths 9th

Last Answer : Putting \(x\) = 0 in equation of one of the lines say 9\(x\) + 40y -20 = 0, we get y = \(rac{1}{2}\)∴ A point on 9\(x\) + 40y - 20 = 0 is \(\big(0,rac{1}{2}\big)\)∴ Distance of \(\big(0,rac{1}{2}\big) ... imesrac{1}{2}+21\big|}{\sqrt{9^2+40^2}}\) = \(rac{|41|}{\sqrt{1681}}\) = \(rac{41}{41}\) = 1.

Description : The point P is equidistant from A(1, 3), B(–3, 5) and C(5, –1). Then PB is equal to : -Maths 9th

Last Answer : (b) (2, 2)Let the point be P whose abscissa = ordinate = a. ∴ P ≡ (a, a) Given, PA = PB ⇒ (a + 1)2 + a2 = a2 + (a – 5)2 ⇒ 2a2 + 2a + 1 = 2a2 – 10a + 25 ⇒ 12a = 24 ⇒ a = 2. ∴ The point is (2, 2).

Description : If M(x, y) is equidistant from A(a + b, b – a) and B(a – b, a + b), then -Maths 9th

Last Answer : (b)10 + \(5\sqrt2\)Perimeter of ΔABC = AB + BC + CA= \(\sqrt{(0+4)^2+(-1-2)^2}\) + \(\sqrt{(3-0)^2+(3+1)^2}\) + \(\sqrt{(3-4)^2+(3-2)^2}\)= \(\sqrt{16+9}\) + \(\sqrt{9+16}\) +\(\sqrt{49+1}\)= \(\sqrt{25}\) + \(\sqrt{25}\) + \(\sqrt{50}\) = 5 + 5 + \(5\sqrt2\) = 10 + \(5\sqrt2\)

Description : If point A (0,2) is equidistant from the point B (3, p)and C (p, 5), find p. -Maths 9th

Last Answer : Given, AB=AC (AB)2=(AC)2 Distance between two points=(x2​−x1​)2+(y2​−y1​)2​(AB)2=(AC)2⟹(0−3)2+(2−p)2=(0−p)2+(2−5)2 9+4+p2−4p=p2+9 p=1 Distance=(0−3)2+(2−1)2​Distance=10​

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Last Answer : (1) avoid the tracks being distorted due to seasonal temperature variation Explanation: A small gap is left at the joints of rails in a railway track to provide space for the expansion of rail pieces when the temperature rises during summer.

Description : The difference of levels between two stations A and B is to be determined. For best results, the instrument station should be (A) Equidistant from A and B (B) Closer to the higher station (C) Closer to the lower station (D) As far as possible from the line AB

Last Answer : (A) Equidistant from A and B

Description : The neutral axis of a beam cross-section must (A) Pass through the centroid of the section (B) Be equidistant from the top of bottom films (C) Be an axis of symmetry of the section (D) None of these

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Description : A small gap is left at the joints of rails in a railway track to (1) avoid the tracks being distorted due to seasonal temperature variation (2) avoid the heating of tracks to high temperature (3) control the speed of train (4) keep the rails equidistant

Last Answer : avoid the tracks being distorted due to seasonal temperature variation

Description : There are 3 poles M, N and O in a straight line such that point N is equidistant from points M and O. A boat can travel from point M to O downstream in 6 hours and from N to M upstream in 4 hours. Find the ratio of boat in still water to speed of stream. A) 2:3 B) 7:1 C) 3:2 D) 1:7

Last Answer : ANSWER: B Explanation: Let speed in still water = x km/hr, of current = y km/hr Downstream speed = (x+y) km/hr Upstream speed = (x - y) km/hr Let MO = 2p km. So MN = NO = p km.  So 2p/(x+y) = 6 --------1  p/ ... - 2y) = 6x + 6y  8x - 8y = 6x +6y  2x = 14y  x/y = 14 / 2 = 7/1  x : y = 7 :1

Description : X, Y , Z are three towns on a lake which flows uniformly. Y is equidistant from X and Z. A man rows from X to Y and returns in 20hrs. He can row from X to Z in 8 hr. The ratio of speed of the man in still water to the speed of the current is. A) 3:5 B) 5:3 C) 2:3 D) None of these

Last Answer : ANSWER: A Explanation: Let the speed of man in still water = x km/hr Speed of the current = y km/hr Speed of downstream = (x+ y) km/hr Speed of upstream = ( x - y) km/hr Let the lake be flowing from X to Z and  xy = yz a ... y = 1 / 4  4x - 4y = x + y  3x = 5y x / y = 3 / 5 x : y = 3 : 5

Description : Is it possible for a right angled triangle with sides 3 and 4 units long to have a hypotenuse 6 units in length?

Last Answer : answer:I'm not quite getting you. It isn't actually a triangle when the hypotenuse has these indentations, right? The hypotenuse isn't a straight line as you describe it. If the other sides are 3 ... and 5.00001, you don't have a straight line. Unless I'm misunderstanding what you're suggesting.

Description : A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm (see figure). -Maths 9th

Last Answer : NCERT Solutions for Class 9 Maths Chapter 12 Heron's Formula NCERT Solutions for Class 9 Maths Chapter 12 Heron's Formula Ex 12.1 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths ... = 48 m Sides ∆ABC are a = AB = 30m, b = AD = 30m, c = BD = 48m S

Description : A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base 8 cm and sides 6 cm each is to be made of three different shades as shown in figure. -Maths 9th

Last Answer : Each shade of paper is divided into 3 triangles i.e., I, II, III 8 cm For triangle I: ABCD is a square [Given] ∵ Diagonals of a square are equal and bisect each other. ∴ AC = BD = 32 cm Height of AABD ... are: Area of shade I = 256 cm2 Area of shade II = 256 cm2 and area of shade III = 17.92 cm2

Description : A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, -Maths 9th

Last Answer : For the given triangle, we have a = 28 cm, b = 30 cm, c = 26 cm Area of the given parallelogram = Area of the given triangle ∴ Area of the parallelogram = 336 cm2 ⇒ base x height = 336 ⇒ ... be the height of the parallelogram. ⇒ h = 33628 = 12 Thus, the required height of the parallelogram = 12 cm