There are three events A, B and C, one of which must and can only happen. If the odds one 8 : 3 against A, 5 : 2 against -Maths 9th

There are three events A, B and C, one of which must and can only happen. If the odds one 8 : 3 against A, 5 : 2 against -Maths 9th
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1 Answer

Answer :

(c) \(rac{3}{8}\)Total number of ways of checking in the 4 hotels by 3 men = 4 × 4 × 4 = 43. Number of ways in which each man checks into a different hotel = 4 × 3 × 2 (As for the 1st person, there are 4 choices, for 2nd remaining 3, and for the 3rd remaining 2). ∴ P(Each person checks into a different hotel)= \(rac{4 imes3 imes2}{4 imes4 imes4}\) = \(rac{3}{8}\).
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Related questions

There are three events A, B and C , one of which must and only can happen. If the odds are 8:3 against A, 5:2 against B, then the odds against C must be: e) 13:7 f) 3:2 g) 43:77 h) 43:34

Description : There are three events A, B and C , one of which must and only can happen. If the odds are 8:3 against A, 5:2 against B, then the odds against C must be: e) 13:7 f) 3:2 g) 43:77 h) 43:34

Last Answer : Answer : d

There are three events E1, E2 and E3, one of which is must and only one can happen. -Maths 9th

Description : There are three events E1, E2 and E3, one of which is must and only one can happen. -Maths 9th

Last Answer : Since one and only one of the three events E1, E2 and E3 can happen, i.e, they are mutually exclusive. Therefore, P(E1) + P(E2) + P(E3) = 1 ...(i) Odds against E1 are 7 : 4 ⇒ Odds in favour of E1 are 4 : 7⇒ ... \(rac{1-rac{23}{88}}{rac{23}{88}}\) = \(rac{rac{65}{88}}{rac{23}{88}}\) = 65 : 23.

The odds against certain event are 5:2 and the odds in favour of another in dependent event are 6:5. The probability that at least one of -Maths 9th

Description : The odds against certain event are 5:2 and the odds in favour of another in dependent event are 6:5. The probability that at least one of -Maths 9th

Last Answer : (c) \(rac{52}{77}\)Given, odds against Event 1 = 5 : 2⇒ P(Event 1 not happening) = \(rac{5}{5+2}\) = \(rac{5}{7}\)Odds in favour of Event 2 = 6 : 5⇒ P(Event 2 happens) = \(rac{6}{6+5}\) = \( ... }\)(∵ Both event are independent)⇒ P(At least one event happens) = 1 - \(rac{25}{77}\) = \(rac{52}{77}\).

The odds against a certain event is 5 : 2 and the odds in favour of another event is 6 : 5. If the both the events are independent, then the probabili

Description : The odds against a certain event is 5 : 2 and the odds in favour of another event is 6 : 5. If the both the events are independent, then the probabili

Last Answer : The odds against a certain event is 5 : 2 and the odds in favour of another event is 6 : 5. If the both the ... B. `52/77` C. `25/88` D. `63/88`

If the three independent events E1, E2 and E3, the probability that only E1 occurs is α, E2 occurs -Maths 9th

Description : If the three independent events E1, E2 and E3, the probability that only E1 occurs is α, E2 occurs -Maths 9th

Last Answer : (c) 6Let \(x\), y, z be the probabilities of happening of events E1, E2 and E3 respectively. Then, \(\alpha\) = P (occurrence of E1 only) = x (1 - y) (1 - z) \(\beta\) = P (occurrence of E2 only) = (1 - \(x\)) y (1 - ... (x\) = 6z (From (i) and (ii))⇒ \(rac{x}{z}\) = 6 ⇒ \(rac{P(E_1)}{P(E_3)}\) = 6.

What are the odds....freaky chance events?

Description : What are the odds....freaky chance events?

Last Answer : The odds are indeed small. But you should realize that with so many people on Earth, and with so much time that goes on, improbable events such as this become increasingly probable! Because I understand the ... , I do not consider it as God having a chuckle as I don't believe a god exists.

The probability of student A passing examination is 3/7 and of student B passing is 5/7 Assuming the two events “A passes”, -Maths 9th

Description : The probability of student A passing examination is 3/7 and of student B passing is 5/7 Assuming the two events “A passes”, -Maths 9th

Last Answer : p1 = P(A) = \(rac{3}{7}\), p2 = P(B) = \(rac{5}{7}\) ∴ q1 = P(\(\bar{A}\)) = 1 - P(A) = 1 - \(rac{3}{7}\) = \(rac{4}{7}\). q2 = P(\(\bar{B}\)) = 1 - P(B) = 1 - \(rac{5}{7}\) = \(rac{2}{7}\) ... passes) = p1 q2 + q1 p2 = \(rac{3}{7}\) x \(rac{2}{7}\) + \(rac{4}{7}\) x \(rac{5}{7}\) = \(rac{26}{49}.\)

A coin is tossed thrice and all eight outcomes are assumed equally likely. Find whether the events E -Maths 9th

Description : A coin is tossed thrice and all eight outcomes are assumed equally likely. Find whether the events E -Maths 9th

Last Answer : When a coin is tossed three times, the sample space is given by S = [HHH, HHT, HTH, THT, THH, HTT, TTH, TTT] E = {HHH, HTT, THT, TTH}, F = {TTT, HTH, THH, HHT}E ∩ F = ϕP(E) = \(rac{4}{8}\) = \(rac{1}{2}\ ... rac{1}{2}\) x \(rac{1}{2}\) x \(rac{1}{4}\) ≠ P(E ∩ F) ∴ E and F are not independent events.

Let a pair of fair coins be tossed. Here S = {HH, HT, TH, TT}. Consider the events A = {heads on the first coin} = {HH, HT}, -Maths 9th

Description : Let a pair of fair coins be tossed. Here S = {HH, HT, TH, TT}. Consider the events A = {heads on the first coin} = {HH, HT}, -Maths 9th

Last Answer : ThenP (A) = P (B) = P (C) = \(rac{2}{4}\) = \(rac{1}{2}\) andP (A ∩ B) = P ({HH}) = \(rac{1}{4}\), P (A ∩ C) = P ({HT}) = \(rac{1}{4}\)P ( ... C)Thus condition (i) is satisfied, i.e., the events are pairwise independent. But condition (ii) is not satisfied and so the three events are not independent

What do you mean by Exhaustive Events? -Maths 9th

Description : What do you mean by Exhaustive Events? -Maths 9th

Last Answer : The total number of possible outcomes of a random experiment is called exhaustive events. Ex. (i) In tossing a coin, exhaustive events are 2 (Head or tail) (ii) In throwing a die, the exhaustive number of cases ... number of cases is 52 C4, since 4 cards can be drawn out of 52 cards in 52 C4 ways.

What do you mean by Mutually Exclusive Events? -Maths 9th

Description : What do you mean by Mutually Exclusive Events? -Maths 9th

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Description : Define : Algebra of Events. -Maths 9th

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A and B are two mutually exclusive and exhaustive events with P(B) = 3P(A). What is the value of P (bar(B)) ? -Maths 9th

Description : A and B are two mutually exclusive and exhaustive events with P(B) = 3P(A). What is the value of P (bar(B)) ? -Maths 9th

Last Answer : (c) 43 : 34Given, odds against A = 8 : 3⇒ P(not A) = \(rac{8}{8+3}\) = \(rac{8}{11}\) ⇒ P(A happens) = \(rac{3}{11}\)Odds against B = 5 : 2⇒ P(not B) = \(rac{5}{5+2}\) = \(rac{5}{7}\) ⇒ P(B happens ... {43}{77}\)odds against C = \(rac{P(not\,c)}{P(c)}\) = \(rac{rac{43}{77}}{rac{34}{77}}\) = 43 : 34.

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Description : What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

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The probability of India winning a test match against Westindies is 1/2 . -Maths 9th

Description : The probability of India winning a test match against Westindies is 1/2 . -Maths 9th

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Description : A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base 8 cm and sides 6 cm each is to be made of three different shades as shown in figure. -Maths 9th

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Description : l,m and n are three parallel lines intersected by transversal p and q such that l,m and n cut-off equal intersepts AB and BC on p (Fig.8.55). Show that l,m and n cut - off equal intercepts DE and EF on q also. -Maths 9th

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If three cubes of copper, each with an edge 6 cm, 8 cm and 10 cm respectively are melted to form a single cube, -Maths 9th

Description : If three cubes of copper, each with an edge 6 cm, 8 cm and 10 cm respectively are melted to form a single cube, -Maths 9th

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The volume of a certain rectangular solid is 8 cm^3. Its total surface area is 32 cm^2 and its three dimensions are in geometric progression. -Maths 9th

Description : The volume of a certain rectangular solid is 8 cm^3. Its total surface area is 32 cm^2 and its three dimensions are in geometric progression. -Maths 9th

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Description : ‘If two sides and an angle of one triangle are equal to two sides and an angle of another triangle , then the two triangles must be congruent’. -Maths 9th

Last Answer : No, because in the congruent rule, the two sides and the included angle of one triangle are equal to the two sides and the included angle of the other triangle i.e., SAS rule.

What must be substract from x(to the power 4) + 3x(cube) + 4x(square) - 3x - 6 to get 3x(cube) + 4x(square) - x + 3? -Maths 9th

Description : What must be substract from x(to the power 4) + 3x(cube) + 4x(square) - 3x - 6 to get 3x(cube) + 4x(square) - x + 3? -Maths 9th

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Prove that a triangle must have atleast two acute angles. -Maths 9th

Description : Prove that a triangle must have atleast two acute angles. -Maths 9th

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Description : In how many ways can the letters of the word “AFLATOON” be arranged if the consonants and vowels must occupy alternate places? -Maths 9th

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In the given figure, line DE is parallel to line AB. CD = 3 while DA = 6. Which of the following must be true? -Maths 9th

Description : In the given figure, line DE is parallel to line AB. CD = 3 while DA = 6. Which of the following must be true? -Maths 9th

Last Answer : answer:

What are the odds of a cancer patient surviving ten years without eating or drinking orally and being fed liquids only pumped into the stomach?

Description : What are the odds of a cancer patient surviving ten years without eating or drinking orally and being fed liquids only pumped into the stomach?

Last Answer : I would suggest editing this question to include better tags. Your only tag is cancer and survival. It is unlikely this will be routed to anyone who can help because cancer and ... , doctor, doctors, cancer, probability, survival, prognosis, expectancy, eating, drinking, stomach, throat.

What are the odds of a human getting sick if they opened up a can of expired bienna sausages that expired in april of 2021, rinsed them off, and only ate one?

Description : What are the odds of a human getting sick if they opened up a can of expired bienna sausages that expired in april of 2021, rinsed them off, and only ate one?

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Description : The Three attributes of project risk are _________, ___________ and ___________. 1. What might happen, who it happens to, and how much will it cost  2. Notification, frequency of relevant events, ... planning, total number of risk events 5. Risk event, probability occurrence, the amount at stake

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5. In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively (see Fig. 8.31). Show that the line segments AF and EC trisect the diagonal BD. -Maths 9th

Description : 5. In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively (see Fig. 8.31). Show that the line segments AF and EC trisect the diagonal BD. -Maths 9th

Last Answer : . Solution: Given that, ABCD is a parallelogram. E and F are the mid-points of sides AB and CD respectively. To show, AF and EC trisect the diagonal BD. Proof, ABCD is a parallelogram , AB || CD also, ... (i), DP = PQ = BQ Hence, the line segments AF and EC trisect the diagonal BD. Hence Proved.

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Description : How many bricks will be required to construct a wall 8 m long, 6 m high and 22.5 cm thick, if each brick measures 25 cm x 11.25 cm x 6 cm? -Maths 9th

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The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

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Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

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In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Description : In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Last Answer : (a) We know that, the perpendicular from the centre of a circle to a chord bisects the chord. AC = CB = 1/2 AB = 1/2 x 8 = 4 cm given OA = 5 cm AO2 = AC2 + OC2 (5)2 = (4)2 + OC2 25 = 16 + OC2 ... length is always positive] OA = OD [same radius of a circle] OD = 5 cm CD = OD - OC = 5 - 3 = 2 cm

How many bricks will be required to construct a wall 8 m long, 6 m high and 22.5 cm thick, if each brick measures 25 cm x 11.25 cm x 6 cm? -Maths 9th

Description : How many bricks will be required to construct a wall 8 m long, 6 m high and 22.5 cm thick, if each brick measures 25 cm x 11.25 cm x 6 cm? -Maths 9th

Last Answer : ∵ Volume of one brick = (25 × 11.25 × 6) cm3 and volume of the wall = (800 × 600 × 22.5) cm3 ∴ Number of bricks = Volume of the walls / Volume of one brick = 800 × 600 × 22.5 / 25 × 11.25 × 6 = 6400

The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Description : In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Last Answer : (a) We know that, the perpendicular from the centre of a circle to a chord bisects the chord. AC = CB = 1/2 AB = 1/2 x 8 = 4 cm given OA = 5 cm AO2 = AC2 + OC2 (5)2 = (4)2 + OC2 25 = 16 + OC2 ... length is always positive] OA = OD [same radius of a circle] OD = 5 cm CD = OD - OC = 5 - 3 = 2 cm

A football player scored the following number of goals in the 10 matches 1, 3, 2, 5, 8, 6,1, 4, 7 and 9. Since, the number of matches is 10 (an even number), therefore -Maths 9th

Description : A football player scored the following number of goals in the 10 matches 1, 3, 2, 5, 8, 6,1, 4, 7 and 9. Since, the number of matches is 10 (an even number), therefore -Maths 9th

Last Answer : NEED ANSWER

If (8/15)^3 - (1/3)^3 - (1/5)^3 = x/75, find x. -Maths 9th

Description : If (8/15)^3 - (1/3)^3 - (1/5)^3 = x/75, find x. -Maths 9th

Last Answer : NEED ANSWER

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : NEED ANSWER

A football player scored the following number of goals in the 10 matches 1, 3, 2, 5, 8, 6,1, 4, 7 and 9. Since, the number of matches is 10 (an even number), therefore -Maths 9th

Description : A football player scored the following number of goals in the 10 matches 1, 3, 2, 5, 8, 6,1, 4, 7 and 9. Since, the number of matches is 10 (an even number), therefore -Maths 9th

Last Answer : No. It is not the correct answer, because the data have to be arranged in ascending or descending order before finding the median. Arranging the data in ascending order 1,1,2, 3, 4, 5, 6, 7, 8, 9. Here, number of observations is 10, which is even.