Eighteen quests have to be seated, half on each side of a long table. Four particular guests desire to sit on one particular side and -Maths 9th

Eighteen quests have to be seated, half on each side of a long table. Four particular guests desire to sit on one particular side and -Maths 9th
by

1 Answer

Answer :

Since four particular guests want to sit on particular side and three others on the other side. So, we are left with 11 guests out of which we choose 5 for side A in  ways and remaining 6 for other side in  ways. Hence, the number of selection for two sides is . Now 9 persons on each side of the table can be arranged among themselves in 9! Ways. Hence, the total number of arrangements =
by

Related questions

There are 10 persons who are to be seated around a circular table. Find the probability that two particular persons will always sit together. -Maths 9th

Description : There are 10 persons who are to be seated around a circular table. Find the probability that two particular persons will always sit together. -Maths 9th

Last Answer : Total number of ways in which 10 person can sit around a circular table = 9! (∵ We shall keep one place fixed and the rest of the 9 places will be filled in (9 8 7 6 5 4 3 2 1) ways asthere is ... probability = \(rac{2 imes8!}{9!}\) = \(rac{2 imes8!}{9 imes8!}\) = \(rac{2}{9}.\)

A committee of 11 members sit at a round table. In how many ways can they be seated if the “President” and the “Secretary” choose to sit together. -Maths 9th

Description : A committee of 11 members sit at a round table. In how many ways can they be seated if the “President” and the “Secretary” choose to sit together. -Maths 9th

Last Answer : ∴ Required number of ways of seating = 9!

In how many ways can 6 gentlemen and 3 ladies be seated round a table so that every gentleman may have a lady by his side? -Maths 9th

Description : In how many ways can 6 gentlemen and 3 ladies be seated round a table so that every gentleman may have a lady by his side? -Maths 9th

Last Answer : If each gentleman has to have a lady by his side, the seating arrangement can be done as shown below: This can be done in 5! (Gentlemen) × 3! (Ladies) = 720 ways.

6 boys and 6 girls are seated in a row. Probability that all the boys sit together is -Maths 9th

Description : 6 boys and 6 girls are seated in a row. Probability that all the boys sit together is -Maths 9th

Last Answer : (d) \(rac{1}{132}\)Let S be the sample space for arranging 6 boys and 6 girls in a row. Then, n(S) = 12! If all 6 boys are to sit together, then consider the 6 boys as one entity. Now the ... ) = \(rac{7 imes6 imes5 imes4 imes3 imes2}{12 imes11 imes10 imes9 imes8 imes7}\) = \(rac{1}{132}\).

In how many ways can 8 people sit around a circular Table? (a) 5040 (b) 40320 (c) 20160 (d) 2520 -Maths 9th

Description : In how many ways can 8 people sit around a circular Table? (a) 5040 (b) 40320 (c) 20160 (d) 2520 -Maths 9th

Last Answer : As is known in case of circular permutations, we keep one place fixed, so 8 people can sit around a circular table in (8 – 1) ! ways = 7! ways = 5040 ways.

In how many ways can 7 men and 7 women sit on a round table such that no two women sit together? -Maths 9th

Description : In how many ways can 7 men and 7 women sit on a round table such that no two women sit together? -Maths 9th

Last Answer : Now there are 7 places vacant between these 7 men. ∴ 7 women can seat themselves in these 7 places in 7 ! ways. ∴ Total number of required arrangement where no two women sit together = 6!

There are 6 numbered chairs placed around a circular table. 3 boys and 3 girls want to sit on them such that neither of two boys nor two girls -Maths 9th

Description : There are 6 numbered chairs placed around a circular table. 3 boys and 3 girls want to sit on them such that neither of two boys nor two girls -Maths 9th

Last Answer : Since the chairs are numbered, so they are distinguishable. Therefore 3 boys can be arranged on 3 alternate chairs in 3! ways. 3 girls can be arrenged in 3! ways Also, the girls can be seated before the boys. Total number of required ways = 3! × 3! + 3! × 3! = 2 × (3!)2

A person invites 15 guests for dinner and wishes to arrange them at two round tables that can accommodate 8 persons and 7 persons respectively. -Maths 9th

Description : A person invites 15 guests for dinner and wishes to arrange them at two round tables that can accommodate 8 persons and 7 persons respectively. -Maths 9th

Last Answer : answer:

The given table shows the month of birth of 40 students of class IX of a particular section in a school. -Maths 9th

Description : The given table shows the month of birth of 40 students of class IX of a particular section in a school. -Maths 9th

Last Answer : (a) P (later half of the year) = 23 / 40 (b) P (month having 31 days) = 26 / 40 = 13 / 20 (c) P(month having 30 days) = 10 / 40 = 1 / 4

The given table shows the month of birth of 40 students of class IX of a particular section in a school. -Maths 9th

Description : The given table shows the month of birth of 40 students of class IX of a particular section in a school. -Maths 9th

Last Answer : (a) P (later half of the year) = 23 / 40 (b) P (month having 31 days) = 26 / 40 = 13 / 20 (c) P(month having 30 days) = 10 / 40 = 1 / 4

Two ladies and two men are playing bridge and seated at North, East, South and West of a table. No lady is facing East. Persons sitting opposite to each other are not of the same sex. One man is facing South. Which direction are the ladies facing to? (A) East and West (B) North and West (C) South and East (D) None of these

Description : Two ladies and two men are playing bridge and seated at North, East, South and West of a table. No lady is facing East. Persons sitting opposite to each other are not of the same sex. One man is facing South. ... facing to? (A) East and West (B) North and West (C) South and East (D) None of these 

Last Answer : (B) North and West

In Candy Crush Saga, why do you need to log out of facebook to play the mystery quests?

Description : In Candy Crush Saga, why do you need to log out of facebook to play the mystery quests?

Last Answer : The game runs on a different server.

In addition to its use in the military which brass instrument was used on festive occasions to announce that dinner guests needed to sit down and stand up at the beginning and end of meal?

Description : In addition to its use in the military which brass instrument was used on festive occasions to announce that dinner guests needed to sit down and stand up at the beginning and end of meal?

Last Answer : buccina

The cost of a table is 100 more than half the cost of the chair write the statement linear equation in two varible -Maths 9th

Description : The cost of a table is 100 more than half the cost of the chair write the statement linear equation in two varible -Maths 9th

Last Answer : This answer was deleted by our moderators...

The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Description : The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Last Answer : Given = A △ABC in which D and E are the mid-points of side AB and AC respectively. DE is joined . To Prove : DE || BC and DE = 1 / 2 BC. Const. : Produce the line segment DE to F , such that DE = ... of ||gm are equal and parallel] Also, DE = EF [by construction] Hence, DE || BC and DE = 1 / 2 BC

The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Description : The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Last Answer : Given = A △ABC in which D and E are the mid-points of side AB and AC respectively. DE is joined . To Prove : DE || BC and DE = 1 / 2 BC. Const. : Produce the line segment DE to F , such that DE = ... of ||gm are equal and parallel] Also, DE = EF [by construction] Hence, DE || BC and DE = 1 / 2 BC

A husband and wife are seated facing each other with a barrier between them. Each one takes turns communicating with the other, each speaking only two words at a time. After each two-word message is conveyed, the other person answers with a one-word response. This goes on for some time, until at last, either the husband or his wife suddenly shouts out a four-word phrase which ends this scenario; however, this often causes either the husband or the wife to become angry or frustrated with the person who shouted the four-word phrase. What is going on here? -Riddles

Description : A husband and wife are seated facing each other with a barrier between them. Each one takes turns communicating with the other, each speaking only two words at a time. After each two-word message is ... or frustrated with the person who shouted the four-word phrase. What is going on here? -Riddles

Last Answer : The husband and wife are playing the old game of BATTLESHIP. The two-word communications consist of a letter and a number for the coordinates of where the ships are hidden, and the one-word responses are ... ' or 'Miss'. The final four word phrase which ends the game is, 'You Sank My Battleship!

6 boys and 6 girls are sitting in a row randomly. The probability that boys and girls sit alternately is -Maths 9th

Description : 6 boys and 6 girls are sitting in a row randomly. The probability that boys and girls sit alternately is -Maths 9th

Last Answer : (b) \(rac{1}{462}\)Let S be the sample space. Then, n(S) = Number of ways in which 6 boys and 6 girls can sit in a row = 12! Let E : Event of 6 girls and 6 boys sitting alternately. Then, the ... )= \(rac{2 imes6 imes5 imes4 imes3 imes2 imes1}{12 imes11 imes10 imes9 imes8 imes7}\) = \(rac{1}{462}\).

What is the typical height of a bar table and how many people can be seated around them?

Description : What is the typical height of a bar table and how many people can be seated around them?

Last Answer : Bar tables are typically 40'"-42" in height, with the stools being around 28"-30". The amount of people that can be seated around them varies, but it is typically 3 or 4.

Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Description : Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Last Answer : Total number of books = 700 (i) P(no defective books) = 400 / 700 = 4 / 7 (ii) P(more than 0 but less than 4 defective books) = 269 / 700 (iii) P(more than 4 defective books) = 13 / 700

Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Description : Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Last Answer : Total number of books = 700 (i) P(no defective books) = 400 / 700 = 4 / 7 (ii) P(more than 0 but less than 4 defective books) = 269 / 700 (iii) P(more than 4 defective books) = 13 / 700

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

A cylindrical rod of iron whose height is eight times its radius is melted and cast into spherical balls each of half the radius of the cylinder. -Maths 9th

Description : A cylindrical rod of iron whose height is eight times its radius is melted and cast into spherical balls each of half the radius of the cylinder. -Maths 9th

Last Answer : Let radius of iron rod = r ∴∴ Height = 8r ∴∴ Volume of iron rod =π×(r)2×8r⇒8πr3=π×(r)2×8r⇒8πr3 ⇒⇒ Radius of spherical ball =r2=r2 Volume of spherical ball =43π(r2)3=43π(r2)3 Let n balls are casted ∴n×43π(r38)=8πr3∴n×43π(r38)=8πr3 ⇒n6=8⇒n=48

How many 2 cent stamps are in a dozen? Six Twelve Eighteen Twenty-four

Description : How many 2 cent stamps are in a dozen? Six Twelve Eighteen Twenty-four

Last Answer : Twelve

There are four amendments to the Constitution about who can vote. Describe one of them. Choose one: a. Citizens seventeen (17) and older can vote. b. Citizens by birth only can vote. c. Citizens eighteen (18) and older can vote. d. Only citizens with a job can vote.

Description : There are four amendments to the Constitution about who can vote. Describe one of them. Choose one: a. Citizens seventeen (17) and older can vote. b. Citizens by birth only can vote. c. Citizens eighteen (18) and older can vote. d. Only citizens with a job can vote.

Last Answer : Correct Answer: c. Citizens eighteen (18) and older can vote.

A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each cow be getting? -Maths 9th

Description : A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each cow be getting? -Maths 9th

Last Answer : Here, each side of the rhombus = 30 m. Let ABCD be the given rhombus and the diagonal, BD = 48 m Sides ∆ABC are a = AB = 30m, b = AD = 30m, c = BD = 48m Since, a diagonal divides the rhombus into ... Area of grass for 18 cows to graze = 864 m2 ⇒ Area of grass for 1 cow to graze = 86418 m2 = 48 m2

Two cubes of side 2 cm each are joined end to end. Find the volume of the cuboid so formed. -Maths 9th

Description : Two cubes of side 2 cm each are joined end to end. Find the volume of the cuboid so formed. -Maths 9th

Last Answer : When two cubes of side 2 cm each are joined end to end then, Length (l) = (2 + 2) = 4cm Breadth (b) = 2 cm; Height (h) = 2 cm ∴ Volume of cuboid = lbh = 4 x 2 x 2 = 16 cm3

PQRS is a parallelogram, in which PQ = 12 cm and its perimeter is 40 cm. Find the length of each side of the parallelogram . -Maths 9th

Description : PQRS is a parallelogram, in which PQ = 12 cm and its perimeter is 40 cm. Find the length of each side of the parallelogram . -Maths 9th

Last Answer : Here, PQ = SR = 12cm Let PS = x and PS = QR ∴ x + 12 + x +12 = Perimeter 2x + 24 = 40 2x = 16 x = 8 Hence, length of each side of the parallelogram is 12cm , 8cm , 12cm and 8cm.

Two cubes of side 2 cm each are joined end to end. Find the volume of the cuboid so formed. -Maths 9th

Description : Two cubes of side 2 cm each are joined end to end. Find the volume of the cuboid so formed. -Maths 9th

Last Answer : When two cubes of side 2 cm each are joined end to end then, Length (l) = (2 + 2) = 4cm Breadth (b) = 2 cm; Height (h) = 2 cm ∴ Volume of cuboid = lbh = 4 x 2 x 2 = 16 cm3

PQRS is a parallelogram, in which PQ = 12 cm and its perimeter is 40 cm. Find the length of each side of the parallelogram . -Maths 9th

Description : PQRS is a parallelogram, in which PQ = 12 cm and its perimeter is 40 cm. Find the length of each side of the parallelogram . -Maths 9th

Last Answer : Here, PQ = SR = 12cm Let PS = x and PS = QR ∴ x + 12 + x +12 = Perimeter 2x + 24 = 40 2x = 16 x = 8 Hence, length of each side of the parallelogram is 12cm , 8cm , 12cm and 8cm.

Find the area of an isosceles triangle, whose equal sides are of length 15 cm each and third side is 12 cm. -Maths 9th

Description : Find the area of an isosceles triangle, whose equal sides are of length 15 cm each and third side is 12 cm. -Maths 9th

Last Answer : We have, Three sides13cm,13cm and 20cm. By using Heron's formula We need to get the semi-perimeter s= 2 a+b+c​ = 2 13+13+20​ = 2 46​ =23 Now, put the heron's formula, s= s(s−a)(s−b)(s−c)​ = 23(23−13)(23−13)(23−20)​ = 23×10×10×3​ =10 23×3​ =83.07cm 2

If each side of a triangle is doubled,... -Maths 9th

Description : If each side of a triangle is doubled,... -Maths 9th

Last Answer : Let a, b, c be the sides of the given triangle and s be its semi-perimeter. Then, s = (a + b + c)/2 ...(i) ∴ Area of the given triangle = root under ( √s(s - a)(s - b)(s - c)) = △, say According to ... - c)) = 4 root under ( √ s(s - a)(s - b)(s - c)) = 4 △ Therefore, the required ratio is 4:1

There are two concentric hexagons. Each of the side of both the hexagons are parallel. -Maths 9th

Description : There are two concentric hexagons. Each of the side of both the hexagons are parallel. -Maths 9th

Last Answer : In the second figure, ΔOPQ is an equilateral triangle as a regular hexagon is divided into six equilateral triangles. ∴ ∠OPC = 60º⇒ \(rac{OC}{OP}\) = sin 60° ⇒ OC = OP sin 60° ⇒ OC = 8 x \(rac{\sqrt3}{2 ... Area of outer hexagon - Area of inner hexagon= \(rac{3\sqrt3}{2}\)(122 - 82) cm2 = 120√3 cm2.

If a circular sheet of perimeter 2πr touching each side of a given quadrilateral sheet of perimeter 2p -Maths 9th

Description : If a circular sheet of perimeter 2πr touching each side of a given quadrilateral sheet of perimeter 2p -Maths 9th

Last Answer : Let ABCD be the quadrilateral from which a circular sheet is cut off touching each side of the quadrilateral. Also, given AB + BC + CD + DA = 2p ...(i) Circumference of the circle = 2πr ⇒ ... = pr.∴ Required remaining area = Area of quadrilateral - Area of circle = pr - πr2 = r(p - πr).

The percentage increase in the area of a triangle if each of its side is doubled is -Maths 9th

Description : The percentage increase in the area of a triangle if each of its side is doubled is -Maths 9th

Last Answer : (c) 300%.Let a, b, c be the sides of the original triangle and s be its semi-perimeter.Then, s = \(rac{1}{2}\)(a+b+c)Let s1 be the semi-perimeter of the new triangle. Then,s1 = \(rac{1}{2}\) (2a + 2b ... increase in area = \(\bigg(rac{A_1-A}{A} imes100\bigg)\)%= \(rac{(4A-A)}{A} imes100\)% = 300%.

Find the area of regular octagon with each side ‘a’ cm. -Maths 9th

Description : Find the area of regular octagon with each side ‘a’ cm. -Maths 9th

Last Answer : (a) 2a2 (1 + √2) Let ABCDEFGH be the regular octagon of side a cm. Now if we produce the sides of the octagon on both the sides, we get a square PQRS. Given, BC = DE = FG = HA = a cm. Also, BQ = QC = ... = Area of square PQRS - Total area of shaded isosceles Δs = a2 (3 + 2√2) - a2= 2a2 (1 + √2) cm2.

ABCD is a square of side a cm. AB, BC, CD and AD are all chords of circles with equal radii each. -Maths 9th

Description : ABCD is a square of side a cm. AB, BC, CD and AD are all chords of circles with equal radii each. -Maths 9th

Last Answer : (b) \(\bigg[a^2+4\bigg[rac{\pi{a}^2}{9}-rac{a^2}{4\sqrt3}\bigg]\bigg]\)As shown in the given figures, if a' is each side of the square, then ∠DOC = 120º ⇒ ∠ODC = ∠OCD = 30ºNow in fig. (iii), \(rac{ ... of square + Total area of 4 segments = \(a^2+4\bigg(rac{\pi{a}^2}{9}-rac{a^2}{4\sqrt3}\bigg).\)

The base of a right triangular prism is an equilateral triangle. If the height is halved and each side of the base is doubled, find the ratio of the -Maths 9th

Description : The base of a right triangular prism is an equilateral triangle. If the height is halved and each side of the base is doubled, find the ratio of the -Maths 9th

Last Answer : 1 : 2 Let each side of the base of the original prism be a units and the height of the prism be h units. Then Required ratio = Vol. of original prismVol. of new prismVol. of original ... )2×h3√4×(2a)2×h234×(a)2×h34×(2a)2×h2 = 2a2h4a2h2a2h4a2h = 1 : 2.

A point is selected at random inside an equilateral triangle. From this point a perpendicular is dropped to each side. -Maths 9th

Description : A point is selected at random inside an equilateral triangle. From this point a perpendicular is dropped to each side. -Maths 9th

Last Answer : answer:

For a particular year, following is the distribution of ages (in years) of primary school teachers in a district: -Maths 9th

Description : For a particular year, following is the distribution of ages (in years) of primary school teachers in a district: -Maths 9th

Last Answer : 1.First class interval is 15 - 20 and its lower limit is 15. 2.Fourth class interval is 30 - 35 Lower limit is 30 and upper limit is 35. 3.Class mark of the class 45 - 50 =( 45+50 )/ 2 ... = Upper limit of each class interval - Lower limit of each class interval ∴ Here, class size = 20 - 15 = 5

For a particular year, following is the distribution of ages (in years) of primary school teachers in a district: -Maths 9th

Description : For a particular year, following is the distribution of ages (in years) of primary school teachers in a district: -Maths 9th

Last Answer : 1.First class interval is 15 - 20 and its lower limit is 15. 2.Fourth class interval is 30 - 35 Lower limit is 30 and upper limit is 35. 3.Class mark of the class 45 - 50 =( 45+50 )/ 2 ... = Upper limit of each class interval - Lower limit of each class interval ∴ Here, class size = 20 - 15 = 5

Find the number of ways in which 10 different flowers can be strung to form a garland so that three particular flowers are always together -Maths 9th

Description : Find the number of ways in which 10 different flowers can be strung to form a garland so that three particular flowers are always together -Maths 9th

Last Answer : Consider the three particular flowers as one flower. Then we have (10 – 3) + 1 = 8 flowers which can be strung in the garland. Thus the garland can be formed in (8 – 1)!, i.e., 7! ways But the 3 particular flowers can be arranged amongst themselves in 3!

In how many ways can a committee of five persons be formed out of 8 members when a particular member is taken every time? -Maths 9th

Description : In how many ways can a committee of five persons be formed out of 8 members when a particular member is taken every time? -Maths 9th

Last Answer : ∴Required number of ways = 7C4 = 7!

What's the least number of chairs you would need around a table to sit four fathers, two grandfathers, and four sons? -Riddles

Description : What's the least number of chairs you would need around a table to sit four fathers, two grandfathers, and four sons? -Riddles

Last Answer : Four. The four fathers could be grandfathers and are definitely sons already.

If marketing research shows that an aggregate of people do not desire a particular product, the people in the aggregate : 1. are a market for the product 2. do not have the ability to purchase the product 3. do not have the authority to purchase the product 4. are not market for the product 5. are a market but will not purchase the product

Description : If marketing research shows that an aggregate of people do not desire a particular product, the people in the aggregate : 1. are a market for the product 2. do not have the ability to purchase the ... product 4. are not market for the product 5. are a market but will not purchase the product

Last Answer : are not market for the product

If marketing research shows that an aggregate of people do not desire a particular product, the people in that aggregate: A) are a market for the product B) do not have the ability to purchase the product C) do not have the authority to purchase the product D) are not a market for the product E) are a market but will not purchase the product

Description : If marketing research shows that an aggregate of people do not desire a particular product, the people in that aggregate: A) are a market for the product B) do not have the ability to purchase the product ... D) are not a market for the product E) are a market but will not purchase the product

Last Answer : D) are not a market for the product

What do you mean by demand of a commodity? a) A desire for the commodity b) Need for the commodity c) Quantity demanded of that commodity d) Quantity of the commodity demanded at a certain price during any particular period of time

Description : What do you mean by demand of a commodity? a) A desire for the commodity b) Need for the commodity c) Quantity demanded of that commodity d) Quantity of the commodity demanded at a certain price during any particular period of time

Last Answer : Answer- d

Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X and exactly opposite to Q. II. P is 2nd to the left of W. III. S and R are facing each other as well R & Y are neighbors. Which of the following is correct for neighbors? a) X, W b) R, X c) S, W d) P, S

Description : Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X ... . Which of the following is correct for neighbors? a) X, W b) R, X c) S, W d) P, S

Last Answer : Ans: option (d)

Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X and exactly opposite to Q. II. P is 2nd to the left of W. III. S and R are facing each other as well R & Y are neighbors. Who is the only female in between X & R? a) Z b) P c) Y d) Q

Description : Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X and ... R & Y are neighbors. Who is the only female in between X & R? a) Z b) P c) Y d) Q

Last Answer : Ans: option (c)