Description : The points A(2, 3), B(3, 5), C(7, 7) and D(5, 6) are such that: -Maths 9th
Last Answer : (d) 24 unitsAB ⊥ chord PQ ⇒ AB bisects chord PQ ⇒ PQ = 2PB. AB = \(\sqrt{(2-5)^2+(-3-1)^2}\) = \(\sqrt{(-3)^2+(-4)^2}\)= \(\sqrt{9+16}\) = \(\sqrt{25}\) = 5AP = radius of circle = 13 ∴ By Pythagoras' ... = \(\sqrt{AP^2-AB^2}\)= \(\sqrt{169-25}\) = \(\sqrt{144}\) = 12 units∴ PQ = 2 PB = 24 units.