In the class intervals 10-20, 20-30, the number 20 is included in -Maths 9th

In the class intervals 10-20, 20-30, the number 20 is included in -Maths 9th
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In the class intervals 10-20, 20-30, the number 20 is included in -Maths 9th

Description : In the class intervals 10-20, 20-30, the number 20 is included in -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency table with class intervals of equal sizes using 250-270 (270 not included in this interval) as one of the class interval is constructed for the following data -Maths 9th

Description : A grouped frequency table with class intervals of equal sizes using 250-270 (270 not included in this interval) as one of the class interval is constructed for the following data -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency table with class intervals of equal sizes using 250-270 (270 not included in this interval) as one of the class interval is constructed for the following data -Maths 9th

Description : A grouped frequency table with class intervals of equal sizes using 250-270 (270 not included in this interval) as one of the class interval is constructed for the following data -Maths 9th

Last Answer : (c) Here, we arrange the given data into groups like 210-230, 230-250 390-410. (since, our data is from 210 to 406). The class width in this case is 20. Now, the given data can be arrange in tabular form as follows

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

In amylopectin the intervals of glucose units of each branch is (A) 10–20 (B) 24–30 (C) 30–40 (D) 40–50

Description : In amylopectin the intervals of glucose units of each branch is (A) 10–20 (B) 24–30 (C) 30–40 (D) 40–50

Last Answer : B

A class consists of 80 students, 25 of them are girls and 55 boys. 10 of them are rich and 20 are fair complexioned. -Maths 9th

Description : A class consists of 80 students, 25 of them are girls and 55 boys. 10 of them are rich and 20 are fair complexioned. -Maths 9th

Last Answer : Let P (A) = Probability of selecting a fair complexioned person. ThenP(A) = \(rac{20}{80}\) = \(rac{1}{4}\)Let P(B) = Probability of selecting a rich person. Then P(B) = \(rac{10}{80}\) = \(rac{1}{8}\)Let P (C) = ... ) = \(rac{1}{4}\)x \(rac{1}{8}\)x \(rac{5}{16}\) = \(rac{5}{512}\) = 0.009.

Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Last Answer : In conclusion, the range of data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, and 20 is 26.

The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Last Answer : (d) In a given data, maximum value = 32 and minimum value = 6 We know, range of the data = maximum value – minimum value = 32 – 6 = 26 Hence, the range of the given data is 26.

The blood groups of 30 students of class VIII are recorded as follows: -Maths 9th

Description : The blood groups of 30 students of class VIII are recorded as follows: -Maths 9th

Last Answer : Frequency Distribution Table Blood group O is most common as it has highest frequency, i.e., 12. Blood group AB is rarest as it has lowest frequency, i.e., 3.

A class consists of 50 students out of which 30 are girls. -Maths 9th

Description : A class consists of 50 students out of which 30 are girls. -Maths 9th

Last Answer : Mean marks scored by girls ( x̅1 ) = 73 Number of girls (n1) = 30 Mean marks scored by boys ( x̅2 ) = 71 Number of boys (n2) = 50 - 30 = 20 Mean score of the whole class ( x̅12 ) = n1 x̅1 + n2 x̅2 /n1 + n2 = 30 x 73 + 20 x 71/30 + 20 = 2190 + 1420/50 = 3610/50 x̅ 2 = 72.2

Prove that if in two triangles,two angles and the included side of one triangle are equal to two angles and the included side of the other triangle,then two triangles are congruent. -Maths 9th

Description : Prove that if in two triangles,two angles and the included side of one triangle are equal to two angles and the included side of the other triangle,then two triangles are congruent. -Maths 9th

Last Answer : Solution :-

Out of 5 men and 2 women, a committee of 3 is to be formed. In how many ways can it be formed if at least one woman is to be included? -Maths 9th

Description : Out of 5 men and 2 women, a committee of 3 is to be formed. In how many ways can it be formed if at least one woman is to be included? -Maths 9th

Last Answer : Number of selections = Number of ways of selecting 2 men out of 5 men x number of ways of selecting l woman out of 3 women. = 5C2×3C1=5×41×2×3=30

A committee of 5 persons is to be formed out of 6 gents and 4 ladies. In how many ways can this be done if at most two ladies are included? -Maths 9th

Description : A committee of 5 persons is to be formed out of 6 gents and 4 ladies. In how many ways can this be done if at most two ladies are included? -Maths 9th

Last Answer : hope its clear

The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Description : The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Last Answer : NEED ANSWER

The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Description : The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Last Answer : (b) Since, the difference between mid value is 5. So, the corresponding class to the class mark 20 must have difference 5. Therefore, option (c) and (d) are wrong. Since, the mid value is 20 which can get only, if we take option (b)

he frame has a base diameter of 20 cm and height of 30 cm. A margin of 2.5 cm is to be given for folding it over the top and bottom of the frame. -Maths 9th

Description : he frame has a base diameter of 20 cm and height of 30 cm. A margin of 2.5 cm is to be given for folding it over the top and bottom of the frame. -Maths 9th

Last Answer : Say h = height of the frame of lampshade, looks like cylindrical shape r = radius Total height is h = (2.5+30+2.5) cm = 35cm and r = (20/2) cm = 10cm Use curved surface area formula to find the ... 2πrh = (2 (22/7) 10 35) cm2 = 2200 cm2 Hence, 2200 cm2 cloth is required for covering the lampshade.

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of theseSix bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Description : Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Last Answer : Answer – D (16) Explanation – L.C.M. of 2, 4, 6, 8, 10, 12 is 120.So, the bells will toll together after every 120 seconds, i.e, 2 minutes.In 30 minutes, they will toll together 30/2 + 1 = 16

Six bells commencing tolling together toll at intervals of 2, 3, 6, 8 , 10 and 12 seconds respectively.In 30 minutes how many times do they toll together?

Description : Six bells commencing tolling together toll at intervals of 2, 3, 6, 8 , 10 and 12 seconds respectively.In 30 minutes how many times do they toll together?

Last Answer : Ans 1. L.C.M of 2, 4, 6, 8, 10 and 12 is 120. so, the bells will toll together after 120 seconds i.e. 2 minutes . In 30 minutes the bells toll together 30/2 + 1 times i.e. times.

MCQ Questions for Class 9 Maths Chapter 10 Circles Number Systems with answers -Maths 9th

Description : MCQ Questions for Class 9 Maths Chapter 10 Circles Number Systems with answers -Maths 9th

Last Answer : Below you will find MCQ Questions of Chapter 10 Circles Class 9 Maths Free PDF Download that will help you in gaining good marks in the examinations and also cracking competitive exams. These Class ... . These Circles MCQ Questions will help you in practising more and more questions in less time.

Busses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? a) 3 km/hr b) 4 km/hr c) 5 km/hr d) 7 km/hr e) None of these

Description : Busses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? a) 3 km/hr b) 4 km/hr c) 5 km/hr d) 7 km/hr e) None of these

Last Answer : Distance covered in 10 minutes at 20 kmph = distance covered in 8 minutes at (20+x) kmph 20× 10/60=8/60(20+x) 200 = 160 + 8x 8x = 40 x=40/8=5 kmph Answer: c)

Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Description : Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Last Answer : see in book okay!!!

Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Description : Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Last Answer : see in book okay!!!

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Description : In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Last Answer : NEED ANSWER

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Description : The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Last Answer : NEED ANSWER

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Description : In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Last Answer : (b) Let x and y be the upper and lower class limit in a frequency distribution. Now, mid value of a class (x + y )/2=10 [given] ⇒ x + y = 20 (i) Also, given that, width of class x- y = 6 (ii) On ... putting x = 13 in Eq. (i), we get 13+y = 20 ⇒ y = 7 Hence, the lower limit of the class is 7.

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Description : The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Last Answer : (c) Let x and y be the upper and lower class limit of frequency distribution. Given, width of the class = 5 ⇒ x-y= 5 (i) Also, given lower class (y) = 10 On putting y = 10 in Eq. (i), we get ... 20-25, 25-30 and 30-35. Thus, the highest class is 30-35, Hence, the upper limit of this class is 35.

NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.1 -Maths 9th

Last Answer : 1. Fill in the blanks: (i) The centre of a circle lies in _________ of the circle. (ii) A point, whose distance from the centre of a circle is greater than its radius lies in _________ of the circle. ( ... the chord and its corresponding arc is a segment.] (vi) True [∵ A circle is drawn on a plane.]

NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.2 -Maths 9th

Last Answer : 1. Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centres. We have a circle having its centre at O and two equal chords ... [SAS criterion] ∴ Their corresponding parts are equal, i.e. AB = CD

NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.3 -Maths 9th

Last Answer : 1. Draw different pairs of circles. How many points does each pair have in common? What is the maximum number of common points? Let us draw different pairs of circles as shown below: We have Thus, two circles ... .c.t.] ⇒ M is the mid-point of AB. Thus, OO' is the perpendicular bisector of AB.

NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.4 -Maths 9th

Last Answer : 1. Two circles of radii 5 cm and 3 cm intersect at two points and the distance between their centres is 4 cm. Find the length of the common chord. We have two intersecting circles with centres at O and O' respectively. ... = 2x m = 2 x 103 m Thus, the length of the string of each phone = 2 x 103 m.

NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.5 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.5 -Maths 9th

Last Answer : 1. In the figure, A, B and C are three points on a circle with centre O such that ∠ BOC = 30º and ∠AOB = 60°. If D is a point on the circle other than the arc ABC, find ∠ADC. We have a ... = 90º Similarly, ∠B= ∠D = 90º ⇒ Each angle of the parallelogram ABCD is of 90º. Thus, ABCD is a rectangle.

NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.6 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.6 -Maths 9th

Last Answer : 1. Prove that the line of centres of two intersecting circles subtends equal angles at the two points of intersection. We have two circles with centres O and O' respectively such that they intersect ... , the circle passes through the point of intersection (O) of the diagonals of the rhombus ABCD.

Cbqs (case base study ) of chapter 10 Circles of maths class 9th -Maths 9th

Description : Cbqs (case base study ) of chapter 10 Circles of maths class 9th -Maths 9th

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The inspection pit or chamber is a manhole provided in a base drainage system (A) At every change of direction (B) At every change of gradient (C) At every 30 m intervals (D) All the above

Description : The inspection pit or chamber is a manhole provided in a base drainage system (A) At every change of direction (B) At every change of gradient (C) At every 30 m intervals (D) All the above

Last Answer : (D) All the above

An umbrella is made by stitching 10 triangular pieces of cloth of two different colours (see figure), each piece measuring 20 cm, 50 cm and 50 cm. -Maths 9th

Description : An umbrella is made by stitching 10 triangular pieces of cloth of two different colours (see figure), each piece measuring 20 cm, 50 cm and 50 cm. -Maths 9th

Last Answer : Let the sides of each triangular piece be a = 20 cm, b = 50 cm, c = 50 cm

Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Description : Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.

Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Description : Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.

In Fig. 10.20, two circles intersects at two points A and B.AD and AC are diameters to the circles. Prove that B lies on the line A segment DC. -Maths 9th

Description : In Fig. 10.20, two circles intersects at two points A and B.AD and AC are diameters to the circles. Prove that B lies on the line A segment DC. -Maths 9th

Last Answer : Solution :- Jion AB ∠ABD = 90° (Angle in a semicircle) Similarly, ∠ABC = 90° So, ∠ABD + ∠ABC = 90° + 90° = 180° Therefore,DBC is a line i.e.,B lies on the segment DC.

Write each of the following as decimals. (a) 20 + 9 + 4 / 10 + 1 / 100 (b) 137 + 5 / 100 (c) 7 / 10 + 6 / 100 + 4 / 1000 (d) 23 + 2 / 10 + 6 / 1000 (e) 700 + 20 + 5 + 9 / 100 -Maths 9th

Description : Write each of the following as decimals. (a) 20 + 9 + 4 / 10 + 1 / 100 (b) 137 + 5 / 100 (c) 7 / 10 + 6 / 100 + 4 / 1000 (d) 23 + 2 / 10 + 6 / 1000 (e) 700 + 20 + 5 + 9 / 100 -Maths 9th

Last Answer : (a) 20 + 9 + 4 / 10 + 1 / 100 = 29 + 0.4 + 0.01 = 29.41 (b) 137 + 5 / 100 = 137 + 0.05 = 137.05 (c) 7 / 10 + 6 / 100 + 4 / 1000 = 0.7 + 0.06 + 0.004 =0.764 (d) 23 + 2 / 10 + 6 / 1000 = 23 + 0.2 + 0.006 = 23.206 (e) 700 + 20 + 5 + 9 / 100 = 725 + 0.09 = 725.09

A boat covers 14 kms in upstream and 20 kms downstream in 7 hours. Also it covers 22 kms upstream and 34 kms downstream in 10 hours. Find the speed of the boat in still water and of that the stream. -Maths 9th

Description : A boat covers 14 kms in upstream and 20 kms downstream in 7 hours. Also it covers 22 kms upstream and 34 kms downstream in 10 hours. Find the speed of the boat in still water and of that the stream. -Maths 9th

Last Answer : Given, The boat covers 14 km upstream and 20km downstream . at time 7 hours also cover 22km ups. and 34km dwn in10 hours total speed = total distance/total time :.total distance = 14+20+22+34=90km and total time=7+10= ... =90/17 => 5.294km/h => 5.294km/h the speed of boat in still water is 5.29 km/h

The ratio of girls and boys in a class is 1: 3. Set up an equation between the students of a class and boys and then draw its graph. Also find the number of boys in a class of 40 students from the graph. -Maths 9th

Description : The ratio of girls and boys in a class is 1: 3. Set up an equation between the students of a class and boys and then draw its graph. Also find the number of boys in a class of 40 students from the graph. -Maths 9th

Last Answer : Total number of boys and girl = 40, Ratio = 1 : 3 Number of girls be A and Number of boys be B. Ratio of number of girls and boys is 1 : 3, so Therefore 3A=B To find number of boys we ... the number 30 represents the number of girls. 40 as total on the line A = 10, which is the common equation.

The number of sincere students (x) in a class -Maths 9th

Description : The number of sincere students (x) in a class -Maths 9th

Last Answer : x = 2 + 2y Sincere students always progress in life as they value time and channelise their talent in productive activities while a careless student always wastes his talent and time.

Number Systems Class 9th Formula -Maths 9th

Description : Number Systems Class 9th Formula -Maths 9th

Last Answer : Rational Numbers : Rational Numbers are numbers , which can be expressed in the form p/q, q≠0; where p and q are integers . The collection of all rationals are represented by Q. ∴ Q = {p/q ; p,q ... number of rational numbers x2 , x1, x3,... between any two rational numbers a and b so that a

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.3 -Maths 9th

Last Answer : 1. Write the following in decimal form and say what kind of decimal expansion each has : (i) 36/100 Solution: = 0.36 (Terminating) (ii)1/11 Solution: Solution: = 4.125 (Terminating) ... Since the number,1.101001000100001 , is non-terminating non-repeating (non-recurring), it is an irrational number.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.2 -Maths 9th

Last Answer : Solids Bodies occupying space are called solids. A solid has three dimensions viz., length, breadth and thickness or depth or height. The space occupied by a solid body is called its volume .Volume ... a right-angled triangle VOA is revolved about OV, it generates a cone shown in figure alongside.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.4 -Maths 9th

Last Answer : 1. Is zero a rational number ? Can you write it in the form p/q , where p and q are integers and q ≠ 0? Yes, zero is a rational number. We can write it in the form (p/q). That is zero. 2. ... such as -1, -2 are non-whole numbers] (iii) False statement [∵ Rational number (1/2) is not a whole number]

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.5 . -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.5 . -Maths 9th

Last Answer : 1. State whether the following statements are true or false. Justify your answers. (i) Every irrational number is a real number. (ii) Every point on the number line is of the form √m , where m is a natural ... 5 ⇒ OC = √5 With O as centre and OC as radius, draw an arc intersecting OX at D. Since