Description : Write the following decimals in the place value table. (a) 0.29 (b) 2.08 (c) 19.60 (d) 148.32 (e) 200.812 -Maths 9th
Last Answer : (a) 0.29 = 0.2 + 0.09 = 2 / 10 + 9 / 100 (b) 2.08 = 2 + 0.08 = 2 + 8 / 100 (c) 19.60 = 19 + 0.60 = 10 + 9 + 6 / 10 (d) 148.32 = 148 + 0.3 + 0. ... / 100 (e) 200.812 = 200 + 0.8 + 0.01 + 0.002 =200 + 8 / 10 + 1 / 100 + 2 / 1000HundredsTensOnesTenthsHundredthsThousandths000290002080019600148320200812
Description : Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th
Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.
Description : Write each of the following as decimals: (a) 5 / 10 (b) 3 + 7 / 10 (c) 200 + 60 + 5 + 1 / 10 (d) 70 + 8 / 10 (e) 88 / 10 -Maths
Last Answer : (a) 5 / 10 = 0.5 (b) 3 + 7 / 10 = 3 + 0.7 = 3.7 (c) 200 + 60 + 5 + 1 / 10 = 265 + 0.1 = 265.1 (d) 70 + 8 / 10 = 70 + 0.8 = 70.8 (e) 88 / 10 = 80 / 10 + 8 / 10 = 8 + 0.8 = 8.8 (f) (g) 3 / 2 = (2 + 1) / ... + 0.5 = 1.5 (h) 2 / 5 = 0.4 (i) 12 / 5 = (10 + 2) / 5 = 10 / 5 + 2 / 5 = 2 + 0.4 = 2.4 (j) (k)
Description : Express the following as cm using decimals. (a) 2 mm (b) 30 mm (c) 116 mm (d) 4 cm 2 mm (e) 162 mm (f) 83 mm -Maths 9th
Last Answer : We know that 1 cm = 10 mm 1 mm = 1 / 10 cm (a) 2 mm = 2 / 10 cm = 0.2 cm (b) 30 mm = 30 / 10 cm = 3.0 cm (c) 116 mm = 116 / 10 cm = 11.6 cm (d) 4 cm 2 mm = [(4 + 2 / 10)] cm = 4.2 cm (e) 162 mm = 162 / 10 cm = 16.2 cm (f) 83 mm = 83 / 10 cm = 8.3 cm
Description : 2. Arrange the following fractions in ascending order:(i) \( \frac{3}{8}, \frac{5}{6}, \frac{6}{8}, \frac{2}{4}, \frac{1}{3} \)(ii) \( \frac{4}{6}, \frac{3}{8}, \frac{6}{12}, \frac{5}{16} \)3. Arrange the ... ( \frac{23}{3} \) and 6(iii) \( \frac{18}{20} \) and \( \frac{21}{25} \)(iv) \( 3 \frac{3
Last Answer : 2. Arrange the following fractions in ascending order: (i) \( \frac{3}{8}, \frac{5}{6}, \frac{6}{8}, \frac ... frac{3}{10} \) and \( 2 \frac{7}{15} \)
Description : In Fig. 9.23, ABCD is a parallelogram in which BC is produced to E such A B that CE = BC. AE intersects CD at F. If area of △BDF = 3 cm2, find the area of parallelogram ABCD. -Maths 9th
Last Answer : Solution :-
Description : Write each of the following as decimals: (a) Seven-tenths (b) Two tens and nine-tenths (c) Fourteen point six (d) One hundred and two ones (e) Six hundred point eight -Maths
Last Answer : (a) The decimal form of Seven-tenths is 7 / 10 = 0.7 (b) The decimal form of two tens and nine tenths is 20 + 9 / 10 = 20.9 (c) The decimal form of fourteen point six is 14.6 (d) The decimal form of one hundred and two ones is 100 + 2 = 102.0 (e) The decimal form of six hundred point eight is 600.8
Description : A 15-year-old girl was seen by her family physician because of increasing lethargy. She had a recent history of the "flu". Biochemistry tests show that she has renal impairement. ... will likely develop a restrictive lung disease 5) She will probably improve with additional corticosteroid therapy
Last Answer : Answers-2 The findings point to focal segmental glomerulosclerosis (FSGS), which leads to chronic renal failure in half of cases. The lack of resolution with corticosteroid therapy and the progression to chronic renal failure is what sets FSGS apart from minimal change disease.
Description : If a + b + c = 9 and ab + bc + ca = 23, then a3 + b3 + c3 – 3 abc = (a) 108 (b) 207 (c) 669 (d) 729 -Maths 9th
Last Answer : a+b+c=9 and a2+b2+c2=35 Using formula, (a+b+c)2=a2+b2+c2+2(ab+bc+ca) 92=35+2(ab+bc+ca) 2(ab+bc+ca)=81−35=46 (ab+bc+ca)=23 using formula, (a3+b3+c3)−3abc=(a2+b2+c2−ab−bc−ca)(a+b+c) a3+b3+c3−3abc=(35−23)×9=9×12=108
Description : If a + b + c = 9 and ab + bc + ca = 23, find the value of a2 + b2 + c2 -Maths 9th
Last Answer : (a+b+c)2=a2+b2+c2+2ab+2bc+2ca =a2+b2+c2+2(ab+bc+ca) Given, ⇒92=a2+b2+c2+2(23) ⇒81−46=a2+b2+c2 ∴a2+b2+c2=35
Description : A football player scored the following number of goals in the 10 matches 1, 3, 2, 5, 8, 6,1, 4, 7 and 9. Since, the number of matches is 10 (an even number), therefore -Maths 9th
Last Answer : NEED ANSWER
Last Answer : No. It is not the correct answer, because the data have to be arranged in ascending or descending order before finding the median. Arranging the data in ascending order 1,1,2, 3, 4, 5, 6, 7, 8, 9. Here, number of observations is 10, which is even.
Description : Find the coordinate where the linear equation 4x - 23 y = 7 meets at y-axis. -Maths 9th
Last Answer : 4x-2=-7*3y 4x+21y=2 The equation meets y axis when x=0 4.0+21y=2 y=21/2 Hence , the equation meets y-axis at (0,21/2)
Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles
Last Answer : 22
Description : Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x
Last Answer : c. y = 1.98 x + 0.436
Description : The photosynthetically active (PAR) falls in the range of (A) 400 – 700 nm (B) 100- 400 nm (C) 700- 1000 nm (D) None of the above
Last Answer : (A) 400 – 700 nm
Description : Optimum reaction temperature in steam reforming of naphtha is __________ °C. (A) 700 - 1000 (B) 300 - 450 (C) 1500-1700 (D) 100-200
Last Answer : (A) 700 - 1000
Description : Convert each of the following decimals into a percentage: (i) 0.6 (ii) 0.42 (iii) 0.07 (iv) 0.005 -Maths
Last Answer : answer:
Description : Two filling tap can fill a dumper in 14 and 28 min. respectively and when the waste tap is open, they can together fill it in 35 min. The waste pipe can empty the full dumper in – A) 152/9 hrs. B) 137/7 hrs. C) 60/9 hrs. D) 140/11 hrs.
Last Answer : D 1/14 + 1/28 – 1/35 =>10 + 5 – 4/140 =>11/140 =>140/11 => hence answer is 140/11 hours.
Description : ABCD is a trapezium in which AB || CD and AD = BC (see Fig. 8.23). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint : Extend AB and draw a line through C parallel to DA intersecting AB produced at E.] -Maths 9th
Last Answer : ] Solution: To Construct: Draw a line through C parallel to DA intersecting AB produced at E. (i) CE = AD (Opposite sides of a parallelogram) AD = BC (Given) , BC = CE ⇒∠CBE = ∠CEB also, ∠A+∠CBE = ... BC (Given) , ΔABC ≅ ΔBAD [SAS congruency] (iv) Diagonal AC = diagonal BD by CPCT as ΔABC ≅ ΔBA.
Description : A flag pole 18 m high casts a shadow 9.6 m long. Then the distance of the top of the pole from the far end of the shadow is (a) 25.6 (b) 20.4 (c) 23.7 (d) 32.5
Last Answer : (b) 20.4
Description : The paint in a certain container is sufficient to paint an area equal to 9.375 m2. How many bricks of dimensions 22.5 cm×10 cm×7.5 cm can be painted out of this container? -Maths 9th
Last Answer : Total surface area of one brick = 2(lb +bh+lb) = [2(22.5 10+10 7.5+22.5 7.5)] cm2 = 2(225+75+168.75) cm2 = (2 468.75) cm2 = 937.5 cm2 Let n bricks can be painted out by the ... 93750 cm2 So, we have, 93750 = 937.5n n = 100 Therefore, 100 bricks can be painted out by the paint of the container.
Description : A spherical metal of radius 10 cm is melted and made into 1000 smaller spheres of equal sizes. In this process the surface area of the -Maths 9th
Last Answer : Option (C) is correct. Solution: Let the radius of the small spheres be r' cm. Volume of metal remains the same in both cases. So, vol of the spherical metal of radius 10 cm = total ... Total Surface area of 1000 smaller spheres: 1000*4π12 = 4000π Hence, the surface area increased by 10 times.
Description : According to Indian Standards Institute, the actual size of modular bricks is (A) 23 cm × 11.5 cm × 7.5 cm (B) 25 cm × 13 cm × 7.5 cm (C) 19 cm × 9 cm × 9 cm (D) 20 cm × 10 cm × 10 cm
Last Answer : (C) 19 cm × 9 cm × 9 cm
Description : If the velocity of moving vehicles on a road is 24 km/per hour, stopping distance is 19 metres and average length of vehicles is 6 metres, the basic capacity of lane, is (A) 500 vehicles per hour (B) 700 vehicles per hour (C) 1000 vehicles per hour (D) 1250 vehicles per hour
Last Answer : Answer: Option C
Description : Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th
Description : A boat covers 14 kms in upstream and 20 kms downstream in 7 hours. Also it covers 22 kms upstream and 34 kms downstream in 10 hours. Find the speed of the boat in still water and of that the stream. -Maths 9th
Last Answer : Given, The boat covers 14 km upstream and 20km downstream . at time 7 hours also cover 22km ups. and 34km dwn in10 hours total speed = total distance/total time :.total distance = 14+20+22+34=90km and total time=7+10= ... =90/17 => 5.294km/h => 5.294km/h the speed of boat in still water is 5.29 km/h
Description : Find the mode of the following scores : 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18 -Maths 9th
Last Answer : 14 repeat maximum number of times (4 times) in the given data. Mode = 14
Description : Express the following numbers in the form of p/q.(1)0.15 (2)0.00026 (3)23.434343434343...... (4)0.6666666.... -Maths 9th
Last Answer : (i) 0.15 = 15/100 = 3/20 (ii) 0.00026 = 26/100000 = 13/50000 (iii) 23.43434343.... Let p/q = 23.434343...... - (i) Multiply both side by 100:- 100 * p/q = 100 * 23.434343...... 100p/q = 2343. ... .434343...... 99p/q = 2320.0 p/q = 2320/99 (iv) 0.6666.... = 6/9 Proceed same as question no. (iii)
Description : Express 1.23(bar 23) in the form of p/q -Maths 9th
Last Answer : Let X = 1.23(bar on 23) 100X = 123.23(bar on 23) 100X-X = 123.23+1.23(bar on 23) 100X-99x = 122(bar on 23) 99X = 122 x=122/99
Last Answer : Let X = 1.23(bar on 23) 100X = 123.23(bar on 23) 100X-X = 123.23+1.23(bar on 23) 99X = 122(bar on 23) X = 122/99
Description : The sides BA and DC of quad. ABCD are produced as shown in Fig. 8.23. Prove that x + y = a + b -Maths 9th
Description : An article manufactured by a company consists of two parts X and Y. In the process of manufacture of the part X, 9 out of 100 parts may be defective. -Maths 9th
Last Answer : (b) \(rac{1}{4}\)Since A and B are mutually exclusive and exhaustive events, therefore, P(A ∩ B) = 0, P(A ∪ B) = 1 We know that, P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ⇒ 1 = P(A) + 3 P(A) (Given P(B) ... ∵ P(A) + P(B) = 1)⇒ P(\(\bar{B}\)) = 1 - P(B) = 1 - \(rac{3}{4}\) = \(rac{1}{4}\).
Description : An umbrella is made by stitching 10 triangular pieces of cloth of two different colours (see figure), each piece measuring 20 cm, 50 cm and 50 cm. -Maths 9th
Last Answer : Let the sides of each triangular piece be a = 20 cm, b = 50 cm, c = 50 cm
Description : 11 girls went to a canteen. 10 of them spent 10 each and the 11th girl spent 25 more than the average expenditure of all. Find the total money spent by them? A) 172 .5 B) 178 .5 C) 137.5 D) 165.5
Last Answer : C) Let the average money spent by the 11girls = x Money spent by the 11th girl = (x + 25) Money spent by the other 10 girls = (10*10) = 100 Total money spent by the 11 girls = (100 + x + 25) =(x + ... = (x + 125)/ 11 =>10x=125 x =12.5 Total money spent by the 11 girls = 11*12.5 = 137.5.
Description : NCERT Solutions for class 9 Maths Chapter 10 Circles Exercise 10.6 -Maths 9th
Last Answer : 1. Prove that the line of centres of two intersecting circles subtends equal angles at the two points of intersection. We have two circles with centres O and O' respectively such that they intersect ... , the circle passes through the point of intersection (O) of the diagonals of the rhombus ABCD.
Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th
Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88
Description : If AB = PQ, BC = QR and AC = PR, then write the congruence relation between the triangles. [Fig. 7.6] -Maths 9th
Last Answer : Solution :- △ ABC ≅ △PQR
Description : If x+y=9 and xy=20,then find the value of x(square) + y(square). -Maths 9th
Description : What is the normal level of K+ in the serum ? (A) 137–148 mEq/L (B) 120–160 mEq/L (C) 3.9–5.0 mEq/L (D) 0.3–0.59 mEq/L
Last Answer : Answer : C
Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th
Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26
Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th
Last Answer : In conclusion, the range of data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, and 20 is 26.
Last Answer : (d) In a given data, maximum value = 32 and minimum value = 6 We know, range of the data = maximum value – minimum value = 32 – 6 = 26 Hence, the range of the given data is 26.
Description : Late Jorwe Culture – 1000-700 B.C.E. , Kutch – Saurashtra was abandoned by 1900 B.C.E. , Early Jorwe Culture – 1400-1000 B.C.E.
Last Answer : Write the correct chronological order: (a) Late Jorwe Culture - 1000-700 B.C.E. (b) Kutch - Saurashtra ... (d) Malwa Culture - 1600-1400 B.C.E.
Description : Payments bank of the postal department will have how much corpus at the beginning? A) Rs 900 crore B) Rs 600 crore C) Rs 1000 crore D) Rs 800 crore E) Rs 700 crore
Last Answer : D) Rs 800 crore Explanation: The payments bank of eth department will be functional by March 2017. It is one of the 11 applicants which got in principle approval to set up payments bank in the country.