A committee of 5 persons is to be formed out of 6 gents and 4 ladies. In how many ways can this be done if at most two ladies are included? -Maths 9th

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Description : In how many ways can a committee of five persons be formed out of 8 members when a particular member is taken every time? -Maths 9th

Last Answer : ∴Required number of ways = 7C4 = 7!

Description : Out of 5 men and 2 women, a committee of 3 is to be formed. In how many ways can it be formed if at least one woman is to be included? -Maths 9th

Last Answer : Number of selections = Number of ways of selecting 2 men out of 5 men x number of ways of selecting l woman out of 3 women. = 5C2×3C1=5×41×2×3=30

Description : From a total of six men and four ladies, a committee of three is to be formed. If Mrs.X is not willing to join the committee in which Mr.Y is a member, whereas Mr.Y is willing to join the committee only if Mrs.Z is included. How many such committees are possible? a) 138 b) 128 c) 112 d) 91

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Last Answer : If each gentleman has to have a lady by his side, the seating arrangement can be done as shown below: This can be done in 5! (Gentlemen) × 3! (Ladies) = 720 ways.

Description :  In how many ways can a team of 6 persons be formed out of a total of 12 persons such that 3 particular persons should not be included in any team? A) 56 B) 112 C) 84 D) 128

Last Answer : Answer: C) Three particular persons should not be included in each team. i.e., we have to select remaining 6- 3= 3 persons from 12-3 = 9 persons.  Hence, required number of ways = 9C3  = {9×8 × 7} / {3 × 2 × 1} = 504 / 6 = 84

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Description : Gents. What are your favourite shoes seen on a woman? Ladies. What are your favourite shoes you like to wear?

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Description : The average age of a morning class is 108, if the average age of 72 ladies in the class is as same as the total average and the number of gents in the class is 2 more than the ladies in the class, what is the average age of gents in the class? A) 152 B) 108 C) 156 D) 154 

Last Answer : B) According to question, (72+74)X=72×108+74X 146x-74x=7776 72x=7776 X=7776/72= 108years

Description : 7 relatives of a man comprise 4 ladies and 3 gentlemen; his wife also has 7 relatives; 3 of them are ladies and 4 gentlemen. In how many ways -Maths 9th

Last Answer : The possible cases are: Case I : A man invites (3 ladies) and woman invites (3 gentlemen) 4 C 3 4 C 3 =16 Case II : A man invites (2 ladies,1 gentleman) and woman invites (2 gentleman, 1 lady) ( 4 ... and woman invites (3 ladies) 3 C 3 3 C 3 =1 Total number of ways =16+324+144+1=485

Description : A committee of 11 members sit at a round table. In how many ways can they be seated if the “President” and the “Secretary” choose to sit together. -Maths 9th

Last Answer : ∴ Required number of ways of seating = 9!

Description : Out of 5 women and 4 men, a committee of three members is to be formed in such a way that at least one member is woman. In how many different ways can this be done? 1) 60 2) 100 3) 120 4) 90 5) 80

Last Answer : 5) 80

Description : In how many way can a committee of 4 women and 5 men be chosen from 9 women and 7 men, if Mr. A refuse to serve on the committee if Ms. B is a member? -Maths 9th

Last Answer : First of all number of ways. Committees can be founded =6C3 5C2 Now, we remove committees with both A and B =4 5C2 again we need to remove committees with B and not C =5C2 4. Now we shall add the committees with A, ... −4 5C2 −5C2 4+4 4C2 =124. Hence, the answer is =124.

Description : A committee is to be formed comprising 7 members such that there is a simple majority of men and at-least 1 woman. The shortlist consists of 9 men and 6 women. In how many ways can this committee be formed? a) 3724 b) 4914 c) 3928 d) 4913

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Last Answer : Let the radius of the hemispherical bowl be r cm Then, 2πr=176⇒r=176×72×22⇒r=282πr=176⇒r=176×72×22⇒r=28 Volume of liquid in the bowl : =12×( ... : =Volume of liquid in the bowlVolume of 1 glass=(14×28×282×2×2)= 1372

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Description : In the class intervals 10-20, 20-30, the number 20 is included in -Maths 9th

Last Answer : NEED ANSWER

Description : A grouped frequency table with class intervals of equal sizes using 250-270 (270 not included in this interval) as one of the class interval is constructed for the following data -Maths 9th

Last Answer : NEED ANSWER

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

Description : In the class intervals 10-20, 20-30, the number 20 is included in -Maths 9th

Last Answer : B is the correct answer

Description : A grouped frequency table with class intervals of equal sizes using 250-270 (270 not included in this interval) as one of the class interval is constructed for the following data -Maths 9th

Last Answer : (c) Here, we arrange the given data into groups like 210-230, 230-250 390-410. (since, our data is from 210 to 406). The class width in this case is 20. Now, the given data can be arrange in tabular form as follows

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

Description : A box contains 5 different red and 6 different white balls. In how many ways can 6 balls be selected so that there are at least -Maths 9th

Last Answer : The selection of 6 balls, consisting of at least two balls of each color from 5 red and 6 white balls can be made in the following ways: Red balls (5) White balls(6) Number of ways 2 4 5 C 2 ​ × 6 C 4 ​ =150 3 3 5 C 3 ​ × 6 C 3 ​ =200 4 2 5 C 4 ​ × 6 C 2 ​ =75 Total 425

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Description : In the linear equation y = 4x + 13, if x is the number of hours a labourer is on work and y are his wages in rupees then draw the graph. Also find the wages when work is done for 6 hours. -Maths 9th

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Description : Two ladies and two men are playing bridge and seated at North, East, South and West of a table. No lady is facing East. Persons sitting opposite to each other are not of the same sex. One man is facing South. ... facing to? (A) East and West (B) North and West (C) South and East (D) None of these 

Last Answer : (B) North and West

Description : Annapurna Scheme fulfills the food requirements of: (a) indigent senior citizens (b) children (c) pregnant ladies (d) young persons

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Description : There are 5 boys and 3 girls. In how many ways can they stand in a row so that no two girls are together? -Maths 9th

Last Answer : Have the 55 boys stand in a line. This can be done in 5!5! ways. For the moment, add a boy at each end, who will be removed when we're done. Now send the 33 girls, one at a time, to ... that each girl can either wedge herself between two boys or else stand next to a boy at one end or the other.

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Last Answer : Answer: Committee organisation

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Last Answer : A) You will convene an urgent meeting of the members and request them collectively to extend their support

Description : Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Last Answer : The two digit numbers can be formed by putting any of 5 digits at the one 's place and also one of the 5 digits at ten's place. So, Total number of 2-digit numbers that can be formed using these 5-digits = 5 5 = ... 52}, i.e, 5 in number. ∴ Required probability = \(rac{5}{25}\) = \(rac{1}{5}.\)

Description : ABCD is a rectangle formed by the points A(–1, –1), B(–1, 4), C(5, 4) and D(5, –1). P, Q, R and S are mid-points -Maths 9th

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Description : In how many ways can 7 men and 7 women sit on a round table such that no two women sit together? -Maths 9th

Last Answer : Now there are 7 places vacant between these 7 men. ∴ 7 women can seat themselves in these 7 places in 7 ! ways. ∴ Total number of required arrangement where no two women sit together = 6!

Description : In how many ways can a team of 11 players be selected from 14 players when two of them play as goalkeepers only? -Maths 9th

Last Answer : As each team of 11 players has one goalkeeper and 10 team members, and out of 14 players there are 2 goalkeepers and 12 team members. = 12×112×2 = 132.

Description : In how many ways can the letters of the word “AFLATOON” be arranged if the consonants and vowels must occupy alternate places? -Maths 9th

Last Answer : 24 ways is the answer