Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th
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Answer :

Let x = 0.7Bar ⇒ x = 0.777..........  .........(1) Multiplying (1) by 10  ⇒ 10x = 7.7...... = 7.777 ...........(2) Subtracting (1) from (2) ⇒ 10x - x = 9x   ⇒ 7.777 - 0.777 = 7      ⇒ 9x = 7  ⇒ x = 7/9 Let y = 0.47Bar ⇒ y = 0.4747 ..............  ........(1) Multiplying (1) by 100  ⇒ 100y = 47.4747  ............(2) Subtracting (1) from (2) ⇒ 100y - y = 99y ⇒ 47.4747 - 0.4747 = 47 ⇒ 99y = 47 ⇒ y = 47/99 Now, 0.7Bar = 7/9 and 0.47Bar = 47/99 0.6 = 6/10 6/10 + 7/9 + 47/99 Taking L.C.M. of the denominator and then solving it, we get. ⇒ (594 + 770 + 470)/990 ⇒ 1834/990 ⇒ 917/495 Hence, 0.6 + 0.7Bar + 0.47Bar = 917/495
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Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Description : Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Last Answer : Let x=0.666....... (1) Multiply equation (1 by 10 10x = 6.666....... (2) Subtract equation (1) from (2) x=6/9 Similarly 0.7bar =7/9 and 0.47bar = 47/99. 6/9+7/9+47/99=190/99

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Last Answer : x + 5x + 5 = 476x = 42x = 7x + 1 = 8

When the smaller of the two consecutive integers is added to five times the larger the result is 47?

Description : When the smaller of the two consecutive integers is added to five times the larger the result is 47?

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