Is it ok to average grade equivalent scores from a norm referenced test?

Is it ok to average grade equivalent scores from a norm referenced test?
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I dont see why not…..
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Which type of reliability refers to the consistency of a group of individuals' scores on two equivalent forms of a test designed to measure the same characteristic? a. Split-half b. Test-retest c. Split-forms d. Equivalent forms

Description : Which type of reliability refers to the consistency of a group of individuals' scores on two equivalent forms of a test designed to measure the same characteristic? a. Split-half b. Test-retest c. Split-forms d. Equivalent forms

Last Answer : d. Equivalent forms

Which of the following types of reliability refers to the consistency of test scores over time? a. Equivalent forms reliability b. Split-half reliability c. Test-retest reliability d. Inter-scorer reliability

Description : Which of the following types of reliability refers to the consistency of test scores over time? a. Equivalent forms reliability b. Split-half reliability c. Test-retest reliability d. Inter-scorer reliability

Last Answer : c. Test-retest reliability

Which of the following statements accurately describes test-retest reliability? a. Measure of consistency of test scores over time b. Measure of consistency of scores obtained from two equivalent halves of same test c. Measure of consistency with which a test measures a single construct or concept d. Measure of degree of agreement between two or more scorers, judges, or raters

Description : Which of the following statements accurately describes test-retest reliability? a. Measure of consistency of test scores over time b. Measure of consistency of scores obtained from two equivalent halves of ... concept d. Measure of degree of agreement between two or more scorers, judges, or raters

Last Answer : a. Measure of consistency of test scores over time

When testing a grade calculation system, a tester determines that all scores from 90 to 100 will yield a grade of A, but scores below 90 will not. This analysis is known as: A. Equivalence partitioning B. Boundary value analysis C. Decision table D. Hybrid analysis

Description : When testing a grade calculation system, a tester determines that all scores from 90 to 100 will yield a grade of A, but scores below 90 will not. This analysis is known as: A. Equivalence partitioning B. Boundary value analysis C. Decision table D. Hybrid analysis

Last Answer : A. Equivalence partitioning

When testing a grade calculation system, a tester determines that all scores from 90 to 100 will yield a grade of A, but scores below 90 will not. This analysis is known as: A. Equivalence partitioning B. Boundary value analysis C. Decision table D. Hybrid analysis

Description : When testing a grade calculation system, a tester determines that all scores from 90 to 100 will yield a grade of A, but scores below 90 will not. This analysis is known as: A. Equivalence partitioning B. Boundary value analysis C. Decision table D. Hybrid analysis

Last Answer : B. Boundary value analysis

The average scores of a batch of students in a test is 84. The 36% of students's average score is 57 and 42% of students's score is 84. Then find the average score of remaining 22% of students approximately, A) 128 B) 131 C) 119 D) 106

Description : The average scores of a batch of students in a test is 84. The 36% of students's average score is 57 and 42% of students's score is 84. Then find the average score of remaining 22% of students approximately, A) 128 B) 131 C) 119 D) 106 

Last Answer : Answer: A)  let the number of students be 100, then, 100*84 = 36*57 + 42*84 + 22*x 22x = 8400-2052-3528 x = 128.18

Who should select the specific welds for NDT, to cover the 10% contractual percentage required by the specification/Code? a) Anyone can select the welds as its just a random choice b) The welder as he knows which welds are likely to produce the least defects c) This will be referenced in the inspection and test plan d) Nobody, as welding is always carried out to a high standard the use of percentage NDT is of no real value

Description : Who should select the specific welds for NDT, to cover the 10% contractual percentage required by the specification/Code? a) Anyone can select the welds as its just a random choice b) The welder ... welding is always carried out to a high standard the use of percentage NDT is of no real value

Last Answer : c) This will be referenced in the inspection and test plan

Evaluating lo ting location alternatives by c ves by comparing the ing their composite (weighted-averag -average) scores involves involves a. factor rating analysis b. cost-volume analysis cost-volume analysis c. transportation transportation model analysis analysis d. linear regression regression analysis e. crossover crossover analysis

Description : Evaluating lo ting location alternatives by c ves by comparing the ing their composite (weighted-averag -average) scores involves involves a. factor rating analysis b. cost- ... transportation model analysis analysis d. linear regression regression analysis e. crossover crossover analysis

Last Answer : a. factor rating analysis

The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 35 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

Description : The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark ... integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

Last Answer : D Average = Sum of observations/Number of observations Given, average score in a bank examination of 13 students of a class is 50. Sum of total scores = 13 50= 650 Given, if the scores of the top five students are not ... b + c + d + e = 290 ⇒46+ 47 + 48+ 49 +e = 290 ⇒e = 100

The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875

Description : The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875

Last Answer : C) According to the question, 90*126=(4*0)+(60*116)+(24*118)+2y 11340=6960+2832+2y 2y=1548 y=774

The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20

Description : The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20 

Last Answer : A) According to the question 40*21=23*8+26*10+18*14+8×X 840=184+260+252+8x 8x=144  X=144/8=18 runs

A cricketer played 3 matches in tournament. The respective ratio between the scores of first and second matches was 3:7 and that between the scores of second and third matches between was 7 :2. the difference between first and third matches was 84 runs, what was the cricketer average score in all the matches together? A) 336 B) 146 C) 168 D) 189

Description : A cricketer played 3 matches in tournament. The respective ratio between the scores of first and second matches was 3:7 and that between the scores of second and third matches between was 7 :2. the difference ... the cricketer average score in all the matches together? A) 336 B) 146 C) 168 D) 189

Last Answer : A) The ratio between first and second matches equal to 3 :7 The ratio between second and third matches=7:2 The difference between first and third matches=3x-2x=84 runs = 84 Required average=1008/3=336 .

In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Description : In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to ... what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Last Answer : A) Maximum mark consist of a three digit number let's consider Unit digit place is Z,ten's place digit is Y and hundred's place digit is X. According to the question, Y=x+z---------1 X+Y ... Total number of Mahi, Nitesh and Ritesh =164/100 451=739.61 Required average =739.64/3=246.54~247.

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A virtual memory has a page size of 1K words. There are eight pages and four blocks. The associative memory page table contains the following entries: Image Which of the following list of virtual addresses (in decimal) will not cause any page fault if referenced by the CPU? (A) 1024, 3072, 4096, 6144 (B) 1234, 4012, 5000, 6200 (C) 1020, 3012, 6120, 8100 (D) 2021, 4050, 5112, 7100

Description : A virtual memory has a page size of 1K words. There are eight pages and four blocks. The associative memory page table contains the following entries:  Which of the following list of virtual addresses (in ... 1234, 4012, 5000, 6200 (C) 1020, 3012, 6120, 8100 (D) 2021, 4050, 5112, 7100

Last Answer : Answer: C Explanation: The pages which are not in main memory are: 1020 will not cause page fault (1024-2047) 3012 will not cause page fault (3072-4095) 6120 will not cause page fault (4096-5119) 8100 will not cause page fault (6144-7167)

How far can I raise my test scores, from going on a low FODMAP diet for IBS (Irritable Bowel Syndrome)?

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Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

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Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.

The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88

Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Description : Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.

The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88

In an online test, sami scores 18 points for correct answers and -3 points for incorrect answers. Find his score.

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What is the standard deviation and what is the probability that a student scored higher than 322 if the mean test score is 312 and 16 percent of the scores are under 307?

Description : What is the standard deviation and what is the probability that a student scored higher than 322 if the mean test score is 312 and 16 percent of the scores are under 307?

Last Answer : Assuming a normal distribution:If 16% are less than 307, then 84% are greater than 307.Using single tailed normal tables we want the z value whichgives 84%-50% = 34% = 0.34 to the left of the mean; this is z ≈ ... 1 - 0.977 = 0.023 = 2.3 % are greater than 322→ probability greater than 322 is 2.3%

Is it allowed to number of ASVAB prep test , in order to get higher scores?

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Last Answer : Rather than retaking the test to try and get higher scores you should practice first. Here is one practice test http://www.testprepreview.com/asvab_practice.htm

What kind of scores are necessary on the ASVAB test?

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Which is the process of gathering evidence supporting inferences based test scores? a. Validation b. Validity c. Reliability d. Prediction

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Reliability is most simply known as which of the following? a. Consistency or stability b. Appropriateness of interpretations on the basis of test scores c. Ways in which people are the same d. A rank order of participants on some characteristic

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Last Answer : a. Consistency or stability

Let’s say that a test accurately indicates participants’ scores on a future criterion (e.g., the PSAT is used to indicate high-school GPA scores). This test would clearly have which of the following? a. Face validity b. Concurrent validity c. Predictive validity d. Content validity

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The mean score on any class test is the result of Options: A) dividing the sum of all scores by the number of scores B) determining the middle score when all the scores have been listed from the highest to the lowest C) determining the most frequent score. D) Adding all the scores and dividing by the most frequent score

Description : The mean score on any class test is the result of Options: A) dividing the sum of all scores by the number of scores B) determining the middle score when all the scores have been listed from ... C) determining the most frequent score. D) Adding all the scores and dividing by the most frequent score 

Last Answer : A) dividing the sum of all scores by the number of scores 

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Last Answer : Consider who is working at fast food shacks.