If there was a family of hunchback with two sons and one daughter, then the first son married a girl and then the girl became a hunchback and then the other son also married a woman and then the woman became a hunchback too, but then when the daughter married a man, the girl's hunchback is gone. Why did the girl's hunchback lost?

If there was a family of hunchback with two sons and one daughter, then the first son married a girl and then the girl became a hunchback and then the other son also married a woman and then the woman became a hunchback too, but then when the daughter married a man, the girl's hunchback is gone. Why did the girl's hunchback lost?
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1 Answer

Answer :

I bet that was a weight off her shoulders.
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A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was: A.14 B.19 C.38 D.40 E.None of these

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Last Answer : Answer – A (14) Explanation – Let son’s present age be X years. Then, (38 – X) = X 2X = 38 X = 19 Son’s age 5 years back = (19 – 5) years = 14 years

Vasu said to his son, "I was as old as you at the time of your birth". If vasu’s age is 76 years now, the son's age ten years back was: a)14 years b)19 years c)33 years d)28 years

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Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35 

Four years ago, the average of a 4 member family was 40 years. 3 years ago, a boy got married to a 23 years old girl, and they had a baby boy last year. what is the average of the family 2 years from now assuming no one joins or leaves from the family in the next 2 years.

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Last Answer : Four years ago, sum of all the family members age = 4× 40 = 160 three years ago, sum of all the family members age = 164 + 23 = 187 last year, sum = 197 (187 + 5 + 5) two years from now, sum = 197 + 18 = 215 hence, average = 215/6 = 35.8 Answer: e)