An IPv6 address is _________ bits long A. 32 B. 64 C. 128 D. none of the above

An IPv6 address is _________ bits long
A. 32
B. 64
C. 128
D. none of the above
by

1 Answer

Answer :

C. 128
by

Related questions

What is size of the IPv6 Address? A. 32 bits B. 64 bits C. 128 bits D. 256 bits

Description : What is size of the IPv6 Address? A. 32 bits B. 64 bits C. 128 bits D. 256 bits

Last Answer : C. 128 bits 

An IPv6address is _________ bits long. A) 32B) 64 C) 128 D) none of the above

Description : An IPv6address is _________ bits long. A) 32 B) 64 C) 128 D) none of the above

Last Answer : 128

IPv6 has _______ -bit addresses. A. 32B. 64 C. 128 D. Variable

Description : IPv6 has _______ -bit addresses. A. 32 B. 64 C. 128 D. Variable

Last Answer : C. 128

What is the size of an IP address? A. 64 bit B. 128 bit C. 16 bit D. 32 bit

Description : What is the size of an IP address? A. 64 bit B. 128 bit C. 16 bit D. 32 bit

Last Answer : D. 32 bit

In IPv6,a _________address comprises 80 bits of zero, followed by16 bitsof one, followed by the 32-bit IPv4address. A) link local B) site local C) mapped D) none of the above

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Last Answer : mapped

An IPv4 address consistsof _______ bits. A) 4 B) 8 C) 32 D) 64

Description : An IPv4 address consistsof _______ bits. A) 4 B) 8 C) 32 D) 64

Last Answer : 32

How many bits internet address isassigned to eachhost on a TCP/IP internet which is used in all communications withthehost? A. 16 - bits B. 32 - bits C. 48 - bits D. 64 - bits E. None of the above

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In IPv6,a ___________ address is anaddress of 96 bits of zero followed by32 bits of IPv4 address. A) link local B) site local C) mapped D) none of the above

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Last Answer : none of the above

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Last Answer : (C) Number of bits required for IPv4 address is less than number of bits required for IPv6 address.

Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it is assumed that each sample requires 8 bits? (A) 32 kbps (B) 64 kbps (C) 128 kbps (D) 256 kbps

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Last Answer : (C) 128 kbps

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Description : Which of the following statement is true? I. An address with all bits 1 is interpreted as all networks or all hosts. II. The class A network 128.0.0.0 is defined as the loopback network. a. i only b. ii only c. Both A and B d. None of the above

Last Answer : a. i only

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Description : Which of the following is correct IPv4 address? a. 124.201.3.1.52 b. 01.200.128.123 c. 300.142.210.64 d. 128.64.0.0

Last Answer : d. 128.64.0.0

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Last Answer : 8

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Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______. a. 64 Kbps b. 32 Mbps c. 32 Kbps d. 64 MbpS

Last Answer : c. 32 Kbps

The Internet addresses are ______ bits in length in IPV4 addressing scheme A. 16 B. 64 C. 32 D. 48

Description : The Internet addresses are ______ bits in length in IPV4 addressing scheme A. 16 B. 64 C. 32 D. 48

Last Answer : C. 32

The Internet addresses are ……….. bits in length in IPV4 addressing scheme a. 16 b. 64 c. 48 d. 32

Description : The Internet addresses are ……….. bits in length in IPV4 addressing scheme a. 16 b. 64 c. 48 d. 32

Last Answer : d. 32

The processor 80386/80486 and the Pentium processor uses _____ bits address bus: a. 16 b. 32 c. 36 d. 64

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Last Answer : b. 32

The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Description : The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Last Answer : (C) 16 bits Explanation: VirtualAddress = 32 bits PageSize = 4KB = 12 bits therefore : VPNTag = 20 bits, OffsetTag = 12 bits TLBEntryLength = VPNTag = 20 bits TotalTLBEntries = 64, 4-way implies ... therefore : TLBIndex = 4 bits TLBTag = TLBEntryLength - TLBIndex = 20 - 4 = 16 bits

A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32

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Last Answer : (3) 15 and 14

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Description : In Ethernet addressing, ifall the bits are 1s, the address is _________. A) unicast B) multicast C) broadcast D) none of the above

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