.12 X 13+105% of 993 +879/18 +15 (1)1150 (2)1170 (3)1185 (4)1200 (5) 1215 .12 X 13+105% of 993 +879/18 +15 (1)1150 (2)1170 (3)1185 (4)1200 (5) 1215

.12 X 13+105% of 993 +879/18 +15
(1)1150
(2)1170
(3)1185
(4)1200
(5) 1215
by

1 Answer

Answer :

(4)1200
by

Related questions

12 X 13+105% of 993 +879/18 +15 (1)1150 (2)1170 (3)1185 (4)1200 (5) 1215

Description : 12 X 13+105% of 993 +879/18 +15 (1)1150 (2)1170 (3)1185 (4)1200 (5) 1215

Last Answer : (1)1150

Ghaznavi rule lasted in the Subcontinent from 1010 A.D. to _____. A. 1180 B. 1170 C. 1187 D. 1185

Description : Ghaznavi rule lasted in the Subcontinent from 1010 A.D. to _____. A. 1180 B. 1170 C. 1187 D. 1185

Last Answer : ANSWER: C

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

In 2001, 6400 candidates appeared at the exam and 40% of them qualified. In 2005 the ratio between qualified males and females was 3:5. What is the total number of female candidates who qualified in these two years? A. 1120 B. 1220 C. 1330 D. 1150

Description : In 2001, 6400 candidates appeared at the exam and 40% of them qualified. In 2005 the ratio between qualified males and females was 3:5. What is the total number of female candidates who qualified in these two years? A. 1120 B. 1220 C. 1330 D. 1150

Last Answer : B. 1220

The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180

Description : The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180

Last Answer : LCM = 45× HCF LCM + HCF = 46× HCF = 1150 HCF = 25, LCM =1125. product of 2 numbers = LCM×HCF required number = (25× 1125) / 125 = 225. Answer: d)

A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has the son covered at the point when the father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters

Description : A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has ... father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters

Last Answer : Time taken is same for both father and son Let x be the distance son travelled before being overtaken by his father Time taken by son = x/5 km/hour Time taken by father = (1000 + x) / 7.5 km/hr Since, time taken is same x/5 = (1000 + x) / 7.5 or x = 2000m Answer: b)

A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms per hour, should he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Description : A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms ... he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Last Answer : Let x' be the distance between house and station. Time taken to travel a distance of x at the speed of 10km/hr, T1 = x/10 hours Time taken to travel a distance of x at the speed of 15km/hr, T2 = x/15 hours we ... the station at 5 pm, speed = 60/5 = 12 km/hr [12 pm - 5pm, time = 5 hours] Answer: a)

Find the number which when multiplied by 13 is increased by 180: 1. 20 2. 15 3. 12 4. 5 5. 14

Description : Find the number which when multiplied by 13 is increased by 180: 1. 20 2. 15 3. 12 4. 5 5. 14

Last Answer : Answer- 2 (15) Explanation:- let no. be X X *13= X+180 !2x=180 x=15

18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Description : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Last Answer : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 Sol: 322 + 372.6 = ? ÷4 694.6 x 4 = ? ? = 2778.4 Answer: a)

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

8/15 of 3/17 of 12/13 of 15470 = ? a) 1242 b) 1344 c) 1464 d) 1504 e) 1624

Description : 8/15 of 3/17 of 12/13 of 15470 = ? a) 1242 b) 1344 c) 1464 d) 1504 e) 1624

Last Answer : b) 1344

A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, 50% of the components were rejected. What is the loss to the manufacture? [TCS recruitment exam question] A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Description : A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, ... A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Last Answer : Answer - B. Rs 13,000 Explanation: 5% of 2000=100 so 2000-100=1900 so,if he sells 1900 he will get 25% profit cost per piece rs 25 so 25x 1900 don't solve here if 125% . ... /125=38000=CP if 50% rejected,only 1000 pieces sold so 1000 25=25000=SP loss=cp-sp= 38000-25000=13000

What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Description : What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Last Answer : Answer: d)

15 30 ? 40 8 48 a) 10 b) 20 c) 18 d) 12 e) None of these

Description : 15 30 ? 40 8 48 a) 10 b) 20 c) 18 d) 12 e) None of these

Last Answer : The series is ×2, ÷3, ×4, ÷5, ... Answer: a)

Two pipes fills a tank in 12 hours and 15 hours respectively while a third pipe empties the tank in 18 hours. !f all three pipes operate simultaneously, in what time will the tank be full? a) 10 hours b) 10 10/17 hours c) 11 hours d) 9 hours e) 12 1/17 hours

Description : Two pipes fills a tank in 12 hours and 15 hours respectively while a third pipe empties the tank in 18 hours. !f all three pipes operate simultaneously, in what time will the tank be full? a) 10 hours b) 10 10/17 hours c) 11 hours d) 9 hours e) 12 1/17 hours

Last Answer : b) 10 10/17 hours

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Description : Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Last Answer : Answer – A (10 min) Explanation – Due to stoppages, it covers 9 km less.Time taken to cover 9 km = (9/54 x 60) min = 10 min

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. What is the proportion of the solution Y in the liquid in the tank after 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15

13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Description : 13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Last Answer : ?=189+405-141 = 453 Answer: d)

7171 + 3854 + 1195) ÷ (892 + 214 + 543) = ? 1) 13 2) 18 3) 3 4) 26 5) 7

Description : 7171 + 3854 + 1195) ÷ (892 + 214 + 543) = ? 1) 13 2) 18 3) 3 4) 26 5) 7

Last Answer : 5) 7

(7171+3854+1195)÷(892 + 214 +543)=? a) 13 b) 18 c) 3 d) 26 e) 7

Description : (7171+3854+1195)÷(892 + 214 +543)=? a) 13 b) 18 c) 3 d) 26 e) 7

Last Answer : Answer: e)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

Shweta deposits a certain amount on 1st January and 1st July (Same amount on both days) in a bank that offers 5% compound interest, compounded half-yearly. Shweta gains interest of Rs.121 at the end of the year. How much money did Shweta deposit? a) 1200 b) 1300 c) 1400 d) 1500 e) 1600

Description : Shweta deposits a certain amount on 1st January and 1st July (Same amount on both days) in a bank that offers 5% compound interest, compounded half-yearly. Shweta gains interest of Rs.121 at the end of the year. How much money did Shweta deposit? a) 1200 b) 1300 c) 1400 d) 1500 e) 1600

Last Answer : Let the amount be P Half yearly rate = 5/2 = 2.5% For the deposit on January, Amount = P (1 + 2.5 / 100)2 For the deposit on July, Amount = P (1 + 2.5 /100) We can solve the question by ... Amount in July = 1600 1.025 = 1640 So total interest = 81 + 40 = 121 Required answer is 1600 Answer: e)

Ashok being the sleeping partner receives 1/10th of profit and the remaining is divided between pramod and prakash in the ratio of 1:2..If the difference between the profit shares of Ashok and Prakash is Rs.2000.What is pramod’s share in Rs.? A.Rs.1800 B.Rs.2200 C.Rs.1200 D.Rs.1500

Description : Ashok being the sleeping partner receives 1/10th of profit and the remaining is divided between pramod and prakash in the ratio of 1:2..If the difference between the profit shares of Ashok and Prakash is Rs.2000.What is pramod’s share in Rs.? A.Rs.1800 B.Rs.2200 C.Rs.1200 D.Rs.1500

Last Answer : Answer:- C (1200) Explanation:- let total profit =x ashok's share in profit is (1/10)x remaining profit = x= (1/10)x= (9/10)x pramod's share= 1/3 x (9/10)x = (3/10 )x Prakash's share= 2/3 ... /10)x = (5/10)x 5/10 x = 2,000 so, x= 4000 pramod's share= (3/10) x 4000=1200

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Last Answer : If the distance be x km, then x/40-x/50=6/60 x/4-x/5=1 x=20 km. Required time = (20/40) hour – 11 minutes = (1/2×60-11) minutes = 19 minutes Answer: c)

What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Description : What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Last Answer : Answer- 2 ( 3) Explanation:- On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted 

A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Description : A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Last Answer : 4) 1/12

An engine working on air standard Otto cycle has a cylinder diameter of 10 cm and stroke length of 15 cm. The ratio of specific heats for air is 1.4. If the clearance volume is 196.3 cc and the heat supplied per kg of air per cycle is 1800 kJ/kg, then work output per cycle per kg of air is a. 879.1 kJ/ b. 890.2 kJ c. 895.3 kJ d. 973.5 kJ

Description : An engine working on air standard Otto cycle has a cylinder diameter of 10 cm and stroke length of 15 cm. The ratio of specific heats for air is 1.4. If the clearance volume is 196.3 cc and the heat supplied per kg of air per ... kg of air is a. 879.1 kJ/ b. 890.2 kJ c. 895.3 kJ d. 973.5 kJ

Last Answer : ANSWER d. 973.5 kJ

3 ? 113 673 3361 13441 40321 a) 13 b) 14 c) 15 d) 16 e) 17

Description : 3 ? 113 673 3361 13441 40321 a) 13 b) 14 c) 15 d) 16 e) 17

Last Answer : The series is: 3 × 8 – 7 = 17; 17 × 7 – 6 = 113; 113 × 6 – 5 = 673; 673 × 5 – 4 = 3361; 3361 × 4 – 3 = 13441; 13441 × 3 – 2 = 40321 Answer: e)

24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Description : 24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Last Answer : The series consists of two series 1 and 2: Series 1 : 24 26 28 30 +2 +2 +2 Series 2 : 14 15 16 +1 +1 Answer: c)

13, 15, 22, 50, 113, ? a) 239 b) 272 c) 287 d) 296 e) 306

Description : 13, 15, 22, 50, 113, ? a) 239 b) 272 c) 287 d) 296 e) 306

Last Answer : Answer: a)

(32.3)2 ÷ 4 + √361 = ?2 + 50 a) 15 b) 13 c) 11 d) 17 e) None of these

Description : (32.3)2 ÷ 4 + √361 = ?2 + 50 a) 15 b) 13 c) 11 d) 17 e) None of these

Last Answer : 32*32 = 1024 1024/4 + 19 = 256+19= 275 Answer: a)

The average age of four boys, five years ago was 9 of all the five is 15 years. The present age of the new boy is 1. 22 years 2. 24 years 3. 21 years 4. 18 years 5. 19 years

Description : The average age of four boys, five years ago was 9 of all the five is 15 years. The present age of the new boy is 1. 22 years 2. 24 years 3. 21 years 4. 18 years 5. 19 years

Last Answer : 5; Five years ago the average age of 4 boys = 9 years The present average age of 4 boys = 9+5 = 14 So the present age of new boys = 15 + 4 x 1 = 19 years

When a ball bounces, it rises to 2/3 of the height from which it fell. If the ball is dropped from a height of 36m, how high will it rise at the third bounce? a) 10 2/3 m b) 13 2/3 m c) 12 1/3 m d) 12 2/3m e) None of these

Description : When a ball bounces, it rises to 2/3 of the height from which it fell. If the ball is dropped from a height of 36m, how high will it rise at the third bounce? a) 10 2/3 m b) 13 2/3 m c) 12 1/3 m d) 12 2/3m e) None of these

Last Answer : Height at third bounce =36 × (2/3)3 = 10 2/3 metre Answer: a)

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of theseSix bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Description : Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Last Answer : Answer – D (16) Explanation – L.C.M. of 2, 4, 6, 8, 10, 12 is 120.So, the bells will toll together after every 120 seconds, i.e, 2 minutes.In 30 minutes, they will toll together 30/2 + 1 = 16

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

At the time of marriage, a man was 6 years older to his wife. 12 years after their marriage, his age is 6/5 times the age of his wife. What was wife’s age at the time of marriage? a) 18 years b) 24 years c) 30 years d) 36 years e) None of these

Description : At the time of marriage, a man was 6 years older to his wife. 12 years after their marriage, his age is 6/5 times the age of his wife. What was wife’s age at the time of marriage? a) 18 years b) 24 years c) 30 years d) 36 years e) None of these

Last Answer : ratio of their ages, 12 years hence = 6 : 5  Difference in ages = 1 ratio = 6 years wife’s age (12 years hence) = 5 ratio = 5 × 6 years = 30 years wife’s age at the time of marriage = 30 – 12 = 18 years Answer: a)

One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.

Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these

Description : Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these

Last Answer : Total money = 55x + 85x + 105x = 3920 245x = 3920 x = 16 Answer: c)

15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Description : 15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Last Answer : The series is a geometric progression with a common ratio 1.2. Hence the next term is 25.92 × 1.2 = 31.104 Answer: a)

Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Description : Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Last Answer : Let the required time be x years. then (50+x) = 2 (18 + x) = 50 + x = 36 + 2x  x = 14 years. Alternative method : Double of B’s age = 2 × 18 = 36 years difference between A’s present age and double of B’s age = 50 – 36= 14 years. A will be twice of B’s age after 14 years. Answer: a)

Ishath bought 15 pieces of [email protected],500/- each and sold all of them at the total price of Rs.81, 000/-. What is the percent profit earned in the deal? a) 18.66 b) 20 c) 25 d) 36 e) None of these

Description : Ishath bought 15 pieces of [email protected],500/- each and sold all of them at the total price of Rs.81, 000/-. What is the percent profit earned in the deal? a) 18.66 b) 20 c) 25 d) 36 e) None of these

Last Answer : Total cost of 15 pieces of Mobiles= 15×4500 = Rs. 67500 Total Sales prices of 15 pieces of Mobiles= Rs. 81000 Profit% = 81000 – 67500 / 67500 × 100 = 13500/67500 × 100 = 20% Answer: b)

The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: A.68 B.98 C.180 D.364 E.None of these

Description : The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: A.68 B.98 C.180 D.364 E.None of these

Last Answer : Answer – D (364) Explanation – L.C.M. of 6, 9, 15 and 18 is 90. Let required number be 90k + 4, which is multiple of 7. Least value of k for which (90k + 4) is divisible by 7 is k = 4. Required number = (90 x 4) + 4 = 364.

The average age of a family of 6 members is 22 years. If the age of the youngest member be 7 years, then what was the average age of the family at the birth of the youngest member? A.15 B.18 C.28 D.24 E.None of these

Description : The average age of a family of 6 members is 22 years. If the age of the youngest member be 7 years, then what was the average age of the family at the birth of the youngest member? A.15 B.18 C.28 D.24 E.None of these

Last Answer : Answer – B (18) Explanation – Total age of all members = 6 x 22 = 132 years 7 years ago, total sum of ages = 132 – (6 x 7) = 90 years But at that time there were 5 members in the family Average at that time = 90 /5 = 18 years

Hemant sold 10 sarees for a total profit of Rs. 460 and 12 sarees for a total profit of Rs. 144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of Rs. 18 per sarees? A. Rs 7.10 B. Rs 7.60 C. Rs 7.99 D. Rs 8

Description : Hemant sold 10 sarees for a total profit of Rs. 460 and 12 sarees for a total profit of Rs. 144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of Rs. 18 per sarees? A. Rs 7.10 B. Rs 7.60 C. Rs 7.99 D. Rs 8

Last Answer : Answer – B (Rs 7.60) Explanation – Total profit required = Rs.(42 x 18) = Rs.756 Profit on 22 sarees = Rs. (460 + 144) = Rs. 604 Profit on 20 sarees = Rs. (756 – 604) = Rs. 152 Average profit on these sarees = Rs.(152/20) = Rs. 7.60

The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books? A.Rs 10 and Rs 16 B.Rs 12 and Rs 24 C.Rs 24 and Rs 18 D.Rs 28 and Rs 12 E.None of these

Description : The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of ... and Rs 16 B.Rs 12 and Rs 24 C.Rs 24 and Rs 18 D.Rs 28 and Rs 12 E.None of these

Last Answer : Answer - A (Rs 10 and Rs 16) Explanation - Total price of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26 Let the price of one book be Rs.x Then, the price of other book = Rs. (x ... /5)x= (8/5)x so, x +(8/5)x=26 , x=10 The prices of the two books are Rs. 10 and Rs. 16

If x:y =3:4,in the ratio of (7x-4y) : ( 3x + y) a) 2:11 b) 4:9 c) 5:13 d) 6:5 e) 13:5

Description : If x:y =3:4,in the ratio of (7x-4y) : ( 3x + y) a) 2:11 b) 4:9 c) 5:13 d) 6:5 e) 13:5

Last Answer : An easy way to solve this question is use x = 3, y=4 7x – 4y = 21 – 16 = 5 3x + y = 9+4 = 13 Required ratio = 5:13 Answer: c)