Shweta deposits a certain amount on 1st January and 1st July (Same amount on both days) in a bank that offers 5% compound interest, compounded half-yearly. Shweta gains interest of Rs.121 at the end of the year. How much money did Shweta deposit? a) 1200 b) 1300 c) 1400 d) 1500 e) 1600

Shweta deposits a certain amount on 1st January and 1st July (Same amount on both days) in a bank that offers 5% compound interest, compounded half-yearly. Shweta gains interest of Rs.121 at the end of the year. How much money did Shweta deposit?
a) 1200
b) 1300
c) 1400
d) 1500
e) 1600
by

1 Answer

Answer :

Let the amount be P
Half yearly rate = 5/2 = 2.5%
For the deposit on January, Amount = P (1 + 2.5 / 100)2
For the deposit on July, Amount = P (1 + 2.5 /100)
We can solve the question by substituting options now.
If P = 1600, Amount in January = 1600 × 1.025 × 1.025 = 1681
Amount in July = 1600 × 1.025 = 1640
So total interest = 81 + 40 = 121
Required answer is 1600
Answer: e)
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Last Answer : Labelled price = [(14280×100)/85] = Rs. 16800 Or, 23X/120 = 69/5 Or, X= [(69×120)/(23×5)] = 72km. Answer is: c)

A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, 50% of the components were rejected. What is the loss to the manufacture? [TCS recruitment exam question] A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Description : A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, ... A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Last Answer : Answer - B. Rs 13,000 Explanation: 5% of 2000=100 so 2000-100=1900 so,if he sells 1900 he will get 25% profit cost per piece rs 25 so 25x 1900 don't solve here if 125% . ... /125=38000=CP if 50% rejected,only 1000 pieces sold so 1000 25=25000=SP loss=cp-sp= 38000-25000=13000

By selling a telephone for Rs. 2400, a shopkeeper make a profit of 25%. Then, his profit percentage, if he had sold it for Rs. 2016, is ? (a) 10% (b) 6.25% (c) 6.5% (d) 5% (e) 12%

Description : By selling a telephone for Rs. 2400, a shopkeeper make a profit of 25%. Then, his profit percentage, if he had sold it for Rs. 2016, is ? (a) 10% (b) 6.25% (c) 6.5% (d) 5% (e) 12%

Last Answer : (d) 5%

The difference between the cost price and sale price of an article is Rs. 500 if the profit is 20%. The selling price is: A. Rs 4000 B. Rs 1500 C. Rs 3000 D. Rs 3300

Description : The difference between the cost price and sale price of an article is Rs. 500 if the profit is 20%. The selling price is: A. Rs 4000 B. Rs 1500 C. Rs 3000 D. Rs 3300

Last Answer : Answer – C. Rs.3000 Explanation – 120%-100%=20% 20%…………………500 120%…………….? ?=3000

57% of 400 + 23% of 700 + 32% of 1100 – 28% of 1300 = ? a) 401 b) 389 c) 377 d) 364 e) 352

Description : 57% of 400 + 23% of 700 + 32% of 1100 – 28% of 1300 = ? a) 401 b) 389 c) 377 d) 364 e) 352

Last Answer : ? = 57×4 + 23×7 + 32×11 - 28×13 = 228 + 161 + 352 – 364 = 377 Answer: c)

Arun and Bharat started a business with investments of Rs.10000 and Rs.15000 respectively. Arun being a working partner gets Rs.100 every month as salary from the profit. At the end of one year the business makes a profit of Rs.4800. Find the total share of Arun out o this amount (in Rs.) a)2880 b)2640 c)3240 d)2760

Description : Arun and Bharat started a business with investments of Rs.10000 and Rs.15000 respectively. Arun being a working partner gets Rs.100 every month as salary from the profit. At the end of one year the business makes a ... the total share of Arun out o this amount (in Rs.) a)2880 b)2640 c)3240 d)2760

Last Answer : b)2640

The synchronous speed for a 3 phase 6-pole induction motor is 1200 rpm. If the number of poles is now reduced to 4 with the frequency remaining constant, the rotor speed with a slip of 5% will be _________. (A) 1690 rpm (B) 1750 rpm (C) 1500 rpm (D) 1710 rpm

Description : The synchronous speed for a 3 phase 6-pole induction motor is 1200 rpm. If the number of poles is now reduced to 4 with the frequency remaining constant, the rotor speed with a slip of 5% will be _________. (A) 1690 rpm (B) 1750 rpm (C) 1500 rpm (D) 1710 rpm

Last Answer : (D) 1710 rpm

A shopkeeper sold a toothpaste at a profit of 12.5%. His cost price was Rs.5 less than his selling price. find his cost price (in Rs.) a)30 b)36 c)40 d)50

Description : A shopkeeper sold a toothpaste at a profit of 12.5%. His cost price was Rs.5 less than his selling price. find his cost price (in Rs.) a)30 b)36 c)40 d)50

Last Answer : c)40

A man purchased wheat worth Rs. 400. He sold 3/4 at a loss of 10% and the reminder at a gain of 10%. On the whole he gets: A. loss of 5% B. gain of 5 C. loss of 19% D. loss of 6%

Description : A man purchased wheat worth Rs. 400. He sold 3/4 at a loss of 10% and the reminder at a gain of 10%. On the whole he gets: A. loss of 5% B. gain of 5 C. loss of 19% D. loss of 6%

Last Answer : Answer – A (loss of 5%) Explanation – C.P of 3/4th = Rs. (3/4 x 400) = Rs. 300, C.P of 1/4th = Rs. 100 ∴ Total S.P = (90% of Rs. 300 + 110% of Rs. 100) = Rs. 380 Loss = (20/400 x 100)% = 5%

A dealer sold a Radio at a loss of 2.5%. Had he sold it for Rs. 100 more, he would have gained 7.5%. To gain 12.5% he should sell it for : A. Rs 2200 B. Rs 1000 C. Rs 1100 D. Rs 1125

Description : A dealer sold a Radio at a loss of 2.5%. Had he sold it for Rs. 100 more, he would have gained 7.5%. To gain 12.5% he should sell it for : A. Rs 2200 B. Rs 1000 C. Rs 1100 D. Rs 1125

Last Answer : Answer – D. Rs.1125 Explanation – Let C.P be Rs.x then,(107.5 % of x) – (97.5 % of x) = 100 => 10% of x = 100 => x =1000 ∴ desired S.P = 112.5 % of Rs. 100 = Rs.(225/2 x 1/100 x 1000) =Rs. 1125