What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14
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Answer- 2 ( 3) Explanation:- On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted 
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Related questions

A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Description : A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is  subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Last Answer : Answer- 3(65) Explanation:- let the number be written as xy x-ten’s place y units place x+y=11…………………1 (10x+y)-(10y+x)=9 10x+y-10y-x=9 9x-9y=9 x-y=1………………….2 Add (1) & (2) 2x=12 x=6 y=5 the number is 65

Find the number which when multiplied by 13 is increased by 180: 1. 20 2. 15 3. 12 4. 5 5. 14

Description : Find the number which when multiplied by 13 is increased by 180: 1. 20 2. 15 3. 12 4. 5 5. 14

Last Answer : Answer- 2 (15) Explanation:- let no. be X X *13= X+180 !2x=180 x=15

A number gets reduced to its one-third when 48 is subtracted from it. What is two-third of that number? 1. 22 2. 76 3. 36 4. 48 5. None of these

Description : A number gets reduced to its one-third when 48 is subtracted from it. What is two-third of that number? 1. 22 2. 76 3. 36 4. 48 5. None of these

Last Answer : Answer:- 4 (48) Expalanation – let number be X X-48 = X/3 X-X/3 =48 2/3X= 48 so 2/3th of number=48

The sum of twice the square of a number and 7 times the number equals 15. What is the number? 1.1/2 2.3/4 3.3/2 4.5/3

Description : The sum of twice the square of a number and 7 times the number equals 15. What is the number? 1.1/2 2.3/4 3.3/2 4.5/3

Last Answer : Answer-3 (3/2) Explanation:-2x^2 + 7x = 15 2x^2 + 7x – 15 = 0 2x^2 + 10x-3x – 15 = 0 2x(x+5)-3(x+5) = 0 (x+5)(2x-3) = 0 x = -5 or x = 3/2

One number is 3 more than another and the sum of their square is 269.Find the number. 1.10 2.12 3.15 4.20

Description : One number is 3 more than another and the sum of their square is 269.Find the number. 1.10 2.12 3.15 4.20

Last Answer : Answer-1 (10) Explanation:- x is one number x+3 the other x^2 +x^2 +6x+9 ; (that is (x+3)(x+3) =269 2x^2+6x -260=0 x^2+3x-130=0 , dividing by 2. (x+13)(x-10)=0 one number is 10, the other is 13 squared 10=100 square 13=169 sum is 269

One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these

Description : One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these

Last Answer : Answer- 3(40) Explanation:- (1/5)x =(5/8)y………..1 if 35 is added to first no. , x + 35= 4y so,x= 4y -35 put in eq 1… (1/5)( 4y-35) = (5/8)y y=40 =second number

The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Description : The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Last Answer : Answer- 4 (69) Explanation:- lets digit at tens and ones place be 2x and 3x So,number is 2x*10 + 3x After interchanging number will be 3x*10 +2x so, [3x*10 +2x] – [2x*10 + 3x]27 we get,x=3 so number =69

Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Description : Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Last Answer : Answer- 3( 19,20,21) Explanation:- let number be x,x+1,x+2 2x + 3(x+1)+4(x+2)=180 x=19 so numbers are 19,20,21

In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, the dividend is: 1.4236 2.4306 3.4336 4.5336

Description : In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, the dividend is: 1.4236 2.4306 3.4336 4.5336

Last Answer : Answer – 4 (5336) Explanation – Divisor = (5 x 46) = 230. Also, 10 x Q = 230 Q = 23. And, R = 46. Dividend = (230 x 23 + 46) = 5336

24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Description : 24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Last Answer : The series consists of two series 1 and 2: Series 1 : 24 26 28 30 +2 +2 +2 Series 2 : 14 15 16 +1 +1 Answer: c)

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

The average age of the students in a class is 14. The average age of half of the students in that class and the class teacher is 16. The average age of the remaining half of the students is 15. What is the number of students in that class? a) 20 b) 70 c) 80 d) Cannot be determined e) None of these

Description : The average age of the students in a class is 14. The average age of half of the students in that class and the class teacher is 16. The average age of the remaining half of the students is 15. What is the number of students in that class? a) 20 b) 70 c) 80 d) Cannot be determined e) None of these

Last Answer : Because total no. of students is not known we cannot find the answer. Answer: d)

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Description : The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Last Answer : Answer – C (23) Explanation – L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23

3 ? 113 673 3361 13441 40321 a) 13 b) 14 c) 15 d) 16 e) 17

Description : 3 ? 113 673 3361 13441 40321 a) 13 b) 14 c) 15 d) 16 e) 17

Last Answer : The series is: 3 × 8 – 7 = 17; 17 × 7 – 6 = 113; 113 × 6 – 5 = 673; 673 × 5 – 4 = 3361; 3361 × 4 – 3 = 13441; 13441 × 3 – 2 = 40321 Answer: e)

vIf the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Description : If the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Last Answer : 2) 39 : 28: 20

The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books? A.Rs 10 and Rs 16 B.Rs 12 and Rs 24 C.Rs 24 and Rs 18 D.Rs 28 and Rs 12 E.None of these

Description : The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of ... and Rs 16 B.Rs 12 and Rs 24 C.Rs 24 and Rs 18 D.Rs 28 and Rs 12 E.None of these

Last Answer : Answer - A (Rs 10 and Rs 16) Explanation - Total price of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26 Let the price of one book be Rs.x Then, the price of other book = Rs. (x ... /5)x= (8/5)x so, x +(8/5)x=26 , x=10 The prices of the two books are Rs. 10 and Rs. 16

The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Description : The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Last Answer : Let it be x . Then : 5×10+5×14+20×x=30×12 20x=360-120 or 20x=240 or x = 12 Answer: c)

Out of the total number of students studying Dentistry, what percent knows at least two languages? (1) 6112/13 (2) 5713/16 (3) 5913/17 (4) 661/4 (5) 6212/19

Description : Out of the total number of students studying Dentistry, what percent knows at least two languages? (1) 6112/13 (2) 5713/16 (3) 5913/17 (4) 661/4 (5) 6212/19

Last Answer : (4) 661/4

Find the polynomial of least degree which should be subtracted from the polynomial x4 + 2x3 – 4x2 + 6x – 3 so that it is exactly divisible by x2 – x + 1. -Maths 10th

Description : Find the polynomial of least degree which should be subtracted from the polynomial x4 + 2x3 – 4x2 + 6x – 3 so that it is exactly divisible by x2 – x + 1. -Maths 10th

Last Answer : Here, p(x) = x4 + 2x3 - 4x2 + 6x - 3, g(x) = x2 - x +1 On dividing p(x) by g(x) Therefore (x-1) must be subtracted from the polynomial p(x) to make it divisible by g(x).

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of theseSix bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Description : Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Last Answer : Answer – D (16) Explanation – L.C.M. of 2, 4, 6, 8, 10, 12 is 120.So, the bells will toll together after every 120 seconds, i.e, 2 minutes.In 30 minutes, they will toll together 30/2 + 1 = 16

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Last Answer : If the distance be x km, then x/40-x/50=6/60 x/4-x/5=1 x=20 km. Required time = (20/40) hour – 11 minutes = (1/2×60-11) minutes = 19 minutes Answer: c)

A can build up a wall in 8 days while B can break it in 3 days. A has worked for 4 days and then B joined to work with A for another 2 days only. In how many days will A alone build up the remaining part of the wall? a) 13/3 days b) 22/3 days c) 7/4 days d) 7 days e) None of these

Description : A can build up a wall in 8 days while B can break it in 3 days. A has worked for 4 days and then B joined to work with A for another 2 days only. In how many days will A alone build up the remaining part of the wall? a) 13/3 days b) 22/3 days c) 7/4 days d) 7 days e) None of these

Last Answer : Amount of work done by A in one day = 1/8th of the total work B can break 1/3rd of the work in one day Therefore, if both of them are working together then the work done in one day = 1/8 - 1/3 = -5/24 ... = 11/12 Time taken by A to finish 11/12th of the work = 11/12 8 = 22/3 days Answer: b)

A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, 50% of the components were rejected. What is the loss to the manufacture? [TCS recruitment exam question] A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Description : A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, ... A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Last Answer : Answer - B. Rs 13,000 Explanation: 5% of 2000=100 so 2000-100=1900 so,if he sells 1900 he will get 25% profit cost per piece rs 25 so 25x 1900 don't solve here if 125% . ... /125=38000=CP if 50% rejected,only 1000 pieces sold so 1000 25=25000=SP loss=cp-sp= 38000-25000=13000

(32.3)2 ÷ 4 + √361 = ?2 + 50 a) 15 b) 13 c) 11 d) 17 e) None of these

Description : (32.3)2 ÷ 4 + √361 = ?2 + 50 a) 15 b) 13 c) 11 d) 17 e) None of these

Last Answer : 32*32 = 1024 1024/4 + 19 = 256+19= 275 Answer: a)

Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs. What is the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67

Description : Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs ... the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67 

Last Answer : Answer – B (Rs 10.875) Explanation – Total C.P = Rs. (120 x 110) =Rs. 13200. Total S.P = Rs.[(30 x 110 + 30 x 12) + (75 x 110 + 75 x 14) + (15 x 110 – 15 x 7) =Rs..14505 Average profit = Rs. (14505 – 13200) /120 = Rs. 1305/120= 10.875

A vendor bought 30 dozen bananas at Rs.16 per dozen. He sold 10 dozens at Rs.20 per dozen and 16 dozens at Rs.25 per dozen. The remaining 4 dozens were rotten and he threw away. Find his profit percentage. a)20% b)25% c)30% d)33 1/3%

Description : A vendor bought 30 dozen bananas at Rs.16 per dozen. He sold 10 dozens at Rs.20 per dozen and 16 dozens at Rs.25 per dozen. The remaining 4 dozens were rotten and he threw away. Find his profit percentage. a)20% b)25% c)30% d)33 1/3%

Last Answer : b)25%

Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Description : Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Last Answer : Let the required time be x years. then (50+x) = 2 (18 + x) = 50 + x = 36 + 2x  x = 14 years. Alternative method : Double of B’s age = 2 × 18 = 36 years difference between A’s present age and double of B’s age = 50 – 36= 14 years. A will be twice of B’s age after 14 years. Answer: a)

If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj? A.44 B.60 C.80 D.92

Description : If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj? A.44 B.60 C.80 D.92

Last Answer : Answer : B (60) Explanation - Let Anuj's age be X Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 - 2 = 3) If Arun had born 6 years before, his age would had been X - 6. As per the ... as that of Gokul's age. i.e. (X - 6) /18= 3 X-6 =3 x 18 x = 60

A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Description : A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Last Answer : 125% C.P. of sugar per kg = Rs. 4.25 C.P of the sugar per kg = [4.25×100] / 125 = Rs. 3.40. thus, the profit on 1 kg 85 paise by reducing price to 5 paise, to make same profit he must sell, 85/5 = 17kg so required ratio = 1 : 17. Answer: d)

All active prostaglandins have at least one double bond between positions (A) 7 and 8 (B) 10 and 11 (C) 13 and 14 (D) 16 and 17

Description : All active prostaglandins have at least one double bond between positions (A) 7 and 8 (B) 10 and 11 (C) 13 and 14 (D) 16 and 17

Last Answer : Answer : A

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Let A and B be two fuzzy integers defined as: A={(1,0.3), (2,0.6), (3,1), (4,0.7), (5,0.2)} B={(10,0.5), (11,1), (12,0.5)} Using fuzzy arithmetic operation given by Image (A) {(11,0.8), (13,1), (15,1)} (B) {(11,0.3), (12,0.5), (13,1), (14,1), (15,1), (16,0.5), (17,0.2)} (C) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,1), (16,0.5), (17,0.2)} (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Description : Let A and B be two fuzzy integers defined as: A={(1,0.3), (2,0.6), (3,1), (4,0.7), (5,0.2)} B={(10,0.5), (11,1), (12,0.5)} Using fuzzy arithmetic operation given by (A) {(11,0.8), (13,1), (15,1)} ( ... ,0.2)} (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Last Answer : (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB(x))) Then, f(A+B) is equal to (A) {(0.5,12), (0.6,13), (1,14), (0.7,15), (0.7,16), (1,17), (1,18)} (B) {(0.5,12), (0.6,13), (1,14), (1,15), (1,16), (1,17), (1,18)} (C) {(0.3,12), (0.5,13), (0.5,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Description : Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB( ... ,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Last Answer : (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} 

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Description : 13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Last Answer : ?=189+405-141 = 453 Answer: d)

A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Description : A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Last Answer : 4) 1/12

If x:y =3:4,in the ratio of (7x-4y) : ( 3x + y) a) 2:11 b) 4:9 c) 5:13 d) 6:5 e) 13:5

Description : If x:y =3:4,in the ratio of (7x-4y) : ( 3x + y) a) 2:11 b) 4:9 c) 5:13 d) 6:5 e) 13:5

Last Answer : An easy way to solve this question is use x = 3, y=4 7x – 4y = 21 – 16 = 5 3x + y = 9+4 = 13 Required ratio = 5:13 Answer: c)

Two pipes A and B can fill a tank in 5 and 6hrs.Pipe C can empty it in 12hrs.If all the 3 pipes are opened together,then the tank will be filled in 1)1(13/17)hrs 2)2(8/11)hours. 3)3(9/17)hrs 4)4(1/2)hrs

Description : Two pipes A and B can fill a tank in 5 and 6hrs.Pipe C can empty it in 12hrs.If all the 3 pipes are opened together,then the tank will be filled in 1)1(13/17)hrs 2)2(8/11)hours. 3)3(9/17)hrs 4)4(1/2)hrs

Last Answer : 3)3(9/17)hrs Exp:Net part filled in 1hr=>(1/5+1/6-1/12)=17/60 Tank filled in=60/17=3(9/17).

A cartoon contains 15 torch lights out of which 3 are defective. Two torch light are chosen at random from this cartoon. The probability that at least one of these is defective is. A) 13/35 B) 14/35 C) 11/35 D) 17/35

Description : A cartoon contains 15 torch lights out of which 3 are defective. Two torch light are chosen at random from this cartoon. The probability that at least one of these is defective is. A) 13/35 B) 14/35 C) 11/35 D) 17/35

Last Answer : Answer: A) P (none is defective) = 12c2/15c2 = (12*11/2*1)/(15*14/2*1) = 66/105=22/35 P (at least one is defective) = (1 – 22/35) =13/35

the range of the data 13, 18, 20, 15, 12, 17, 9, 14, 11, and 16 is ________.

Description : the range of the data 13, 18, 20, 15, 12, 17, 9, 14, 11, and 16 is ________.

Last Answer : the range of the data 13, 18, 20, 15, 12, 17, 9, 14, 11, and 16 is ________.

The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Description : The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Last Answer : D) Calculated mean of 8 articles = 15 Incorrect sum of these 8 articles = (15*8) = 120. Correct sum of these 8 articles = (incorrect sum) - (sum of incorrect articles) + (sum of actual articles) = [120 ... (30)] = 130 Therefore, correct mean = 130/8 = 16.25 Hence, the correct mean is 16.25.

Prasad and Satish started a business with investments of Rs.2000 and Rs.5300 respectively. At the end of every month, Prasad invests Rs.300 while Satish withdraws Rs.300. What is the ratio in which they should share the profits at the end of one year. a)13:14 b)1:1 c)14:13 d)Cannot be determined

Description : Prasad and Satish started a business with investments of Rs.2000 and Rs.5300 respectively. At the end of every month, Prasad invests Rs.300 while Satish withdraws Rs.300. What is the ratio in which they should share the profits at the end of one year. a)13:14 b)1:1 c)14:13 d)Cannot be determined

Last Answer : b)1:1

A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms per hour, should he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Description : A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms ... he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Last Answer : Let x' be the distance between house and station. Time taken to travel a distance of x at the speed of 10km/hr, T1 = x/10 hours Time taken to travel a distance of x at the speed of 15km/hr, T2 = x/15 hours we ... the station at 5 pm, speed = 60/5 = 12 km/hr [12 pm - 5pm, time = 5 hours] Answer: a)

Is X divisible by 12? a. X leaves a remainder 2 when divided by 8 b. X is divisible by 3. c. X is divisible by 6. a) If the data in statement a is sufficient to answer the question, while the data in statement b and c are not required to answer the question. b) If the data in statement b is sufficient to answer the question, while the data in statement a and c are not required to answer the question c) If the data in statement a and b are sufficient to answer the question, while the data in statement c is not required to answer the question. d) If the data in statement a, b and c together are necessary to answer the question. e) If the data in statement a, b and c together are not sufficient to answer the question.

Description : Is X divisible by 12? a. X leaves a remainder 2 when divided by 8 b. X is divisible by 3. c. X is divisible by 6. a) If the data in statement a is sufficient to answer the question, while ... the question. e) If the data in statement a, b and c together are not sufficient to answer the question.

Last Answer : From (a), we notice that the number is of the form 8n+2, which means it also leaves a remainder 2 on being divided by 4. So, its not divisible by 12. From (b) and (c) together, the number can be any multiple of 6, from which we cant conclusively say if number is divisible by 12. Answer: a)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Description : A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Last Answer : c) 8 Let first two digit no. and second two digit no. be x and y respectively. x = y × 40/100 +16 x - 2y/5 = 16....(i) x + y = 72...(ii) From equation (i) and (ii) x = 32, y = 40 Difference = 8 Answer: c)