Description : 259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these
Last Answer : Difference of odd numbers 3, 5, 7, 9, 11. Answer: b)
Description : 16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these
Last Answer : Answer- 1(7016) Explanation16×2 =32 32+3=35 35×4=140 140+5=145 145×6=870 870+7=877 877×8=7016
Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these
Last Answer : Answer: a)
Description : 729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541
Last Answer : Difference of Difference 9. Answer: a)
Description : 3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these
Description : 9654 ÷ 21 +7638 ÷ 44 = ? a) 633 b) 600 c) 643 d) 621 e) 598
Last Answer : 9654 ÷ 21 + 7338 ÷ 44 = ? = 459.714 + 173.59 = 633.304 = 633 (approx) Answer: a)
Description : 1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338
Last Answer : ? = 7897 × 4 × 3 / 8 × 5 × 7 = 338.31 = 338 (approx.) Answer: e)
Description : 2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03
Last Answer : 2.5 × 0.08 ÷ (1.9)^2 = ? = 2.5 × 0.08/3.61 = ? = 0.0554 = 0.06 (approx) Answer: d)
Description : 3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555
Last Answer : 3√7469 × √668 = ? = 19.5 × 25.9 = 505.05 = 505 (approx) Answer: c)
Description : (4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885
Last Answer : (4.36)^2 × 66.5 - 371 = ? = 19.0096 × 66.5 - 371 = ? = 1264.1384 - 371 = 893.1384 = 893 (approx.) Answer: b)
Description : 196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862
Last Answer : Answer-5 (862) Explanation- add square of prime no. in each step 4,9,25,49,121,so on
Description : 5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these
Last Answer : Answer- 2 (3910) Explanationadd 5^1,5^2,5^3,5^4,5^5 and so on in each step.
Description : 5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these
Last Answer : Answer-3(509) Explanation5 x2 +3 =13 13×2 +3=29 29×2+3=61 and so on..
Description : 5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975
Last Answer : Answer- 5(51975) Explanation- multiply by consecutive odd numbers 5×1=5 5×3=15 15×5=75 75×9=4725 4725×11=51975
Description : 363,795,1227,1659,2091, ? 1 : 2423 2 : 2613 3 : 2813 4 : 2513 5 : 2523
Last Answer : Answer- 5 (2523) Explanation- +432 in every step
Description : 24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240
Last Answer : Answer- 1 (17280) Explanation- 24 x 2=48 48×3=144 144×4=576 576×5=2880
Description : 4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60
Last Answer : Answer-2 (160) Explanation- 4725 / 4.5=1050 1050/3.5=300 300/2.5=120 120/1.5=80 80/0.5=160
Description : 3,25,255,2545,25455, ? 1 : 254550 2 : 254555 3 : 254545 4 : 254555 5 : 254556
Last Answer : Answer-3 (254545) Explanation25=(3×10)-5 255=(25×10)+5 2545=(255×10)-5 25455=(2545×10)+5 ?=(2545×10)-5 = 254545
Description : 3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624
Last Answer : Answer- 3 (3754) Explanation- x4+2
Description : The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180
Last Answer : LCM = 45× HCF LCM + HCF = 46× HCF = 1150 HCF = 25, LCM =1125. product of 2 numbers = LCM×HCF required number = (25× 1125) / 125 = 225. Answer: d)
Description : The midrange frequency range of sound is from A. 256 to 2048 Hz B. 2048 to 4096 Hz C. 512 to 2048 Hz D. 16 to 64 Hz
Last Answer : A. 256 to 2048 Hz
Description : 6000 ÷ 15 × 225 – 70000 = ? a) 20000 b) 18000 c) 16000 d) 14000 e) 15000
Last Answer : ? = 6000 – 225 / 15 - 70000 = 90000 – 70000 = 20000 Answer: a)
Description : 0 1 9 36 99 225 441 a) 9 b) 36 c) 99 d) 225 e) 441
Last Answer : Answer: c)
Description : 104 153 189 214 ? a) 239 b) 225 c) 264 d) 235 e) None of these
Last Answer : Answer: e)
Description : If the length of a rice field is increased by 20% and the breadth is reduced by 20%, the area of the field will be 192 sq. m. What is the area of the original field? (a) 184 sq. m. (b) 196 sq. m. (c) 204 sq. m. (d) 225 sq. m. (e) None of these
Last Answer : (e) None of these
Description : 188, 212, 236, ?, 268, 284 a) 260 b) 256 c) 252 d) 248 e) 244
Last Answer : The pattern is 47×4=188, 53×4=212, 59×4=236, 61×4=244, 67×4=268, 71×4=284 47, 53, 59, 61, 69 and 71 are consecutive prime numbers. Answer: e)
Description : 256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176
Last Answer : The series is ×0.5, ÷1, ×1.5, ÷2, ×2.5.... Answer: d)
Description : 256×256 + 173×173 = ? a) 96432 b) 94465 c) 95465 d) 90510 e) None of these
Last Answer : a2+b2 = [(a+b)2 +(a-b)2 ] / 2 ? = 184041 + 6889 ? = 95465 Answer: c)
Description : 5 6 16 57 ? 1245 7506 a) 240 b) 248 c) 244 d) 250 e) 260
Last Answer : Answer: b)
Description : A portion of Rs.6600 is invested at a 5% per annum, while the remainder is invested at a 3% per annum. If the annual income from the portion earning a 5% per annum is twice that of the other portion, what is the ... investments after one year? a) Rs.270 b) Rs.370 c) Rs.250 d) Rs.280 e) None of these
Last Answer : 5x + 3y = z (Total Income) x + y = 6600 -(1) 5x= 2(3y) 5x – 6y = 0 -(2) By solving (1) and (2) we get, x = 3600 so y = 3000 (3600*5*1)/100 + (3000*3*1)/100 = 180 + 90 = 270 Answer: a)
Description : The cost of 3 horses is same as the cost of 5 cows. If total cost of 4 horses and 6 rows is Rs.1900.Find the cost of one horse? a) Rs.50 b) Rs.150 c) Rs.200 d) Rs.250 e) None of these
Last Answer : Ratio of cost of horse and cow = 1/3 : 1/5 =5 : 3 Let cost of horse and cow are 5x and 3x respectively: Then 4 × 5x +6 × 3x = Rs.1900 =>38x = 1900 => x = 1900/38 = Rs.50 Cost of one horse = 5 × Rs.50 = Rs.250 Answer: d)
Description : Vignesh purchased a TV set for Rs.11, 250 after getting discount of 10% on the labelled price. He spent Rs.150 on transport and Rs.800 on installation. At what price should it be sold so that the profit earned would have ... a) Rs.11877.50 b) Rs.16367.50 c) Rs.14247.50 d) Rs.15467.50 e) Rs.17567.50
Last Answer : Marked price = 11250 × 10/9 = Rs. 12500 Total cost=12500 + 150 + 800=Rs. 13450 S.P = 13450 × 115/100 = Rs. 15467.50 Answer: d)
Description : On an IQ test consisting of 250 questions, Jasvinder answered 40% of the first 125 questions correctly. What per cent of the other 125 questions does he need to answer correctly for his grade on the entire exam to be 60%? (a) 75% (b) 80% (c) 60% (d) Cannot be determined (e) None of these
Last Answer : (b) 80%
Description : There are two sets of five numbers each - set P and set Q. P is a set of consecutive even numbers and Q is a set of consecutive numbers. The sum of the numbers of P is 230. The second least number in Q is 33 less ... the sum of the numbers in Q. 1 : 260 2 : 250 3 : 240 4 : 270 5 : None of these
Last Answer : 1 : 260
Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these
Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)
Description : 36 – 0.036 × 100 = ? a) 3.6 b) 36.6 c) 29.6 d) 32.4 e) None of these
Last Answer : ? = 36 – 3.6 = 32.41 Answer: d)
Description : 1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these
Last Answer : Its alternatively ratio of n2 and n3 Now, after 25:125, it would be 63 : 62 216:36 Answer: b)
Description : My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, ... father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years
Last Answer : Let my age = x Then My brother's age = x + 3 My mother's age = x + 26 My sister's age = (x + 3) + 4 = x + 7 My Father's age = (x + 7) + 28 = x + 35 => age my father when my brother was born = x + 35 – (x + 3) = 32. Answer: d)
Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84
Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)
Description : In a class of 24 students, each student shakes hand with everyone els. In another class of 32 students, each student shakes hand with all other students. What is the difference between total number of hand shakes in the 2 classes? a) 180 b) 200 c) 22 d) 240 e) 260
Last Answer : 1 st class : Total Hand shakes = 24 × 23 /2 = 12 × 23 =276 2nd class :Total Hand shakes =32 × 31 / 2 = 16 × 31 = 496 Difference =220 Answer : c
Description : 15 17 32 49 81 130 ? a) 179 b) 211 c) 194 d) 226 e) None of these
Last Answer : 15 + 17 = 32 17 + 32 = 49 32 + 49 = 81 49 + 81 = 130 81 + 130 = 211 Answer: b)
Description : The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32
Last Answer : A:B = 7:8 B:C = 2:3 = 8:12 SO, A:B:C = 7:8:12 C:D = 4:5 = 12:15 A:B:C:D = 7:8:12:15 D:E = 5:7 = 15:21 SO, A:B:C:D:E = 7:8:12:15:21 given x(7+8+12+15+21) = 126 or 63x = 126 or x =2 E – A = 21X – 7X = 14X = 28 Answer: d)
Description : 2 9 ? 105 436 2195 13182 a) 32 b) 45 c) 40 d) 30 e) 25
Last Answer : The series is (2 + 7) × 1 = 9; (9 + 6) × 2 = 30; (30 + 5) × 3 = 105; (105 + 4) × 4 = 436; (436 + 3) × 5 = 2195; (2195 + 2) × 6 = 13182 Answer: d)
Description : A copper wire is bent to form an equilateral triangle of area 16√3 sq.cm. What will be the area (in sq.cm) if the same copper wire was bent to form a square? a) 16 b) 24 c) 32 d) 40 e) None of the above
Last Answer : Area of equilateral triangle = 16√3 = √3 (side)2 /4 Or side2 = 16×4 = 64 So each side = 8cm Perimeter = 8×3 = 24 cm Since perimeter of the square is 24 cm, each side = 6cm So area = 6×6 = 36 sq cm Answer: e)
Description : 520, 130, 32.5, 8.125, 2.03125,? a) 0.5087125 b) 0.5071875 c) 0.5012875 d) 0.5028125 e) 0.5078125
Last Answer : The series is a geometric progression with common ratio 1/4 Hence the next term is 2.03125/4=0.5078125 Answer: e)
Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these
Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)
Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40
Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)
Description : (32.3)2 ÷ 4 + √361 = ?2 + 50 a) 15 b) 13 c) 11 d) 17 e) None of these
Last Answer : 32*32 = 1024 1024/4 + 19 = 256+19= 275 Answer: a)
Description : 38% of 3976 +(32)2 – 13% of 8271 + 7/6 × 3400 =? a) 5427 b) 5325 c) 5537 d) 5612 e) 5554
Last Answer : ?=3976 × (38/100) + 1024 – 8271 × (13 / 100) + (7/6) × 3400 =1510.88 + 1024-1075.23 + 3966.66 =5426.31 ≈ 5427 Answer: a)