53 × 47 + 64 × 56 -72 × 68 = ? a) 1221 b) 1403 c) 1249 d) 1337 e) 1179

53 × 47 + 64 × 56 -72 × 68 = ?
a) 1221
b) 1403
c) 1249
d) 1337
e) 1179
by

1 Answer

Answer :

Answer: e)
by

Related questions

?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Description : ?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Last Answer : ?% × 725 +14 × 21=700 =>?% × 725 +294 =700 => ?% × 725 =406 =>?=406/725 × 100 =56 Answer: d)

A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the certain place. What is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Description : A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the ... is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Last Answer : B Let speed of the jeep =x kmph Then, speed of the bus =(100+25)x/100 =125x/100 =5x/4 kmph Time taken by the jeep to travel from P to Q =225/x hours Time taken by the bus to travel from p to Q =225/(5x/4) + ... 225/x=900/5x+37.5/60 225/x=180/x+37.5/60 45/x =37.5/60 37.5x=45*60 X=72 km/hr

34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Description : 34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Last Answer : 34.8% x 950 – 33.2% of 850 = ? Sol: 0.348 x 950 – 0.332 x 850=? 330.6 – 282.2=? ?= 48.4 Answer: b)

Saina spent Rs. 44,668/- on her air tickets, Rs.56,732 on buying gifts to the family members and the remaining 22% of the total amount she had as cash with her. What was the total amount ? a) Rs. 1,25,800/- b) Rs. 1,30,000/- c) Rs. 1,10,500/- d) Rs. 1,68,300/- e) Rs. 1,50,000/-

Description : Saina spent Rs. 44,668/- on her air tickets, Rs.56,732 on buying gifts to the family members and the remaining 22% of the total amount she had as cash with her. What was the total amount ? a) Rs. 1,25,800/- b) Rs. 1,30,000/- c) Rs. 1,10,500/- d) Rs. 1,68,300/- e) Rs. 1,50,000/- 

Last Answer : Saving = 22% Spent = a00 - 22) = 78% Spending money = 44668 + 56732 = 101400 78%- 101400 100% = 101400 100/78 = 130000 Answer: b)

10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. What is the present average age of all the teachers? a) Between 52 and 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)

The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight of the group of 75 women? (rounded off to two digits after decimal) (a) 46.73 kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Description : The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight ... kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Last Answer : (a) 46.73 kg

3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Description : 3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Last Answer : Series is 1× 2 + 1, 2 × 3 + 3, 3 × 4 + 5, 4 × 5 + 7, 5 × 6 + 9 Answer: b)

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of the replacement of A and now the average weight is 72 kg. Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Description : The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of ... . Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Last Answer : 3) 56 kg

Avinash, Bala and Chandran invested Rs.45,000/-, Rs. 70, 000/- and Rs. 90,000/- respectively to start a business. At the end of two years, they earned a profit of Rs.1,64,000/-. What will be Bala’s share in the profit? a) Rs.56, 000/- b) Rs.46, 000/- c) Rs. 50, 000/- d) Rs.75, 000/- e) None of these

Description : Avinash, Bala and Chandran invested Rs.45,000/-, Rs. 70, 000/- and Rs. 90,000/- respectively to start a business. At the end of two years, they earned a profit of Rs.1,64,000/-. What will be Bala’s share in the profit? a) Rs.56, 000/- b) Rs.46, 000/- c) Rs. 50, 000/- d) Rs.75, 000/- e) None of these

Last Answer : Profit sharing ratio of Avinash,Bala & Chandran = 45000 : 70000 : 90,000 = 45 : 70 : 90 = 9 : 14 : 18 Bala's share of profit after two year =Rs.164000 × 14 × 41 = Rs. 4000 ×14 = Rs. 56000 Answer: a)

Three-fourth of two-third of one-sixth of a number is 15.What is 30 percent of that number? a) 54 b) 48 c) 72 d) 64 e) None of these

Description : Three-fourth of two-third of one-sixth of a number is 15.What is 30 percent of that number? a) 54 b) 48 c) 72 d) 64 e) None of these

Last Answer : Suppose no. is x 3x/4 ×2/3 ×1/6 x/12 = 15/1 x = 180, 30% of 180 = 54 Answer: a)

A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6.26, CO : 1.56, O2 : 3.91, H2O :15.66, N2 : 72.60 (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02 (C) CO2 : 6.39, CO : 1.60, O2 : 3.99, H2O:25.96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02

The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Description : The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Last Answer : (D) 72,000

Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Description : Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Last Answer : (C) 72

Madhan was 3 times as old as his daughter 10 years ago. After 10 years, Madhan will be twice as old as his daughter. Find out the present age of Madhan. a) 68 years b) 70 years c) 40 years d) 55 years e) 80 years

Description : Madhan was 3 times as old as his daughter 10 years ago. After 10 years, Madhan will be twice as old as his daughter. Find out the present age of Madhan. a) 68 years b) 70 years c) 40 years d) 55 years e) 80 years

Last Answer : b Let age of the daughter before 10 years = x Then, age of Madhan before 10 years = 3x After 10 years, Madhan will be twice as old as his daughter. ⇒ 3x + 20 = 2( x+20) ⇒ x = 20 ⇒ Present age of Madhan = 3x + 10 = 3× 20+ 10 = 70 years.

The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: A.68 B.98 C.180 D.364 E.None of these

Description : The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: A.68 B.98 C.180 D.364 E.None of these

Last Answer : Answer – D (364) Explanation – L.C.M. of 6, 9, 15 and 18 is 90. Let required number be 90k + 4, which is multiple of 7. Least value of k for which (90k + 4) is divisible by 7 is k = 4. Required number = (90 x 4) + 4 = 364.

1 15 16 31 47 78 125 ? a) 172 b) 203 c) 139 d) 167 e) None of these

Description : 1 15 16 31 47 78 125 ? a) 172 b) 203 c) 139 d) 167 e) None of these

Last Answer : 15 + 1 = 16 15 + 16 = 31 16 + 31 = 47 31 + 47 = 78 47 + 78 = 125 78 + 125 = 203 Answer: b)

13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Description : 13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Last Answer : The series is × 0.5 – 0.5, × 1 + 1, ×1.5 – 1.5, ×2 + 2, ... Answer: e)

What is the ratio between money spent by company Q on tax and money spent by P on salary? a) 23:121 b) 33:144 c) 47:144 d) 144:157 e) None of these

Description : What is the ratio between money spent by company Q on tax and money spent by P on salary? a) 23:121 b) 33:144 c) 47:144 d) 144:157 e) None of these

Last Answer : e) None of these

21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Description : 21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Last Answer : Difference between each successive tam is factorial of number starting from 2, like 23-21 = 2, then 29-23 = 6 means 3!, then 53-29 = 24 means 4!, then next difference is 173-53 = 120 means 5!, so next difference would be 6! i.e. 720 so term will be 173+720 = 893. Answer: b)

3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Description : 3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Last Answer : ? + 75 = 52 + 58 = 110 ? = 110 – 75 = 35 Answer: e)

60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Description : 60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Last Answer : b) 44 kg

The quantity of Orange available at vendor A is approximately what percent more than that of Apple available at vendor B? 1) 61.52% 2) 68.4% 3) 82% 4) 90% 5) 71.43%

Description : The quantity of Orange available at vendor A is approximately what percent more than that of Apple available at vendor B? 1) 61.52% 2) 68.4% 3) 82% 4) 90% 5) 71.43%

Last Answer : 5) 71.43%

If the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, Grapes is Rs. 115 per kg and Guava is Rs. 68 per kg at both vendor A and B then what is the difference between the cost of all fruits at vendor A and that at Vendor B? 1) Rs. 72000 2) Rs. 55000 3) Rs. 64000 4) Rs. 51000

Description : If the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, Grapes is Rs. 115 per kg and Guava is Rs. 68 per kg at both vendor A and B then what is the difference between ... at vendor A and that at Vendor B? 1) Rs. 72000 2) Rs. 55000 3) Rs. 64000 4) Rs. 51000

Last Answer : 4) Rs. 51000

The cash difference between the selling price of an article at a profit of 8% and 4% is Rs 3 the ratio of the two selling price is A. 51 : 52 B. 27 : 26 C. 51 : 53 D. 52 : 55

Description : The cash difference between the selling price of an article at a profit of 8% and 4% is Rs 3 the ratio of the two selling price is A. 51 : 52 B. 27 : 26 C. 51 : 53 D. 52 : 55

Last Answer : Answer – B (27:26) Explanation – Let the C.P of the article be Rs. x Then required ratio = 108% of x / 104% of x = 108/104= 27:26

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)

Deepa decided to donate 16% of her monthly salary to an NGO. On the day of donation she changed her mind and donated Rs. 6,567/- which was 75%of what she had decided earlier. How much is Deepa’s monthly salary? a) Rs. 54,725/- b) Rs. 58,756/- c) Rs. 56,700/- d) Rs. 55,696/- e) Rs. 52,696/-

Description : Deepa decided to donate 16% of her monthly salary to an NGO. On the day of donation she changed her mind and donated Rs. 6,567/- which was 75%of what she had decided earlier. How much is Deepa’s monthly salary? a) Rs. 54,725/- b) Rs. 58,756/- c) Rs. 56,700/- d) Rs. 55,696/- e) Rs. 52,696/-

Last Answer : Let the Deepa Monthly Salary = x Deepa decided to donate 16% of her monthly salary. On the day of donation she changed. So, 75%of she had decided earlier of 16% 16 × 75/100 = 12% Therefore = 12%= Rs. 6567 100% = Rs .6567 × 100 / 12 x = Rs. 54725 Answer: a)

Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec

The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Description : The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Last Answer : Answer – B (56) Explanation – The total of 11 results = 11 x 50 = 550 The total of first 6 results = 6 x 49 = 294 The total of last 6 results = 6 x 52 = 312 The sixth result is common to both: Sixth result = 294 + 312 – 550 = 56

187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Description : 187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Last Answer : The pattern is -5.5, -11, -16.5, -22 and so on. Answer: c)

24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Description : 24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Last Answer : 72÷48×8+14 = (72/48) × 8 + 14 = (3/2) × 8 + 14 = 12 +14 = 26 24 + (72 ÷ 48 × 8 + 14) ×36 ÷ (3 × 4) + 36 ÷ 3 × 4 = 24 + 26 × 36÷12 + 36 ÷ 3 × 4 = 24 + 26 × 3 + 12 × 4 = 24 + 78 + 48 = 150 Answer: e)

72× 25 + 45× 96 = 163 + ? a) 1912 b) 2024 c) 1844 d) 1908 e) 1960

Description : 72× 25 + 45× 96 = 163 + ? a) 1912 b) 2024 c) 1844 d) 1908 e) 1960

Last Answer : 1800 + 4320 = 4096 + ? ? = 1800 + 4320 – 4096 = 2024 Answer: b)

1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)

72, 115, 244, ?, 760, 1147 a) 501 b) 431 c) 473 d) 459 e) 445

Description : 72, 115, 244, ?, 760, 1147 a) 501 b) 431 c) 473 d) 459 e) 445

Last Answer : The pattern is: 72+43×1=115, 115+43×3=244, 244+43×5=459, 459+43×7=760, 760+43×9=1147 Answer: d)

The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C,D and E becomes 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Description : The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C ... 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Last Answer : A+B+C = 3×84=252 A+B+C+D= (4×80)=320 D = (320-252)=68 and E = (68+3)=71 Now, B+C+D+E = (4×79)=316 B+C+D=(316-71)=245 kg So, A = (320-245)=75 kg Answer: c)

Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)

In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Description : In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Last Answer : Total ways = 4 ! x 2 ! = 4 × 3 × 2 x 2= 48 Answer: a)

A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Description : A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Last Answer : c) 8 Let first two digit no. and second two digit no. be x and y respectively. x = y × 40/100 +16 x - 2y/5 = 16....(i) x + y = 72...(ii) From equation (i) and (ii) x = 32, y = 40 Difference = 8 Answer: c)

The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

.What is the sum between money spent on bonus by these two companies? a) Rs.72 lakhs b) Rs.62 lakhs c) Rs.60 lakhs d) Rs.65 lakhs e) None of these

Description : .What is the sum between money spent on bonus by these two companies? a) Rs.72 lakhs b) Rs.62 lakhs c) Rs.60 lakhs d) Rs.65 lakhs e) None of these

Last Answer : e) None of these

I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 2 : if a < b

The profit made by David in selling his calculator for Rs.400 would be the same as the loss he would have made in selling it at a 25% loss. If he sold his calculator after offering a discount of Rs.100, find the percentage at which he marked it above the cost price. a)56.25% b)62.5% c)60% d)50%

Description : The profit made by David in selling his calculator for Rs.400 would be the same as the loss he would have made in selling it at a 25% loss. If he sold his calculator after offering a discount of Rs.100, find the percentage at which he marked it above the cost price. a)56.25% b)62.5% c)60% d)50%

Last Answer : a)56.25%

A shopkeeper marked a suit at Rs.400. He sold it after allowing a discount, and still made at a profit of 25%. At what percentage above its cost price did he marked the suit, if he sold it for Rs.320? a)50% b)66 2/3% c)62 1/2% d)56 1/4%

Description : A shopkeeper marked a suit at Rs.400. He sold it after allowing a discount, and still made at a profit of 25%. At what percentage above its cost price did he marked the suit, if he sold it for Rs.320? a)50% b)66 2/3% c)62 1/2% d)56 1/4%

Last Answer : d)56 1/4%

Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs. What is the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67

Description : Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs ... the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67 

Last Answer : Answer – B (Rs 10.875) Explanation – Total C.P = Rs. (120 x 110) =Rs. 13200. Total S.P = Rs.[(30 x 110 + 30 x 12) + (75 x 110 + 75 x 14) + (15 x 110 – 15 x 7) =Rs..14505 Average profit = Rs. (14505 – 13200) /120 = Rs. 1305/120= 10.875

When a article is sold for Rs.3400, there is a loss of 2%. What is the cost price of the commodity? A. Rs 3500.50 B. Rs 3200 C. Rs 3400.56 D. Rs 3469.34

Description : When a article is sold for Rs.3400, there is a loss of 2%. What is the cost price of the commodity? A. Rs 3500.50 B. Rs 3200 C. Rs 3400.56 D. Rs 3469.34

Last Answer : Answer – D. Rs 3469.34 Explanation – loss=2% so, 98%………….3400 100%………..? ?=(3400×100)/98=3469.34

1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Description : 1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Last Answer : Its alternatively ratio of n2 and n3 Now, after 25:125, it would be 63 : 62  216:36 Answer: b)

1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Description : 1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Last Answer : Answer: d)

676, 400, 196, 64, 4, ? a) 4 b) 36 c) 16 d) -4 e) -16

Description : 676, 400, 196, 64, 4, ? a) 4 b) 36 c) 16 d) -4 e) -16

Last Answer : Answer: c)

22.222 + 2220.2 + 202.20 + 0.0202 – 2.0022 = ? a) 2244.24 b) 2442.64 c) 2424.44 d) 2444.64 e) 2224.84

Description : 22.222 + 2220.2 + 202.20 + 0.0202 – 2.0022 = ? a) 2244.24 b) 2442.64 c) 2424.44 d) 2444.64 e) 2224.84

Last Answer : b) 2442.64