8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ? a) 31 b) 18 c) 14 d) 27 e) 23

8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ?
a) 31
b) 18
c) 14
d) 27
e) 23
by

1 Answer

Answer :

? = (33/4) × (27/5) – (25/6) × (21/5) =891/20 -35/2 ≈ 44.5 – 17.5 =27
Answer: d)
by

Related questions

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Description : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Last Answer : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 Sol: 322 + 372.6 = ? ÷4 694.6 x 4 = ? ? = 2778.4 Answer: a)

Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Description : Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Last Answer : c. y = 1.98 x + 0.436

On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Last Answer : b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 - (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29

15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Description : 15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Last Answer : The series is a geometric progression with a common ratio 1.2. Hence the next term is 25.92 × 1.2 = 31.104 Answer: a)

2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Description : 2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Last Answer : The series is an alternate series, having S 1 = 2 5 14 41; ×3 – 1 in each term S 2 = 3 8 23 69; ×3 – 1 in each term Answer: e)

1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Description : 1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Last Answer : Answer: d)

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Description : Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and  they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Last Answer : Answer - C (3 : 2) Explanation - Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres, and length of the second train = 17y metres. relative speed = total ... 23x + 23y = 27x + 17 y 27x-23x= 23 y-17y 4x=6y x/y=6/4=3/2= 3:2

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Description : The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Last Answer : Answer – C (23) Explanation – L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23

Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

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Last Answer : According to question, l×b = ¶r2 l ×22 = 22/7 ×14 × 14 l = 22/7 ×14 × 14/22 cms = 28 cms. Answer: b)

The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Description : The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Last Answer : Let the two numbers be 3x and 4x. When they are increased by 9 they become 3x + 9 and 4x + 9. It is given that the ratio is 18:23 Thus, 3x + 9/4x + 9 = 18:23 23(3x + 9) = 18(4x + 9) 69x + 207 = 72x ... = -45 X = 15 Thus two numbers are 3x15 = 45 and 4 x 15 = 60 And the sum is 60+45 = 105 Answer: b)

A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Description : A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is  subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Last Answer : Answer- 3(65) Explanation:- let the number be written as xy x-ten’s place y units place x+y=11…………………1 (10x+y)-(10y+x)=9 10x+y-10y-x=9 9x-9y=9 x-y=1………………….2 Add (1) & (2) 2x=12 x=6 y=5 the number is 65

Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Description : Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

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What is the total number of literate people in city 'A'? 1) 21.62 lakh 2) 22.18 lakh 3) 23.94 lakh 4) 24.63 lakh 5) 25.02 lakh

Description : What is the total number of literate people in city 'A'? 1) 21.62 lakh 2) 22.18 lakh 3) 23.94 lakh 4) 24.63 lakh 5) 25.02 lakh

Last Answer : 3) 23.94 lakh

If the S.P of Rs.40 results in a 20% discount on list price. What S.P would result in a 30% discount on list price? A. Rs 18 B. Rs 20 C. Rs 35 D. Rs 27

Description : If the S.P of Rs.40 results in a 20% discount on list price. What S.P would result in a 30% discount on list price? A. Rs 18 B. Rs 20 C. Rs 35 D. Rs 27

Last Answer : Answer – C. Rs 35 Explanation – Let the list price be Rs. x 80/100x = 40 => x = 40 x 100/80 = 50 ∴ Required S.P. = 70% of Rs. 50=Rs.35

What is the frequency range of C-band? A. 8.5 to 12.5 GHz B. 3.4 to 6.425 GHz C. 12.95 to 14.95 GHz D. 27.5 to 31 GHz

Description : What is the frequency range of C-band? A. 8.5 to 12.5 GHz B. 3.4 to 6.425 GHz C. 12.95 to 14.95 GHz D. 27.5 to 31 GHz

Last Answer : B. 3.4 to 6.425 GHz

What is the difference between money spent by both companies on tax ( in lakh Rs.)? a) 26.8 b) 24.4 c) 24.6 d) 23.8 e) None of these

Description : What is the difference between money spent by both companies on tax ( in lakh Rs.)? a) 26.8 b) 24.4 c) 24.6 d) 23.8 e) None of these

Last Answer : e) None of these

13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Description : 13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Last Answer : ?=189+405-141 = 453 Answer: d)

One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.

Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)

By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

Description : By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

Last Answer : Selling price = Rs. 40 Loss = 20% Therefore, cost price = 40×100 /(100 - 20) = Rs. 50 Therefore, cost price of each lemon = Rs. 50/45 Now, selling price = Rs. 24 Profit = 20% Cost price = 24×100/120 = Rs. 20 Number of lemons for Rs. 20 = 20/(50/45) = 900/50 = 18 Answer: d)

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Description : Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Last Answer : Let the required time be x years. then (50+x) = 2 (18 + x) = 50 + x = 36 + 2x  x = 14 years. Alternative method : Double of B’s age = 2 × 18 = 36 years difference between A’s present age and double of B’s age = 50 – 36= 14 years. A will be twice of B’s age after 14 years. Answer: a)

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

What is the respective ratio of the number of people preferring to travel by rail in 2006 to the number of people preferring to travel by rail in 2002? a) 31 : 27 b) 31 : 23 c) 23 : 31 d) 27 : 31 e) None of these

Description : What is the respective ratio of the number of people preferring to travel by rail in 2006 to the number of people preferring to travel by rail in 2002? a) 31 : 27 b) 31 : 23 c) 23 : 31 d) 27 : 31 e) None of these

Last Answer : b) 31 : 23

1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Description : 1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Last Answer : Its alternatively ratio of n2 and n3 Now, after 25:125, it would be 63 : 62  216:36 Answer: b)

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

6 pens and 14 exercise books cost Rs.162. 5pens and 8 exercise books cost Rs.102. The ratio of cost of 1 pen to that of 1 exercise book is : a) 10 : 3 b) 2 : 3 c) 3 : 2 d) 5 : 6 e) None of these

Description : 6 pens and 14 exercise books cost Rs.162. 5pens and 8 exercise books cost Rs.102. The ratio of cost of 1 pen to that of 1 exercise book is : a) 10 : 3 b) 2 : 3 c) 3 : 2 d) 5 : 6 e) None of these

Last Answer : Let cost of 1 pen be Rs.x and that of 1 exercise book be Rs.y. Then 6x +14 y = 162 =>3x + 7y =81……..(1) 5x + 8y =102…………………………………………..(2) (1)× 5 – (2) × 3 =>11y=99=>y=9.Putting y=9 in equation (1),we get : x = 6 x : y =6 : 9 =2 : 3 Answer: b)

Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Description : Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Last Answer : Numerator = 4 + 72 – 14 = 62 Denominator = 738 – 730 = 8 Required value = 62/8 = 7.75 Answer: b)

A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Description : A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Last Answer : % profit = Loss/Actual Weight x 100 = 500 – 425/500 × 100 = 75/500 x 100 = 15% Answer: b)

1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17

Description : 1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17

Last Answer : d) 8980.77

A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Description : A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Last Answer : c) 8 Let first two digit no. and second two digit no. be x and y respectively. x = y × 40/100 +16 x - 2y/5 = 16....(i) x + y = 72...(ii) From equation (i) and (ii) x = 32, y = 40 Difference = 8 Answer: c)

What is the frequency range of C-band? A. 10.95 to 14.5 GHzB. 27.5 to 31 GHz C. 3.4 to 6.424 GHz D. 1.53 to 2.7 GHz

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Last Answer : C. 3.4 to 6.424 GHz

A tank can be filled by a tap in 6 hours and emptied by an outlet pipe in 8 hours. How long will it take to fill the cistern if both the taps are opened together? 1. 24 hours 2. 22 hours 3. 21 hours 4. 18 hours 5. 20 hours

Description : A tank can be filled by a tap in 6 hours and emptied by an outlet pipe in 8 hours. How long will it take to fill the cistern if both the taps are opened together? 1. 24 hours 2. 22 hours 3. 21 hours 4. 18 hours 5. 20 hours

Last Answer : 1;

501/58 * 291/101 ÷ 31/155 = ? a) 140 b) 125 c) 95 d) 85 e) 110

Description : 501/58 * 291/101 ÷ 31/155 = ? a) 140 b) 125 c) 95 d) 85 e) 110

Last Answer : Answer: b)

1 3 9 31 ? 651 a) 97 b) 127 c) 129 d) 109 e) None of these

Description : 1 3 9 31 ? 651 a) 97 b) 127 c) 129 d) 109 e) None of these

Last Answer : The series is ×1 + 2, ×2 + 3, ×3 + 4, ... Answer: c)

1 15 16 31 47 78 125 ? a) 172 b) 203 c) 139 d) 167 e) None of these

Description : 1 15 16 31 47 78 125 ? a) 172 b) 203 c) 139 d) 167 e) None of these

Last Answer : 15 + 1 = 16 15 + 16 = 31 16 + 31 = 47 31 + 47 = 78 47 + 78 = 125 78 + 125 = 203 Answer: b)

112 111 119 92 156 31 ? a) 375 b) 287 c) 387 d) 247 e) None of these

Description : 112 111 119 92 156 31 ? a) 375 b) 287 c) 387 d) 247 e) None of these

Last Answer : Answer: d)

(?)2 + (9.99)3 = (45.02)2 – (4.01)3 a) 34 b) 19 c) 26 d) 31 e) 12

Description : (?)2 + (9.99)3 = (45.02)2 – (4.01)3 a) 34 b) 19 c) 26 d) 31 e) 12

Last Answer : ?2 + 1000 = 2025 – 64 ?2 = 961  ? = 31 Answer: d)

Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39

Description : Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39

Last Answer : 1;  Total number of students

5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Description : 5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Last Answer : The series is +5, +7, +9, +11, .... Answer: c)

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

5 7.5 11.25 17.5 ? 50 a) 28.75 b) 26.50 c) 27.50 d) 28.25 e) None of these

Description : 5 7.5 11.25 17.5 ? 50 a) 28.75 b) 26.50 c) 27.50 d) 28.25 e) None of these

Last Answer : 7.5 – 5 = 2.5 11.25 – 7.5 = 3.75 => 3.75 – 2.5 = 1.25 11.25 – 7.5 = 3.75 17.5 – 11.25 = 6.25 => 6.25 – 3.75 = 2.5 Answer: a)

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 

Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

Percentage of alcohol in **** may be around __________ percent. (A) 2-8 (B) 18-23 (C) 27-32 (D) 1-4

Description : Percentage of alcohol in beer may be around __________ percent. (A) 2-8 (B) 18-23 (C) 27-32 (D) 1-4

Last Answer : (A) 2-8

The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Description : The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Last Answer : A:B = 7:8 B:C = 2:3 = 8:12 SO, A:B:C = 7:8:12 C:D = 4:5 = 12:15 A:B:C:D = 7:8:12:15 D:E = 5:7 = 15:21 SO, A:B:C:D:E = 7:8:12:15:21 given x(7+8+12+15+21) = 126 or 63x = 126 or x =2 E – A = 21X – 7X = 14X = 28 Answer: d)

The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Description : The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Last Answer : Let it be x . Then : 5×10+5×14+20×x=30×12 20x=360-120 or 20x=240 or x = 12 Answer: c)