Roughly what is the total weight of air in the entire earth?  a. 1 x 10^5 tons  b. 2 x 10^6 tons  c. 6 x 10^15 tons  d. 8 x 10^10 tons

Roughly what is the total weight of air in the entire earth?  a. 1 x 10^5 tons  b. 2 x 10^6 tons  c. 6 x 10^15 tons  d. 8 x 10^10 tons
by

1 Answer

Answer :

6 x 10^15 tons
by

Related questions

A car whose mass is 2 metric tons is accelerated uniformly from stand hill to 100 kmph in 5 sec. Find the driving force in Newton’s.  a. 11,120 N  b. 11,320 N  c. 11,420 N  d. 11520 N formula: F= ma / k

Description : A car whose mass is 2 metric tons is accelerated uniformly from stand hill to 100 kmph in 5 sec. Find the driving force in Newton’s.  a. 11,120 N  b. 11,320 N  c. 11,420 N  d. 11520 N formula: F= ma / k

Last Answer : 11,120N

A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is the partial pressure of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Description : A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is ... of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Last Answer : 84.6

How many kilocalories of heat are required to heat 750 g of water from 35˚C to 55˚C.  a. 15  b. 1500  c. 1.5 x 10^4  d. 6.3 x 10^4

Description : How many kilocalories of heat are required to heat 750 g of water from 35˚C to 55˚C.  a. 15  b. 1500  c. 1.5 x 10^4  d. 6.3 x 10^4

Last Answer : 15

The concrete roof of a house is 10 m by 8 m and 10 cm thick (4"). Estimate the total heat the roof would absorb over the 12 day?  a. 1.3 x 108 J  b 2.3 x 108 J  c. 3.3 x 108 J  d. 4.3 x 108 J formula: ΔQ = ΔQ/Δtx Δt

Description : The concrete roof of a house is 10 m by 8 m and 10 cm thick (4"). Estimate the total heat the roof would absorb over the 12 day?  a. 1.3 x 108 J  b 2.3 x 108 J  c. 3.3 x 108 J  d. 4.3 x 108 J formula: ΔQ = ΔQ/Δtx Δt

Last Answer : 1.3 x 108 J

The compression ratio for Diesel engines is  A. 3 to 6  B. 5 to 8  C. 15 to 20  D. 20 to 30

Description : The compression ratio for Diesel engines is  A. 3 to 6  B. 5 to 8  C. 15 to 20  D. 20 to 30

Last Answer : Answer: C

The compression ratio for petrol engines is  A.3 to 6  B.5 to 8  C.15 to 20  D.20 to 30

Description : The compression ratio for petrol engines is  A.3 to 6  B.5 to 8  C.15 to 20  D.20 to 30

Last Answer : Answer: B

What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Description : What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Last Answer : 28.6 psia

3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

Executes the entire cycle in just two strokes the power stroke and the compression stroke.  a. One-stroke engine  b. Two-stroke engine  c. Four-stroke engine  d. Eight-stroke engine

Description : Executes the entire cycle in just two strokes the power stroke and the compression stroke.  a. One-stroke engine  b. Two-stroke engine  c. Four-stroke engine  d. Eight-stroke engine

Last Answer : Two-stroke engine

A system is in ______ equilibrium if the temperature is the same throughout the entire system.  A. Static  B. Thermal  C. Mechanical  D. Phase

Description : A system is in ______ equilibrium if the temperature is the same throughout the entire system.  A. Static  B. Thermal  C. Mechanical  D. Phase

Last Answer : Thermal

The thermodynamic property of a system is said to be an intensive property whose value for the entire system __________ the sum of their value for the individual parts of the system.  A. is equal to  B. is not equal to

Description : The thermodynamic property of a system is said to be an intensive property whose value for the entire system __________ the sum of their value for the individual parts of the system.  A. is equal to  B. is not equal to

Last Answer : Answer: B

In a non-flow reversible process for which p = (- 3V+ 15) x 105N/m2,V changes from 1 m to 2 m3. The work done will be about  (a) 100 xlOO5 joules  (b) lxlO5 joules  (c) 10 xlO5 joules  (d) 10 xlO5 kilo joules  (e) 10xl04ki\ojoules.

Description : In a non-flow reversible process for which p = (- 3V+ 15) x 105N/m2,V changes from 1 m to 2 m3. The work done will be about  (a) 100 xlOO5 joules  (b) lxlO5 joules  (c) 10 xlO5 joules  (d) 10 xlO5 kilo joules  (e) 10xl04ki\ojoules.

Last Answer : Answer : c

According to Dalton’s law, the total pres sure of the mixture of gases is equal to  (a) greater of the partial pressures of all  (b) average of the partial pressures of all  (c) sum of the partial pressures of all  (d) sum of the partial pressures of all divided by average molecular weight  (e) atmospheric pressure.

Description : According to Dalton's law, the total pres sure of the mixture of gases is equal to  (a) greater of the partial pressures of all  (b) average of the partial pressures of all  (c) sum ... all  (d) sum of the partial pressures of all divided by average molecular weight  (e) atmospheric pressure.

Last Answer : Answer : c

Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

Description : Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

Last Answer : 15.7 BTU

While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Description : While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Last Answer : 217.17 kpa

One erg is equivalent to how many joules?  A. 10^-8  B. 10^-7  C. 10^-6  D. 10^-5

Description : One erg is equivalent to how many joules?  A. 10^-8  B. 10^-7  C. 10^-6  D. 10^-5

Last Answer : 10^-7

Twenty grams of ice at 0˚C melts to water at 0˚C. How much does the entropy of the 20g change in this process?  a. 30.5 J/K  b. 24.6 J/K  c. 21.3 J/K  d. 15.7 J/K

Description : Twenty grams of ice at 0˚C melts to water at 0˚C. How much does the entropy of the 20g change in this process?  a. 30.5 J/K  b. 24.6 J/K  c. 21.3 J/K  d. 15.7 J/K

Last Answer : 24.6 J/K

A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Description : A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Last Answer : 12 kJ

On weight basis, air contains following parts of oxygen  (a) 21  (b) 23  (c) 25  (d) 73  (e) 79.

Description : On weight basis, air contains following parts of oxygen  (a) 21  (b) 23  (c) 25  (d) 73  (e) 79.

Last Answer : Answer : b

Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Description : Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Last Answer : Answer : a

A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Description : A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Last Answer : 42.41 ft^3

How much does an object having the mass of 100kg weight in newton.  a. 981 N  b. 991 N  c. 981.6 N  d. 980.1N F = ma

Description : How much does an object having the mass of 100kg weight in newton.  a. 981 N  b. 991 N  c. 981.6 N  d. 980.1N F = ma

Last Answer : 900,000lb/hr;625 ft/s981 N

If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Last Answer : 13.33 ft^3/lbm

A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Description : A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Last Answer : 130.08 {(10atm)(10)(32)/(0.0821) (300K)}

___________ is the percent by weight that is saturated liquid.  a) Quality, x  b) Percent Moisture, y  c) Vapor  c) Liquid

Description : ___________ is the percent by weight that is saturated liquid.  a) Quality, x  b) Percent Moisture, y  c) Vapor  c) Liquid

Last Answer : Percent Moisture, y

___________ is the percent by weight that is saturated vapor.  a) Quality, x  b) Percent Moisture, y  c) Vapor  d) Liquid

Description : ___________ is the percent by weight that is saturated vapor.  a) Quality, x  b) Percent Moisture, y  c) Vapor  d) Liquid

Last Answer : Quality, x

Water is flowing through a 1 foot diameter pipe at the rate of 10ft/sec. What is the volume flow rate of water in ft³/sec?  a. 7.85  b. 6.85  c. 8.85  d. 5.85 V = Aν

Description : Water is flowing through a 1 foot diameter pipe at the rate of 10ft/sec. What is the volume flow rate of water in ft³/sec?  a. 7.85  b. 6.85  c. 8.85  d. 5.85 V = Aν

Last Answer : 7.85

How many Newton’s (N) in 900,000 dynes?  a) 8 Newton’s  b) 9 Newton’s  c) 7 Newton’s  d) 6 Newton’s Formula: 1Newton (N)=100,000dynes

Description : How many Newton’s (N) in 900,000 dynes?  a) 8 Newton’s  b) 9 Newton’s  c) 7 Newton’s  d) 6 Newton’s Formula: 1Newton (N)=100,000dynes

Last Answer : 9 Newton’s

A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2.  a.1520°R  b. 1620°R  c. 1720°R  d. 1820°R formula: T2= T1V2/V1

Description : A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2.  a.1520°R  b. 1620°R  c. 1720°R  d. 1820°R formula: T2= T1V2/V1

Last Answer : 1620°R

A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia.  a. T2=1.620ºR, ∫H = 122.83 Btu  b. T2 = 2°R, ∫H = 122.83 Btu  c. T2 = 2.620ºR, ∫H = 122.83 Btu  d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

Description : A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia.  a. T2=1.620ºR, ∫H = 122.83 Btu  b. T2 = 2°R, ∫H = 122.83 Btu  c. ... , ∫H = 122.83 Btu  d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

Last Answer : T2=1.620ºR, ∫H = 122.83 Btu

A certain gas, with cp = 0.529Btu/lb.°R and R = 96.2 ft.lb/lb.°R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5 psia. Compute for T2. (Formula: T2= T1V2/V1)  a. 460°R  b. 270°R  c. 1620 °R  d. None of the above

Description : A certain gas, with cp = 0.529Btu/lb.°R and R = 96.2 ft.lb/lb.°R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5 psia. Compute for T2. (Formula: T2= T1V2/V1)  a. 460°R  b. 270°R  c. 1620 °R  d. None of the above

Last Answer : 1620 °R

An ideal gas of volume 1liter and pressure 10 bar undergoes a quasistatic adiabatic expansion until the pressure drops to 1 bar. Assume γ to be 1.4 what is the final volume?  a. 3.18 l  b. 4.18 l  c. 5.18 l  d. 6.18 l

Description : An ideal gas of volume 1liter and pressure 10 bar undergoes a quasistatic adiabatic expansion until the pressure drops to 1 bar. Assume γ to be 1.4 what is the final volume?  a. 3.18 l  b. 4.18 l  c. 5.18 l  d. 6.18 l

Last Answer : 5.18 l

A 600kg hammer of a pile driver is lilted 2m the pilling head. What is the change of potential energy? If the hammer is realest. What will be its velocity and the instant if it sticks the pilling?  a. 10,772 N-m and 5.26m/s  b. 13,200 N-m and 5.26m/s  c. 11,772 N-m and 6.26m/s  d. 11,77 2N-m and5.26m/s ∫PE = mgo(∫Z)/gc

Description : A 600kg hammer of a pile driver is lilted 2m the pilling head. What is the change of potential energy? If the hammer is realest. What will be its velocity and the instant if it sticks the pilling?  a. 10,772 N-m and 5.26m/s ...  c. 11,772 N-m and 6.26m/s  d. 11,77 2N-m and5.26m/s ∫PE = mgo(∫Z)/gc

Last Answer : 11,772 N-m and 6.26m/s

1 bar is equivalent to how many pascals?  A. 10^3  B. 10^4  C. 10^5  D. 10^6

Description : 1 bar is equivalent to how many pascals?  A. 10^3  B. 10^4  C. 10^5  D. 10^6

Last Answer : 10^5

Utilizing the answer to the previous problem, estimate the overall or average increase in temperature ( ΔT) of the concrete roof from the energy absorbed from the sun during a12hour day. Assume that all of the radiation absorbed goes into heating the roof. The specific heat of concrete is about 900 J/kg, and the density is about 2,300 kg/m3 .  a. 7.9 °C  b. 8.9°C  c. 9.9°C  d. 10.9°C formula: ΔQ = m c ΔT

Description : Utilizing the answer to the previous problem, estimate the overall or average increase in temperature ( ΔT) of the concrete roof from the energy absorbed from the sun during a12hour day. Assume that all of the radiation absorbed goes into ... °C  b. 8.9°C  c. 9.9°C  d. 10.9°C formula: ΔQ = m c ΔT

Last Answer : 7.9 °C

Oxygen at 15ºC and 10.3 Mpa gauge pressure occupies 600L. What is the occupied by the oxygen at 8.28 Mpa gauge pressure and 35ºC?  a. 789.32 L  b. 796.32 L  c. 699 L  d. 588 L V2= P1V1/T1P2

Description : Oxygen at 15ºC and 10.3 Mpa gauge pressure occupies 600L. What is the occupied by the oxygen at 8.28 Mpa gauge pressure and 35ºC?  a. 789.32 L  b. 796.32 L  c. 699 L  d. 588 L V2= P1V1/T1P2

Last Answer : 796.32 L

Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

What is the value of the universal gas constant in kJ/kmol K? ∙  A. 10.73  B. 1.986  C. 8.314  D. 1545

Description : What is the value of the universal gas constant in kJ/kmol K? ∙  A. 10.73  B. 1.986  C. 8.314  D. 1545

Last Answer : 8.314

Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Description : Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Last Answer : 1.1577 BTU/lbm-˚R

What is known as the total heat and heat content at various times in the history?  a. enthalpy  b. entropy  c. internal energy  d. latent heat

Description : What is known as the total heat and heat content at various times in the history?  a. enthalpy  b. entropy  c. internal energy  d. latent heat

Last Answer : enthalpy

Is a steady flow process at total constant pressure through a control volume for which there is no heat?  a. Adiabatic Saturation Process  b. Dew point  c. Adiabatic Ratio  d. None of the above

Description : Is a steady flow process at total constant pressure through a control volume for which there is no heat?  a. Adiabatic Saturation Process  b. Dew point  c. Adiabatic Ratio  d. None of the above

Last Answer : Adiabatic Saturation Process

The first law of thermodynamics may be expressed in the following equivalent  a. the net heat transfer id equal to the network  b. the sum of the total energy forms leaving the system boundary is always equal to the energy input  c. energy can neither be created nor destroyed but only converted from one form to another  d. all of the above

Description : The first law of thermodynamics may be expressed in the following equivalent  a. the net heat transfer id equal to the network  b. the sum of the total energy forms leaving the system boundary is ... neither be created nor destroyed but only converted from one form to another  d. all of the above

Last Answer : all of the above

_________ is the grand total of all energies inside a substance.  a. Internal Energy  b. Grand Energy  c. Atomic Energy  d. Elemental Energy

Description : _________ is the grand total of all energies inside a substance.  a. Internal Energy  b. Grand Energy  c. Atomic Energy  d. Elemental Energy

Last Answer : Internal Energy

“The total volume of a mixture of non-reacting gases is equal to the sum of the partial volumes.” This statement is known as ______.  A. Law of Dulong and Petit  B. Maxwell-Boltzmann law  C. Amagat’s law  D. Avogadro’s law

Description : “The total volume of a mixture of non-reacting gases is equal to the sum of the partial volumes.” This statement is known as ______.  A. Law of Dulong and Petit  B. Maxwell-Boltzmann law  C. Amagat’s law  D. Avogadro’s law

Last Answer : Amagat’s law

Thermal efficiency is the ratio of:  A. Network input to total heat input  B. Network output to total heat output  C. Network output to total heat input  D. Network input to total heat output

Description : Thermal efficiency is the ratio of:  A. Network input to total heat input  B. Network output to total heat output  C. Network output to total heat input  D. Network input to total heat output

Last Answer : Network output to total heat input

What states that the net change in the total energy of the system during a process is equal to the difference between the total energy entering and the total energy leaving the system during that process?  A. Third law of thermodynamics  B. Conservation of energy principle  C. Second law of thermodynamics  D. Conservation of mass principle

Description : What states that the net change in the total energy of the system during a process is equal to the difference between the total energy entering and the total energy leaving the system during ... Conservation of energy principle  C. Second law of thermodynamics  D. Conservation of mass principle

Last Answer : Conservation of energy principle

Which of the following statements is TRUE for an ideal gas, but not for a real gas?  A. PV = nRT  B. An increase in temperature causes an increase in the kinetic energy of the gas  C. The total volume of molecules on a gas is nearly the same as the volume of the gas as a whole  D. No attractive forces exists between the molecule of a gas

Description : Which of the following statements is TRUE for an ideal gas, but not for a real gas?  A. PV = nRT  B. An increase in temperature causes an increase in the kinetic energy of the gas  C. The ... same as the volume of the gas as a whole  D. No attractive forces exists between the molecule of a gas

Last Answer : PV = nRT

What states that the net mass transfer to or from a system during a process is equal to the net change in the total mass of the system during that process?  A. Third law of thermodynamics  B. Conservation of energy principle  C. Second law of thermodynamic  D. Conservation of mass principle

Description : What states that the net mass transfer to or from a system during a process is equal to the net change in the total mass of the system during that process?  A. Third law of thermodynamics  B. Conservation of energy principle  C. Second law of thermodynamic  D. Conservation of mass principle

Last Answer : Conservation of mass principle

The ratio of the mass of vapor to the total mass of the mixture is called ______.  A. Vapor ratio  B. Vapor content  C. Vapor index  D. Quality

Description : The ratio of the mass of vapor to the total mass of the mixture is called ______.  A. Vapor ratio  B. Vapor content  C. Vapor index  D. Quality

Last Answer : Quality