The expression for entropy change, ΔS = n Cp. ln (T2/T1), is valid for the __________ of a substance. (A) Simultaneous pressure & temperature change (B) Heating (C) Cooling (D) Both (B) and (C)

The expression for entropy change, ΔS = n Cp. ln (T2/T1), is valid for the __________ of a substance.
(A) Simultaneous pressure & temperature change
(B) Heating
(C) Cooling
(D) Both (B) and (C)
by

1 Answer

Answer :

(D) Both (B) and (C)
by

Related questions

The expression for entropy change given by, ΔS = nR ln (V2/V1) + nCvln (T2/T1) is valid for (A) Reversible isothermal volume change (B) Heating of a substance (C) Cooling of a substance (D) Simultaneous heating and expansion of an ideal gas

Description : The expression for entropy change given by, ΔS = nR ln (V2/V1) + nCvln (T2/T1) is valid for (A) Reversible isothermal volume change (B) Heating of a substance (C) Cooling of a substance (D) Simultaneous heating and expansion of an ideal gas

Last Answer : (D) Simultaneous heating and expansion of an ideal gas

The expression for entropy change given by, ΔS = - nR ln (P2/P1), holds good for (A) Expansion of a real gas (B) Reversible isothermal volume change (C) Heating of an ideal gas (D) Cooling of a real gas

Description : The expression for entropy change given by, ΔS = - nR ln (P2/P1), holds good for (A) Expansion of a real gas (B) Reversible isothermal volume change (C) Heating of an ideal gas (D) Cooling of a real gas

Last Answer : (B) Reversible isothermal volume change

To obtain integrated form of Clausius-Clapeyron equation, ln (P2/P1) = (∆HV/R) (1/T1- 1/T2) from the exact Clapeyron equation, it is assumed that the (A) Volume of the liquid phase is negligible compared to that of vapour phase (B) Vapour phase behaves as an ideal gas (C) Heat of vaporisation is independent of temperature (D) All (A), (B) & (C)

Description : To obtain integrated form of Clausius-Clapeyron equation, ln (P2/P1) = (∆HV/R) (1/T1- 1/T2) from the exact Clapeyron equation, it is assumed that the (A) Volume of the liquid phase is negligible compared to ... gas (C) Heat of vaporisation is independent of temperature (D) All (A), (B) & (C)

Last Answer : (D) All (A), (B) & (C)

The expression, ∆G = nRT. ln(P2/P1), gives the free energy change (A) With pressure changes at constant temperature (B) Under reversible isothermal volume change (C) During heating of an ideal gas (D) During cooling of an ideal gas

Description : The expression, ∆G = nRT. ln(P2/P1), gives the free energy change (A) With pressure changes at constant temperature (B) Under reversible isothermal volume change (C) During heating of an ideal gas (D) During cooling of an ideal gas

Last Answer : (A) With pressure changes at constant temperature

The heat supplied to the gaS at constant volume is (where m = Mass of gas, cv = Specific heat at constant volume, cp = Specific heat at constant pressure, T2 – T1 = Rise in temperature, and R = Gas constant)  A. mR(T2 – T1)  B. mcv(T2 – T1)  C. mcp(T2 – T1)  D. mcp(T2 + T1)

Description : The heat supplied to the gaS at constant volume is (where m = Mass of gas, cv = Specific heat at constant volume, cp = Specific heat at constant pressure, T2 – T1 = Rise in temperature, and R = Gas constant)  A. mR(T2 – T1)  B. mcv(T2 – T1)  C. mcp(T2 – T1)  D. mcp(T2 + T1)

Last Answer : Answer: B

What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Description : What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Last Answer : W = mRTln (V2/V1)

A perfect gas has a value of R= 319.2 J/ kf.K and k= 1.26. If 120 kJ are added to 2.27 kf\g of this gas at constant pressure when the initial temp is 32.2°C? Find T2.  a. 339.4 K  b. 449.4 K  c. 559.4K  d. 669.4K formula: cp = kR/ k-1 Q= mcp(T2-T1)

Description : A perfect gas has a value of R= 319.2 J/ kf.K and k= 1.26. If 120 kJ are added to 2.27 kf\g of this gas at constant pressure when the initial temp is 32.2°C? Find T2.  a. 339.4 K  b. 449.4 K  c. 559.4K  d. 669.4K formula: cp = kR/ k-1 Q= mcp(T2-T1)

Last Answer : 339.4 K

A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia.  a. T2=1.620ºR, ∫H = 122.83 Btu  b. T2 = 2°R, ∫H = 122.83 Btu  c. T2 = 2.620ºR, ∫H = 122.83 Btu  d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

Description : A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia.  a. T2=1.620ºR, ∫H = 122.83 Btu  b. T2 = 2°R, ∫H = 122.83 Btu  c. ... , ∫H = 122.83 Btu  d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

Last Answer : T2=1.620ºR, ∫H = 122.83 Btu

The expression, nCv(T2- T1), is for the __________ of an ideal gas. (A) Work done under adiabatic condition (B) Co-efficient of thermal expansion (C) Compressibility (D) None of these

Description : The expression, nCv(T2- T1), is for the __________ of an ideal gas. (A) Work done under adiabatic condition (B) Co-efficient of thermal expansion (C) Compressibility (D) None of these

Last Answer : (A) Work done under adiabatic condition

High pressure steam is expanded adiabatically and reversibly through a well insulated turbine, which produces some shaft work. If the enthalpy change and entropy change across the turbine are represented by ΔH and ΔS respectively for this process: (A) Δ H = 0 and ΔS = 0 (B) Δ H ≠ 0 and ΔS = 0 (C) Δ H ≠ 0 and ΔS ≠ 0 (D) Δ H = 0 and ΔS ≠ 0

Description : High pressure steam is expanded adiabatically and reversibly through a well insulated turbine, which produces some shaft work. If the enthalpy change and entropy change across the turbine are represented by ΔH and ΔS respectively for this process: ... (C) Δ H ≠ 0 and ΔS ≠ 0 (D) Δ H = 0 and ΔS ≠ 0

Last Answer : (B) Δ H ≠ 0 and ΔS = 0

Pick out the wrong statement. (A) Cp of monatomic gases such as metallic vapor is about 5 kcal/kg.atom (B) The heat capacity of solid inorganic substance is exactly equal to the heatcapacity of the substance in the molten state(C) There is an increase in entropy, when a spontaneous change occurs in anisolated system(D) At absolute zero temperature, the heat capacity for many pure crystallinesubstances is zero

Description : Pick out the wrong statement. (A) Cp of monatomic gases such as metallic vapor is about 5 kcal/kg.atom (B) The heat capacity of solid inorganic substance is exactly equal to the ... isolated system (D) At absolute zero temperature, the heat capacity for many pure crystalline substances is zero

Last Answer : (C) There is an increase in entropy, when a spontaneous change occurs in an isolated system

Heat transfer by radiation between two bodies at T1 & T2 and in an ambient temperature of Ta °C depends on (A) T1 - T2 (B) T1 - Ta (C) T2 - Ta (D) None of these

Description : Heat transfer by radiation between two bodies at T1 & T2 and in an ambient temperature of Ta °C depends on (A) T1 - T2 (B) T1 - Ta (C) T2 - Ta (D) None of these

Last Answer : (D) None of these

What is the value of maximum COP in case of absorption refrigeration, if refrigeration provided is at temperature, TR (where, T1 and T2 are source & surrounding temperatures respectively.)? (A) TR/(T2 - TR) × (T1 - T2 )/T1 (B) TR/(T2 - TR) × T1 /(T1 - T2 ) (C) TR/(T1 - TR) × (T1 - T2 )/T1 (D) None of these

Description : What is the value of maximum COP in case of absorption refrigeration, if refrigeration provided is at temperature, TR (where, T1 and T2 are source & surrounding temperatures respectively.)? (A) TR/(T2 - TR) (T1 - T2 )/T1 (B) TR ... T1 /(T1 - T2 ) (C) TR/(T1 - TR) (T1 - T2 )/T1 (D) None of these

Last Answer : (A) TR/(T2 - TR) × (T1 - T2 )/T1

Cp- Cv = R is valid for __________ gases. (A) Ideal (B) Very high pressure (C) Very low temperature (D) All of the above

Description : Cp- Cv = R is valid for __________ gases. (A) Ideal (B) Very high pressure (C) Very low temperature (D) All of the above

Last Answer : (A) Ideal

A gas having a volume of100 ft³ at 27ºC is expanded to 120 ft³by heated at constant pressure to what temperature has it been heated to have this new volume?  a. 87°C  b. 85°C  c. 76°C  d. 97°C t2= T2–T1

Description : A gas having a volume of100 ft³ at 27ºC is expanded to 120 ft³by heated at constant pressure to what temperature has it been heated to have this new volume?  a. 87°C  b. 85°C  c. 76°C  d. 97°C t2= T2–T1

Last Answer : 87°C

A Term is either an individual constant (a 0-ary function), or a variable, or an n-ary function applied to n terms: F(t1 t2 ..tn). a) True b) False

Description : A Term is either an individual constant (a 0-ary function), or a variable, or an n-ary function applied to n terms: F(t1 t2 ..tn). a) True b) False

Last Answer : a) True

The clock period is denoted by: a. T p b. T1+T2+T3-------+T n c. Pt d. None of these

Description : The clock period is denoted by: a. T p b. T1+T2+T3-------+T n c. Pt d. None of these

Last Answer : a. T p

Heat transfer co-efficient equation for forced convection, Nu = 0.023 Re 0.8 . Pr n , is not valid, if the value of (A) n = 0.4 is used for heating (B) n = 0.3 is used for cooling (C) Reynolds number for the flow involved is > 10000 (D) Reynolds number for the flow involved is < 2100

Description : Heat transfer co-efficient equation for forced convection, Nu = 0.023 Re 0.8 . Pr n , is not valid, if the value of (A) n = 0.4 is used for heating (B) n = 0.3 is used for cooling (C) Reynolds number for the flow involved is > 10000 (D) Reynolds number for the flow involved is < 2100

Last Answer : (D) Reynolds number for the flow involved is < 2100

Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Description : Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 126m³

The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Description : The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 14026.5 m³

The volume of the gas held at constant pressure increases 4 cm² at 0°C to 5cm². What is the final pressure?  a. 68.65ºC  b. 68.25ºC  c. 70.01°C  d. 79.1ºC t2= T2–T1

Description : The volume of the gas held at constant pressure increases 4 cm² at 0°C to 5cm². What is the final pressure?  a. 68.65ºC  b. 68.25ºC  c. 70.01°C  d. 79.1ºC t2= T2–T1

Last Answer : 981 N

An ideal gas at 45psig and 80ºF is heated in the close container to 130ºF. What is the final pressure?  a. 65.10 psi  b. 65.11 psi  c. 65.23 psi  d. 61.16 psi P1V1/T1= P2V2/T2;V = Constant

Description : An ideal gas at 45psig and 80ºF is heated in the close container to 130ºF. What is the final pressure?  a. 65.10 psi  b. 65.11 psi  c. 65.23 psi  d. 61.16 psi P1V1/T1= P2V2/T2;V = Constant

Last Answer : 65.23 psi

What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Description : What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Last Answer : 28.6 psia

The most efficient heat engine that can operate between two temperature reservoirs T1 and T2 is: w) jet engine x) internal combustion engine y) Carnot engine (pron: car-no) z) steam engine

Description : The most efficient heat engine that can operate between two temperature reservoirs T1 and T2 is: w) jet engine x) internal combustion engine y) Carnot engine (pron: car-no) z) steam engine

Last Answer : ANSWER: Y -- CARNOT ENGINE

A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2.  a.1520°R  b. 1620°R  c. 1720°R  d. 1820°R formula: T2= T1V2/V1

Description : A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2.  a.1520°R  b. 1620°R  c. 1720°R  d. 1820°R formula: T2= T1V2/V1

Last Answer : 1620°R

A certain gas, with cp = 0.529Btu/lb.°R and R = 96.2 ft.lb/lb.°R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5 psia. Compute for T2. (Formula: T2= T1V2/V1)  a. 460°R  b. 270°R  c. 1620 °R  d. None of the above

Description : A certain gas, with cp = 0.529Btu/lb.°R and R = 96.2 ft.lb/lb.°R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5 psia. Compute for T2. (Formula: T2= T1V2/V1)  a. 460°R  b. 270°R  c. 1620 °R  d. None of the above

Last Answer : 1620 °R

Co-efficient of performance for a reversed Carnot cycle working between temperatures T1 and T2(T1 > T2) is (A) T2/(T1- T2) (B) T1/(T1- T2) (C) (T1- T2)/T1 (D) (T1- T2)/T2

Description : Co-efficient of performance for a reversed Carnot cycle working between temperatures T1 and T2(T1 > T2) is (A) T2/(T1- T2) (B) T1/(T1- T2) (C) (T1- T2)/T1 (D) (T1- T2)/T2

Last Answer : (A) T2/(T1- T2)

The efficiency of a Carnot heat engine operating between absolute temperatures T1 and T2 (when, T1 > T2) is given by (T1- T2)/T1. The co efficient of performance (C.O.P.) of a Carnot heat pump operating between T1 and T2is given by (A) T1/(T1-T2) (B) T2/(T1-T2) (C) T1/T2 (D) T2/R1

Description : The efficiency of a Carnot heat engine operating between absolute temperatures T1 and T2 (when, T1 > T2) is given by (T1- T2)/T1. The co efficient of performance (C.O.P.) of a Carnot heat pump operating between T1 and T2is given by (A) T1/(T1-T2) (B) T2/(T1-T2) (C) T1/T2 (D) T2/R1

Last Answer : (A) T1/(T1-T2)

The ratio of equilibrium constants (Kp2/Kp1) at two different temperatures is given by (A) (R/∆H) (1/T1- 1/T2) (B) (∆H/R) (1/T1- 1/T2) (C) (∆H/R) (1/T2- 1/T1) (D) (1/R) (1/T1- 1/T2)

Description : The ratio of equilibrium constants (Kp2/Kp1) at two different temperatures is given by (A) (R/∆H) (1/T1- 1/T2) (B) (∆H/R) (1/T1- 1/T2) (C) (∆H/R) (1/T2- 1/T1) (D) (1/R) (1/T1- 1/T2)

Last Answer : (B) (∆H/R) (1/T1- 1/T2)

The equilibrium constant for a chemical reaction at two different temperatures is given by (A) Kp2/Kp1 = - (∆H/R) (1/T2- 1/T1) (B) Kp2/Kp1 = (∆H/R) (1/T2- 1/T1) (C) Kp2/Kp1 = ∆H (1/T2- 1/T1) (D) Kp2/Kp1 = - (1/R) (1/T2- 1/T1)

Description : The equilibrium constant for a chemical reaction at two different temperatures is given by (A) Kp2/Kp1 = - (∆H/R) (1/T2- 1/T1) (B) Kp2/Kp1 = (∆H/R) (1/T2- 1/T1) (C) Kp2/Kp1 = ∆H (1/T2- 1/T1) (D) Kp2/Kp1 = - (1/R) (1/T2- 1/T1)

Last Answer : (A) Kp2/Kp1 = - (∆H/R) (1/T2- 1/T1)

Efficiency of a Carnot engine working between temperatures T1 and T2(T1 < T) is (A) (T2- T1)/T2 (B) (T2- T1)/T1 (C) (T1- T2)/T2 (D) (T1- T2)/T1

Description : Efficiency of a Carnot engine working between temperatures T1 and T2(T1 < T) is (A) (T2- T1)/T2 (B) (T2- T1)/T1 (C) (T1- T2)/T2 (D) (T1- T2)/T1

Last Answer : (A) (T2- T1)/T2

The efficiency of a Carnot heat engine operating between absolute temperatures T1 and T2(when, T1 > T2) is given by (T1- T2)/T1. The co efficient of performance (CO.P.) of a Carnot heat pump operating between T1 and T2is given by (A) T1/(T1-T2) (B) T2/(T1-T2) (C) T1/T2 (D) T2/T1

Description : The efficiency of a Carnot heat engine operating between absolute temperatures T1 and T2(when, T1 > T2) is given by (T1- T2)/T1. The co efficient of performance (CO.P.) of a Carnot heat pump operating between T1 and T2is given by (A) T1/(T1-T2) (B) T2/(T1-T2) (C) T1/T2 (D) T2/T1

Last Answer : (B) T2/(T1-T2)

PVγ = Constant (where, γ = Cp/Cv) is valid for a/an __________ process. (A) Isothermal (B) Isentropic (C) Isobaric (D) Adiabatic

Description : PVγ = Constant (where, γ = Cp/Cv) is valid for a/an __________ process. (A) Isothermal (B) Isentropic (C) Isobaric (D) Adiabatic

Last Answer : (D) Adiabatic

Why does CSF appears to be dark in T1 and white in T2?

Description : Why does CSF appears to be dark in T1 and white in T2?

Last Answer : I think that it is because the two types of MRI detirmine to color differently. T1 determines color based on spin-lattice relaxation time, while T2 determine color based on spin-spin relation time. Both ... dark. Since cerebrospinal fluid is mostly water, it shows up dark in T1 and light in T2.

What is the difference between T1 and T2 mri scans?

Description : What is the difference between T1 and T2 mri scans?

Last Answer : Wikipedia has some stuff to get you going: http://en.wikipedia.org/wiki/MRI#Basic_MRI_scans

If w is the angular velocity of the pulley and T1 and T2 are tensions of driving and driven side then power transmitted equals a.(T1 + T2) w b.(T1 + 2T2) w c.107 dynes d.(T1 - T2) w e.wT1

Description : If w is the angular velocity of the pulley and T1 and T2 are tensions of driving and driven side then power transmitted equals a.(T1 + T2) w b.(T1 + 2T2) w c.107 dynes d.(T1 - T2) w e.wT1

Last Answer : d. (T1 - T2) w

Let R be a relation defined on the set A of all triangles such that R = {(T1, T2) : T1 is similar to T2}. Then R is -Maths 9th

Description : Let R be a relation defined on the set A of all triangles such that R = {(T1, T2) : T1 is similar to T2}. Then R is -Maths 9th

Last Answer : (d) An equivalence relation.Every triangle is similar to itself, so (T1, T1) ∈ R ⇒ R is reflexive. (T1, T2) ∈ R ⇒ T1 ~ T2 ⇒T2 ~ T1, ⇒ (T2, T1) ∈ R ⇒ R is symmetrictransitive. ∴ R is an equivalence relation.

What digital carrier transmits a digital signal at 274.176 Mbps? A. T1 B. T3 C. T2 D. T4

Description : What digital carrier transmits a digital signal at 274.176 Mbps? A. T1 B. T3 C. T2 D. T4

Last Answer : D. T4

What carrier system multiplexes 96 voice band channels into a single 6.312 Mbps data signal? A. T1 carrier system B. T2 carrier system C. T1C carrier system D. T3 carrier system

Description : What carrier system multiplexes 96 voice band channels into a single 6.312 Mbps data signal? A. T1 carrier system B. T2 carrier system C. T1C carrier system D. T3 carrier system

Last Answer : B. T2 carrier system

A digital carrier facility used to transmit a DSI-formatted signal at 1.544. Mbps. A. T2 B. T1 C. T4 D. T3

Description : A digital carrier facility used to transmit a DSI-formatted signal at 1.544. Mbps. A. T2 B. T1 C. T4 D. T3

Last Answer : B. T1

Bamboo plant is growing in a fir forest then what will be the trophic level of it? (a) First trophic level (T1) (b) Second trophic level (T2) (c) Third trophic level (T3) (d) Fourth trophic level (T4)

Description : Bamboo plant is growing in a fir forest then what will be the trophic level of it? (a) First trophic level (T1) (b) Second trophic level (T2) (c) Third trophic level (T3) (d) Fourth trophic level (T4)

Last Answer : a) First trophic level (T1)

Which of the following high-speed circuits is the fastest? A) T1 B) T2 C) T3 D) DS3

Description : Which of the following high-speed circuits is the fastest? A) T1 B) T2 C) T3 D) DS3

Last Answer : DS3

For the same draw down in two observations wells at distances r1 and r2, the times after start of pumping are t1 and t2 hours respectively. The relation which holds good is (A) t2 = r2/r1 × t1 (B) t2 = (r2/r1)² × t1 (C) t2 = (r2/r1)3 × t1 (D) t2 = (r2/r1) × t1 2

Description : For the same draw down in two observations wells at distances r1 and r2, the times after start of  pumping are t1 and t2 hours respectively. The relation which holds good is  (A) t2 = r2/r1 × t1 (B) t2 = (r2/r1)² × t1 (C) t2 = (r2/r1)3  × t1 (D) t2 = (r2/r1) × t1 2

Last Answer : (B) t2 = (r2/r1)² × t1

S1 and S2 are the draw downs in an observation well at times t1 and t2 after pumping. For discharge Q and coefficient of transmissibility T, the relationship, is (A) S2 - S1 = (2.3Q/ ) log10 (t2/t1) (B) S2 - S1 = (2.3Q/4 ) log10 (t2/t1) (C) S2 - S1 = (2.3Q/4 ) loge (t2/t1) (D) S2 - S1 = (2.3Q/4 ) loge (t1/t2

Description : S1 and S2 are the draw downs in an observation well at times t1 and t2 after pumping. For  discharge Q and coefficient of transmissibility T, the relationship, is  (A) S2 - S1 = (2.3Q/ ) log10 (t2/t1)  (B) S2 - S1 ... - S1 = (2.3Q/4 ) loge (t2/t1)  (D) S2 - S1 = (2.3Q/4 ) loge (t1/t2

Last Answer : (B) S2 - S1 = (2.3Q/4 ) log10 (t2/t1) 

Ten cu. ft of air at 300psia and 400°F is cooled to 140°F at constant volume. What is the transferred heat?  a.-120Btu  b. -220Btu  c.-320Btu  d. -420Btu formula: Q= mcv(T2-T1)

Description : Ten cu. ft of air at 300psia and 400°F is cooled to 140°F at constant volume. What is the transferred heat?  a.-120Btu  b. -220Btu  c.-320Btu  d. -420Btu formula: Q= mcv(T2-T1)

Last Answer : -420Btu

There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat. Determine t2. (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

For heat engine operating between two temperatures (T1>T2), what is the maximum efficiency attainable?  A. Eff = 1 – (T2/T1)  B. Eff = 1 - (T1/T2)  C. Eff = T1 - T2  D. Eff = 1 - (T2/T1)^2

Description : For heat engine operating between two temperatures (T1>T2), what is the maximum efficiency attainable?  A. Eff = 1 – (T2/T1)  B. Eff = 1 - (T1/T2)  C. Eff = T1 - T2  D. Eff = 1 - (T2/T1)^2

Last Answer : Eff = 1 – (T2/T1)

Which of the following is the mathematical representation of the Charles’s law?  A. V1/V2= P2/P1  B. V1/T1=V2/T2  C. V1/T2=V2/T1  D. V1/V2=√P2/√P1

Description : Which of the following is the mathematical representation of the Charles’s law?  A. V1/V2= P2/P1  B. V1/T1=V2/T2  C. V1/T2=V2/T1  D. V1/V2=√P2/√P1

Last Answer : V1/T1=V2/T2

Which of the following is the Ideal gas law (equation)?  A. V/T = K  B. V= k*(1/P)  C. P1/T1 = P2/T2  D. PV = nRT

Description : Which of the following is the Ideal gas law (equation)?  A. V/T = K  B. V= k*(1/P)  C. P1/T1 = P2/T2  D. PV = nRT

Last Answer : PV = nRT

-For two shafts in parallel or for two concentric shafts a. T = T1 + T2 b. T = T1 = T2 c. T = T1 – T2 d. T = (T1.T2)^1/2

Description : -For two shafts in parallel or for two concentric shafts a. T = T1 + T2 b. T = T1 = T2 c. T = T1 – T2 d. T = (T1.T2)^1/2

Last Answer : a. T = T1 + T2