Description : If the long chord and tangent length of a circular curve of radius R are equal the angle of deflection, is (A) 30° (B) 60° (C) 90° (D) 120°
Last Answer : D
Description : What is the value of included angle of a triangular notch for maximum discharge? (A) 30° (B) 60° (C) 90° (D) 120°
Last Answer : (C) 90°
Description : The angle of intersection of a contour and a ridge line, is (A) 30° (B) 45° (C) 60° (D) 90°
Last Answer : (D) 90°
Description : A lemniscate curve will not be transitional throughout, if its deflection angle, is (A) 45° (B) 60° (C) 90° (D) 120°
Last Answer : (A) 45°
Description : At what value of crank angle (roughly), no flow of water from or into the air vessel takes place in case of a double acting reciprocating pump? (A) 40° and 140° (B) 45° and 60° (C) 90° and 80° (D) 20° and 120°
Last Answer : (A) 40° and 140
Description : The bond angle between carbon atoms in cyclohexane is (a) 60° (b) 90° (c) 109.5° (d) 120°
Last Answer : 109.5°
Description : The bond angle between carbon atoms in cyclohexane is (a) 109°28' (b) 60° (c) 90° (d) 120°
Last Answer : 109°28'
Description : The H–C–H bond angle in ethylene is (a) 60° (b) 120° (c) 90° (d) 180°
Last Answer : 120°
Description : If the angle of incidence formed on a concave mirror at a point is 30° then the angle of reflection will be: (1) 15° (2) 30° (3) 60° (4) 90°
Last Answer : (2) 30° Explanation: The angle between the incident ray and the normal is known as the angle of inci dence. The angle between the reflected ray and the normal is known as the angle of reflection.
Description : ABCD is a rectangular plot of land. If the bearing of the side AB is 75°, the bearing of DC is (A) 75° (B) 255° (C) 105° (D) 285°
Last Answer : (A) 75°
Description : Back bearing of a line is equal to (A) Fore bearing ± 90° (B) Fore bearing ± 180° (C) Fore bearing ± 360° (D) Fore bearing ± 270°
Last Answer : (B) Fore bearing ± 180°
Description : If the whole circle bearing of a line is 270°, its reduced bearing is (A) N 90° W (B) S 90° W (C) W 90° (D) 90° W
Last Answer : (C) W 90°
Description : If whole circle bearing of a line is 120°, its reduced bearing is (A) S 20° E (B) S 60° E (C) N 120° E (D) N 60° E
Last Answer : (B) S 60° E
Description : In any good staircase, the maximum and minimum pitch respectively should be (A) 90° and 0° (B) 75° and 30° (C) 60° and 10° (D) 40° and 25°
Last Answer : Option D
Description : A turbine is said to have an axial discharge when the steam leaves the blade tip at _________ to the direction of the blade motion. (A) 60° (B) 90° (C) 180° (D) 270°
Last Answer : (B) 90°
Description : In case of full journal bearing, the angle of contact of the bushing with the journal is (A) 60° (B) 90° (C) 180° (D) 360°
Last Answer : (D) 360°
Description : 30°, 60° and 90° connections are made in a directional relay to render the relay (A) Sufficient torque under fault conditions (B) Zero torque under fault conditions (C) Current grading (D) Time grading
Last Answer : 30°, 60° and 90° connections are made in a directional relay to render the relay Sufficient torque under fault conditions
Description : For determining the support reactions at A and B of a three hinged arch, points B and Care joined and produced to intersect the load line at D and a line parallel to the load line through A at D'. Distances AD, DD ... reactions at A and B is (A) 30° (B) 45° (C) 60° (D) 90
Last Answer : (D) 90
Description : An angle of deflection right, may be directly obtained by setting the instrument to read (A) Zero on back station (B) 180° on back station (C) 90° (D) 270° on back station
Last Answer : (A) Zero on back station
Description : Diagonals AC and BC of parallelogram ABCD Intersect at point O. Angle BOC=90° and BDC=50°.find angle OAB. -Maths 9th
Last Answer : NEED ANSWER
Last Answer : Its given ABCD is a IIgram and AC and BD are its diagonals intersecting at point O. . Given : angle BOC = 900 angle BDC = 500 To find : angle OAB Answer : i) ...
Description : The bearing of C from A is N 30° E and from B, 50 metres east of A, is N 60° W. The departure of C from A is (A) 50 m (B) 50 m (C) 25 m (D) 25 m
Last Answer : (D) 25 m
Description : 5. In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively (see Fig. 8.31). Show that the line segments AF and EC trisect the diagonal BD. -Maths 9th
Last Answer : . Solution: Given that, ABCD is a parallelogram. E and F are the mid-points of sides AB and CD respectively. To show, AF and EC trisect the diagonal BD. Proof, ABCD is a parallelogram , AB || CD also, ... (i), DP = PQ = BQ Hence, the line segments AF and EC trisect the diagonal BD. Hence Proved.
Description : In an amplifier if conductor during the cycle is from 0 to 90° and again from 180° to 270°, the amplifier will be termed as A) Class A B) Class B C) Class C D) Class AB.
Last Answer : B) Class B
Description : A member is balanced at its end by two inclined members carrying equal forces. For equilibrium the angle between the inclined bars must be (A) 3° (B) 45° (C) 90° (D) 120°
Last Answer : (D) 120°
Description : If the output of a dragline for 90° angle of swing at optimum depth of cut is X, then the output for 120° angle of swing at 120 % of optimum depth of cut will be (A) Equal to X (B) More than X (C) Less than X (D) Any of the above
Last Answer : (C) Less than X
Description : A well conditioned triangle has no angle less than (A) 20° (B) 30° (C) 45° (D) 60°
Last Answer : (B) 30°
Description : The angle between two plane mirrors of optical square, is (A) 20° (B) 30° (C) 45° (D) 60°
Last Answer : (C) 45°
Description : A projectile is fired at an angle to the vertical. Its horizontal range will be maximum when is (A) 0° (B) 30° (C) 45° (D) 60°
Description : The maximum shear stress occurs on the filament which makes an angle with the horizontal plane equal to (A) 30° (B) 45° (C) 60° (D) 90
Last Answer : (B) 45°
Description : The angle between skew back of a flat arch and the horizontal, is kept approximately equal to (A) 0° (B) 30° (C) 60° (D) 90
Last Answer : Answer: Option C
Description : Maximum number of vehicles can be parked with (A) Parallel parking (B) 30° angle parking (C) 45° angle parking (D) 90° angle parking
Last Answer : Answer: Option D
Description : A ship strikes the berth generally at an angle (A) 90° with the face of the dock (B) 45° with the face of the dock (C) 30° with the face of the dock (D) 10° with the face of the dock
Last Answer : (D) 10° with the face of the dock
Description : Plywood is made by bonding together thin layers of wood in such a way that the angle between grains of any layer to grains of adjacent layers is (A) 0° (B) 30° (C) 45° (D) 90°
Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th
Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.
Description : Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ . -Maths 9th
Last Answer : Join AQ and PC . Since ABCD is a parallelogram . ⇒ AB | | DC ⇒ AP | | QC ∵ AP and QC are parts of AB and DC respectively] Also, AP = CQ [given] Thus, APCQ is a parallelogram . We know that diagonals of a parallelogram bisect each other . Hence AC and PQ bisect each other .
Description : Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ. Show that AC and PQ bisect each other. -Maths 9th
Last Answer : According to question parallelogram ABCD such that AP = CQ.
Description : P and Q are the mid-points of the opposite sides AB and CD of a parallelogram ABCD. -Maths 9th
Last Answer : Given In a parallelogram ABCD, P and Q are the mid-points of AS and CD, respectively. To show PRQS is a parallelogram. Proof Since, ABCD is a parallelogram. AB||CD ⇒ AP || QC
Description : In Fig. 8.40, points M and N are taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AM = CN. Show that AC and MN bisect each other. -Maths 9th
Last Answer : Solution :-
Description : ABCD is a parallelogram in which P and Q are the mid-points of opposite sides AB and CD (Fig. 8.48). If AQ intersects DP at S and BQ intersects CP at R, show that -Maths 9th
Description : The middle points of the parallel sides AB and CD of a parallelogram ABCD are P and Q respectively. If AQ and CP divide the diagonal BD -Maths 9th
Last Answer : answer:
Description : What will be the phase angle relationship of a six-pole, three-phase, rotating field generator? A. 60° B. 120° C. 180° D. 360°
Last Answer : Answer: B
Description : The H–C–C bond angle in ethane is (a) 60° (b) 109.5° (c) 120° (d) 118°28′
Description : Which of the following is closest to the C–O–C bond angle in CH3–O–CH3? (a) 180° (b) 120° (c) 109.5° (d) 90°
Description : The zone in which transverse bending is likely to occur may be obtained by drawing a line from the (A) 30° (B) 45° (C) 60° (D) None of these
Last Answer : Answer: Option B
Description : The angle of minimum deviation of an equiangular prism, having a refractive index of 1.732 is (a) 60° (b) 30° (c) 45° (d) 0°
Last Answer : Ans:(a)
Description : The angle in which a cricket ball should be hit to travel maximum horizontal distance is : (1) 60° with horizontal (2) 45° with horizontal (3) 30° with horizontal (4) 15° with horizontal
Last Answer : (2) 45° with horizontal Explanation: This has to do with the equation of a parabola or trajectory which is z = (tane)x 2 cos 9) 2. We can see that if the ball is fired at a 45 degree angle from the ground, the horizontal distance will be a maximum.