If the radius of a simple curve is R, the length of the chord for calculating offsets by the method of chords produced, should not exceed. (A) R/10 (B) R/15 (C) R/20 (D) R/25

If the radius of a simple curve is R, the length of the chord for calculating offsets by the method of 

chords produced, should not exceed. 

(A) R/10 

(B) R/15 

(C) R/20 

(D) R/25 

by

1 Answer

Answer :

(C) R/20 

by

Related questions

If the radius of a simple curve is 600 m, the maximum length of the chord for calculating offsets, is taken (A) 15 m (B) 20 m (C) 25 m (D) 30 m

Description : If the radius of a simple curve is 600 m, the maximum length of the chord for calculating offsets, is  taken  (A) 15 m  (B) 20 m  (C) 25 m  (D) 30 m

Last Answer : (D) 30 m

For setting out a simple curve, using two theodolites. (A) Offsets from tangents are required (B) Offsets from chord produced are required (C) Offsets from long chord are required (D) None of these

Description : For setting out a simple curve, using two theodolites.  (A) Offsets from tangents are required  (B) Offsets from chord produced are required  (C) Offsets from long chord are required  (D) None of these 

Last Answer : (D) None of these 

For setting out a simple curve, using two theodolites. (A) Offsets from tangents are required (B) Offsets from chord produced are required (C) Offsets from long chord are required (D) None of these

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Last Answer : (C) R/20

If is the length of a sub-chord and is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to (A) 573 S/R (B) 573 R/S (C) 1718.9 R/S (D) 1718.9 S/R

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The radius of a simple circular curve is 300 m and length of its specified chord is 30 m. The degree of the curve is (A) 5.73° (B) 5.37° (C) 3.57° (D) 3.75°

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Explain the procedure of curve setting by method of offsets from long chord

Description : Explain the procedure of curve setting by method of offsets from long chord

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If the long chord and tangent length of a circular curve of radius R are equal the angle of deflection, is (A) 30° (B) 60° (C) 90° (D) 120°

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If D is the degree of the curve of radius R, the exact length of its specified chord, is (A) Radius of the curve × sine of half the degree (B) Diameter of the curve × sine of half the degree (C) Diameter of the curve × cosine of half the degree (D) Diameter of the curve × tangent of half the degree

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Offsets are measured with an accuracy of 1 in 40. If the point on the paper from both sources of error (due to angular and measurement errors) is not to exceed 0.05 cm on a scale of 1 cm = 20 m, the maximum length of offset should be limited to (A) 14.14 m (B) 28.28 m (C) 200 m (D) None of these

Description : Offsets are measured with an accuracy of 1 in 40. If the point on the paper from both sources of error (due to angular and measurement errors) is not to exceed 0.05 cm on a scale of 1 cm = 20 m, the maximum length of ... should be limited to (A) 14.14 m (B) 28.28 m (C) 200 m (D) None of these

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The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Find the distance of the chord from the centre. -Maths 9th

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Designation of a curve is made by: (A) Angle subtended by a chord of any length (B) Angle subtended by an arc of specified length (C) Radius of the curve (D) Curvature of the curve

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The tangent length of a simple circular curve of radius R (A) R tan (B) R tan (C) R sin (D) R sin

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If S, L and R are the arc length, long chord and radius of the sliding circle then the perpendicular distance of the line of the resultant cohesive force, is given by (A) a = S.R/L (B) a = L.S/R (C) a = L.R/S (D) None of these

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For a curve of radius 100 m and normal chord 10 m, the Rankine's deflection angle, is (A) 0°25'.95 (B) 0°35'.95 (C) 1°25'.53 (D) 2°51'.53

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Last Answer : (D) 2°51'.53

Describe the method of setting out simple curve by using the method of offset from long chord with sketch.

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Last Answer : Given data: Direction of two straights, chainage of point of intersection, radius of curve. Procedure:  1) Set theodolite over B and measure deflection angle Ф  2) Calculate tangent length by ... equal to tangent length.  4) Divide long chord into even number of equal parts.     

Rankine's deflection angle in minutes is obtained by multiplying the length of the chord by (A) Degree of the curve (B) Square of the degree of the curve (C) Inverse of the degree of the curve (D) None of these

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In testing a pile by load test, pile platform is loaded with one and half times the design load and a maximum settlement is noted. The load is gradually removed and the consequent rebound is measured. For a safe pile, the net settlement (i.e. total settlement minus rebound) per tonne of test load should not exceed (A) 10 mm (B) 15 mm (C) 20 mm (D) 25 mm

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If R is the radius of a main curve and L is the length of the transition curve, the shift of the curve, is (A) L/24 R (B) L2 /24 R (C) L3 /24 R (D) L4 /24 R

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If two equal chords of a circle intersect, prove that the parts of one chord are separately equal to the parts of the other chord. -Maths 9th

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The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, what is the distance of other chord from the centre? -Maths 9th

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The distances of two chords AB and CD from the centre of a circle are 6 cm and 8 cm respectively. Then, which chord is longer?

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AB and AC are two chords of a circle of radius r such that AB = 2AC. -Maths 9th

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Last Answer : According to question 4q 2 = p 2+ 3r 2.

AB and AC are two chords of a circle of radius r such that AB = 2AC. -Maths 9th

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Last Answer : According to question 4q 2 = p 2+ 3r 2.

AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre. Prove that -Maths 9th

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The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

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Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

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The approximate formula for radial or perpendicular offsets from the tangent, is (A) x/2R (B) x²/2R (C) x/R (D) x²/R

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A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

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A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

Find the length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm. -Maths 9th

Description : Find the length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm. -Maths 9th

Last Answer : Let AB be a chord of circle with centre O and radius 13cm. Draw OM perpendicular AB and join OA. In the right triangle OMA, we have OA2 = OM2 + AM2 ⇒ 132 = 122 + AM2 ⇒ AM2 = 169 - 144 ... . As the perpendicular from the centre of a chord bisects the chord.Therefore, AB = 2AM = 2 x 5 = 10cm.

A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

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Point A(5, 1) is the centre of the circle with radius 13 units. AB ⊥ chord PQ. B is (2, –3). The length of chord PQ is -Maths 9th

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Minimum radius of a simple circular curve deflecting through 5°, is (A) 1618.9 m (B) 1816.9 m (C) 1718.9 m (D) 1817.9 m

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The angle of intersection of a curve is the angle between (A) Back tangent and forward tangent (B) Prolongation of back tangent and forward tangent (C) Forward tangent and long chord (D) Back tangent and long chord

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Last Answer : Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r ={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20 = { 3.14 ... Area of major segment = area of circle - area of minor segment = 1256 - 114 = 1142 HOPE IT HELPS YOU

The weight of a good quality brick when immersed in water for a period of 16 hours should not exceed the weight of dry brick (A) 20 % (B) 15 % (C) 10 % (D) None of these

Description : The weight of a good quality brick when immersed in water for a period of 16 hours should not exceed the weight of dry brick (A) 20 % (B) 15 % (C) 10 % (D) None of these

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If V is speed in km/hour and R is radius of the curve, the super-elevation e is equal to (A) V²/125 R (B) V²/225 R (C) V²/325 R

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If V is the design speed in km/hour and R is the radius of the curve of a hill road, the super￾elevation (A) e = V / 127 R (B) e = V² / 127 R (C) e = V ²/ 225 R (D) e = V / 225 R

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If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

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If the ruling gradient on any highway is 3%, the gradient provided on the curve of 300 metre radius, is (A) 2.00 % (B) 2.25 % (C) 2.50 % (D) 2.75 %

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If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum perpendicular offset for the transition curve, is (A) 0.70 m (B) 1.70 m (C) 2.70 m (D) 3.70 m

Description : If the length of a transition curve to be introduced between a straight and a circular curve of  radius 500 m is 90 m, the maximum perpendicular offset for the transition curve, is  (A) 0.70 m  (B) 1.70 m  (C) 2.70 m  (D) 3.70 m

Last Answer : (C) 2.70 m