Description : _____ isa digital multiplexing technique for combiningseveral low-ratechannels into onehigh-rate one. A) FDM B) TDM C) WDM D) None of the above
Last Answer : TDM
Description : _____ isan analog multiplexing technique to combine optical signals. A) FDM B) TDM C) WDM D) None of the above
Last Answer : WDM
Description : We candivide ____ into two different schemes: synchronousor statistical. A) FDM B) TDM C) WDM D) none of the above
Description : ____ is designed to use thehigh bandwidthcapabilityof fiber-optic cable. A) FDM B) TDM C) WDM D) None of the above
Description : Which multiplexing technique involves signals composed of light beams? A) FDM B) TDM C) WDM D) none of the above
Description : Which multiplexing technique transmits digital signals? A) FDM B) TDM C) WDM D) None of the above
Description : Which multiplexing technique transmits analog signals? A) FDM B) TDM C) WDM D) (a) and (c)
Last Answer : (a) and (c)
Description : Using_________each connected device is assigned a time slot whether or not the device has any thing to send. (A) WDM (B) FDM (C) TDM (D) STDM
Last Answer : (C) TDM
Description : Time synchronization is necessary in (A) FDM. (B) TDM. (C) WDM. (D) Quadrature multiplexing
Last Answer : (B) TDM.
Description : Which of the following statement is incorrect? A. The Addresses Resolution Protocol, ARP, allows a host to find the physicaladdress ofa target host on the samephysical network, given only the target IP address. ... -addresses of our choice to every machine. D. All of theabove E. None of the above
Last Answer : All of theabove
Description : Given the following statements: (a) Frequency Division Multiplexing is a technique that can be applied when the bandwidth of a link is greater than combined bandwidth of signals to be transmitted. (b) Wavelength Division Multiplexing (WDM) ... c) is true. (D) (a), (b) and (d) are true; (c) is false.
Last Answer : (D) (a), (b) and (d) are true; (c) is false.
Description : DMT is a modulation technique that combineselements of _______ and _______. A) FDM; TDM B) QDM; QAM C) FDM; QAM D) PSK; FSK
Last Answer : FDM; QAM
Description : The ______ technique expands the bandwidthof a signal by replacing each data bit with n bits. A) FDM B) DSSS C) FHSS D) TDM
Last Answer : DSSS
Description : The _______ technique uses M different carrier frequencies that are modulated by the source signal. At one moment, the sign modulates one carrier frequency; at the next moment, thesignal modulates another carrier frequency. A) FDM B) DSSS C) FHSS D) TDM
Last Answer : FHSS
Description : Which multiplexing technique shifts each signal to a different carrier frequency? A) FDM B) TDM C) Both (a)and (b) D) None of the above
Last Answer : FDM
Description : An ______signal is the optical modulation of an STS-n (or STM-n) signal. A) OC-n B) TDM-n C) FDM-n D) none of the above
Last Answer : TDM-n
Description : Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is __________. a. 400 bps b. 800 bps c. 1600 bps d. 3200 bps
Last Answer : d. 3200 bps
Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______. a. 64 Kbps b. 32 Mbps c. 32 Kbps d. 64 MbpS
Last Answer : c. 32 Kbps
Description : Which of the following is oldest multiplexing scheme? A. Frequency Division Multiplexing (FDM) B. Time Division Multiplexing (TDM) C. Code Division Multiplexing (CDM) D. Space Division Multiplexing (SDM)
Last Answer : D. Space Division Multiplexing (SDM)
Description : Multiplexing scheme use by baseband transmission. A. FDM B. Space multiplexing C. TDM D. Statistical multiplexing
Last Answer : C. TDM
Description : One of the reasons why FDM is being replaced by TDM is A. noise is amplified with voice when an FDM system is used B. it is difficult to place channels side by side C. there is more time than frequency D. Most available frequencies has been used
Last Answer : A. noise is amplified with voice when an FDM system is used
Description : Compare FDM & TDM systems
Last Answer : Sr. No. FDM TDM 1 Divides the channel into the two or more frequency ranges that do not overlap. Divides and allocates certain Time periods to each channel. 2 Code word is ... Needs guard bands Needs guard time 4 Problem of crosstalk No problem of crosstalk
Description : An approach that permits the computer to work on several programs instead of one is a. On-line thesaurus b. Multiprogramming c. Over lapped processing d. Outline processor
Last Answer : Over lapped processing
Description : Which OSI layer assumes responsibility for managing network connections between applications? a. Network layer b. Data link layer c. Application layer d. Session layer
Last Answer : d. Session layer
Description : _____ is an ideaor concept that isa precursor to an Internet standard. A) RCF B) RFC C) ID D) none of the above
Last Answer : RCF
Description : A _______LAN allows several LANs to be connected. A) backbone B) wireless C) wired D) none of the above
Last Answer : backbone
Description : When data moves from one set of major connections to another on theInternet, we call theseconnections the Internet _____. A) Pathway B) Backbone C) Communications system D) Routers
Last Answer : Backbone
Description : Inthe _______method, after thestation finds the line idle it sends or refrainfrom sending based on the outcome ofa random number generator. If the line is busy, it tries again A) nonpersistent B) 1-persistent C) p-persistent D) none of the above
Last Answer : p-persistent
Description : The _______ address in theheader ofa packet in adatagram network normally remains thesame during the entire journeyof the packet. A) source B) destination C) local D) none of the above
Last Answer : destination
Description : _________ media transportelectromagnetic waves without the use ofa physical conductor. A) Guided B) Unguided C) Either (a) or (b) D) None of the above
Last Answer : Unguided
Description : ______ cables arecomposed ofa glass or plastic inner core surrounded by cladding, allencasedin an outside jacket. A) Coaxial B) Fiber-optic C) Twisted-pair D) none of the above
Last Answer : Fiber-optic
Description : The Nyquist theorem specifies the minimum samplingrate to be_______. A) equal to the lowest frequency of asignal B) equal to the highest frequency ofa signal C) twice thebandwidth of a signal D) twice thehighest frequencyof a signal
Last Answer : twice thehighest frequencyof a signal
Description : What is the bandwidth ofa signal that ranges from 1 MHz to4 MHz? A) 4 MHz B) 1 KHz C) 3 MHz D) none of the above
Last Answer : 3 MHz
Description : The ____layer is responsible for the movement ofa signal across aphysical line. A) section B) line C) path D) photonic
Last Answer : section
Description : In IPv6, the _______ field inthe baseheader restricts the lifetime ofa datagram. A) version B) next-header C) hoplimit D) neighbor-advertisemen
Last Answer : hoplimit
Description : A DVD is an example ofa(n) – (A) hard disk (B) opticaldisc (C) output device (D) solid-state storage device (E) None of these
Last Answer : opticaldisc
Description : The basic unit ofa worksheet into which you enter data in Excel is called a– (A) tab (B) cell (C) box (D) range (E) None of these
Last Answer : cell
Description : To instruct Wordto fit the width ofa column to the contents ofa table automatically, click the button and then point to AutoFit Contents. (A) Fit to Form (B) Format (C) Autosize (D) Contents (E) AutoFit
Last Answer : AutoFit
Description : In mesh topology, every device has a dedicated topology of a. Point to point linking b. Both a and b c. Multipoint linking d. None of given
Last Answer : a. Point to point linking
Description : ________is the set of techniques that allows the simultaneous transmission of multiple signalsacrossa single data link. A) Demodulating B) Multiplexing C) Compressing D) None of the above
Last Answer : Multiplexing
Description : ………………...is a minimal protocol that allows isolated hosts to link via TCP/IP over the telephone network and ………………..uses a proposed international standard for transmitting HDLC over asynchronous lines. A. LCP, PPP B. PPP, LCP C. SLIP, PPP D. PPP, SLIP
Last Answer : C. SLIP, PPP
Description : In IPv6,a ______address is used ifa site with several networks uses the Internetprotocols but is not connectedto the Internet for security reasons. A) link local B) site local C) mapped D) none of the abov
Last Answer : site local
Description : In OSPF, a _______ link is a network with several routersattachedto it. A) point-to-point B) transient C) stub D) none of the above
Last Answer : transient
Description : In ________ TDM, slots are dynamically allocated to improvebandwidth efficiency. A) synchronous B) statistical C) isochronous D) none of the above
Last Answer : statistical
Description : In ________ TDM, each input connection hasan allotment in the outputeven if it is not sendingdata. A) synchronous B) statistical C) isochronous D) none of the above
Last Answer : synchronous
Description : In TDM, the transmissionrate of the multiplexed path isusually_______ thesum of thetransmission rates of thesignal sources. A) greater than B) less than C) equal to D) not related to
Last Answer : greater than
Description : In synchronous TDM, forn signal sources of the same data rate, eachframe contains _______ slots. A) n B) n + 1 C) n- 1 D) 0to n
Last Answer : n
Description : SONET is a _______ TDM system. A) asynchronous B) synchronous C) statistical D) none of the above
Last Answer : none of the above
Description : What type of network device allows youto share your connection to the Internet with other computers in your home? A) Ethernet card B) NIC C) Router D) Cat 5
Last Answer : Router
Description : Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is ............... (A) 400 bps (B) 800 bps (C) 1600 bps (D) 3200 bps
Last Answer : (D) 3200 bps Answer: D Explanation: The multiplexer is shown in the Figure. Each frame carries 1 byte from each channel; the size of each frame, therefore, is 4 bytes, or 32 bits. Because each ... channel, the frame rate must be 100 frames per second. The bit rate is 100 32 = 3200 bps.