The principal strain due to σ1(tensile) and σ2 (Compressive ) stress is (a) Firstly (b)Secondly (c)Thirdly (d) None

The principal strain due to σ1(tensile) and σ2 (Compressive ) stress is

(a) Firstly

(b)Secondly

(c)Thirdly

(d) None
by

1 Answer

Answer :

(b)Secondly
by

Related questions

Nature of the three principal stresses is a. Firstly All tensile b. Secondly All compressive c. Thirdly All shear d. None

Description : Nature of the three principal stresses is a. Firstly All tensile b. Secondly All compressive c. Thirdly All shear d. None

Last Answer : a. Firstly All tensile

Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum Principal stress theory (d) None

Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum Principal stress theory (d) None

Last Answer : (c) Thirdly Maximum Principal stress theory

Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum shear stress theory (d) None

Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum shear stress theory (d) None

Last Answer : (d) None

For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure fails (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal strain Theory (c) Thirdly Maximum Principal Energy Theory (d) None

Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure fails (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal strain Theory (c) Thirdly Maximum Principal Energy Theory (d) None

Last Answer : (c) Thirdly Maximum Principal Energy Theory

A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal Strain Theory (c) Thirdly Maximum principal strain energy theory (d) None

Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal Strain Theory (c) Thirdly Maximum principal strain energy theory (d) None

Last Answer : (d) None

Maximum principal strain is equal to when σ1 and σ2 are tensile (a) (σ1 –μσ2)/E (b) (σ1 + μσ2)/E (c) (–σ1 –μσ2)/E (d) None

Description : Maximum principal strain is equal to when σ1 and σ2 are tensile (a) (σ1 –μσ2)/E (b) (σ1 + μσ2)/E (c) (–σ1 –μσ2)/E (d) None

Last Answer : (a) (σ1 –μσ2)/E

Shear strain energy under principal tensile stresses σ1 and σ2 is (a) (1/12E) (σ1 — σ2) 2 + σ2 2 — σ1 2 ) (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (c) (1/12K) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (d) None

Description : Shear strain energy under principal tensile stresses σ1 and σ2 is (a) (1/12E) (σ1 — σ2) 2 + σ2 2 — σ1 2 ) (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (c) (1/12K) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (d) None

Last Answer : (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 )

For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure does not fail (a) Firstly Maximum Principal Theory (b) Secondly Maximum Shear Stress Theory (c) Thirdly Maximum Principal Energy Theory (d) None

Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure does not fail (a) Firstly Maximum Principal Theory (b) Secondly Maximum Shear Stress Theory (c) Thirdly Maximum Principal Energy Theory (d) None

Last Answer : (a) Firstly Maximum Principal Theory

Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None

Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None

Last Answer : c. Thirdly (σ 1 –σ 2 )/2

The magnitude of maximum principal stress is a. Firstly (σ x +σ y )/2+ (1/2)( σ x +σ y ) +4τ 2 ) 5 b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5 c. Thirdly (σ x +σ y )/2+ (1/2)( σ x +σ y ) 2 +4τ 2 ) 5 d. None

Description : The magnitude of maximum principal stress is a. Firstly (σ x +σ y )/2+ (1/2)( σ x +σ y ) +4τ 2 ) 5 b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5 c. Thirdly (σ x +σ y )/2+ (1/2)( σ x +σ y ) 2 +4τ 2 ) 5 d. None

Last Answer : b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5

Which is the maximum principal stress? a. Firstly σ 2 b. Secondly σ 3 c. Thirdly σ 1 d. None

Description : Which is the maximum principal stress? a. Firstly σ 2 b. Secondly σ 3 c. Thirdly σ 1 d. None

Last Answer : c. Thirdly σ 1

Under complex loading, principal stresses exist as (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None

Description : Under complex loading, principal stresses exist as (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None

Last Answer : (d) None

The order of magnitude of the principal stresses is a. Firstly σ 1 >σ 2 >σ 3 b. Secondly σ 2 >σ 3 >σ 1 c. Thirdly σ 1 >σ 3 >σ 2 d. None

Description : The order of magnitude of the principal stresses is a. Firstly σ 1 >σ 2 >σ 3 b. Secondly σ 2 >σ 3 >σ 1 c. Thirdly σ 1 >σ 3 >σ 2 d. None

Last Answer : a. Firstly σ 1 >σ 2 >σ 3

Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2) (d) None

Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2) (d) None

Last Answer : (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2)

Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None

Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None

Last Answer : (d) None

Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None

Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None

Last Answer : (d) None

In a body under hydrostatic pressure, the case exists (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None

Description : In a body under hydrostatic pressure, the case exists (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None

Last Answer : (b) Secondly σ 1 = σ 2 =σ 3

In a ductile material, the strength are (a)Firstly Ultimate >yield > elastic limit (b) Secondly Ultimate > yield =elastic limit (c) Thirdly Ultimate=yield=elastic limit (d) None

Description : In a ductile material, the strength are (a)Firstly Ultimate >yield > elastic limit (b) Secondly Ultimate > yield =elastic limit (c) Thirdly Ultimate=yield=elastic limit (d) None

Last Answer : (a)Firstly Ultimate >yield > elastic limit

In a brittle material, the strength are (a) Firstly Ultimate >yield > elastic limit (b) Secondly Ultimate > yield =elastic limit (c) Thirdly Ultimate=yield=elastic limit (d) None

Description : In a brittle material, the strength are (a) Firstly Ultimate >yield > elastic limit (b) Secondly Ultimate > yield =elastic limit (c) Thirdly Ultimate=yield=elastic limit (d) None

Last Answer : (c) Thirdly Ultimate=yield=elastic limit

Maximum total strain energy is equal to (a) (σ1 2 +σ2 2 )/2E (b) ( σ1 2 +σ2 2 + 2μ σ1 σ2)/2E (c) ( σ1 2 +σ2 2 — 2μ σ1 σ2)/2E (d) None

Description : Maximum total strain energy is equal to (a) (σ1 2 +σ2 2 )/2E (b) ( σ1 2 +σ2 2 + 2μ σ1 σ2)/2E (c) ( σ1 2 +σ2 2 — 2μ σ1 σ2)/2E (d) None

Last Answer : (c) ( σ1 2 +σ2 2 — 2μ σ1 σ2)/2E

A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Shear Stress Theory (b) Secondly Maximum Shear Strain Energy Theory (c) Both (a) & (b) (d) None

Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Shear Stress Theory (b) Secondly Maximum Shear Strain Energy Theory (c) Both (a) & (b) (d) None

Last Answer : (c) Both (a) & (b)

In a body under pure shear, the magnitude and nature of the two principal stresses are a. Firstly Equals shear stress, opposite nature b. Secondly Equals shear stress, same nature c. Both (a) & (b) d. None

Description : In a body under pure shear, the magnitude and nature of the two principal stresses are a. Firstly Equals shear stress, opposite nature b. Secondly Equals shear stress, same nature c. Both (a) & (b) d. None

Last Answer : a. Firstly Equals shear stress, opposite nature

Maximum shear stress is equal to (a) (σ1 –σ2)/2 (b) (σ1 + σ2)/2 (c) (σ1 + 2σ2)/2 (d) None

Description : Maximum shear stress is equal to (a) (σ1 –σ2)/2 (b) (σ1 + σ2)/2 (c) (σ1 + 2σ2)/2 (d) None

Last Answer : (a) (σ1 –σ2)/2

Symbols for principal stresses are a. Firstly σ, τ & γ b. Secondly σ 1 , σ 2 & σ 3

Description : Symbols for principal stresses are a. Firstly σ, τ & γ b. Secondly σ 1 , σ 2 & σ 3

Last Answer : b. Secondly σ 1 , σ 2 & σ 3

Principal stresses are a. Firstly Maximum and minimum shear stresses b. Secondly Maximum and minimum normal stresses c. Both (a) & (b) d. None

Description : Principal stresses are a. Firstly Maximum and minimum shear stresses b. Secondly Maximum and minimum normal stresses c. Both (a) & (b) d. None

Last Answer : b. Secondly Maximum and minimum normal stresses

The angle of obliquity is the angle between the a. Firstly Resultant and the shear stress b. Secondly Resultant & the normal stress c. Both (a) & (b) d. None

Description : The angle of obliquity is the angle between the a. Firstly Resultant and the shear stress b. Secondly Resultant & the normal stress c. Both (a) & (b) d. None

Last Answer : b. Secondly Resultant & the normal stress

If compressive yield stress and tensile yield stress are equivalent, then region of safety from maximum principal stress theory is of which shape? a) Rectangle b) Square c) Circle d) Ellipse

Description : If compressive yield stress and tensile yield stress are equivalent, then region of safety from maximum principal stress theory is of which shape? a) Rectangle b) Square c) Circle d) Ellipse

Last Answer : b) Square

A principal stress is a. Tensile or shear stress b. Compressive or shear stress c. Tensile or compressive stress d. None

Description : A principal stress is a. Tensile or shear stress b. Compressive or shear stress c. Tensile or compressive stress d. None

Last Answer : c. Tensile or compressive stress

A principal plane is a plane of (a) Zero tensile stress (b) Zero compressive stress (c) Zero shear stress (d) None

Description : A principal plane is a plane of (a) Zero tensile stress (b) Zero compressive stress (c) Zero shear stress (d) None

Last Answer : (c) Zero shear stress

Theories of elastic failure establishes the (a) Firstly Reasons of failure (b) Secondly Reasons of safety (c) Both (a) & (b) (d) None

Description : Theories of elastic failure establishes the (a) Firstly Reasons of failure (b) Secondly Reasons of safety (c) Both (a) & (b) (d) None

Last Answer : (c) Both (a) & (b)

Theories of elastic failure is the (a) Firstly analysis of the various failures (b) Secondly analysis of the strength of a material (c) Both (a) & (b) (d) None

Description : Theories of elastic failure is the (a) Firstly analysis of the various failures (b) Secondly analysis of the strength of a material (c) Both (a) & (b) (d) None

Last Answer : (c) Both (a) & (b)

While designing screw threads, adequate length of engaged threads between the screw and nut is provided so as to prevent failure of threads due to (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Description : While designing screw threads, adequate length of engaged threads between the screw and nut is provided so as to prevent failure of threads due to (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Last Answer : (A) Direct shear stress

In the analysis, all the principal stresses are assumed as a. Shear stresses b. Compressive stresses c. Tensile stresses d. None

Description : In the analysis, all the principal stresses are assumed as a. Shear stresses b. Compressive stresses c. Tensile stresses d. None

Last Answer : c. Tensile stresses

The equations for principal stresses are valid only when (a)σ x and σ y are both tensile (b) σ x is compressive and σ y is tensile (c) σ x is tensile and σ y is compressive (d) None

Description : The equations for principal stresses are valid only when (a)σ x and σ y are both tensile (b) σ x is compressive and σ y is tensile (c) σ x is tensile and σ y is compressive (d) None

Last Answer : (a)σ x and σ y are both tensile

Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None

Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None

Last Answer : a. Failure is due to simple stress or strain

The spokes of the flywheel are subjected to 1. direct shear stress 2. torsional shear stress 3. tensile stress 4. compressive stress

Description : The spokes of the flywheel are subjected to 1. direct shear stress 2. torsional shear stress 3. tensile stress 4. compressive stress

Last Answer : 3. tensile stress

The rim of the flywheel is subjected to, 1. direct tensile stress and bending stress 2. torsional shear stress and bending stress 3. direct shear stress and bending stress 4. compressive stress and bending stress

Description : The rim of the flywheel is subjected to, 1. direct tensile stress and bending stress 2. torsional shear stress and bending stress 3. direct shear stress and bending stress 4. compressive stress and bending stress

Last Answer : 1. direct tensile stress and bending stress

The spokes of the flywheel are subjected to, (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Description : The spokes of the flywheel are subjected to, (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Last Answer : (C) Tensile stress

When the helical torsion spring is subjected to torque, the type of stress induced in the spring wire is, (A) Tensile stress (B) Compressive stress (C) Bending stress (D) Torsional shear stress

Description : When the helical torsion spring is subjected to torque, the type of stress induced in the spring wire is, (A) Tensile stress (B) Compressive stress (C) Bending stress (D) Torsional shear stress

Last Answer : (C) Bending stress

When the helical compression spring is subjected to axial compressive force, the type of stress induced in the spring wire is, (A) Tensile stress (B) Compressive stress (C) Bending stress (D) Torsional shear stress

Description : When the helical compression spring is subjected to axial compressive force, the type of stress induced in the spring wire is, (A) Tensile stress (B) Compressive stress (C) Bending stress (D) Torsional shear stress

Last Answer : (D) Torsional shear stress

When the helical extension spring is subjected to axial tensile force, the type of stress induced in the spring wire is, (A) Tensile stress (B) Compressive stress (C) Bending stress (D) Torsional shear stress

Description : When the helical extension spring is subjected to axial tensile force, the type of stress induced in the spring wire is, (A) Tensile stress (B) Compressive stress (C) Bending stress (D) Torsional shear stress

Last Answer : (D) Torsional shear stress

Parallel fillet welds are under (i) Shear stress (ii)Compressive stress (iii)Tensile stress (iv)None

Description : Parallel fillet welds are under (i) Shear stress (ii)Compressive stress (iii)Tensile stress (iv)None

Last Answer : (i) Shear stress

Transverse fillet welds are under (i) Shear stress (ii) Compressive stress (iii) Tensile stress

Description : Transverse fillet welds are under (i) Shear stress (ii) Compressive stress (iii) Tensile stress

Last Answer : (iii) Tensile stress

Butt welds are under (i) Shear stress (ii) Compressive stress (iii) Tensile stress

Description : Butt welds are under (i) Shear stress (ii) Compressive stress (iii) Tensile stress

Last Answer : (iii) Tensile stress

When a nut is tightened by placing a washer below it, the threads of bolt are subjected to (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Description : When a nut is tightened by placing a washer below it, the threads of bolt are subjected to (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Last Answer : (A) Direct shear stress

When a nut is tightened by placing a washer below it, the shank of bolt is subjected to (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Description : When a nut is tightened by placing a washer below it, the shank of bolt is subjected to (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Last Answer : (C) Tensile stress

The stress which vary from a minimum value to a maximum value of the same nature (i.e. tensile or compressive) is called (a) repeated stress (b) yield stress (c) fluctuating stress (d) alternating stress

Description : The stress which vary from a minimum value to a maximum value of the same nature (i.e. tensile or compressive) is called (a) repeated stress (b) yield stress (c) fluctuating stress (d) alternating stress

Last Answer : (c) fluctuating stress

A complementary shear stress is equal in magnitude and opposite in rotational tendency of an applied (a) Tensile stress (b) Compressive stress (c) Shear stress (d) None

Description : A complementary shear stress is equal in magnitude and opposite in rotational tendency of an applied (a) Tensile stress (b) Compressive stress (c) Shear stress (d) None

Last Answer : (c) Shear stress

The strain due to tensile stress is : a) Compressive strain b) Shear strain c) Volumetric strain d) Tensile strain

Description : The strain due to tensile stress is : a) Compressive strain b) Shear strain c) Volumetric strain d) Tensile strain

Last Answer : d) Tensile strain

Identify the principal stress (a) Shear stress (b) Bending stress (c) Compressive stress (d) None

Description : Identify the principal stress (a) Shear stress (b) Bending stress (c) Compressive stress (d) None

Last Answer : (c) Compressive stress