Description : Shear strain energy under principal tensile stresses σ1 and σ2 is (a) (1/12E) (σ1 — σ2) 2 + σ2 2 — σ1 2 ) (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (c) (1/12K) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (d) None
Last Answer : (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 )
Description : The principal strain due to σ1(tensile) and σ2 (Compressive ) stress is (a) Firstly (b)Secondly (c)Thirdly (d) None
Last Answer : (b)Secondly
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2) (d) None
Last Answer : (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2)
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None
Last Answer : (d) None
Description : Maximum total strain energy is equal to (a) (σ1 2 +σ2 2 )/2E (b) ( σ1 2 +σ2 2 + 2μ σ1 σ2)/2E (c) ( σ1 2 +σ2 2 — 2μ σ1 σ2)/2E (d) None
Last Answer : (c) ( σ1 2 +σ2 2 — 2μ σ1 σ2)/2E
Description : Maximum shear stress is equal to (a) (σ1 –σ2)/2 (b) (σ1 + σ2)/2 (c) (σ1 + 2σ2)/2 (d) None
Last Answer : (a) (σ1 –σ2)/2
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure fails (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal strain Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (c) Thirdly Maximum Principal Energy Theory
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum Principal stress theory (d) None
Last Answer : (c) Thirdly Maximum Principal stress theory
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum shear stress theory (d) None
Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal Strain Theory (c) Thirdly Maximum principal strain energy theory (d) None
Description : Maximum principal strain theory is also called as (a) Guest’s theory (b) Haigh theory (c) St.Venant’s theory (d) None
Last Answer : (c) St.Venant’s theory
Description : Maximum principal strain theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Last Answer : (b) Brittle materials
Description : If compressive yield stress and tensile yield stress are equivalent, then region of safety from maximum principal stress theory is of which shape? a) Rectangle b) Square c) Circle d) Ellipse
Last Answer : b) Square
Description : The total strain energy for a unit cube subjected to three principal stresses is given by? a) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/3 b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ c) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/4 d) None of the mentioned
Last Answer : b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ
Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None
Last Answer : a. Failure is due to simple stress or strain
Description : A principal stress is a. Tensile or shear stress b. Compressive or shear stress c. Tensile or compressive stress d. None
Last Answer : c. Tensile or compressive stress
Description : In the analysis, all the principal stresses are assumed as a. Shear stresses b. Compressive stresses c. Tensile stresses d. None
Last Answer : c. Tensile stresses
Description : Nature of the three principal stresses is a. Firstly All tensile b. Secondly All compressive c. Thirdly All shear d. None
Last Answer : a. Firstly All tensile
Description : The equations for principal stresses are valid only when (a)σ x and σ y are both tensile (b) σ x is compressive and σ y is tensile (c) σ x is tensile and σ y is compressive (d) None
Last Answer : (a)σ x and σ y are both tensile
Description : A principal plane is a plane of (a) Zero tensile stress (b) Zero compressive stress (c) Zero shear stress (d) None
Last Answer : (c) Zero shear stress
Description : Maximum principal stress is equal to (a) (σx + σy)/2 + [ (σx –σy) 2 + τ 2 ] 0.5 (b) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + τ 2 ] 0.5 (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5 (d) None
Last Answer : (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5
Description : Under maximum principal stress theory, maximum principal stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None
Last Answer : (a) Allowable stress in tension
Description : The stress which vary from a minimum value to a maximum value of the same nature (i.e. tensile or compressive) is called (a) repeated stress (b) yield stress (c) fluctuating stress (d) alternating stress
Last Answer : (c) fluctuating stress
Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Shear Stress Theory (b) Secondly Maximum Shear Strain Energy Theory (c) Both (a) & (b) (d) None
Last Answer : (c) Both (a) & (b)
Description : Maximum total strain energy theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Last Answer : (a) Ductile materials
Description : Maximum total strain energy theory is also known as (a) Huber theory (b) Rankine theory (c) St.Venant’s theory (d) None
Last Answer : (a) Huber theory
Description : Maximum total strain energy theory is also known as (a) Guest’s theory (b) Haigh theory (c) St.Venant’s theory (d) None
Last Answer : (b) Haigh theory
Description : When the shear strength of nut is equal to the tensile strength of bolt, the height of nut (h) should be (A) h = 0.5 dc (B) h = 0.25 dc (C) h = 0.75 dc (D) h = dc
Last Answer : (A) h = 0.5 dc
Description : A complementary shear stress is equal in magnitude and opposite in rotational tendency of an applied (a) Tensile stress (b) Compressive stress (c) Shear stress (d) None
Last Answer : (c) Shear stress
Description : A transmission shaft subjected to pure bending moment should be designed on the basis of (A) Maximum principal stress theory (B) Maximum shear stress theory (C) Distortion energy theory (D) Goodman or Soderberg diagrams
Last Answer : (A) Maximum principal stress theory
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure does not fail (a) Firstly Maximum Principal Theory (b) Secondly Maximum Shear Stress Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (a) Firstly Maximum Principal Theory
Description : Maximum principal theory is also known as (a) Beltrami Theory (b) Maximum normal stress theory (c) Saint Venant’s theory (d) None
Last Answer : (b) Maximum normal stress theory
Description : Maximum principal theory is also known as (a) Guest Theory (b) Beltrami Theory (c) Rankine Theory (d) None
Last Answer : (c) Rankine Theory
Description : Maximum principal stress theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Description : In a general two dimensional stress system, planes of maximum shear stress are inclined at ___ with principal planes. a. 90 degree b. 180 degree c. 45 degree d. 60 degree
Last Answer : c. 45 degree
Description : Principal planes are those planes on which a. Normal stress is maximum b. Normal stress is minimum c. Normal stress is either maximum or minimum d. Shear stress is maximum
Last Answer : c. Normal stress is either maximum or minimum
Description : Maximum Principal Stress Theory is not good for brittle materials. a) True b) False
Last Answer : b) False
Description : The maximum number of principal stresses is a. 1 b. 3 c. 5 d. None
Last Answer : b. 3
Description : The maximum number of principal stresses is a. 2 b. 4 c. 6 d. None
Last Answer : d. None
Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None
Last Answer : c. Thirdly (σ 1 –σ 2 )/2
Description : The magnitude of maximum principal stress is a. Firstly (σ x +σ y )/2+ (1/2)( σ x +σ y ) +4τ 2 ) 5 b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5 c. Thirdly (σ x +σ y )/2+ (1/2)( σ x +σ y ) 2 +4τ 2 ) 5 d. None
Last Answer : b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5
Description : Which is the maximum principal stress? a. Firstly σ 2 b. Secondly σ 3 c. Thirdly σ 1 d. None
Last Answer : c. Thirdly σ 1
Description : The angle between a principal plane and a plane of maximum shear is a. 15 0 b. 45 0 c. 75 0 d. None
Last Answer : b. 45 0
Description : The angle between a principal plane and a plane of maximum shear is a. 30 0 b. 60 0 c. 90 0 d. None
Description : How many maximum shear stresses are there with three principal stresses? a. 1 b. 2 c. 3 d. None
Last Answer : c. 3
Description : Principal stresses are a. Firstly Maximum and minimum shear stresses b. Secondly Maximum and minimum normal stresses c. Both (a) & (b) d. None
Last Answer : b. Secondly Maximum and minimum normal stresses
Description : Maximum shear stress is (a) Average sum of principal stresses (b) Average difference of principal stresses (c) Average sum as well as difference of principal stresses (d) None
Last Answer : (b) Average difference of principal stresses
Description : The strain energy (E) stored in the spring is given by Where P=Load and δ = deflection of spring (A) Pδ/2 (B) 2Pδ (C) Pδ/3 (D) Pδ/4
Last Answer : (A) Pδ/2