Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None
Last Answer : c. Thirdly (σ 1 –σ 2 )/2
Description : The magnitude of maximum principal stress is a. Firstly (σ x +σ y )/2+ (1/2)( σ x +σ y ) +4τ 2 ) 5 b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5 c. Thirdly (σ x +σ y )/2+ (1/2)( σ x +σ y ) 2 +4τ 2 ) 5 d. None
Last Answer : b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5
Description : Under complex loading, principal stresses exist as (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None
Last Answer : (d) None
Description : The order of magnitude of the principal stresses is a. Firstly σ 1 >σ 2 >σ 3 b. Secondly σ 2 >σ 3 >σ 1 c. Thirdly σ 1 >σ 3 >σ 2 d. None
Last Answer : a. Firstly σ 1 >σ 2 >σ 3
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure does not fail (a) Firstly Maximum Principal Theory (b) Secondly Maximum Shear Stress Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (a) Firstly Maximum Principal Theory
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum Principal stress theory (d) None
Last Answer : (c) Thirdly Maximum Principal stress theory
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum shear stress theory (d) None
Description : The principal strain due to σ1(tensile) and σ2 (Compressive ) stress is (a) Firstly (b)Secondly (c)Thirdly (d) None
Last Answer : (b)Secondly
Description : In a body under hydrostatic pressure, the case exists (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None
Last Answer : (b) Secondly σ 1 = σ 2 =σ 3
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure fails (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal strain Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (c) Thirdly Maximum Principal Energy Theory
Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal Strain Theory (c) Thirdly Maximum principal strain energy theory (d) None
Description : Nature of the three principal stresses is a. Firstly All tensile b. Secondly All compressive c. Thirdly All shear d. None
Last Answer : a. Firstly All tensile
Description : Symbols for principal stresses are a. Firstly σ, τ & γ b. Secondly σ 1 , σ 2 & σ 3
Last Answer : b. Secondly σ 1 , σ 2 & σ 3
Description : In a ductile material, the strength are (a)Firstly Ultimate >yield > elastic limit (b) Secondly Ultimate > yield =elastic limit (c) Thirdly Ultimate=yield=elastic limit (d) None
Last Answer : (a)Firstly Ultimate >yield > elastic limit
Description : In a brittle material, the strength are (a) Firstly Ultimate >yield > elastic limit (b) Secondly Ultimate > yield =elastic limit (c) Thirdly Ultimate=yield=elastic limit (d) None
Last Answer : (c) Thirdly Ultimate=yield=elastic limit
Description : In a body under pure shear, the magnitude and nature of the two principal stresses are a. Firstly Equals shear stress, opposite nature b. Secondly Equals shear stress, same nature c. Both (a) & (b) d. None
Last Answer : a. Firstly Equals shear stress, opposite nature
Description : Principal stresses are a. Firstly Maximum and minimum shear stresses b. Secondly Maximum and minimum normal stresses c. Both (a) & (b) d. None
Last Answer : b. Secondly Maximum and minimum normal stresses
Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Shear Stress Theory (b) Secondly Maximum Shear Strain Energy Theory (c) Both (a) & (b) (d) None
Last Answer : (c) Both (a) & (b)
Description : The angle of obliquity is the angle between the a. Firstly Resultant and the shear stress b. Secondly Resultant & the normal stress c. Both (a) & (b) d. None
Last Answer : b. Secondly Resultant & the normal stress
Description : Theories of elastic failure establishes the (a) Firstly Reasons of failure (b) Secondly Reasons of safety (c) Both (a) & (b) (d) None
Description : Theories of elastic failure is the (a) Firstly analysis of the various failures (b) Secondly analysis of the strength of a material (c) Both (a) & (b) (d) None
Description : The maximum tangential stress σ t = (σ x sin 2θ)/2 is maximum if, θ is equal to ________ a. 45 o b. 90 o c. 270 o d. all of the above
Last Answer : a. 45 o
Description : The equations for principal stresses are valid only when (a)σ x and σ y are both tensile (b) σ x is compressive and σ y is tensile (c) σ x is tensile and σ y is compressive (d) None
Last Answer : (a)σ x and σ y are both tensile
Description : The magnitude of principal stresses due to complex stresses is (a) (1/2)[ (σ x + σ y ) ± ((σ x –σ y ) 2 + 4 τ 2 )) 0.5 ] (b) (1/2)[ (σx + σy) ± (1/2)((σx –σy) 2 + 4 τ 2 )) 0.5 ] (c) (1/2)[ (σx + σy) ± ((1/2)(σx –σy) 2 + 4 τ 2 )) 0.5 ]
Last Answer : (a) (1/2)[ (σ x + σ y ) ± ((σ x –σ y ) 2 + 4 τ 2 )) 0.5 ]
Description : The relationship between the alternating stress and mean stress is given by the following equation: σ a =σ e [1-(σ m /σ u )x], where σ e is the fatigue limit for completely reversed loading. The value of x for Gerber line is equal to _________ a) 1 b) 2 c) 0.5 d) -1
Last Answer : b) 2
Description : The relationship between the alternating stress and mean stress is given by the following equation: σ a = σ e [1-(σ m /σ u ) x ]. The value of x for Goodman line is equal to _________ a) 1 b) 2 c) 0.5 d) -1
Last Answer : a) 1
Description : Which of the following conditions is true for repeated stress? 1. σ m = 0 2. σ m = σ max / 2 3. σ m = σ a 4. σ min = 0 5. σ min = - σ max 6. σ a = σ max / 2 where σ m = mean ... amplitude a. condition 2 and 3 b. condition 1, 3 and 5 c. condition 2, 4, and 6 d. condition 3,4, 5 and 6
Last Answer : c. condition 2, 4, and 6
Description : Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by a shear stress? a. [(σ x - σ y )/2 ]sin θ - τ cos 2θ b. [(σ x - ... τ cos 2θ c. [(σ x - σ y )/2 ]sin θ - τ 2 cos θ d. None of the above
Last Answer : c. [(σ x – σ y )/2 ]sin θ – τ 2 cos θ
Description : A transmission shaft subjected to pure bending moment should be designed on the basis of (A) Maximum principal stress theory (B) Maximum shear stress theory (C) Distortion energy theory (D) Goodman or Soderberg diagrams
Last Answer : (A) Maximum principal stress theory
Description : Maximum principal stress is equal to (a) (σx + σy)/2 + [ (σx –σy) 2 + τ 2 ] 0.5 (b) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + τ 2 ] 0.5 (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5 (d) None
Last Answer : (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5
Description : Maximum principal theory is also known as (a) Beltrami Theory (b) Maximum normal stress theory (c) Saint Venant’s theory (d) None
Last Answer : (b) Maximum normal stress theory
Description : Under maximum principal stress theory, maximum principal stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None
Last Answer : (a) Allowable stress in tension
Description : Maximum principal stress theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Last Answer : (b) Brittle materials
Description : In a general two dimensional stress system, planes of maximum shear stress are inclined at ___ with principal planes. a. 90 degree b. 180 degree c. 45 degree d. 60 degree
Last Answer : c. 45 degree
Description : Principal planes are those planes on which a. Normal stress is maximum b. Normal stress is minimum c. Normal stress is either maximum or minimum d. Shear stress is maximum
Last Answer : c. Normal stress is either maximum or minimum
Description : Maximum Principal Stress Theory is not good for brittle materials. a) True b) False
Last Answer : b) False
Description : If compressive yield stress and tensile yield stress are equivalent, then region of safety from maximum principal stress theory is of which shape? a) Rectangle b) Square c) Circle d) Ellipse
Last Answer : b) Square
Description : Maximum shear stress is (a) Average sum of principal stresses (b) Average difference of principal stresses (c) Average sum as well as difference of principal stresses (d) None
Last Answer : (b) Average difference of principal stresses
Description : In a general two dimensional stress system, there are a. Two principal planes b. Only one plane c. Three principal planes d. No principal plane
Last Answer : a. Two principal planes
Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None
Last Answer : a. Failure is due to simple stress or strain
Description : The principal stress ha a a. Variable b. Constant c. Constant & variable d. None
Last Answer : b. Constant
Description : Is principal a? a. Simple stress b. Complex stress c. Bending stress d. None
Last Answer : a. Simple stress
Description : A principal stress is a. Tensile or shear stress b. Compressive or shear stress c. Tensile or compressive stress d. None
Last Answer : c. Tensile or compressive stress
Description : A principal stress is a a. Shear stress with zero normal stress b. Normal stress with zero shear stress c. Both (a) & (b) d. None
Last Answer : b. Normal stress with zero shear stress
Description : Identify the principal stress (a) Shear stress (b) Bending stress (c) Compressive stress (d) None
Last Answer : (c) Compressive stress
Description : A principal plane is a plane of (a) Only normal stress (b) Only shear stress (c) Only bending stress (d) None
Last Answer : (a) Only normal stress
Description : A principal plane is a plane of (a) Zero tensile stress (b) Zero compressive stress (c) Zero shear stress (d) None
Last Answer : (c) Zero shear stress
Description : Minor principal stress has minimum ________ a. value of shear stress acting on the plane b. intensity of direct stress c. both a. and b. d. none of the above
Last Answer : b. intensity of direct stress
Description : Which of the following stresses can be determined using Mohr's circle method? a. Torsional stress b. Bending stress c. Principal stress d. All of the above
Last Answer : c. Principal stress
Description : Principal stress is the magnitude of ________ stress acting on the principal plane. a. Normal stress b. Shear stress c. Both a. and b. d. None of the above
Last Answer : a. Normal stress