What is the breathing rate of human being body? A. 15-11 minutes B. 16-20 minutes (Answer) C. 25-26 minutes D. 32-35 minutes

What is the breathing rate of human being body?

A. 15-11 minutes

B. 16-20 minutes (Answer)

C. 25-26 minutes

D. 32-35 minutes
by

1 Answer

Answer :

B. 16-20 minutes (Answer)
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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

A thermometer measures temperature in whole degrees only. If the temperature falls below 18 degrees, the heating is switched off. It is switched on again when the temperature reaches 21 degrees. What are the best values in degrees to cover all equivalence partitions? A. 15,19 and 25. B. 17,18 and19. C. 18, 20 and22. D. 16, 26 and 32.

Description : A thermometer measures temperature in whole degrees only. If the temperature falls below 18 degrees, the heating is switched off. It is switched on again when the temperature reaches 21 degrees. What are the best values in degrees to ... and 25. B. 17,18 and19. C. 18, 20 and22. D. 16, 26 and 32.

Last Answer : A. 15,19 and 25.

Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Last Answer : In conclusion, the range of data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, and 20 is 26.

The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Last Answer : (d) In a given data, maximum value = 32 and minimum value = 6 We know, range of the data = maximum value – minimum value = 32 – 6 = 26 Hence, the range of the given data is 26.

What will be the values of x, m and n after execution of the following statements? Int x, m, n; m=10; n=15; x= ++m + n++; A) x=25, m=10, n=15 B) x=27, m=10, n=15 C) x=26, m=11, n=16 D) x=27, m=11, n=16

Description : What will be the values of x, m and n after execution of the following statements? Int x, m, n; m=10; n=15; x= ++m + n++; A) x=25, m=10, n=15 B) x=27, m=10, n=15 C) x=26, m=11, n=16 D) x=27, m=11, n=16

Last Answer : C) x=26, m=11, n=16

24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Description : 24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Last Answer : The series consists of two series 1 and 2: Series 1 : 24 26 28 30 +2 +2 +2 Series 2 : 14 15 16 +1 +1 Answer: c)

vIf the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Description : If the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Last Answer : 2) 39 : 28: 20

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

Find the range of the data : 14, 15, 16, 18, 19, 25, 30, 41, 26, 16, 13, 18, 20 and 26.

Description : Find the range of the data : 14, 15, 16, 18, 19, 25, 30, 41, 26, 16, 13, 18, 20 and 26.

Last Answer : Find the range of the data : 14, 15, 16, 18, 19, 25, 30, 41, 26, 16, 13, 18, 20 and 26.

f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence partitions? A. 15, 19 and 25 degrees B. 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Description : f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence ... 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Last Answer : A. 15, 19 and 25 degrees

When a voltage of 442.7 VDC is applied to the illustrated circuit with a resistance of 1.25 ohms the current will be _______. EL-0018 A. 28.25 amps B. 35.32 amps C. 354.16 amps D. 443.62 amps

Description : When a voltage of 442.7 VDC is applied to the illustrated circuit with a resistance of 1.25 ohms the current will be _______. EL-0018 A. 28.25 amps B. 35.32 amps C. 354.16 amps D. 443.62 amps

Last Answer : Answer: C

Insert the missing number: 16/32, 15 /33, 17/31, 14/34, ? (A) 19/35 (B) 19/30 (C) 18/35 (D) 18/30

Description : Insert the missing number: 16/32, 15 /33, 17/31, 14/34, ? (A) 19/35 (B) 19/30 (C) 18/35 (D) 18/30

Last Answer : Answer: D 16/32 then 15/33 means -1/+1, 17/31 means +2/-2, 14/34 means -3/+3 next +4/-4 i.e 18/30

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

For Sugarcane growth best temperature is— degree C a. 26 to 32 b. 10 to 15 c. 10 to 20 d. None of these

Description : For Sugarcane growth best temperature is— degree C a. 26 to 32 b. 10 to 15 c. 10 to 20 d. None of these

Last Answer : a. 26 to 32

Just born baby has the respiratory rate as – (1) 32 times/minute (2) 26 times/minute (3) 18 times/minute (4) 15 times/minute

Description : Just born baby has the respiratory rate as – (1) 32 times/minute (2) 26 times/minute (3) 18 times/minute (4) 15 times/minute

Last Answer : (1) 32 times/minute Explanation: New born babies and children normally breathe faster than older children and adults. Their respiratory rate is about 30-60 breaths per minute. The respiratory rate for the different age-categories of ... :-6-1.2 months: 24-30; 1-5 years: 20-30: 6-12 years: 12- 20.

Just born baby has the respiratory rate as (1) 32 times/minute (2) 26 times/minute (3) 18 times/minute (4) 15 times/minute

Description : Just born baby has the respiratory rate as (1) 32 times/minute (2) 26 times/minute (3) 18 times/minute (4) 15 times/minute

Last Answer : 32 times/minute

My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age my father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years

Description : My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, ... father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years

Last Answer : Let my age = x Then My brother's age = x + 3 My mother's age = x + 26 My sister's age = (x + 3) + 4 = x + 7 My Father's age = (x + 7) + 28 = x + 35 => age my father when my brother was born = x + 35 – (x + 3) = 32. Answer: d)

Household refrigerators usually run at ____º to ____ºF. a. 45.5, 50.2 c. 32.3, 35.7 b. 40.5, 44.6 d. 21.4, 26.5

Description : Household refrigerators usually run at ____º to ____ºF. a. 45.5, 50.2 c. 32.3, 35.7 b. 40.5, 44.6 d. 21.4, 26.5

Last Answer : b. 40.5, 44.6

A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Description : A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take ... flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Last Answer : C 1st puncture made the tyre flat in 27 mins 2nd puncture made the tyre flat in 18 mins 1 minute’s work of both the punctures = (1/27 + 1/18) =(2+3)/54 =5/54 So, both the punctures will make the tyre flat in 54/5 mins =>10 4/5 minutes

After AT Welding First train is to be passed after ? (i) 20 Minutes from pouring of weld metal. (ii) 35 Minutes from pouring of weld metal. (iii) 30 Minutes from pouring of weld metal.* (iv) 25 Minutes from pouring of weld metal.

Description : After AT Welding First train is to be passed after ? (i) 20 Minutes from pouring of weld metal. (ii) 35 Minutes from pouring of weld metal. (iii) 30 Minutes from pouring of weld metal.* (iv) 25 Minutes from pouring of weld metal.

Last Answer : (iii) 30 Minutes from pouring of weld metal.*

Which of the following is a typical consequence of dental crowding, assuming no primary tooth has been lost prematurely? A. Overlapping of lower incisors B. Palatal displacement of upper canines C. Impaction of 15 and 25 between first premolars and first molars D. Mesial tipping of 16 and 26 E. Rotation of 16 and 26

Description : Which of the following is a typical consequence of dental crowding, assuming no primary tooth has been lost prematurely? A. Overlapping of lower incisors B. Palatal displacement of upper canines C. Impaction ... and first molars D. Mesial tipping of 16 and 26 E. Rotation of 16 and 26

Last Answer : A. Overlapping of lower incisors

You are measuring noise in a voice channel at 7 dB test point level. The meter reads -56 dBm (FIA weighted). What is the reading in dBrnc? A. 20 B. 32 C. 35 D. 25

Description : You are measuring noise in a voice channel at 7 dB test point level. The meter reads -56 dBm (FIA weighted). What is the reading in dBrnc? A. 20 B. 32 C. 35 D. 25

Last Answer : C. 35

The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

The haemoglobin content per 100 mL of blood of a normal healthy human adult is (a) 5 - 11 gm (b) 25 - 30 gm (c) 17 - 20 gm (d) 12 - 16 gm.

Description : The haemoglobin content per 100 mL of blood of a normal healthy human adult is (a) 5 - 11 gm (b) 25 - 30 gm (c) 17 - 20 gm (d) 12 - 16 gm.

Last Answer : (d) 12 - 16 gm.

What is the median of this set of data values 11 13 14 15 18 20 23 26?

Description : What is the median of this set of data values 11 13 14 15 18 20 23 26?

Last Answer : Feel Free to Answer

A mass of 1 kg is attached to two identical springs each with stiffness k = 20 kN/m as shown in the figure. Under frictionless condition, the natural frequency of the system in Hz is close to * 1 point (A) 32 (B) 23 (C) 16 (D) 11

Description : A mass of 1 kg is attached to two identical springs each with stiffness k = 20 kN/m as shown in the figure. Under frictionless condition, the natural frequency of the system in Hz is close to * 1 point (A) 32 (B) 23 (C) 16 (D) 11

Last Answer : (A) 32

A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Description : A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Last Answer : A Speed of the Car = 1120 m/minute Speed of the bus=56 kms in 44 minutes =56/44 km/m =56000/44 m/mints Speed of the car : Speed of the bus, =1120:56000/44 =280:14000/44 =20:1000/44 =880:1000 =88:100 Required ratio =22:25

A bacterium divides every 35 minutes. If a culture containing 105 cells per mL is grown for 175 minutes, what will be the cell concentration per mL after 175 minutes? (a) 35 × 105 cells (b) 32 × 105 cells (c) 175 × 105 cells (d) 85 × 105 cells

Description : A bacterium divides every 35 minutes. If a culture containing 105 cells per mL is grown for 175 minutes, what will be the cell concentration per mL after 175 minutes? (a) 35 × 105 cells (b) 32 × 105 cells (c) 175 × 105 cells (d) 85 × 105 cells

Last Answer : b) 32 × 105 cells

A bacterium divides every 35 minutes. If a culture containing 105 cells per mL is grown for 175 minutes, what will be the cell concentration per mL after 175 minutes? (a) 35 × 105 cells (b) 32 × 105 cells (c) 175 × 105 cells (d) 85 × 105 cells

Description : A bacterium divides every 35 minutes. If a culture containing 105 cells per mL is grown for 175 minutes, what will be the cell concentration per mL after 175 minutes? (a) 35 × 105 cells (b) 32 × 105 cells (c) 175 × 105 cells (d) 85 × 105 cells

Last Answer : (b) 32 × 105 cells

A sum of Rs. 1550 was lent partly at 5% and partly at 8% per annum simple interest. The total interest received after 4 yr was Rs. 400. The ratio of the money lent at 8% to that lent at 5% is? (a) 15:16 (b) 16:17 (c) 19:17 (d) 21:26 (e) 20:17

Description : A sum of Rs. 1550 was lent partly at 5% and partly at 8% per annum simple interest. The total interest received after 4 yr was Rs. 400. The ratio of the money lent at 8% to that lent at 5% is? (a) 15:16 (b) 16:17 (c) 19:17 (d) 21:26 (e) 20:17

Last Answer : (a) 15:16

The normal range of filtration factor in an adult is (A) 0.10–0.15 (B) 0.16–0.21 (C) 0.25–0.30 (D) 0.35–0.40

Description : The normal range of filtration factor in an adult is (A) 0.10–0.15 (B) 0.16–0.21 (C) 0.25–0.30 (D) 0.35–0.40

Last Answer : Answer : B

The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Description : The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Last Answer : Let the number of girls be x. The number of boys is 45. :. Total age of boys and girls in the class = (x+45) × 12.05 or, (x+45) × 12.05 = 45 × 11.75 + x × 12.5 or, 12.05x + 542.25 = 528.75 + 12.5x or, 13.5 = 0.45x or, x = 13.5/0.45 = 30 Answer is: c)

What is the decimal value of 25? 38) A) 10 B) 20 C) 16 D) 32

Description : What is the decimal value of 25? 38) A) 10 B) 20 C) 16 D) 32

Last Answer : D) 32

To the nearest rupee, what is the net present value of a replacement project whose cash flows are -Rs.104,000; Rs.34,444; Rs.39,877; Rs.25,000; and Rs.52,800 for years 0 through 4, respectively? The firm has decided to assume that the appropriate cost of capital is 10% and the appropriate risk-free rate is 6%. A. Rs.15,115 B. Rs.26,798 C. Rs.33,346 D. Rs.48,121

Description : To the nearest rupee, what is the net present value of a replacement project whose cash flows are -Rs.104,000; Rs.34,444; Rs.39,877; Rs.25,000; and Rs.52,800 for years 0 through 4, respectively? The firm has decided to ... -free rate is 6%. A. Rs.15,115 B. Rs.26,798 C. Rs.33,346 D. Rs.48,121

Last Answer : C. Rs.33,346

A noodles merchant buys two varieties of noodles the price of the first being twice that of the second. He sells the mixture at Rs 17.50 per kilogram thereby making a profit of 25% . If the ratio of the amounts of the first noodles and the second noodles in the mixture is 2:3, then the respective costs of each noodles are A) Rs 20, Rs 10 B) Rs 24, Rs 12 C) Rs 16, Rs 8 D) Rs 26, Rs 13 E) NONE

Description : A noodles merchant buys two varieties of noodles the price of the first being twice that of the second. He sells the mixture at Rs 17.50 per kilogram thereby making a profit of 25% . If the ratio of the amounts of the first noodles ... , Rs 10 B) Rs 24, Rs 12 C) Rs 16, Rs 8 D) Rs 26, Rs 13 E) NONE

Last Answer : Answer: A

The mode of the data 35, 25, 26, 33, 31, x, and 30 is 26, then x is ________.

Description : The mode of the data 35, 25, 26, 33, 31, x, and 30 is 26, then x is ________.

Last Answer : The mode of the data 35, 25, 26, 33, 31, x, and 30 is 26, then x is ________. A. 25 B. 26 C. 31 D. 33

The phase constant of a wave propagation with frequency of 35 radian/sec and time delay of 7.5 sec is a) 4.66 b) 262.5 c) 46.6 d) 26.25

Description : The phase constant of a wave propagation with frequency of 35 radian/sec and time delay of 7.5 sec is a) 4.66 b) 262.5 c) 46.6 d) 26.25

Last Answer : b) 262.5

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Description : The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Last Answer : (C) 16 bits Explanation: VirtualAddress = 32 bits PageSize = 4KB = 12 bits therefore : VPNTag = 20 bits, OffsetTag = 12 bits TLBEntryLength = VPNTag = 20 bits TotalTLBEntries = 64, 4-way implies ... therefore : TLBIndex = 4 bits TLBTag = TLBEntryLength - TLBIndex = 20 - 4 = 16 bits

What is the interval between a high tide and neaptide at a given place? (1) 12 hours (2) 12 hours 26 minutes (3) 15 hours 30 minutes (4) 24 hours

Description : What is the interval between a high tide and neaptide at a given place? (1) 12 hours (2) 12 hours 26 minutes (3) 15 hours 30 minutes (4) 24 hours

Last Answer : (2) 12 hours 26 minutes Explanation: Tide clocks are popular clocks used amongst surfers, sailors, and anyone else who is concerned with the tidal cycle. They run on a 12 hour and 25 or 26 minute cycle, which is the time it takes for the high tide to ebb and flow back to high tide again.

What is the interval between a high tide and neaptide at a given place ? (1) 12 hours (2) 12 hours 26 minutes (3) 15 hours 30 minutes (4) 24 hours

Description : What is the interval between a high tide and neaptide at a given place ? (1) 12 hours (2) 12 hours 26 minutes (3) 15 hours 30 minutes (4) 24 hours

Last Answer : 12 hours 26 minutes

The human brain uses----- percent of the total oxygen and blood in the body? A. 20 (Answer) B. 12 C. 35 D. 48

Description : The human brain uses----- percent of the total oxygen and blood in the body? A. 20 (Answer) B. 12 C. 35 D. 48

Last Answer : A. 20 (Answer)

On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Description : On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Last Answer : Answer: B Solution:. Let us find the day on 1st April, 1994. 2000 years have 0 odd day. We have to calculate day on 1st April, 1994. 2000-1994 = 6 Years. 1996 is leap year and have 4 odd days Ordinary years ... was Friday Thus, on 3 rd , 10 th , 17 th , 24 th will be Sunday fall on April 1994.

The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Description : The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Last Answer : D) Calculated mean of 8 articles = 15 Incorrect sum of these 8 articles = (15*8) = 120. Correct sum of these 8 articles = (incorrect sum) - (sum of incorrect articles) + (sum of actual articles) = [120 ... (30)] = 130 Therefore, correct mean = 130/8 = 16.25 Hence, the correct mean is 16.25.

Lowfat (1%) chocolate milk has ____ grams of carbohydrates. a. 15 c. 32 b. 26 d. 21

Description : Lowfat (1%) chocolate milk has ____ grams of carbohydrates. a. 15 c. 32 b. 26 d. 21

Last Answer : b. 26

40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)

16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Description : 16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Last Answer : Answer- 1(7016) Explanation16×2 =32 32+3=35 35×4=140 140+5=145 145×6=870 870+7=877 877×8=7016