What is the mass of the Sun? A. 1.5×10 Power 30 Kg B. 1.98×10 Power 30 Kg (Answer) C. 4.5×10 Power 30 Kg D. 8×10 Power 30 Kg

What is the mass of the Sun?

A. 1.5×10 Power 30 Kg

B. 1.98×10 Power 30 Kg (Answer)

C. 4.5×10 Power 30 Kg

D. 8×10 Power 30 Kg
by

1 Answer

Answer :

B. 1.98×10 Power 30 Kg (Answer)
by

Related questions

The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98

Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98 

Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price  = $37.5 - $ 30  = $ 7.5 Therefore, percentage increase in price = Increase in price/ ...  = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %

A mixture of 90 kg of rava and sugar contains 90% of sugar. The new mixture is formed by adding 30 kg of sugar. What is the percentage of sugar in the new mixture? a) 45 1/2 b) 60 1/5 c) 45 1/2 d) 92 1/2 e) 98 1/2

Description : A mixture of 90 kg of rava and sugar contains 90% of sugar. The new mixture is formed by adding 30 kg of sugar. What is the percentage of sugar in the new mixture? a) 45 1/2 b) 60 1/5 c) 45 1/2 d) 92 1/2 e) 98 1/2

Last Answer : Answer: D 90 kg = 81 kg sugar 9 kg rava Adding = 30 kg sugar Total = 111kg sugar 9kg rava (new)  111/120 × 100 = 92.5 =92 1 /2

Utilizing the answer to the previous problem, estimate the overall or average increase in temperature ( ΔT) of the concrete roof from the energy absorbed from the sun during a12hour day. Assume that all of the radiation absorbed goes into heating the roof. The specific heat of concrete is about 900 J/kg, and the density is about 2,300 kg/m3 .  a. 7.9 °C  b. 8.9°C  c. 9.9°C  d. 10.9°C formula: ΔQ = m c ΔT

Description : Utilizing the answer to the previous problem, estimate the overall or average increase in temperature ( ΔT) of the concrete roof from the energy absorbed from the sun during a12hour day. Assume that all of the radiation absorbed goes into ... °C  b. 8.9°C  c. 9.9°C  d. 10.9°C formula: ΔQ = m c ΔT

Last Answer : 7.9 °C

Orbital period of the planet Mercury around the sun is -------? A. 88 days (Answer) B. 365 days C. 2 years D. 98 days E. None of these

Description : Orbital period of the planet Mercury around the sun is -------? A. 88 days (Answer) B. 365 days C. 2 years D. 98 days E. None of these

Last Answer : A. 88 days (Answer)

In a single stage extraction process, 10 kg of pure solvent S (containing no solute A) is mixed with 30 kg of feed F containing A at a mass fraction xf = 0.2. The mixture splits into an extract phase E and a raffinate phase R containing A at xB = 0.5 and xR = 0.05 respectively. The total mass of the extract phase is (in Kg) (A) 6.89 (B) 8.89 (C) 10 (D) 8.25

Description : In a single stage extraction process, 10 kg of pure solvent S (containing no solute A) is mixed with 30 kg of feed F containing A at a mass fraction xf = 0.2. The mixture splits into an extract phase E and a raffinate ... phase is (in Kg) (A) 6.89 (B) 8.89 (C) 10 (D) 8.25

Last Answer : (B) 8.89

In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Description : In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Last Answer : C) 30 & 40

A 5 m ladder of mass 25 kg is placed in a position where its inclination to a vertical wall is at 30?. A 100 kg man is to climb the ladder. If the coefficient of static friction is 0.25 the height along ladder at which the slipping will be induced would be a.2.4 m b.1.6 m c.0.8 m d.1.2 m e.0.5 m

Description : A 5 m ladder of mass 25 kg is placed in a position where its inclination to a vertical wall is at 30?. A 100 kg man is to climb the ladder. If the coefficient of static friction is 0.25 the height along ladder at which the slipping will be induced would be a.2.4 m b.1.6 m c.0.8 m d.1.2 m e.0.5 m

Last Answer : c. 0.8 m

A company manufactures a single product for which cost and selling price data are as follows: Selling price per unit - Rs. 12 Variable cost per unit - Rs. 8 Fixed cost for a period - Rs. 98,000 Budgeted sales for a period - 30,000 units

Description : A company manufactures a single product for which cost and selling price data are as follows: Selling price per unit - Rs. 12 Variable cost per unit - Rs. 8 Fixed cost for a period - Rs. 98,000 Budgeted sales for a period - 30,000 units

Last Answer : (a) 20%

A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98

Description : A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98 

Last Answer : Answer: D 60 kg = 36 kg dhal 24 kg rice -------- 15 kg dhal Total = 15 kg dhal 24 kg rice (new) 24/75×100=32%

98. Monitoring and targeting programs have been so effective that they show typical reductions in annual energy cost in the various industrial sectors between………. a. 10 to 30 % c. 5 to 20% b. 5 to 10 % d. 5 to 30%

Description : 98.Monitoring and targeting programs have been so effective that they show typical reductions in annual energy cost in the various industrial sectors between………. a. 10 to 30 % c. 5 to 20% b. 5 to 10 % d. 5 to 30%

Last Answer : 5 to 20%

When your mass is 96 kg. The acceleration due to gravity is 9.8 ms 2 . How much work against gravity do you do when you climb a flight of stairs 3.8 m high Answer in units of J.?

Description : When your mass is 96 kg. The acceleration due to gravity is 9.8 ms 2 . How much work against gravity do you do when you climb a flight of stairs 3.8 m high Answer in units of J.?

Last Answer : 4

An iron sphere of mass 30 kg and an aluminium sphere of mass 10 kg, both having the same diameter are dropped vertically from a cliff. When they are 10 metrs from the ground, they have identical a.Accelerations b.Momenta c.Kinetic energies d.Potential energies e.All of the above

Description : An iron sphere of mass 30 kg and an aluminium sphere of mass 10 kg, both having the same diameter are dropped vertically from a cliff. When they are 10 metrs from the ground, they have identical a.Accelerations b.Momenta c.Kinetic energies d.Potential energies e.All of the above

Last Answer : a. Accelerations

A cannon of weight 10 tonnes fires a shell of 50 kg with a muzzle velocity of 900 m/sec at an angle of 30?. The time taken for the shell to emerge from the barrel is 0.004 sec. The velocity of the cannon would be a.3.9 m/sec b.7.8 m/sec c.8.95 m/sec d.1.95 m/sec e.5.85 m/sec

Description : A cannon of weight 10 tonnes fires a shell of 50 kg with a muzzle velocity of 900 m/sec at an angle of 30?. The time taken for the shell to emerge from the barrel is 0.004 sec. The velocity of the cannon would be a.3.9 m/sec b.7.8 m/sec c.8.95 m/sec d.1.95 m/sec e.5.85 m/sec

Last Answer : a. 3.9 m/sec

What mass of NaCl would be decomposed by 98 g of `H_(2)SO_(4)` if 120 g of `NaHSO_(4)` and 27 .5 g of HCl are produced in a reaction. Assuming that la

Description : What mass of NaCl would be decomposed by 98 g of `H_(2)SO_(4)` if 120 g of `NaHSO_(4)` and 27 .5 g of HCl are produced in a reaction. Assuming that la

Last Answer : What mass of NaCl would be decomposed by 98 g of `H_(2)SO_(4)` if 120 g of `NaHSO_(4)` and 27 .5 g of HCl ... .95 g B. 49 .5 g C. 0. 495 g D. 495 h

Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Description : Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Last Answer : c. y = 1.98 x + 0.436

Account Receivables lag impacts sales. At no credit terms, the appeal falls to about ______ %, at 30 days, appeal is _____ %, at 60 days, appeal is ______%. a. 98.5, 92, 65 b. 65, 92, 98.5 c. 70, 85, 99 d. none of the above, there is no impact

Description : Account Receivables lag impacts sales. At no credit terms, the appeal falls to about ______ %, at 30 days, appeal is _____ %, at 60 days, appeal is ______%. a. 98.5, 92, 65 b. 65, 92, 98.5 c. 70, 85, 99 d. none of the above, there is no impact

Last Answer : b. 65, 92, 98.5

The mass and energy equivalent to 1 a.m.u. respectively are - (1) 1.67 x 10−27 g, 9.30 MeV (2) 1.67 x 10−27kg, 930 MeV (3) 1.67 x 10−27kg, 1 MeV (4) 1.67 x 10−34 kg, 1 MeV

Description : The mass and energy equivalent to 1 a.m.u. respectively are - (1) 1.67 x 10−27 g, 9.30 MeV (2) 1.67 x 10−27kg, 930 MeV (3) 1.67 x 10−27kg, 1 MeV (4) 1.67 x 10−34 kg, 1 MeV

Last Answer : (2) 1.67 x 10−27kg, 930 MeV Explanation: The mass and energy equivalent to 1 a.m.u. respectively are 1.67 x 10−27kg, 930 MeV.

A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Description : A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Last Answer : B 30 rad/sec

An accelerometer has input range of 0 to 10g, natural frequency 30 Hz and mass 0.001 kg. The range of the

Description : An accelerometer has input range of 0 to 10g, natural frequency 30 Hz and mass 0.001 kg. The range of the secondary displacement transducer in mm required to cover the input range is (A) 0 to 2.76 (B) 0 to 9.81 (C) 0 to 11.20 (D) 0 to 52.10

Last Answer : An accelerometer has input range of 0 to 10g, natural frequency 30 Hz and mass 0.001 kg. The range of the secondary displacement transducer in mm required to cover the input range is 0 to 2.76

In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 days and 8 kg to 10 kg (C) 105 days to 120 days and 18 kg to 21 kg (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg

If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, 6 kg, 4 kg respectively, the fineness modulus of the aggregate, is (A) 7.30 (B) 7.35 (C) 7.40 (D) 7.45

Description : If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, ... , the fineness modulus of the aggregate, is (A) 7.30 (B) 7.35 (C) 7.40 (D) 7.45

Last Answer : Answer: Option C

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

Shan bought 30 liters of milk at the rate of Rs.8 per liter. He got it churned after spending Rs.10 and 5kg of cream and 30 liter of toned milk were obtained. If he sold the cream at Rs.30 per kg and toned milk at Rs.4 per liter, his profit in the transaction is: A. 20% B. 8% C. 30% D. 40%

Description : Shan bought 30 liters of milk at the rate of Rs.8 per liter. He got it churned after spending Rs.10 and 5kg of cream and 30 liter of toned milk were obtained. If he sold the cream at Rs.30 per kg and toned milk at Rs.4 per liter, his profit in the transaction is: A. 20% B. 8% C. 30% D. 40%

Last Answer : Answer – B .8% Explanation: CP =Rs.(30 x 8 + 10) = Rs.250 SP = Rs. (30 x 5 + 30 x 4) = Rs.270 Gain% = (20/250 x 100)% = 8%

About 98 percent of the mass of every living organism is composed of just six elements including carbon, hydrogen, nitrogen, oxygen and (a) sulphur and magnesium (b) magnesium and sodium (c) calcium and phosphorus (d) phosphorus and sulphur.

Description : About 98 percent of the mass of every living organism is composed of just six elements including carbon, hydrogen, nitrogen, oxygen and (a) sulphur and magnesium (b) magnesium and sodium (c) calcium and phosphorus (d) phosphorus and sulphur.

Last Answer : (d) phosphorus and sulphur.

Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Description : Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Last Answer : 1124 cal

Which of the following is true about the Accounts Receivable Lag and its implications on demand? a. If you offer no credit, demand falls to about 60% of normal. b. At 30 days, demand is 90%. c. At 45 days, demand is 95%. d. At 60 days, demand is 98.5%. e. At 90 days, demand is 100%.

Description : Which of the following is true about the Accounts Receivable Lag and its implications on demand? a. If you offer no credit, demand falls to about 60% of normal. b. At 30 days, demand is 90%. c. At 45 days, demand is 95%. d. At 60 days, demand is 98.5%. e. At 90 days, demand is 100%.

Last Answer : d. At 60 days, demand is 98.5%.

A server crashes on the average once in 30 days, that is, the Mean Time Between Failures (MTBF) is 30 days. When this happens, it takes 12 hours to reboot it, that is, the Mean Time to Repair (MTTR) is 12 hours. The availability of server with these reliability data values is approximately: (A) 96.3% (B) 97.3% (C) 98.3% (D) 99.3%

Description : A server crashes on the average once in 30 days, that is, the Mean Time Between Failures (MTBF) is 30 days. When this happens, it takes 12 hours to reboot it, that is, the Mean Time to Repair (MTTR) is 12 ... these reliability data values is approximately: (A) 96.3% (B) 97.3% (C) 98.3% (D) 99.3%

Last Answer : (C) 98.3%

Answer: b, c The body contains fuel reserves which it can mobilize and utilize during times of starvation or stress. By far the greatest energy component is fat, which is calorically dense since it provides about 9 calories/gram. Body protein comprises the next largest mass of utilizable energy, but amino acids yield only about 4 kcal/gram. Unlike fat reserves, body protein is not a storage form of energy but rather serves as a structural functional component of the body; loss of body protein, if severe, is associated with functional consequences. Glycogen stored in muscle and liver and free glucose have a trivial caloric value of less than 1000 kcal for a 70 kg male

Description : Answer: b, c The body contains fuel reserves which it can mobilize and utilize during times of starvation or stress. By far the greatest energy component is fat, which is calorically dense since it ... liver and free glucose have a trivial caloric value of less than 1000 kcal for a 70 kg male

Last Answer : Which of the following statement(s) is/are true concerning the indications and administration of nutritional support to cancer patients? a. Preoperative nutritional support should be provided to all ... total parenteral nutrition solutions maintain integrity of the small bowel e. None of the above

What is the body temperature of a normal man? A. 81.1 °C B. 37.0 °C (Answer) C. 98.6 °C D. 21.7 °C

Description : What is the body temperature of a normal man? A. 81.1 °C B. 37.0 °C (Answer) C. 98.6 °C D. 21.7 °C

Last Answer : B. 37.0 °C (Answer)

Mass of Earth is------? A. 5.972 × 1024 kg? B. 6.972 × 1024 kg C. 7.972 × 1024 kg D. 8.972 × 1024 kg

Description : Mass of Earth is------? A. 5.972 × 1024 kg? B. 6.972 × 1024 kg C. 7.972 × 1024 kg D. 8.972 × 1024 kg

Last Answer : C. 7.972 × 1024 kg

A mass of 5 kg moves on a smooth horizontal plane with a speed of 8 m/s attached to a fixed point on the plane by a string of length 4m. Tension in the string is a.785 b.80N c.392.4N d.None of the above e.Tapered bearing

Description : A mass of 5 kg moves on a smooth horizontal plane with a speed of 8 m/s attached to a fixed point on the plane by a string of length 4m. Tension in the string is a.785 b.80N c.392.4N d.None of the above e.Tapered bearing

Last Answer : b. 80N

A couple applied to a flywheel of mass 5 kg and of radius of gyration 20 cm produces an angular acceleration of 4 radians/sec2. The torque applied in dyne cm is a.8 x 104 b.8 x 106 c.8 x 107 d.8 x 108 e.8 x 1010

Description : A couple applied to a flywheel of mass 5 kg and of radius of gyration 20 cm produces an angular acceleration of 4 radians/sec2. The torque applied in dyne cm is a.8 x 104 b.8 x 106 c.8 x 107 d.8 x 108 e.8 x 1010

Last Answer : b. 8 x 106

A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 Hz B 4.67 Hz C 9.8 Hz D 2.49 Hz

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 Hz B 4.67 Hz C 9.8 Hz D 2.49 Hz

Last Answer : D 2.49 Hz

A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 HzB 4.67 Hz C 9.8 Hz D 2.49 Hz

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 HzB 4.67 Hz C 9.8 Hz D 2.49 Hz

Last Answer : D 2.49 Hz

A car having a mass of 1000 kg deflects its springs 4 cm under its load. D Determine the natural frequency of the car in vertical direction. (A)5 Hz (B) 4.67 Hz (C) 9.8 Hz (D) 2.49 Hz

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. D Determine the natural frequency of the car in vertical direction. (A)5 Hz (B) 4.67 Hz (C) 9.8 Hz (D) 2.49 Hz

Last Answer : (D) 2.49 Hz

The sun is containing ---- % mass of the solar system? A. 75.24% B. 79.36% C. 89.10% D. 99.86% (Answer)

Description : The sun is containing ---- % mass of the solar system? A. 75.24% B. 79.36% C. 89.10% D. 99.86% (Answer)

Last Answer : D. 99.86% (Answer)

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

Find the friction force due to air on a body of mass 1 kg falling with acceleration `8 m//s^(2)` :-

Description : Find the friction force due to air on a body of mass 1 kg falling with acceleration `8 m//s^(2)` :-

Last Answer : Find the friction force due to air on a body of mass 1 kg falling with acceleration `8 m//s^(2)` :- A. 2 N B. 4 N C. Zero D. None

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

What is bigger 30 oz or 8 kg?

Description : What is bigger 30 oz or 8 kg?

Last Answer : gkg

The sag in a tape 100 ft long held between two supports 99.8 ft aprat at the same level is a.3.32 ft b.0.98 ft c.2.73 ft d.1.87 ft e.107 dynes

Description : The sag in a tape 100 ft long held between two supports 99.8 ft aprat at the same level is a.3.32 ft b.0.98 ft c.2.73 ft d.1.87 ft e.107 dynes

Last Answer : c. 2.73 ft

What is 8.98 rounded to the nearest?

Description : What is 8.98 rounded to the nearest?

Last Answer : It is 9 when rounded to the nearest whole number

Is 98 in greater than 8 ft?

Description : Is 98 in greater than 8 ft?

Last Answer : 98 ÷ 12 = 8 feet 2 inchesTherefore. 98 inches is longer than 8 feet.

What us the probability that 4 out of 8 dolphins are cured when treated with an antibiotic that cures 98 percent of all dolphins?

Description : What us the probability that 4 out of 8 dolphins are cured when treated with an antibiotic that cures 98 percent of all dolphins?

Last Answer : pr(exactly 4 out of 8 cured) = ₈C₄ × (98/100)⁴ × (1 - 98/100)⁴ =103305233920/10000000000000000≈ 0.00001

Rewrite each list of number in order from least to gratest 9.08 8.98 98.1 9.8 9.88?

Description : Rewrite each list of number in order from least to gratest 9.08 8.98 98.1 9.8 9.88?

Last Answer : 8.98,9.08,9.8,98.1

Cd for the orifice plate varies from (A) 0.58 to 0.8 (B) 0.93 to 0.98 (C) 0.2 to 0.3 (D) 0.02 to 0.03

Description : Cd for the orifice plate varies from (A) 0.58 to 0.8 (B) 0.93 to 0.98 (C) 0.2 to 0.3 (D) 0.02 to 0.03

Last Answer : (A) 0.58 to 0.8

A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6

Description : A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6

Last Answer : Answer: D Error = 168 – 24 = 144 Therefore, % error = 144/168 [Since, we know decrease% = decrease in value/original value × 100 %]  = 144/168 × 100  = 85.7 %

A ball A of mass 0.25 kg moving on a smooth horizontal table with a velocity of 10 m/s strikes an identical stationary ball B on the table. If the impact is perfectly elastic, the velocity of the ball B just after the impact will be a.2.5 m/s b.zero c.5 m/s d.10 m/s e.107 dynes

Description : A ball A of mass 0.25 kg moving on a smooth horizontal table with a velocity of 10 m/s strikes an identical stationary ball B on the table. If the impact is perfectly elastic, the velocity of the ball B just after the impact will be a.2.5 m/s b.zero c.5 m/s d.10 m/s e.107 dynes

Last Answer : c. 5 m/s