Description : A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98
Last Answer : Answer: D 60 kg = 36 kg dhal 24 kg rice -------- 15 kg dhal Total = 15 kg dhal 24 kg rice (new) 24/75×100=32%
Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price = $37.5 - $ 30 = $ 7.5 Therefore, percentage increase in price = Increase in price/ ... = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %
Description : Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: D Required percentage = 1313/ 1400 × 100 =131300/1400 =93.7
Description : In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98
Last Answer : Answer: A Percentage of plot allowed for construction = (13500/18000 × 100) = 75 %. Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.
Description : Which of the following is true about the Accounts Receivable Lag and its implications on demand? a. If you offer no credit, demand falls to about 60% of normal. b. At 30 days, demand is 90%. c. At 45 days, demand is 95%. d. At 60 days, demand is 98.5%. e. At 90 days, demand is 100%.
Last Answer : d. At 60 days, demand is 98.5%.
Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41
Last Answer : Answer: A (i) Percentage scored in Mathematics = 120/180 100 = 12000/180 =1200/18 = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100) = (40000/510) = 4000/51 = 78 22/51 %
Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98
Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %
Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98
Last Answer : Answer: E Original cost = $140 Decrease in it = 30% of $140 = 30/100 × 140 = 4200/100 = $42 Therefore, decrease cost = $140 - $42 = $98
Description : By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98
Last Answer : Answer: A Let the number be m Increase in its value = 25 % of m = 25/100 × m = m/4 Therefore, increase value = m + m/4 = (4m + m)/4 = 5m/4 Therefore, the given number must be multiplied by 5/4 to increase the number by 25 %.
Description : In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98
Last Answer : Answer: A Let the total number of eggs in the basket be x 20 % of the eggs are rotten, and eggs in good condition are 68 Therefore, according to the question, 80% of x = 68 80/100 × x = 68 x = (68 × 100)/80 x = 6800 / 80 x = 85 Therefore, total number of eggs in the basket is 85.
Description : On a test consisting of 500 questions, Dhivya answered 80% of the first 250 questions correctly. What percent of the other 250 questions does she need to answer correctly for her grade on the entire exam to be 60% ? a) 20 b) 60 c) 45 d) 80 e) 40
Last Answer : Answer: E 60% of 500 = 300 80% of 250 = 200 No. of correct answers in remaining 250 questions = 300 – 200 = 100 Percentage = 100 x 100/ 250 = 40%
Description : What percent of a day in 12 hours? a) 25 b) 60 c) 45 d) 20 e) 50
Last Answer : Answer: E Total hours in a day = 24 Required percent = 12/24 ×100 = 50%
Description : A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6
Last Answer : Answer: D Error = 168 – 24 = 144 Therefore, % error = 144/168 [Since, we know decrease% = decrease in value/original value × 100 %] = 144/168 × 100 = 85.7 %
Description : Two vessels A and B contain sugar and rava in the ratio 4 : 3 and 2 : 3 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing sugar and rava in the ratio 1 : 2? a) 2:9 b) 3:2 c) 7:9 d) 2:7 e) 7:4
Last Answer : E Let Cost Price(CP) of 1 kg sugar be Rs.1 Quantity of sugar in 1kg mixture from vessel A=4/7 Cost Price(CP) of 1kg mixture from vessel A = Rs. =4/7 Quantity of sugar in 1 kg mixture from vessel ... from vessel C=1/2 Cost Price(CP) of 1 kg mixture from vessel C(Mean Price) = Rs.=1/2
Description : Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1
Last Answer : Answer: E Total cost of the items he purchased = Rs.75 Given that out of this Rs.75, 90 Paise is given as tax => Total tax incurred = 90 Paise = Rs.90/100 Let the cost of the tax free items = x Given that tax rate = ... −0.9 −x) = 90 ⇒ (75 − 0.9 − x) = 5 x = 75 − 0.9 - 5 X=69.1
Description : Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855
Last Answer : Answer: E Increase = 90 % of 450 = 90/100 × 450 = 40500/100 = 405 Therefore, increase value = 450 + 405 = 855
Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4
Last Answer : Answer: D Let the marks secured by them be x and (x + 18) Then sum of their marks = x + (x + 18) = 2x + 18 Given that (x + 18) was 72% of the sum of their marks =>(x+18) = 72/100(2x+18) => ... 11x = 126 x = 11.45 Then (x + 18) = 11.45 + 18 = 29.45 Hence their marks are 11.45 and 29.45
Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180
Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45 x = (45 × 100)/25 x = (4500)/25 x = 180 Therefore, the total number of matches played is 180.
Description : A wooden manufacturing company declares that a wooden is now available for $11200 as against $25200 one year before. Find the percentage reduction in the price of wooden offered by the company. a) 25 1/3 b) 691/3 c) 66 1/3 d) 33 1/3 e) 55 5/9
Last Answer : Answer: E Price of the wooden a year before = $25200 Price of the wooden after a year = $11200 Decrease in price = $(25200 - 11200) = $14000 Therefore, decrease % = 14000/25200 × 100 % = 55 5/9 %
Description : The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase in population. a) 25 b) 62 c) 6.25 d) 27.5 e) 59.8
Last Answer : Answer: D Population in a small town last year = 50000 Population in a small town after one year = 63750 Increase in population = 63750 - 50000 = 13750 Therefore, percentage increase in population = ... /50000 100 = 1375000/50000 = 27.5% Thus, the increase in population is 27.5%
Description : An alloy contains 36 % of bronze. What quantity of alloy is required to get 340 g of bronze? a) 1500 b) 944.4 c) 950 d) 1000 e) 980.5
Last Answer : Answer: B Let the quantity of alloy required = x g Then 36 % of x =340 g ⇒ 36/100 × x = 340 g x = (340 × 100)/36 g x = 34000/36 g x = 944.4 g
Description : Chenna dhal is now being sold at Rs. 70 a kg. Last month, is rate was Rs. 80 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed? a)12.5 b)21.8 c)23 d)18
Last Answer : Answer: A Let a family's monthly consumption of chenna dhal be x kg. To keep the expenditure fixed, their consumption for this month should be 70x/80 = 7x/8. Reduction in consumption = x/8 = 12.5% of x
Description : If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241
Last Answer : Answer: A Fraction is x/y (x + 400/100 x ) / (y + 300/100 y) = 18/35 (500/100) x(35) = (400/100)y (18) (5x) × 35 = 18 × 4 y 175 x = 72 y x/y = 72/175
Description : In an election three candidates received 2272 , 15272, and 23256 votes respectively. What percentage of the total votes did the winning candidate got? a) 25 b) 41 c) 75 d) 57 e) 93
Last Answer : Answer: D Total number of votes polled = (2272+15272+23256) =40800 Required percentage = 23256/40800 ×100 = 2325600/40800 = 57
Description : In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989
Last Answer : Answer: B Total marks in the test = (560 + 160) × 100 /25 = 720 ×100/25 = 72000/25 = 2880 Passing marks for girls =2880 × 60/100 = 1728 Required marks = 1728 – 216 = 1512
Description : Nandhini scored 996 marks out of 1200 marks and her elder brother kaviyarasan scored 1020 marks out of 1500 marks. Find the scored percentage which is better? a) 68% b) 83% c) 65% d) 85% e) 97%
Last Answer : Answer: A Percentage of marks scored by nandhini = (994/1200 × 100) = (99400/1200) = (994/12) = 83 % Percentage of marks scored by kaviyarasan = (1020/1500 × 100) = (102000/1500) = (1020/15) = 68 % Hence, the percentage marks scored by nandhini is better.
Description : A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298
Last Answer : Answer: B Let x be the maximum marks, Then (50% of x)+60 = (75% of x)-40 x/2 +60 = 3x/4 -20 60+20 = 3x/4 – x/ 2 X=320 Hence maximum marks = 320 Minimum pass marks = 320/2 + 60 = 220
Description : In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801
Last Answer : Answer: E Number of boys in the college = 60 % of 1335 = 60/100 × 1335 = 80100/100 = 801 Number of girls in the college = Total number of students in the college - Number of boys = 1335 – 801 =534
Description : A shopkeeper bought 1800 blackberry and 1200 blueberry. He found 45% of blackberry and 24% of blueberry were rotten. Find the percentage of fruits in good condition. a) 63.4 b) 32.9 c) 48.5 d) 56.3
Last Answer : Answer: A Total number of fruits shopkeeper bought = 1800 + 1200 = 1000 Number of rotten blackberry = 45% of 1800 = 45/100 1800 = 81000/100 = 810 Number of rotten blueberry = 24% of 1200 ... Therefore Percentage of fruits in good condition = (1902/3000 100) = (190200/3000) = 63.4%
Description : Account Receivables lag impacts sales. At no credit terms, the appeal falls to about ______ %, at 30 days, appeal is _____ %, at 60 days, appeal is ______%. a. 98.5, 92, 65 b. 65, 92, 98.5 c. 70, 85, 99 d. none of the above, there is no impact
Last Answer : b. 65, 92, 98.5
Description : What causes the differences in the percentage of the work force in different countries?
Last Answer : I blame demography.
Description : Idiocy admitted to, disclaimer disclaimed, now how do I figure out what the percentage of one number another number is?
Last Answer : Just divide it.
Description : How to Reduce Your Body Fat Percentage ?
Last Answer : How to Reduce Your Body Fat Percentage Losing weight doesn't only mean bringing down the numbers on your bathroom scale. Most of the time, people lose more muscles than fat because of misguided weight loss ... body you want. Lose weight safely. Don't fall into the pit of fast weight loss programs.
Description : The total power of an AM transmitter having a carrier power of 50 W and the percentage of modulation at 80% is A) 50 W B) 66 W C) 68 W D) 70 W
Last Answer : The total power of an AM transmitter having a carrier power of 50 W and the percentage of modulation at 80% is 66 W
Description : Two transformers A and B having equal outputs and voltage ratios but unequal percentage impedances of 4 and 2 are operating in parallel. The transformer A will be overloaded by
Last Answer : Two transformers A and B having equal outputs and voltage ratios but unequal percentage impedances of 4 and 2 are operating in parallel. The transformer A will be overloaded by 33%
Description : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be ______. (A) 20% (B) 40% (C) 50% (D) 30%
Last Answer : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be 20%.
Description : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Last Answer : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Description : What is the percentage of stray losses in DC machine?
Last Answer : Percentage of stray losses in DC machine is about 1 % .
Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg
Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg
Description : Bed pressure drop in an air fluidised bed of catalyst particles (ρp = 200 kg/m3, Dp = 0.05 cm) of 60 cm bed depth and bed porosity of 0.5 expressed in cm of water (manometer) is (A) 90 (B) 60 (C) 45 (D) 30
Last Answer : (B) 60
Description : If the fare of Rajdhani Exp is Rs. 350 and that of Sapt Kranti Exp is Rs. 450 for all classes of passenger then what is the total income of both the trains during 2011 to 2013? 1) Rs. 95 crore 2) Rs. 98 crore 3) Rs. 90 crore 4) Rs. 89 crore 5) Rs. 92.5 crore
Last Answer : 5) Rs. 92.5 crore
Description : In what proportion must sugar at Price 4.10 per kg must be mixed with weat at Price 4.60 per kg, so that the mixture be worth Rs 4.30 a Kg ? A)3:2 B)2:3 C)5:3 D)None of these
Last Answer : A)3:2
Description : Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5
Last Answer : Answer: D Let the number be m. Decrease = 24 % of m = 24/100 × m = 6m /25 Therefore, decrease number = m – 6m/25 = (25m – 6m)/25 = 19m/25 According to the question 19m/25 = 594 19m = 594 × 25 19m = 14850 m = 14850/19 m =781.5
Description : The Shopkeeper increased the price of a product by 75% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 140% of the required amount. What is the net difference in the ... on that product? a) 12.5 b) 26.0 c) 13.5 d) 17.5 e) 19.8
Last Answer : Answer: D Quantity×Rate=Price 1x1=1 1.4x1.75=2.45 Decrease in price = (0.175/1) × 100 = 17.5%
Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5
Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130 = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X
Description : If the production of a factory grows at a 16% p.a., what will be its production for the year 2016 if its production in 2014 was 140 lakh tonnes? a) 222.734 b) 149.597 c) 188.384 d) 28 3.812 e) 180.534
Last Answer : Answer: C Required Production=140(1 + 16/100)2 lakh tones =140(1 + 4/25)2 =140((25 + 4) /25)² =140(29/25)² =140(1.16)² =140×1.3456 =188.384 lakh tonnes
Description : The population of a town is 378000. It decreases by 16% in the 1st year and increases by 10% in the 2nd year. What is the population in the town at the end of 2 years? a) 182574 b) 482576 c) 282674 d) 283574 e) 349272
Last Answer : Answer: E After 2 years required population is = 378000 (1-16/100) (1+10/100) = 378000 (84/100) (110/100) = 378000 (0.84) (1.1) = 3,49,272
Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313
Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000 = (104/100) × (106/100) × (110/100) × 200000 = 1.04×1.06×1.1×200000 = 2,42,528
Description : In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814
Last Answer : Answer: D Total valid votes = 70% of 7600 = 5320 Number of valid votes to other candidate = 75% of 5320 = 75/100 *5320 = 399000/100 = 3990
Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800
Last Answer : Answer: D Total number of invalid votes = 55 % of 280000 = 55/100 280000 = 15400000/100 = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000 = 40/100 126000 = 5040000/100 = 50400