The value of NA/(NA + NB), for steady state equimolal counter diffusion of two gases 'A' and 'B' is (A) 1 (B) ∞ (C) 0.5

The value of NA/(NA + NB), for steady state equimolal counter diffusion

of two gases 'A' and 'B' is

(A) 1

(B) ∞

(C) 0.5

by

1 Answer

Answer :

(B) ∞

by

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