Colebrook equation for friction factor in turbulent flow is given by,
f
-0.5 = -4 loge
[(ε/D) + (1.26/NRe √F). It reduces to Nikuradse equation for a
value of (ϵ/D) equal to
(A) 0
(B) 1
(C) ∞
(D) 0.5
f
-0.5 = -4 loge
[(ε/D) + (1.26/NRe √F). It reduces to Nikuradse equation for a
value of (ϵ/D) equal to
(A) 0
(B) 1
(C) ∞
(D) 0.5