Three friends Alice, Bond and Charlie divide $1105 amongst them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that they got will be in the ratio of 11 : 18 : 24. How much did Charlie receive? a) $495 b) $510 c) $480 d) $375 e) $360

Three friends Alice, Bond and Charlie divide $1105 amongst them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that they got will be in the ratio of 11 : 18 : 24. How much did Charlie receive? a) $495 b) $510 c) $480 d) $375 e) $360
by

1 Answer

Answer :

Answer: A

Let the sums of money received by A, B and C be x, y and z respectively.

Then x – 10 : y – 20 : z -15 is 11a : 18a : 24a

When $10, $20 and $15 are removed, we are removing a total of $45 from $1105.

Therefore,

11a+18a+24a=1105-45=1060

53a=1060

or a= 20

We know that z – 15 = 24a = (24 * 20) = 480

Therefore, z = 480 + 15 = $495
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The ratio of the price of two houses was 17:24. Two years later, when the price of the first had risen by 20% while the price of second house increases by Rs.500 and their prices become 16:25. Find the original prices of the two houses together? a) Rs.2603 b) Rs.2503 c) Rs.2403 d) Rs.2303 e) None of these

Description : The ratio of the price of two houses was 17:24. Two years later, when the price of the first had risen by 20% while the price of second house increases by Rs.500 and their prices become 16:25. Find the original ... two houses together? a) Rs.2603 b) Rs.2503 c) Rs.2403 d) Rs.2303 e) None of these

Last Answer : Answer: A Let, new price of the first house=17x 120/100=102x/5 Let, new price of the second house=24x+500 According to the question, (102x/5) :(24x+500)=16 :25 ((102x/5))/((24x+500 ... price of second house=24 4000/63=1523.81 ~ Rs.1524 Required answer, =1079+1524=2603 Answer=d) Rs.2603

In Ram nagar Colony, the ratio of school going children to non-school going children is 5 : 4. If in the next year, the number of non-school going children is increased by 20%, making it 35,400 what is the new ratio of school going children to non-school going children? a) 4 : 5 b) 3 : 2 c) 25 : 24 d) 6 : 7 e) None of these

Description :  In Ram nagar Colony, the ratio of school going children to non-school going children is 5 : 4. If in the next year, the number of non-school going children is increased by 20%, making it 35,400 what is the new ratio of school ... children? a) 4 : 5 b) 3 : 2 c) 25 : 24 d) 6 : 7 e) None of these

Last Answer : Answer: C 5 : 4 → 5 : 4.8 → 25 : 24

A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Description : A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Last Answer : Answer: B Sol. Let the number of one-rupee coins, 50-paise coins and 25-paise coins be 2k, 3k and 5k, respectively. ∴ 2k × 1 + 3k × 0.50 + 5k × 0.25 = 114 ⇒ 2k + 1.50k + 1.25k = 114  ⇒ 4.75k = 114 ⇒ k = 24. 50 paise value = 1.5x = 1.5*24 = 36

The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Description : The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Last Answer : Answer: A A/B = 15/16 and B/C = 17*18 So A : B : C = 15*17 : 16*17 : 16*18 = 255 : 272 : 288 So C’s salary = [288/(255+272+288)] * 1,87,450= Rs 66,240

The ratio of the number of boys to that of girls in a school is 3:2. If 30% of boys and 70% of girls appeared in an examination, the ratio of students appeared in the examinations to that not appeared in the examination is A) 23:27 B) 22:25 C) 21:17 D) 18:17 E) None of these

Description : The ratio of the number of boys to that of girls in a school is 3:2. If 30% of boys and 70% of girls appeared in an examination, the ratio of students appeared in the examinations to that not appeared in the examination is A) 23:27 B) 22:25 C) 21:17 D) 18:17 E) None of these 

Last Answer :  Answer: A 3:2 = 30:20 30% boys = (30/100) × 30= 9 70% girls = (70/100) × 20 = 14 (9+14) : (50-23) = 23 : 27

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Description : Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Last Answer : Answer: B Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100=54.8%

The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen.Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Description : The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen. Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Last Answer : Answer: A P present age = 33-9 = 24 M = 24 – 9 =15 D – M = 24 D – 15 = 24 D = 24+15 = 39 15:39 = 5:13 X = 13

Brother A and B had some savings in the ratio 5:6. They decided to buy a gift for their sister, sharing the cost in the ratio 4:5. After they bought, A is left with three-fourth of his amount, while B is left with Rs.497. Then, the value of the gift is a) 215 b) 115 c) 315 d) 415 e) None of these

Description : Brother A and B had some savings in the ratio 5:6. They decided to buy a gift for their sister, sharing the cost in the ratio 4:5. After they bought, A is left with three-fourth of his amount, while B is left with Rs.497. Then, the value of the gift is a) 215 b) 115 c) 315 d) 415 e) None of these

Last Answer : Answer: C Let the savings of A and B are 5x, 6x and the share cost of gift are 4y, 5y respectively. According to question, For A, 5x-4y=3/4×5x =>x=16y/5 For B, 6x-5y=497 =>6×16y/5-5y=497 =>y=35 Cost of gift=4y+5y=9×35 =315

Joseph bought two varieties of rice, costing 5 cents per ounce and 6 cents per ounce each, and mixed them in some ratio. Then he sold the mixture at 7 cents per ounce, making a profit of 20 percent. What was the ratio of the mixture? A) 1:10 B) 1:5 C) 2:7 D) 3:8 E) NONE

Description : Joseph bought two varieties of rice, costing 5 cents per ounce and 6 cents per ounce each, and mixed them in some ratio. Then he sold the mixture at 7 cents per ounce, making a profit of 20 percent. What was the ratio of the mixture? A) 1:10 B) 1:5 C) 2:7 D) 3:8 E) NONE

Last Answer : Answer: B 1) 20% profit at the price of 7 cents means that cost of the mixture should be 70/12 cents per ounce (7 = 120% and x = 100% => x = 7*100/120) 2) Let the amount of 5 cent rice will be x and the amount ... which as we know should equal to 70/12 3) (5x + 6y)/(x + y) = 70/12 => x/y = 1/5

The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Description : The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Last Answer : Answer: C a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number = (7/35)*210 = 42

The students in three classes are in the ratio 4 : 6 : 9. If 12 students are increased in each class, the ratio changes to 7 : 9 : 12. Then the total number of students in the three classes before the increase is: a) 95 b) 76 c) 100 d) 114 e) None of these

Description : The students in three classes are in the ratio 4 : 6 : 9. If 12 students are increased in each class, the ratio changes to 7 : 9 : 12. Then the total number of students in the three classes before the increase is: a) 95 b) 76 c) 100 d) 114 e) None of these 

Last Answer : Answer: B Let originally were 4x, 6x and 9x student there in classes receptively. After 12 students increase in each student then students were 7x, 9x and 12x in each class respectively. Now, Total Students = 7x + 9x ... number of student in three classes, = 4x + 6x + 9x = 19x = 19 * 4 = 76. 

Two cogged wheels of which one has 32 cogs and other 54 cogs, work into each other. If the latter turns 80 times in three quarters of a minute, how often does the other turn in 8 seconds? A) 48 B) 24 C) 38 D) 39 E) None of these

Description : Two cogged wheels of which one has 32 cogs and other 54 cogs, work into each other. If the latter turns 80 times in three quarters of a minute, how often does the other turn in 8 seconds? A) 48 B) 24 C) 38 D) 39 E) None of these

Last Answer : Answer: B  Number of turns required= 80 × 54/32 × 8/45 = 24 24 times

Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these

Description : Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these 

Last Answer : Answer: D F/2 = S/3= T/6 T = 2S = 3F F + S + T = 1870 T( 1/3 +1/2 + 1 ) = 1870 T= 1870 x 6/11 = 170 x 6 = 1020 Or the third part is a multiple of 6 and is large

Two jars having a capacity of 3 and 5 litres respectively are filled with mixtures of milk and water. In the smaller jar 25% of the mixture is milk and in the larger 25% of the mixture is water. The jars are emptied into a 10 litre cask whose remaining capacity is filled up with water. Find the percentage of milk in the cask. a) 55% b) 50% c) 45% d) 25% e) None of these

Description : Two jars having a capacity of 3 and 5 litres respectively are filled with mixtures of milk and water. In the smaller jar 25% of the mixture is milk and in the larger 25% of the mixture is water. The jars are emptied ... the percentage of milk in the cask. a) 55% b) 50% c) 45% d) 25% e) None of these

Last Answer : Answer: D 0.75+3.75=4.5/10+8*100=4.5/18*100=25%

If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Description :  If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Last Answer : Answer: C [ b – (40/100)a] = (3/5)b. So we get a = b. 1:1

The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Description : The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

A bag contains 25p coins, 50p coins and 1 rupee coins whose values are in the ratio of 8:4:2.If the total values of coins is X and the total amount in rupees is Y,then which of the following is true A) X = 840; Y = 360 B) X = 966; Y = 345 C) X = 840; Y = 280 D) X = 740; Y = 260 E) None of these

Description : A bag contains 25p coins, 50p coins and 1 rupee coins whose values are in the ratio of 8:4:2.If the total values of coins is X and the total amount in rupees is Y,then which of the following is true A) X = 840; Y = 360 B) X = 966; Y = 345 C) X = 840; Y = 280 D) X = 740; Y = 260 E) None of these

Last Answer : Answer: A Value is given in the ratio 8:4:2. By option, (8x*0.25) + (4x*0.5) + (2x*1) = 840. So X=840 Y=360

In a bag there are coins of 25p, 10p and 5p in the ratio 1:2:3.If there are Rs.45 in all then find how many 25p coins are there? A) 60 B) 65 C) 70 D) 75 E) None of these

Description : In a bag there are coins of 25p, 10p and 5p in the ratio 1:2:3.If there are Rs.45 in all then find how many 25p coins are there? A) 60 B) 65 C) 70 D) 75 E) None of these

Last Answer : Answer: D [(25x) + (10x × 2) + (5x × 3)] / 100 = 45 [25x + 20x + 15x] / 100 = 45 60 x = 4500 X = 4500/60 = 75

The ratio of prices of 2 dresses is 10:15.If the price of the first dress is increased by 10% and that of the second dress by Rs.400 then the ratio of their prices is 4:7.What are the initial prices of the dresses ? A) 910,1375 B) 920,1380 C) 930,1395 D) 940, 1410 E) None of these

Description : The ratio of prices of 2 dresses is 10:15.If the price of the first dress is increased by 10% and that of the second dress by Rs.400 then the ratio of their prices is 4:7.What are the initial prices of the dresses ? A) 910,1375 B) 920,1380 C) 930,1395 D) 940, 1410 E) None of these

Last Answer : Answer: D Let the initial price of the dress = 10x and 15x Price of the 1st dress after increment = 10x × (110/100) = 11x Price of the 2nd dress after increment = 15x+400 [11x/(15x+400)] = 4/7 77x = 60x + 1600 17x = 1600 X = 1600/17 = 94.11 = 94 So dresses will be 940, 1410