A sum of 12600 is to be distributed between A, B and C. For every rupee A gets, B gets 80p and for every rupee B gets, C get 90 paise. Find the amount get by C. A) 3200 B) 3600 C) 4200 D) 4600 E) None of these

A sum of 12600 is to be distributed between A, B and C. For every rupee A gets, B gets 80p and for every rupee B gets, C get 90 paise. Find the amount get by C. A) 3200 B) 3600 C) 4200 D) 4600 E) None of these
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1 Answer

Answer :

Answer: B

Ratio of money between A and B – 100:80 and that of B and C – 100:90

so the ratio between A : B :C – 100:80:72

so 252x = 12600, x = 50. So C get = 50*72 = 3600
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A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

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The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen.Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

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Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these

Description : Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these 

Last Answer : Answer: D F/2 = S/3= T/6 T = 2S = 3F F + S + T = 1870 T( 1/3 +1/2 + 1 ) = 1870 T= 1870 x 6/11 = 170 x 6 = 1020 Or the third part is a multiple of 6 and is large

Two alloys contain platinum and gold in the ratio of 1:2 and 1:3 respectively. A third alloy C is formed by mixing alloys one and alloy two in the ratio of 3:4. Find the percentage of gold in the mixture a) 79.2/7% b) 71.2/7% c) 73.2/7% d) 71.3/7% e) None of these

Description : Two alloys contain platinum and gold in the ratio of 1:2 and 1:3 respectively. A third alloy C is formed by mixing alloys one and alloy two in the ratio of 3:4. Find the percentage of gold in the mixture a) 79.2/7% b) 71.2/7% c) 73.2/7% d) 71.3/7% e) None of these

Last Answer : Answer: D Platinum = 1/3 and 1/4 gold = 2/3 and 3/4 Alloy one and two are mixed in the ratio of 3:4, so ratio of platinum and gold in final ratio – 2:5 So gold % = (5/7)*100 71.3/7%

180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Description : 180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C ... . What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Last Answer : Answer: B A : B : C : D 2*2*3 : 3*2*3 : 3*5*3 : 3*5*4 4 : 6 : 15 : 20 B and C together = [(6+15)/(4+6+15+20)] * 180 = 84

A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Description : A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Last Answer : Answer: B milk = 4x and water = 3x milk = 4x – 14*4/7 and water = 3x – 14*3/7 + 14 4x – 8: 3x + 8 = 3:4 X = 8, so milk = 8*4 = 32 litres

An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio. a) increases 20:21 b) decreases 21:20 c) increases 21:22 d) decreases 22:21 e) None of these

Description : An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio. a) increases 20:21 b) decreases 21:20 c) increases 21:22 d) decreases 22:21 e) None of these

Last Answer : Answer: B Let initial employees be 7x and then 4x similarly initial wages be 3y and then 5y so total wage = 21xy initially and then 20xy so wages decreases and ratio = 21:20

Two candles of same height are lighted at the same time. The first is consumed in 6 hours and second in 4 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the first and second candles becomes 2:1? a) 1 hour b) 2 hour c) 3 hour d) 4 hour e) None of these

Description : Two candles of same height are lighted at the same time. The first is consumed in 6 hours and second in 4 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between ... becomes 2:1? a) 1 hour b) 2 hour c) 3 hour d) 4 hour e) None of these

Last Answer : Answer: C Let height of both candles is ‘h’ and let after t times ratio between the height be 2:1 h – t*h/6 : h – t*h/4 = 2:1 t = 3

Seats for Mathematics, Science and arts in a school are in the ratio 5:7:8. There is a proposal to increase these seats by X%, Y% and Z% respectively. And the ratio of increased seats is 2:3:4, which of the following is true? A) X = 50; Z = 40 B) Y = 40; Z = 50 C) X = 40; Z = 75 D) X = 50; Z = 40 E) Y = 50; X = 75

Description : Seats for Mathematics, Science and arts in a school are in the ratio 5:7:8. There is a proposal to increase these seats by X%, Y% and Z% respectively. And the ratio of increased seats is 2:3:4, which of the following is true? A) X = ... ; Z = 50 C) X = 40; Z = 75 D) X = 50; Z = 40 E) Y = 50; X = 75

Last Answer : Answer: C Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x) i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x) i.e., 7x, 21x/2 and 14x Required ratio = 7x:21x/2: ... of 8 = 6 total seats 8+6=14 Now compare ratios of all 7:21/2:14=>14:21:28 =>2:3:4

Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his 20 coins and Marat loses 30 coins. Now, the ratio of gold coins with them is 41:34:46, respectively. How many coins did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these

Description : Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his ... did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these 

Last Answer : Answer: A 41x+40+34x+20+46x+30=4325 =>121x=4325-90 =>x=35 Required answer, number of coins received by parat =34x+20=34×35+20=1210

Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 marks in Hindi, 62 marks in Sanskrit, 68 marks in Mathematics and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these

Description : Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 ... and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these

Last Answer : Answer: D Total of maximum marks of all subjects=105×5=525 75% of 525=525 ×60/100= 315 Obtained marks of foru subjects (Hindi, Sanskrit, mathematics and English) =69+62+68+51=250 So, the obtained marks in Science=315-250=65

Two candles of same height are lighted at the same time. The first is consumed in 3 hours and second in 2 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the first and second candles becomes 2:1? A) 2 hour B) 2.5 hour C) 4 hour D) 1.5 hour E) None of these

Description : Two candles of same height are lighted at the same time. The first is consumed in 3 hours and second in 2 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the ... 2:1? A) 2 hour B) 2.5 hour C) 4 hour D) 1.5 hour E) None of these

Last Answer : Answer: D Height of both candles are same i.e. h First one takes 3 hours to burn completely, so in one hour = h/3 Similarly second one will burn in one hour = h/2 Let after t time, ratio between their height is 2:1 so, ... given 2:1, h - t*(h/3) / h - t*(h/2) = 2/1 Solving we get t = 1.5

Rs 5750 is divided among A, B, and C such that if their share be reduced by Rs 10, Rs 15 and Rs 25 respectively, the reminder amounts with them shall be in the ratio 4 : 6 : 9. What was C’s share then? A) Rs 2700 B) Rs 2725 C) Rs 2750 D) Rs 2625 E) None of these

Description : Rs 5750 is divided among A, B, and C such that if their share be reduced by Rs 10, Rs 15 and Rs 25 respectively, the reminder amounts with them shall be in the ratio 4 : 6 : 9. What was C’s share then? A) Rs 2700 B) Rs 2725 C) Rs 2750 D) Rs 2625 E) None of these

Last Answer : Answer: B When the shares reduce, the total amount will also reduce which is to be divided among them. So after reducing shares by Rs 10, Rs 15 and Rs 25 respectively, total amount is 5750 - (10+15+25) = ... share shall be [9/(4+6+9)] * 5700 = 2700 Actually C would have received = 2700 + 25=2725

The ratio of the number of boys to the number of girls in a school is 6 : 5. If 20% of boys and 45% of girls come by bus to school, what percentage of students opt transport other than bus to come to school? A) 68 9/11% B) 68 7/11% C) 72 7/11% D) 73% E) 73 5/11%

Description : The ratio of the number of boys to the number of girls in a school is 6 : 5. If 20% of boys and 45% of girls come by bus to school, what percentage of students opt transport other than bus to come to school? A) 68 9/11% B) 68 7/11% C) 72 7/11% D) 73% E) 73 5/11%

Last Answer : Answer: B If 20% of boys and 45% of girls come by bus, then 80% of boys and 55% of girls opt transport other than bus. Let total number of students in school = x So boys who opt other transport are (80/100) * 6/(6+5 ... (24x/55) + (x/4) = 151x/220 So required % = [(151x/220)/x] * 100 = 68 7/11 %

Rs 650 was divided among 3 children A,B,C in the ratio 2 : 4 : 7. Had it been divided in the ratio 1/2 : 1/4 : 1/7, who would have gained the most and by how much? A) C, Rs 246 B) C, Rs 264 C) B, Rs 18 D) A, Rs 246 E) A, Rs 264

Description : Rs 650 was divided among 3 children A,B,C in the ratio 2 : 4 : 7. Had it been divided in the ratio 1/2 : 1/4 : 1/7, who would have gained the most and by how much? A) C, Rs 246 B) C, Rs 264 C) B, Rs 18 D) A, Rs 246 E) A, Rs 264

Last Answer : Answer: E New ratio = 1/2 : 1/4 : 1/7 = 14 : 7 : 4 So both ratio suggests that C has not gained any money, rather he has lose the money. For both ratio find the shares of A and B With ratio 2 : 4 : 7 ... [7/(14+7+4)] * 650 = 182 B has also lose the money, A gain the money and = 364 - 100 = 264

The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Description : The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Last Answer : Answer: A A/B = 15/16 and B/C = 17*18 So A : B : C = 15*17 : 16*17 : 16*18 = 255 : 272 : 288 So C’s salary = [288/(255+272+288)] * 1,87,450= Rs 66,240