The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be as old as the present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be as old as the present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these
by

1 Answer

Answer :

Answer: B

Let their ages 8 years ago be 2x, 3x, 7x, and 8x.

Their ages now 2x+8, 3x+8, 7x+8, 8x+8.

According to the question,

=2x+8+3x+8+7x+8+8x+8=172

20x+32=172 =>x=140/20=7

Present age of Nishu=2×7+8=22 years

Present age of mother=7×7+8=57 years

Hence, required years (57-22)=35 years
by

Related questions

15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Last Answer : C

Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by ‘A’ is Rs 40,000, out of a total annual profit of Rs 33,000, C’s share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Description : Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by A' is Rs 40,000, out of a total annual ... share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Last Answer : Answer: A Sum invested by A , B and C is 5 * 12:7 * 12:6 * 6 + 3 * 6 or 60 : 84 : 54 or 10 : 14 : 9 :: Share of C = ( 9 / 33 ) * 33000 = Rs. 9000

Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)

12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Description : 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Last Answer : C Let M's age 12 years ago = x years. Then, N's age 12 years ago = 2x years. (x + 12) / (2x+ l2) = 4/5 => x = 4. So, the total of their present ages =(x + 12 + 2x + 12) = (3x + 24) = 36 years.

The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Last Answer : Answer: A

Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20

The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35 

Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)

One year ago the ratio between Laxman and Gopal salary was 3:4. The individual ratios between their last year’s and this year’s salary are 4:5 and 2:3 respectively. At present the total of their salary is Rs.4160. The salary of laxman now is? a) 1800 b) 1500 c) 2160 d) 2560 e) 1600

Description : One year ago the ratio between Laxman and Gopal salary was 3:4. The individual ratios between their last year’s and this year’s salary are 4:5 and 2:3 respectively. At present the total of their salary is Rs.4160. The salary of laxman now is? a) 1800 b) 1500 c) 2160 d) 2560 e) 1600

Last Answer : Answer: E Let the salaries of Laxman and Gopal one year before be x1 ,y1 respectively. ∴ x1/y1 = 3/4 ......(1) x2 + y2 = 4160 .....(2)  From equations (1) and (2) x2 = Rs. 1600.

Ramana divides two sums of money among his four sons Ganesh, Mahesh, Anil and Sunil. The first sum is divided in the ratio 4: 3: 2: 1 and second in the ratio 5: 6: 7: 8. If the second sum is twice the first, the largest total is received by a) Ganesh b) Mahesh c) Anil d) Sunil e) Both Ganesh and Mahesh

Description : Ramana divides two sums of money among his four sons Ganesh, Mahesh, Anil and Sunil. The first sum is divided in the ratio 4: 3: 2: 1 and second in the ratio 5: 6: 7: 8. If the second sum is ... first, the largest total is received by a) Ganesh b) Mahesh c) Anil d) Sunil e) Both Ganesh and Mahesh

Last Answer : Answer: A Let the first sum be 4x, 3x, 2x, x Second sum be 5y, 6y, 7y, 8y The second sum is twice the first sum 26y = 20x; 13y = 10x Take y=10 x= 13 G:M:A:S 4X+5Y: 3X+6Y: 2X +7Y: X+8Y 102: 99: 96: 93

The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Description : The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Last Answer : Answer: C a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number = (7/35)*210 = 42

A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Description :  A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Last Answer : Answer: B 25 paise = 25/100 Rs, 50 paise = 50/100 Rs So value ratio of these coins become = 3*(25/100) : 4*(50/100) : 6*(1) = 3/4 : 2 : 6 = 3 : 8 : 24 So 25 paise coins value= [3/(3+8+24)] * ... 100/50) = 144 So 1 paise coins value= [24/(3+8+24)] * 315 = Rs 216, so coins = 215 * (100/100) = 216

The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17

Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17 

Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.

The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)

Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Description : Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Last Answer : D Let their ages 8 years ago is4x, 5x and 6x years.  4x+8+5x + 8 + 6x + 8= 99 hence x= 5 Q’s present age = (5x + 8)  =33 years

One year ago, the ratio between A's and B's salary was 4:5. The ratio of their individual salaries of last year and present year are 3:5 and 2:3 respectively. If their total salaries for the present year is Rs 6800, the present salary of A is A) Rs 4080 B) Rs 3200 C) Rs 4533.40 D) Rs 2720 E) NONE

Description : One year ago, the ratio between A's and B's salary was 4:5. The ratio of their individual salaries of last year and present year are 3:5 and 2:3 respectively. If their total salaries for the present year is Rs 6800, the present salary of A is A) Rs 4080 B) Rs 3200 C) Rs 4533.40 D) Rs 2720 E) NONE

Last Answer : Answer: B Given, the Ratio of A's last year and present year salary = 3:5. Let salary be 3x and 5x respectively. Also, the Ratio of B's in last year and present year salary = 2:3 Let salary be 2y and 3y ... i) and (ii), we get :- y=1200 and x=640. Hence, A's present salary is 5x=5 640=3200.

The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.

Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Description : Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Last Answer : B Let 8 years ago the age of Micky and Donald be 6x and 5x resp. then, ((6x+8)+12) / ((5x+8)+12) = 11/10 10(6x+20) = 11(5x+20) 5x = 20 => x = 4 So Donald age is (5x+8) = 28

The ratio of the incomes of A and B last year was 9 : 13. Ratio of their incomes of last year to this year is 9 : 10 and 13 : 15 respectively. The sum of their present incomes is Rs 50,000. What is the present income of B? A) Rs 32,000 B) Rs 24,000 C) Rs 20,000 D) Rs 30,000 E) None of these

Description : The ratio of the incomes of A and B last year was 9 : 13. Ratio of their incomes of last year to this year is 9 : 10 and 13 : 15 respectively. The sum of their present incomes is Rs 50,000. What is the present income of B? A) Rs 32,000 B) Rs 24,000 C) Rs 20,000 D) Rs 30,000 E) None of these

Last Answer : Answer: D ratio of the incomes of A and B last year was 9x : 13y Now given that ratio of the incomes of A and B last year was 9 : 13. So 9x/13y = 9/13 This gives x = y Total of incomes of A ... = 50,000 This gives x = 2,000 So present income of B = 15y = 15x = 15*2000 = 30,000

A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these

Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these

Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37  x = 7 Age of A = 2x + 2 = 16 years Answer: d)

Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)

A working partner gets 25% as his commissions after his commissions paid that is equal to Rs.7500, then what is the total profit ? A) Rs.32,000 B) Rs.30,000 C) Rs.37,500 D) Rs.40,000 E) None of these

Description : A working partner gets 25% as his commissions after his commissions paid that is equal to Rs.7500, then what is the total profit ? A) Rs.32,000 B) Rs.30,000 C) Rs.37,500 D) Rs.40,000 E) None of these

Last Answer : Answer: C X=total profit 25/100*[x-7500] = 7500 x-7500 = 7500*100/25 =30,000 x = 37,500

In Ram nagar Colony, the ratio of school going children to non-school going children is 5 : 4. If in the next year, the number of non-school going children is increased by 20%, making it 35,400 what is the new ratio of school going children to non-school going children? a) 4 : 5 b) 3 : 2 c) 25 : 24 d) 6 : 7 e) None of these

Description :  In Ram nagar Colony, the ratio of school going children to non-school going children is 5 : 4. If in the next year, the number of non-school going children is increased by 20%, making it 35,400 what is the new ratio of school ... children? a) 4 : 5 b) 3 : 2 c) 25 : 24 d) 6 : 7 e) None of these

Last Answer : Answer: C 5 : 4 → 5 : 4.8 → 25 : 24

The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen.Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Description : The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen. Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Last Answer : Answer: A P present age = 33-9 = 24 M = 24 – 9 =15 D – M = 24 D – 15 = 24 D = 24+15 = 39 15:39 = 5:13 X = 13

The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

A person’s age is 150% of what it was 15 years ago, but 76% of what it will be after 15years. What is his present age? A) 39.7 B) 45.8 C) 42.8 D) 37.8

Description : A person’s age is 150% of what it was 15 years ago, but 76% of what it will be after 15years. What is his present age? A) 39.7 B) 45.8 C) 42.8 D) 37.8

Last Answer : B)  let the present age be X yrs then 150% of (X-15)=X; and 76 % of (x+15)= X 150% of (X-15)=76% of(X+15) 3/2(X-15)=19/25(X+15)  X=45.8yrs

One year ago the ratio between rahul salary and rohit salary is 4:5. The ratio between their individual salary of the last year and current year is 2:3 and 3:5 respectively. If the total current salary of rahul and rohit is 4300. Then find the current salary of rahul. a) 1200 b) 1800 c) 2400 d) 3600 e) None of these

Description : One year ago the ratio between rahul salary and rohit salary is 4:5. The ratio between their individual salary of the last year and current year is 2:3 and 3:5 respectively. If the total current salary of rahul ... find the current salary of rahul. a) 1200 b) 1800 c) 2400 d) 3600 e) None of these

Last Answer : Answer: B 4x and 5x is the last year salry of rahul and rohit respectively Rahul last year to rahul current year = 2/3 Rohit last year to rohit current year = 3/5 Current of rahul + current of rohit = 4300 (3/2)*4x + (5/3)*5x = 4300. X = 300. So rahul current DDsalary = 3/2 * 4* 300 = 1800

A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Description : A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Last Answer : Answer: B Sol. Let the number of one-rupee coins, 50-paise coins and 25-paise coins be 2k, 3k and 5k, respectively. ∴ 2k × 1 + 3k × 0.50 + 5k × 0.25 = 114 ⇒ 2k + 1.50k + 1.25k = 114  ⇒ 4.75k = 114 ⇒ k = 24. 50 paise value = 1.5x = 1.5*24 = 36

The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4

Description : The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4

Last Answer :  B At present: Ratio of their ages = 7 : 5. Therefore, 7: 5 will be 7x and 5x. kabil's age 6 years ago = 7x - 6 sahul's age after 6years = 5x + 6 Ratio of kabil's age 6years ago and sahul's age after 6 ... Ratio of sahul's age and kabil's age (7x + 6) / (5x - 6) = 48/24 =2/1 =2:1

The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

Description : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

Last Answer : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present age? A.30 B.35 C.40 D.36 E.None of these

Description : Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present age? A.30 B.35 C.40 D.36 E.None of these

Last Answer : Answer - A (30) Explanation - Let Khush's present age be x years and Sam's present age be y years Then, according to the first condition, x - 10 = 3(y - 10) or, x - 3y = -20 ..(1) Now. Khush's age ... (1) and (2), we get x = 70 and y = 30 Khush's age = 70 years and Sam's age = 30 years

if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Description : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Last Answer : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be ... years from now? A. 82 B. 97 C. 75 D. 94

Nandhu is 80years old and Nalini is 90 years old. How many years ago was the ratio of their ages 8 : 10? a) 40 years b) 35 years c) 20 years d) 25 years

Description : Nandhu is 80years old and Nalini is 90 years old. How many years ago was the ratio of their ages 8 : 10? a) 40 years b) 35 years c) 20 years d) 25 years

Last Answer : A Let us assume x years ago At present: Nandhu is 80 years and Nalini is 90 years x years ago: Nandhu's age = (80 - x) and Nalini's age = (90 - x) Ratio of their ages x years ago was 8 : 10 ... 800-10x =720-8x 2x=80 x=40 Therefore, 40 years ago, the ratio of their ages was 8:10

Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Description : Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Last Answer : A At age of son be x and as father's age is 9 times the age of her son, let it be 9x, nine years ago. At present: father's age will be (9x + 30) and son's age will be (x + 30) After 30 years: father's age ... x = 20 We are asked to find the present ratio. (9x + 30) : (x + 30) = 210 : 50 = 21:5

After replacing an old person by a new person, it was found that the average age of five persons of a assembly is the same as it was 6 years ago. What is the difference between the ages of the replaced and the new persons? A) 24 B) 36 C) 30 D) 15

Description : After replacing an old person by a new person, it was found that the average age of five persons of a assembly is the same as it was 6 years ago. What is the difference between the ages of the replaced and the new persons? A) 24 B) 36 C) 30 D) 15 

Last Answer : C) Let the ages of the five persons at present be a, b, c, d & e years. And the age of the new persons be f years. So the new average of five members' age = (a + b + c + d + f)/5 - ... - e + f) = 5x Solving e - f = 30 years. Thus the difference of ages between replaced and new person = 30years.

The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Description : The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

The incomes of A and B are in the ratio 1 : 2 and their expenditures are in the ratio 2 : 5. If A saves Rs 20,000 and B saves Rs 35,000, what is the total income of A and B? A) Rs 30,000 B) Rs 70,000 C) Rs 90,000 D) Rs 60,000 E) Rs 80,000

Description : The incomes of A and B are in the ratio 1 : 2 and their expenditures are in the ratio 2 : 5. If A saves Rs 20,000 and B saves Rs 35,000, what is the total income of A and B? A) Rs 30,000 B) Rs 70,000 C) Rs 90,000 D) Rs 60,000 E) Rs 80,000

Last Answer : Answer: C Income of A = x, of B = 2x Expenditure of A = 2y, of B = 5y Savings is (income – expenditure). So x – 2y = 20,000 2x – 5y = 35,000 Solve the equations, x = 30,000 So total = x+2x = 3x = 3*30,000 = 90,000

The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)

40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)

The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Description : The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Last Answer : Answer: A a^2 + b^2 + c^2 = 5000 a:b:c = 3:4:5 50x^2 = 5000. X = 10. 5x – 3x = 2*10 = 20

The ratio of income of X and Y is 4:3. The sum of their expenditure is Rs.12,000 and the amount of savings is X is equal to the amount of expenditure of Y.What is the salary of Y? A) 9000 B) 7000 C) 12000 D) 15000 E) None of these

Description : The ratio of income of X and Y is 4:3. The sum of their expenditure is Rs.12,000 and the amount of savings is X is equal to the amount of expenditure of Y.What is the salary of Y? A) 9000 B) 7000 C) 12000 D) 15000 E) None of these

Last Answer : Answer: A X’s saving = Expenditure of Y = S 4x-S + S = 12000 X = 3000 3x =3*3000 = 9000

The sum of the three number is 68.If the ratio of the first to second is 3:2 and that of the second to the third is 5:3 , then the second number is approximately A) 21 B) 22 C) 23 D) 24 E) None of these

Description : The sum of the three number is 68.If the ratio of the first to second is 3:2 and that of the second to the third is 5:3 , then the second number is approximately A) 21 B) 22 C) 23 D) 24 E) None of these 

Last Answer : Answer: B A: B = 3:2 B:C = 5 : 3 B:C =(5×[2/5]) : (3×[2/5])= 2: (6/5) A:B:C = 3:2:(6/5) = 15:10:6 Second number = (10/31)×68 = 21.9 = 22

The ratio of marks obtained by Vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted. A) 150 B) 200 C) 400 D) 450 E) None

Description : The ratio of marks obtained by Vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted. A) 150 B) 200 C) 400 D) 450 E) None

Last Answer : Answer: B The sum of the marks=6x+5x=11x But the sum of the marks is given as 275=11x. We get x=25x=25 therefore, Vinod's marks is 6x=1506x=150 and Basu's marks = 5x=125. ... Therefore, if their combined average of their percentage is 137.5 then the total marks would be 137.568.75 100=200

At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60

Description : At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60

Last Answer : 45

Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years

Description : Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years

Last Answer : B We are given that age ratio of tom and ram = 5 : 6 Tom's age = 5x and Ram's age = 6x 3 years ago, their age was 5x and 6x. Hence at present, Tom's age = 5x +3 and Ram's age = 6x +3 After 12years, Tom's ... = 6 / 7 7 (5x + 15) = 6 (6x + 15) X = 15 Ram's present age = (6x + 3) = 93years 

An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio. a) increases 20:21 b) decreases 21:20 c) increases 21:22 d) decreases 22:21 e) None of these

Description : An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio. a) increases 20:21 b) decreases 21:20 c) increases 21:22 d) decreases 22:21 e) None of these

Last Answer : Answer: B Let initial employees be 7x and then 4x similarly initial wages be 3y and then 5y so total wage = 21xy initially and then 20xy so wages decreases and ratio = 21:20