What has 5 faces, 8 edges,5 vertices?

What has 5 faces, 8 edges,5 vertices?
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triangular prism
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In STL files Euler’s rule for solids can be written as a.No. of faces – No. of edges + No. of vertices = 3 x No. of bodies b.No. of faces – No. of edges + No. of vertices = No. of bodies c.No. of faces – No. of edges + No. of vertices = 2 x No. of bodies d.No. of faces – No. of edges + No. of vertices = 4 x No. of bodies

Description : In STL files Euler’s rule for solids can be written as a.No. of faces †No. of edges + No. of vertices = 3 x No. of bodies b.No. of faces †No. of edges + No. of vertices = No. of bodies c.No. of ... = 2 x No. of bodies d.No. of faces †No. of edges + No. of vertices = 4 x No. of bodies

Last Answer : c.No. of faces – No. of edges + No. of vertices = 2 x No. of bodies

How many edges and vertices are there for an octahedron which is a polyhedron with eight congruent triangular faces?

Description : How many edges and vertices are there for an octahedron which is a polyhedron with eight congruent triangular faces?

Last Answer : Need answer

What shape has 0 vertices 2 edges 2 faces and 1 curved surface?

Description : What shape has 0 vertices 2 edges 2 faces and 1 curved surface?

Last Answer : Feel Free to Answer

What shape has 2 flat faces 1 curved face 2 edges 0 vertices?

Description : What shape has 2 flat faces 1 curved face 2 edges 0 vertices?

Last Answer : A cylinder would fit the given description

What shape has 8 congruent equilateral triangles as faces and 6 vertices?

Description : What shape has 8 congruent equilateral triangles as faces and 6 vertices?

Last Answer : The Platonic solid known as an octahedron would fit the givendescription

How many face edges and vertices does a rectangular prism have?

Description : How many face edges and vertices does a rectangular prism have?

Last Answer : A rectangular prism has 6 faces, 12 edges and 8 vertices

For general graph, how one can get rid of repeated states? a) By maintaining a list of visited vertices b) By maintaining a list of traversed edges c) By maintaining a list of non-visited vertices d) By maintaining a list of non-traversed edges

Description : For general graph, how one can get rid of repeated states? a) By maintaining a list of visited vertices b) By maintaining a list of traversed edges c) By maintaining a list of non-visited vertices d) By maintaining a list of non-traversed edges

Last Answer : a) By maintaining a list of visited vertices

A graph is a collection of nodes, called ………. And line segments called arcs or ……….. that connect pair of nodes. A) vertices, edges B) edges, vertices C) vertices, paths D) graph node, edges

Description : A graph is a collection of nodes, called ………. And line segments called arcs or ……….. that connect pair of nodes. A) vertices, edges B) edges, vertices C) vertices, paths D) graph node, edges

Last Answer : A) vertices, edges

A graph is said to be ……………… if the vertices can be split into two sets V1 and V2 such there are no edges between two vertices of V1 or two vertices of V2. A) Partite B) Bipartite C) Rooted D) Bisects

Description : A graph is said to be ……………… if the vertices can be split into two sets V1 and V2 such there are no edges between two vertices of V1 or two vertices of V2. A) Partite B) Bipartite C) Rooted D) Bisects

Last Answer : B) Bipartite

How many edges must be removed to produce the spanning forest of a graph with N vertices, M edges and C connected components? (A) M+N-C (B) M-N-C (C) M-N+C (D) M+N+C

Description : How many edges must be removed to produce the spanning forest of a graph with N vertices, M edges and C connected components? (A) M+N-C (B) M-N-C (C) M-N+C (D) M+N+C

Last Answer : (C) M-N+C

Cyclometric complexity of a flow graph G with n vertices and e edges is (A) V(G) = e+n-2 (B) V(G) = e-n+2 (C) V(G) = e+n+2 (D) V(G) = e-n-2

Description : Cyclometric complexity of a flow graph G with n vertices and e edges is (A) V(G) = e+n-2 (B) V(G) = e-n+2 (C) V(G) = e+n+2 (D) V(G) = e-n-2

Last Answer : (B) V(G) = e-n+2

If the no of faces and vertex in a solid are 7 and 10 respectively the no of edges are?

Description : If the no of faces and vertex in a solid are 7 and 10 respectively the no of edges are?

Last Answer : A prism with an n-sided base will have 2n vertices, n + 2 faces,and 3n edges.15 edges

What is 1 curved face 2 circled faces 2 curved edges?

Description : What is 1 curved face 2 circled faces 2 curved edges?

Last Answer : A cylinder is one possible answer.

How many faces and edges does an icosahedron have?

Description : How many faces and edges does an icosahedron have?

Last Answer : It has 20 faces. The number of edges will depend on the exactconfiguration of the shape. For example, a icosahedron in the formof a prism, with 18-gons as bases, will have 54 edges. On the ... have 38 edges. A bipyramidwith a decagon base will have 30 edges. There are very many morepossible shapes.

What shape has 2 different sets of congruent faces and 12 edges?

Description : What shape has 2 different sets of congruent faces and 12 edges?

Last Answer : A cuboid could fit the given description which as 12 edges, 6faces and 8 vertices

Coordinate of â–¡ABCD is WCS are: lowermost corner A(2,2) & diagonal corner are C(8,6). W.r.t MCS. The coordinates of origin of WCS system are (5,4). If the axes of WCS are at 600 in CCW w.r.t. the axes of MCS. Find new vertices of point A in MCS. a.(4.268, 6.732) b.(5.268, 6.732) c.(4.268, 4.732) d.(6.268, 4.732)

Description : Coordinate of â- ABCD is WCS are: lowermost corner A(2,2) & diagonal corner are C(8,6). W.r.t MCS. The coordinates of origin of WCS system are (5,4). If the axes of WCS are at 600 in CCW w.r.t. the axes of MCS. Find new ... in MCS. a.(4.268, 6.732) b.(5.268, 6.732) c.(4.268, 4.732) d.(6.268, 4.732)

Last Answer : a.(4.268, 6.732)

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : NEED ANSWER

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : This answer was deleted by our moderators...

A (5,-1) , B (-3,-2) and C (-1,8) are the vertices of ∆ ABC . The median from A meets BC at D ,then the coordinates of the point D are: (a) (-4,6) (b) (2,7/2) (c) (1,-3/2) (d) (-2,3)

Description : A (5,-1) , B (-3,-2) and C (-1,8) are the vertices of ∆ ABC . The median from A meets BC at D ,then the coordinates of the point D are: (a) (-4,6) (b) (2,7/2) (c) (1,-3/2) (d) (-2,3)

Last Answer : (d) (-2,3)

In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram (ii) quadrilateral BEFC is a parallelogram (iii) AD || CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Description : In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram ( ... CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Last Answer : . Solution: (i) AB = DE and AB || DE (Given) Two opposite sides of a quadrilateral are equal and parallel to each other. Thus, quadrilateral ABED is a parallelogram (ii) Again BC = EF and BC || EF ... (Given) BC = EF (Given) AC = DF (Opposite sides of a parallelogram) , ΔABC ≅ ΔDEF [SSS congruency]

ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (see Fig. 8.21). Show that (i) ΔAPB ≅ ΔCQD (ii) AP = CQ -Maths 9th

Description : ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (see Fig. 8.21). Show that (i) ΔAPB ≅ ΔCQD (ii) AP = CQ -Maths 9th

Last Answer : Q Solution: (i) In ΔAPB and ΔCQD, ∠ABP = ∠CDQ (Alternate interior angles) ∠APB = ∠CQD (= 90o as AP and CQ are perpendiculars) AB = CD (ABCD is a parallelogram) , ΔAPB ≅ ΔCQD [AAS congruency] (ii) As ΔAPB ≅ ΔCQD. , AP = CQ [CPCT]

Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Description : Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Last Answer : Let A(1, 2), B(0, -1) and C(2, -1) be the mid-points of the sides PQ, QR and RP of the triangle PQR. Let the co-ordinates of P, Q and R be (x1, y1), (x2, y2) and (x3 , y3) respectively. Then, by the mid- ... ordinates of centroid of ΔPQR = \(\bigg(rac{3+(-1)+1}{3},rac{2+2+(-4)}{3}\bigg)\) = (1, 0).

The coordinates of the circumcentre of the triangle whose vertices are (8, 6), (8, –2) and (2, –2). -Maths 9th

Description : The coordinates of the circumcentre of the triangle whose vertices are (8, 6), (8, –2) and (2, –2). -Maths 9th

Last Answer : (a) bx = ayGiven, AM = BM ⇒ AM2 = BM2 ⇒ [x – (a + b)]2 + [y – (b – a)]2 = [x – (a – b)]2 + (y –(a + b))2

How many coins 0.75 cm in diameter and 1/8 cm thick must be malted down to form a rectangular solid whose edges are 5 cm. 4 cm and 3 cm? a.584 b.1087 c.0.00001745 sec-1 d.1234 e.2174

Description : How many coins 0.75 cm in diameter and 1/8 cm thick must be malted down to form a rectangular solid whose edges are 5 cm. 4 cm and 3 cm? a.584 b.1087 c.0.00001745 sec-1 d.1234 e.2174

Last Answer : b. 1087

Given a flow graph with 10 nodes, 13 edges and one connected components, the number of regions and the number of predicate (decision) nodes in the flow graph will be (A) 4, 5 (B) 5, 4 (C) 3, 1 (D) 13, 8

Description : Given a flow graph with 10 nodes, 13 edges and one connected components, the number of regions and the number of predicate (decision) nodes in the flow graph will be (A) 4, 5 (B) 5, 4 (C) 3, 1 (D) 13, 8

Last Answer : (B) 5, 4

The edges of a triangular board are 6 cm, 8 cm and 10 cm. -Maths 9th

Description : The edges of a triangular board are 6 cm, 8 cm and 10 cm. -Maths 9th

Last Answer : s=2a+b+c​=26+8+10​=12 By Heron's formula, Area of the triangle =s(s−a)(s−b)(s−c)​=12(12−6)(12−8)(12−10)​=12(6)(4)(2)​=24cm2 Cost of painting =9×24 paise =216 paise = Rs. 2.16.

The edges of a triangular board are 6 cm, 8 cm and 10 cm. -Maths 9th

Description : The edges of a triangular board are 6 cm, 8 cm and 10 cm. -Maths 9th

Last Answer : s=2a+b+c​=26+8+10​=12 By Heron's formula, Area of the triangle =s(s−a)(s−b)(s−c)​=12(12−6)(12−8)(12−10)​=12(6)(4)(2)​=24cm2 Cost of painting =9×24 paise =216 paise = Rs. 2.16.

Rotor shaft of a large electric motor supported between short bearings at both ends shows a deflection of 1.8 mm in middle of motor. Assuming rotor to be perfectly balanced and supported at knife edges at both ends, likely critical speed (rpm) of shaft isA 350 B 4430 C 705 D 2810

Description : Rotor shaft of a large electric motor supported between short bearings at both ends shows a deflection of 1.8 mm in middle of motor. Assuming rotor to be perfectly balanced and supported at knife edges at both ends, likely critical speed (rpm) of shaft isA 350 B 4430 C 705 D 2810

Last Answer : C 705

A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 17. Two faces measuring 4 cm x 1 cm are coloured in black. 18. Two faces measuring 6 cm x 1 cm are coloured in red. 19. Two faces measuring 6 cm x 4 cm are coloured in green. 20. The block is divided into 6 equal cubes of side 1 cm (from 6 cm side), 4 equal cubes of side 1 cm(from 4 cm side). How many cubes will have green colour on two sides and rest of the four sides having no colour ? (a)12 (b)10 (c)8 (d)4

Description : A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 17. Two faces measuring 4 cm x 1 cm are coloured in black. 18. Two faces measuring 6 cm x 1 cm are coloured in red. 19. Two faces ... colour on two sides and rest of the four sides having no colour ? (a)12 (b)10 (c)8 (d)4

Last Answer : Answer key : (c)

A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 12. Two faces measuring 4 cm x 1 cm are coloured in black. 13. Two faces measuring 6 cm x 1 cm are coloured in red. 14. Two faces measuring 6 cm x 4 cm are coloured in green. 15. The block is divided into 6 equal cubes of side 1 cm (from 6 cm side), 4 equal cubes of side 1 cm(from 4 cm side). How many cubes will have 4 coloured sides and two non-coloured sides ? (a)8 (b)4 (c)16 (d)10

Description : A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 12. Two faces measuring 4 cm x 1 cm are coloured in black. 13. Two faces measuring 6 cm x 1 cm are coloured in red. 14. Two ... How many cubes will have 4 coloured sides and two non-coloured sides ? (a)8 (b)4 (c)16 (d)10

Last Answer : Answer key : (b)

A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 7. Two faces measuring 4 cm x 1 cm are coloured in black. 8. Two faces measuring 6 cm x 1 cm are coloured in red. 9. Two faces measuring 6 cm x 4 cm are coloured in green. 10. The block is divided into 6 equal cubes of side 1 cm (from 6 cm side), 4 equal cubes of side 1 cm(from 4 cm side). How many small cubes will be formed? (a)6 (b)12 (c)16 (d)24

Description : A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 7. Two faces measuring 4 cm x 1 cm are coloured in black. 8. Two faces measuring 6 cm x 1 cm are coloured in red. 9. Two faces measuring ... 1 cm(from 4 cm side). How many small cubes will be formed? (a)6 (b)12 (c)16 (d)24

Last Answer : Answer key : (d)

Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Description : Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Last Answer : The graph obtained by plotting the points A, B and C and D is given below. Take a point C on the graph such that ABCD is a square i.e., all sides AB, BC, CD, and AD are equal. So, abscissa of C should be ... of C should be equal to ordinate of D i.e., -4. Hence, the coordinates of C are (-2, - 4).

Write the coordinates of the vertices of a rectangle whose length and breadth are 5 and 3 units respectively, -Maths 9th

Description : Write the coordinates of the vertices of a rectangle whose length and breadth are 5 and 3 units respectively, -Maths 9th

Last Answer : Given, length of a rectangle = 5 units and breadth of a rectangle = 3 units One vertex is at origin i.e., (0, 0) and one of the other vertices lies in III quadrant. So, the length of the rectangle is 5 ... negative,direction of y-axis and then vertex is C(0, -3). The fourth vertex B is (-5, - 3).

Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Description : Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Last Answer : The graph obtained by plotting the points A, B and C and D is given below. Take a point C on the graph such that ABCD is a square i.e., all sides AB, BC, CD, and AD are equal. So, abscissa of C should be ... of C should be equal to ordinate of D i.e., -4. Hence, the coordinates of C are (-2, - 4).

Write the coordinates of the vertices of a rectangle whose length and breadth are 5 and 3 units respectively, -Maths 9th

Description : Write the coordinates of the vertices of a rectangle whose length and breadth are 5 and 3 units respectively, -Maths 9th

Last Answer : Given, length of a rectangle = 5 units and breadth of a rectangle = 3 units One vertex is at origin i.e., (0, 0) and one of the other vertices lies in III quadrant. So, the length of the rectangle is 5 ... negative,direction of y-axis and then vertex is C(0, -3). The fourth vertex B is (-5, - 3).

Prove that the points (2, –2), (–2, 1) and (5, 2) are the vertices of a right angled triangle. Also find the length of the hypotenuse -Maths 9th

Description : Prove that the points (2, –2), (–2, 1) and (5, 2) are the vertices of a right angled triangle. Also find the length of the hypotenuse -Maths 9th

Last Answer : Let the co-ordinates of any point on the x-axis be (x, 0). Then distance between (x, 0) and (– 4, 8) is 10 units.⇒ \(\sqrt{(x+4)^2+(0-8)^2}\) = 10 ⇒ x2 + 8x + 16 + 64 = 100 ⇒ x2 + 8x – 20 = 0 ⇒ (x + 10) (x – 2) = 0 ⇒ x = –10 or 2 ∴ The required points are (– 10, 0) and (2, 0).

If the points A(a, –11), B(5, b), C(2, 15) and D(1, 1) are the vertices of a parallelogram ABCD, find the values of a and b. -Maths 9th

Description : If the points A(a, –11), B(5, b), C(2, 15) and D(1, 1) are the vertices of a parallelogram ABCD, find the values of a and b. -Maths 9th

Last Answer : Let the x-axis divide the line joining the points (-2, 5) and (1, -9) in the ratio k : 1. Let the point of division on x-axis is P Then,\(x\) = \(rac{k-2}{k+1}\), y = \(rac{-9k+ ... (rac{5}{9}\)k being positive, the division is internal. ∴ x-axis divides the given line internally in the ratio 5 : 9.

Find the area of a triangle whose vertices are (1, 3), (2, 4) and (5, 6). -Maths 9th

Description : Find the area of a triangle whose vertices are (1, 3), (2, 4) and (5, 6). -Maths 9th

Last Answer : Let OR = \(x\) units (i) ΔQOR ~ ΔPAR⇒ \(rac{PA}{AR}\) = \(rac{QO}{OR}\) ⇒ \(rac{6}{x+4}\) = \(rac{3}{x}\)⇒ \(rac{x}{x+4}\) = \(rac{3}{6}\) ⇒ \(rac{x}{x+4}\) = \(rac{1}{2}\)⇒ 2\(x\) = \(x\) + 4 ⇒ \(x ... = \(rac{1}{2}\) (OQ + AP) x OA = \(rac{1}{2}\) (3+6) x 4 = \(rac{1}{2}\) x 9 x 4 = 18 sq. units.

Find the area of the quadrilateral whose vertices are (3, 4), (0, 5), (2, –1) and (3, –2). -Maths 9th

Description : Find the area of the quadrilateral whose vertices are (3, 4), (0, 5), (2, –1) and (3, –2). -Maths 9th

Last Answer : Let A(-36, 7), B(20, 7) and C(0, -8) be the vertices of the given triangle.Then, a = BC = \(\sqrt{(0-20)^2+(-8-7)^2}\) = \(\sqrt{400+225}\) = \(\sqrt{625}\) = 25b = AC =\(\sqrt{(0-36)^2+(-8-7 ... (rac{-900+780}{120},rac{175+273-448}{120}\bigg)\) = \(\bigg(rac{-120}{120},rac{0}{120}\bigg)\) = (-1, 0)

The area of a triangle is 5. Two of its vertices are (2, 1) and (3, –2). The third vertex is (x, y) -Maths 9th

Description : The area of a triangle is 5. Two of its vertices are (2, 1) and (3, –2). The third vertex is (x, y) -Maths 9th

Last Answer : Let A(x1, y1) = (3, 4), B(x2, y2) ≡ (0, 5), C(x3, y3) ≡ (2, -1)and D(x4, y4) ≡ (3, -2) be the vertices of quadrilateral ABCD.Area of quad. ABCD = \(rac{1}{2}\) |{(x1 y2 - x2 y1) + (x2y3 - x3y2) + (x3y4 - x4y3) ... ) + (12 + 6)}|= \(rac{1}{2}\) |{15 - 11 + 0 + 18}| = \(rac{1}{2}\)x 22 = 11 sq. units.

(–2, –1) and (4, –5) are the co-ordinates of vertices B and D respectively of rhombus ABCD. Find the equation of the diagonal AC. -Maths 9th

Description : (–2, –1) and (4, –5) are the co-ordinates of vertices B and D respectively of rhombus ABCD. Find the equation of the diagonal AC. -Maths 9th

Last Answer : 3\(x\) - 2y + 5 = 0 ⇒ -2y = -3\(x\) - 5 ⇒ y = \(rac{3}{2}\)\(x\) + \(rac{5}{2}\)On comparing with y = m\(x\) + c, we see that slope of given line = \(rac{3}{2}\)As the required line is perpendicular to the given line, ... - 4)⇒ 3(y - 5) = - 2\(x\) + 8 ⇒ 3y - 15 = -2\(x\) + 8 ⇒ 3y + 2\(x\) - 23 = 0

Name the quadrilateral ABCD, the coordinates of whose vertices are A(3, 5), B(1, 1), C(5, 3) and D(7, 7). -Maths 9th

Description : Name the quadrilateral ABCD, the coordinates of whose vertices are A(3, 5), B(1, 1), C(5, 3) and D(7, 7). -Maths 9th

Last Answer : (b) Equilateral, \(2\sqrt3a^2\) sq. unitsLet A(a, a), B(-a, -a) and C \((-\sqrt3a,\sqrt3a)\) be the vertices of ΔABC. Then,AB = \(\sqrt{(a+a)^2+(a+a)^2}\) = \(\sqrt{4a^2+4a^2}\) = \(\sqrt{8a^2}\) = \( ... 4}\) (side)2 = \(rac{\sqrt3}{4}\) x (\(2\sqrt2a\))2= \(rac{\sqrt3}{4}\) x 8a2 = \(2\sqrt3a^2\).

The vertices A(4, 5), B(7, 6), C(4, 3) and D(1, 2) from the quadrilateral ABCD whose special name is -Maths 9th

Description : The vertices A(4, 5), B(7, 6), C(4, 3) and D(1, 2) from the quadrilateral ABCD whose special name is -Maths 9th

Last Answer : (a) (5, 2)Let A(8, 6) , B(8, -2) and C(2, -2) be the vertices of the given triangle and P(x, y) be the circum-centre of this triangle. Then, PA2 = PB2 = PC2 Now, PA2 = PB2 ⇒ (x - 8)2 + (y - 6)2 = (x ... 4 = x2 - 4x + 4 + y2 + 4y + 4 ⇒ 12x = 60 ⇒ x = 5. ∴ Co-ordinates of the circumcentre are (5, 2).

If A(3, 5), B(– 5, – 4), C(7, 10) are the vertices of a parallelogram taken in order, then the co-ordinates of the fourth vertex are: -Maths 9th

Description : If A(3, 5), B(– 5, – 4), C(7, 10) are the vertices of a parallelogram taken in order, then the co-ordinates of the fourth vertex are: -Maths 9th

Last Answer : (c) RhombusCo-ordinates of P are \(\bigg(rac{-1-1}{2},rac{-1+4}{2}\bigg)\)i.e, \(\big(-1,rac{3}{2}\big)\)Co-ordinates of Q are \(\bigg(rac{-1+5}{2},rac{4+4}{2}\bigg)\)i.e, (2, 4)Co-ordinates of R ... \sqrt{(2-2)^2+(4+1)^2}\) = \(\sqrt{25}\) = 5⇒ PR ≠ SQ ⇒ Diagonals are not equal ⇒ PQRS is a rhombus.

The point A(0, 0), B(1, 7) and C(5, 1) are the vertices of a triangle. Find the length of the perpendicular from -Maths 9th

Description : The point A(0, 0), B(1, 7) and C(5, 1) are the vertices of a triangle. Find the length of the perpendicular from -Maths 9th

Last Answer : (b) 3x - y = 0 Given lines are 3x - y - 3 = 0 and 3x - y + 5 = 0. Line parallel to the given lines can be written as 3x - y + c = 0 ...(i) Let us taken a point, say ... 5c + 15 = - 3c + 15 ⇒ 8c = 0 ⇒ c = 0. Substituting c = 0 in (i), the required equation is 3x - y = 0.

The two vertices of a triangle are (2, –1), (3, 2) and the third vertex lies on the line x + y = 5. The area of the triangle is 4 units. -Maths 9th

Description : The two vertices of a triangle are (2, –1), (3, 2) and the third vertex lies on the line x + y = 5. The area of the triangle is 4 units. -Maths 9th

Last Answer : (c) (5, 0) or (1, 4) Let the third vertex of the triangle be P(a, b). Since it lies on the line x + y = 5, a + b = 5 ...(i) Also, given area of triangle formed by the points (2, -1), (3, 2) and (a, b) = 4 ... b) - (-3a + b) = 5 + 15⇒ 4a = 20 ⇒ a = 5 ⇒ b = 0. ∴ The points are (1, 4) and (5, 0).

Find the area of triangle ABC whose vertices are A (-5, 7), B (-4, -5) and C (4, 5). -Maths 9th

Description : Find the area of triangle ABC whose vertices are A (-5, 7), B (-4, -5) and C (4, 5). -Maths 9th

Last Answer : the answer is 56.55u because height is 8.7 base is 13 cm

Find the area of quadrilateral ABCD whose vertices are A (1, 0), B (5, 3), C (2, 7), D ( -2, 4) -Maths 9th

Description : Find the area of quadrilateral ABCD whose vertices are A (1, 0), B (5, 3), C (2, 7), D ( -2, 4) -Maths 9th

Last Answer : answer:

what- Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5), I at(-2, 2), and X at (4, -1), where x > 0.What is the value of x?

Description : what- Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5), I at(-2, 2), and X at (4, -1), where x > 0.What is the value of x?

Last Answer : 4

How do you find the area of a triangle whose vertices have the coordinates ( -1 -1) (-13) and (5 -1)?

Description : How do you find the area of a triangle whose vertices have the coordinates ( -1 -1) (-13) and (5 -1)?

Last Answer : If you mean vertices of: (-1, -1) (-1, 3) and (5, -1) then whenplotted on the Cartesian plane it will form a right angle trianglewith a base of 6 units and a height of 4 units.Area of triangle: 0.5*6*4 = 12 square units