0.5 divide 1.41?

0.5 divide 1.41?
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0.3546
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What will Divide 1681 by 41 using division?

Description : What will Divide 1681 by 41 using division?

Last Answer : 1681 divided by 41 equals 41

Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm2. a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Description : Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm2. a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Last Answer : b) 41.2mm

Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm². a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Description : Calculate the shaft diameter on rigidity basis if torsional moment is 196000N-mm, length of shaft is 1000mm. Permissible angle of twist per meter is 0.5’ and take G=79300N/mm². a) None of the listed b) 41.2mm c) 35.8mm d) 38.8mm

Last Answer : b) 41.2mm

An electric motor drives a windless which hauls up a crate A of weight W = 500 kg up an inclined plane through a height of 10 m in 2 minutes. The torque acting on the windless is 25 kgm and the drum of the windless makes 30 rpm. The efficiency of the inclined plane would be a.0.41 b.0.61 c.0.265 d.0.5305 e.0.66

Description : An electric motor drives a windless which hauls up a crate A of weight W = 500 kg up an inclined plane through a height of 10 m in 2 minutes. The torque acting on the windless is 25 kgm and the drum of the ... The efficiency of the inclined plane would be a.0.41 b.0.61 c.0.265 d.0.5305 e.0.66

Last Answer : d. 0.5305

What is 0.41 repeating in its simplest form?

Description : What is 0.41 repeating in its simplest form?

Last Answer : 41/99

How many feet in 0.41 acres?

Description : How many feet in 0.41 acres?

Last Answer : 17859.6 square feet

What is the molarity of a soloution which contains 22.41 grams of NaCl in 50.0 mL of soloutuon?

Description : What is the molarity of a soloution which contains 22.41 grams of NaCl in 50.0 mL of soloutuon?

Last Answer : 0.4482

Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water

Description : Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water

Last Answer : Answer : C

Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Description : Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Last Answer : Answer : a

The ratio of two specific heats of air is equal to  (a) 0.17  (b) 0.24  (c) 0.1  (d) 1.41  (e) 2.71.

Description : The ratio of two specific heats of air is equal to  (a) 0.17  (b) 0.24  (c) 0.1  (d) 1.41  (e) 2.71.

Last Answer : Answer : d

Specific heat of air at constant pressure is equal to  (a) 0.17  (b) 0.21  (c) 0.24  (d) 1.0  (e) 1.41

Description : Specific heat of air at constant pressure is equal to  (a) 0.17  (b) 0.21  (c) 0.24  (d) 1.0  (e) 1.41

Last Answer : Answer : c

A cage weighing 200 kg is lowered down a mine shaft with uniform acceleration. In the first 5 sec the cage reaches a depth of 20 m. The tension in the cord lowering the cage would be a.836 kg b.167.2 kg c.100 kg d.41.8 kg e.200 kg

Description : A cage weighing 200 kg is lowered down a mine shaft with uniform acceleration. In the first 5 sec the cage reaches a depth of 20 m. The tension in the cord lowering the cage would be a.836 kg b.167.2 kg c.100 kg d.41.8 kg e.200 kg

Last Answer : b. 167.2 kg

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Ans: (5) 41. Which one among the following is a correct sequence of production of coal in the Indian States in descending order ? [NDA 2011] (a) Jharkhand - Madhya Pradesh - West Bengal - Meghalaya (b) West Bengal - Madhya Pradesh - Jharkhand - Meghalaya (c) Jharkhand - West Bengal - Meghalaya - Madhya Pradesh (d) Madhya Pradesh - Jharkhand - West Bengal – Meghalaya

Description : Ans: (5) 41. Which one among the following is a correct sequence of production of coal in the Indian States in descending order ? [NDA 2011] (a) Jharkhand - Madhya Pradesh - West Bengal ... - West Bengal - Meghalaya - Madhya Pradesh (d) Madhya Pradesh - Jharkhand - West Bengal - Meghalaya

Last Answer : Ans: (a)

Find the permittivity of the surface when a wave incident at an angle 60 is reflected by the surface at 45 in air. a) 1.41 b) 3.5 c) 2.2 d) 1.73

Description : Find the permittivity of the surface when a wave incident at an angle 60 is reflected by the surface at 45 in air. a) 1.41 b) 3.5 c) 2.2 d) 1.73

Last Answer : d) 1.73

The staff reading at a distance of 80 m from a level with the bubble at its centre is 1.31 m. When the bubble is moved by 5 divisions out of the centre, the reading is 1.39 m. The angular value of the one division of the bubble, is (A) 28.8 sec (B) 41.25 sec (C) 14.52 sec (D) 25.05

Description : The staff reading at a distance of 80 m from a level with the bubble at its centre is 1.31 m. When the bubble is moved by 5 divisions out of the centre, the reading is 1.39 m. The angular value of the one division of the bubble, is (A) 28.8 sec (B) 41.25 sec (C) 14.52 sec (D) 25.05

Last Answer : (B) 41.25 sec

If a steel rod of 20 mm diameter and 5 metres long elongates by 2.275 mm when subjected to an axial pull of 3000 kg, the stress developed, is (A) 9.5541 kg/cm2 (B) 95.541 kg/cm2 (C) 955.41 kg/cm2 (D) 9554.1 kg/cm

Description : If a steel rod of 20 mm diameter and 5 metres long elongates by 2.275 mm when subjected to an  axial pull of 3000 kg, the stress developed, is  (A) 9.5541 kg/cm2 (B) 95.541 kg/cm2 (C) 955.41 kg/cm2 (D) 9554.1 kg/cm

Last Answer : (C) 955.41 kg/cm2

If a steel rod of 20 mm diameter and 5 metres long elongates by 2.275 mm when subjected to an axial pull of 3000 kg, the stress developed, is (A) 9.5541 kg/cm2 (B) 95.541 kg/cm2 (C) 955.41 kg/cm2 (D) 9554.1 kg/cm

Description : If a steel rod of 20 mm diameter and 5 metres long elongates by 2.275 mm when subjected to an  axial pull of 3000 kg, the stress developed, is  (A) 9.5541 kg/cm2 (B) 95.541 kg/cm2 (C) 955.41 kg/cm2 (D) 9554.1 kg/cm

Last Answer : (C) 955.41 kg/cm2

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)

2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Description : 2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Last Answer : The series is an alternate series, having S 1 = 2 5 14 41; ×3 – 1 in each term S 2 = 3 8 23 69; ×3 – 1 in each term Answer: e)

5, 14 , 41 , 86 , ? (a) 149 (b) 123 (c) 157 (d) 131

Description : 5, 14 , 41 , 86 , ? (a) 149 (b) 123 (c) 157 (d) 131

Last Answer : The difference between the numbers is the multiple of 9 with odd numbers .

3, 5, 9, 15, 25, 41 , 67, ? (a) 108 (b) 52 (c) 110 (d) 111

Description : 3, 5, 9, 15, 25, 41 , 67, ? (a) 108 (b) 52 (c) 110 (d) 111

Last Answer : The difference between the number in this series is the sum of two previous differences .

Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Description : Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Last Answer : (2) 35•71

In the series 1, 5, 13, 25, 41, ……., the next term is (A) 59 (B) 63 (C) 61 (D) 68

Description : In the series 1, 5, 13, 25, 41, ……., the next term is (A) 59 (B) 63 (C) 61 (D) 68

Last Answer : Answer: C 

The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Description : The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

The average height of 50 students in a class is 182 cm. 40 students whose average height is 182.5 cm left the class and 50 students whose average height is 180.5 cm joined the class. Find the average height of the present? A) 180.41 B) 175.5 C) 180.55 D) 185.5

Description : The average height of 50 students in a class is 182 cm. 40 students whose average height is 182.5 cm left the class and 50 students whose average height is 180.5 cm joined the class. Find the average height of the present? A) 180.41 B) 175.5 C) 180.55 D) 185.5

Last Answer : A) The average of the students leaving the class as well as joining the class to be 182 so that the average remains the same. But it is given that the average of the 40 students leaving the class is 182. ... strength of the class. Hence the average of the present class = 182 - 95/60 = 180.5 cm

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

In the following question, select the related number from the given alternatives. 41:5::23:?

Description : In the following question, select the related number from the given alternatives.  41:5::23:?  Options: 1)5 2)3 3)8 4)9 

Last Answer : Correct Answer: 5 

The Jelly below me_Part 41?

Description : The Jelly below me_Part 41?

Last Answer : TJBM can see this line of questions going on forever

Why haven't we been to the moon in 41 years?

Description : Why haven't we been to the moon in 41 years?

Last Answer : Personally, I think there are far too many issues for our development here to be concerned with expending resources on lunar landings. When it’s more necessary or productive, we’ll concentrate on it (although I would like to know what the deal with the wet parts of the moon actually are).

Two forces of 6 and 8 kg act at right angles to each other, the resultant force will be a.100 b.28 c.41 d.14 e.10

Description : Two forces of 6 and 8 kg act at right angles to each other, the resultant force will be a.100 b.28 c.41 d.14 e.10

Last Answer : e. 10

41. What was the meaning for liberalisation in early nineteenth century in Europe? -SST 10th

Description : 41. What was the meaning for liberalisation in early nineteenth century in Europe? -SST 10th

Last Answer : Liberalism in the 19th century. As an ideology and in practice liberalism became the preeminent reform movement in Europe during the 19th century.

What did the Atlantic Charter (14-8-41) aim at? -SST 10th

Description : What did the Atlantic Charter (14-8-41) aim at? -SST 10th

Last Answer : The Atlantic Charter aimed at: (i) Maintaining international peace and security. (ii) Encouraging international co-operation and friendly relations in social, economic and cultural spheres. (iii) ... the Right to Equality, self determination and Right to make their own Constitution and Government.

State briefly the terms of Atlantic Charter of dated 14-8-41. -SST 10th

Description : State briefly the terms of Atlantic Charter of dated 14-8-41. -SST 10th

Last Answer : The terms agreed upon by President Roosevelt and Prime Minister Churchill were: (i) No territorial expansion and territorial changes against the wishes of the people. (ii) Recognition of the right of ... peace, giving up of use of force, peaceful settlement of disputes, without resorting to war.

Question 41 : Who brought the River goddess Ganga to Earth from the heavens -Mythology

Description : Question 41 : Who brought the River goddess Ganga to Earth from the heavens -Mythology

Last Answer : NEED ANSWER

Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Description : Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Last Answer : Here's ur answer Hope it has helped u..

Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Description : Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Last Answer : Here's ur answer Hope it has helped u..

In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Description : In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Last Answer : NEED ANSWER

In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Description : In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Last Answer : Median will be a good representative of the data, because 1.each value occurs once. 2.the data is influenced by extreme values.

The sides of a triangular field are 41 m, 40 m and 9 m. -Maths 9th

Description : The sides of a triangular field are 41 m, 40 m and 9 m. -Maths 9th

Last Answer : Let a = 41m, b = 40 m, c = 9 m. s = (a + b + c)/2 = (41 + 40 +9)/2 = 90/2 ⇒ s = 45 m Area of the triangular field = root under( √s(s - a)(s - b)(s -c)) = root under( ... x 5 x 36 ) = 180 m2 = 1800000 cm2 Number of rose beds = Total area / Area needed for one rose bed = 1800000/900 = 2000

25 add what number equals 41?

Description : 25 add what number equals 41?

Last Answer : 66

Maria, Ivan, Leah, Julie, and Scott measured each other’s heights for health class The heights are 42 39 41, 37 and 39 inches Julie is 2 inches shorter than Leah Maria is 1 inch shorter than Scott and 2 inches taller than Leah How tall is each student?

Description : Maria, Ivan, Leah, Julie, and Scott measured each other’s heights for health class The heights are 42 39 41, 37 and 39 inches Julie is 2 inches shorter than Leah Maria is 1 inch shorter than Scott and 2 inches taller than Leah How tall is each student?

Last Answer : it is 5th grade math

Franco bought some gumballs. He gave away 23 of the gumballs and had 41 left. Write an equation to represent the number of gumballs he bought?

Description : Franco bought some gumballs. He gave away 23 of the gumballs and had 41 left. Write an equation to represent the number of gumballs he bought?

Last Answer : 23 + 41Hope this helps

if 41,232=4.1232 x10m, then m=?

Description : if 41,232=4.1232 x10m, then m=?

Last Answer : To get from 4.1232 to 41232 the decimal point need to move 4 digits to the right, so the power of 10 is 4, ie: 41232 = 4.1232 × 10⁴ → m = 4.

Want to explain verse 41 of Surah Fatir ?

Description : Want to explain verse 41 of Surah Fatir ?

Last Answer : Verse 41 of Surah Fatir: In fact, Allah is the One who made the heavens and the earth steadfast and if they were to be shaken, then none other than Allah has the power to keep them steady. Surely ... yet He is not taking swift action in punishing , it is a sign of His mere tolerance and forgiveness.

Find the range of the data : 14, 15, 16, 18, 19, 25, 30, 41, 26, 16, 13, 18, 20 and 26.

Description : Find the range of the data : 14, 15, 16, 18, 19, 25, 30, 41, 26, 16, 13, 18, 20 and 26.

Last Answer : Find the range of the data : 14, 15, 16, 18, 19, 25, 30, 41, 26, 16, 13, 18, 20 and 26.

The heights of 7 students are given below (in cm) : 120, 126, 132.41, 121.52, 120.35, 132, 125. Find the median height of the students.

Description : The heights of 7 students are given below (in cm) : 120, 126, 132.41, 121.52, 120.35, 132, 125. Find the median height of the students.

Last Answer : The heights of 7 students are given below (in cm) : 120, 126, 132.41, 121.52, 120.35, 132, 125. Find the median height of the students.

`._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus is a)`(62)/(41)` b)`(60)/(41)` c)`(61)/(42

Description : `._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus is a)`(62)/(41)` b)`(60)/(41)` c)`(61)/(42

Last Answer : `._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus ... A. 60/41 B. 61/40 C. 62/41 D. 61/42

What is 533 divided by 41?

Description : What is 533 divided by 41?

Last Answer : 13

Do you have names of all baseball players who wore 41?

Description : Do you have names of all baseball players who wore 41?

Last Answer : Need answer