The content of the accumulator after the execution of the following 8085 assembly language program, is MVI A, 35H MOV B, A STC CMC RAR XRA B (A) 00H (B) 35H (C) EFH (D) 2FH

The content of the accumulator after the execution of the following 8085 assembly language program, is

MVI A, 35H

MOV B, A

STC

CMC

RAR

XRA B

(A) 00H (B) 35H

(C) EFH (D) 2FH
by

1 Answer

Answer :

(D) 2FH
by

Related questions

The content of the accumulator after the execution of the following 8085 assembly language program, is: MVI A, 42H MVI B, 05H UGC: ADD B DCR B JNZ UGC ADI 25H HLT (A) 82 H (B) 78 H (C) 76 H (D) 47 H

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Last Answer : (C) 76 H

What will be the output at PORT1 if the following program is executed? MVI B, 82H MOV A, B MOV C, A MVI D, 37H OUT PORT1 HLT (A) 37H (B) 82H (C) B9H (D) 00H

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Last Answer : Answer: B Explanation: In 8085 programming, the result of an operation is stored in the accumulator. So output is 82H.

8253, 8257 c) 8257,8251 d)8251,825721.Consider the following set of 8085 instruction.MVI A,82HORA AJP DSPLYXRA ADSPLY:OUT PORT1HLT.The output at PORT1 isa) 00H b) FFH c) 92H d) 11H

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