For AM, fc =500kHz , fm = 5 kHz Determine: (i) Upper and lower sideband frequencies (ii) Bandwidth

1 Answer

Answer :

Given data

fc = 500KHz , fm = 5KHz

USB =fc+fm

USB = 500+5

 =505 KHz.

LSB =fc – fm

LSB = 500 – 5

 =495 KHz

Bandwidth = 2fm .

 = 2* 5 =10 KHz

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