Which of the diagrams below represents the statement If it is an triangle then it has three vertices?

Which of the diagrams below represents the statement If it is an triangle then it has three vertices?
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Figure Athree vertices-> triangle
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If (0, 0) and (2, 0) are the two vertices of a triangle whose centroid is (1, 1), then the area of the triangle is: -Maths 9th

Description : If (0, 0) and (2, 0) are the two vertices of a triangle whose centroid is (1, 1), then the area of the triangle is: -Maths 9th

Last Answer : (b) \(\bigg(rac{2\sqrt{13}+20\sqrt2}{\sqrt{13}+\sqrt{17}+5\sqrt2},rac{8\sqrt{13}-6\sqrt{17}}{\sqrt{13}+\sqrt{17}+5\sqrt2}\bigg)\)Let A(x1, y1), B(x2, y2), C(x3, y3) be the vertices of ΔABC the ... +6)^2}\) = \(\sqrt{4+196}\) = \(\sqrt{200}=10\sqrt{2}\)∴ Co-ordinates of incentre of Δ ABC are

If A (-2, 4), B (0, 0) and C (4, 2) are the vertices of triangle ABC, then find the length of the median through the vertex A. -Maths 9th

Description : If A (-2, 4), B (0, 0) and C (4, 2) are the vertices of triangle ABC, then find the length of the median through the vertex A. -Maths 9th

Last Answer : D=slid ht of BC D≅(20+4​,20+2​) =(2,1) ∴ Length of median = Light of AD =root(−2−2)2+(4−1)2​=root42+32​=5 hope it helps thank u

If A(5,2), B(2,-2) and C(-2,t) are the vertices of a right angled triangle with ∠B = 900 , then the value of t is: (a) -1 (b) 1 (c) -2 (d) 2

Description : If A(5,2), B(2,-2) and C(-2,t) are the vertices of a right angled triangle with ∠B = 900 , then the value of t is: (a) -1 (b) 1 (c) -2 (d) 2

Last Answer : (b) 1

An equilateral triangle is cut from its three vertices to form a regular hexagon. What is the percentage of area wasted? -Maths 9th

Description : An equilateral triangle is cut from its three vertices to form a regular hexagon. What is the percentage of area wasted? -Maths 9th

Last Answer : (c) 33.33%When an equilateral triangle is cut from its three vertices to form a regular hexagon then out of the 9 equilateral triangles that form ΔABC, three triangle, ΔADE, ΔFCG,ΔIHB are cut off and 6 remain in the ... to get the hexagon.∴ Area wasted = \(\bigg(rac{1}{3} imes100\bigg)\)% = 33.33%

Three of the six vertices of a regular hexagon are chosen at random. The probability that the triangle with these vertices is equilateral equals : -Maths 9th

Description : Three of the six vertices of a regular hexagon are chosen at random. The probability that the triangle with these vertices is equilateral equals : -Maths 9th

Last Answer : (c) \(rac{1}{10}\)Let S be the sample space.Then n(S) = Number of triangles formed by selecting any three vertices of 6 vertices of a regular hexagon= 6C3 = \(rac{6 imes5 imes4}{3 imes2}\) = 20.Let A : Event that the ... Required probability = \(rac{n(A)}{n(S)}\) = \(rac{2}{20}\) = \(rac{1}{10}\).

The sum of the three interior angles of a triangle, the vertices of which lie on the surface of the earth, covering a vast area of several hundreds of sq kms, is : (a) Less than 180° (b) Equal to 180° (c) More than 180° but not less than 270° (d) More than 180° but not more than 225°

Description : The sum of the three interior angles of a triangle, the vertices of which lie on the surface of the earth, covering a vast area of several hundreds of sq kms, is : (a) Less than 180° (b) Equal to 180° (c) More than 180° but not less than 270° (d) More than 180° but not more than 225°

Last Answer : (d) More than 180° but not more than 225°

Which of the following venn-diagrams best represents the sets of females, mothers and doctors ?

Description : Which of the following venn-diagrams best represents the sets of females, mothers and doctors ?

Last Answer : Which of the following venn-diagrams best represents the sets of females, mothers and doctors ? A. B. C. D.

The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to -Maths 9th

Description : The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to -Maths 9th

Last Answer : Solution of this question

The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to -Maths 9th

Description : The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to -Maths 9th

Last Answer : Solution of this question

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : NEED ANSWER

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : This answer was deleted by our moderators...

Prove that the points (2, –2), (–2, 1) and (5, 2) are the vertices of a right angled triangle. Also find the length of the hypotenuse -Maths 9th

Description : Prove that the points (2, –2), (–2, 1) and (5, 2) are the vertices of a right angled triangle. Also find the length of the hypotenuse -Maths 9th

Last Answer : Let the co-ordinates of any point on the x-axis be (x, 0). Then distance between (x, 0) and (– 4, 8) is 10 units.⇒ \(\sqrt{(x+4)^2+(0-8)^2}\) = 10 ⇒ x2 + 8x + 16 + 64 = 100 ⇒ x2 + 8x – 20 = 0 ⇒ (x + 10) (x – 2) = 0 ⇒ x = –10 or 2 ∴ The required points are (– 10, 0) and (2, 0).

Prove that the points (1, –1) ((-1/2),(1/2)) and (1, 2) are the vertices of an isosceles triangle. -Maths 9th

Description : Prove that the points (1, –1) ((-1/2),(1/2)) and (1, 2) are the vertices of an isosceles triangle. -Maths 9th

Last Answer : (x, y) is equidistant from the points (2, 1) and (1, –2) ⇒ Distance between (x, y) and (2, 1) = Distance between (x, y) and (1, –2)⇒ \(\sqrt{(x-2)^2+(y-1)^2}\) = \(\sqrt{(x-1)^2+(y+2)^2}\)⇒ x2 – 4x + 4 + y2 – 2y + 1 = x2 – 2x + 1 + y2 + 4y + 4⇒ – 4x + 2x – 2y – 4y = 0 ⇒ –2x – 6y = 0 ⇒ x + 3y = 0

Find the co-ordinates of the circumcentre of the triangle whose vertices are (3, 0), (–1, –6) and (4, –1). Also find its circum-radius. -Maths 9th

Description : Find the co-ordinates of the circumcentre of the triangle whose vertices are (3, 0), (–1, –6) and (4, –1). Also find its circum-radius. -Maths 9th

Last Answer : Let A ≡ (2, - 2), B ≡ (-2, 1), C ≡ (5, 2 ). Then,AB = \(\sqrt{(-2-2)^2+(1+2)^2}\) = \(\sqrt{16+9}\) = \(\sqrt{25}\) = 5BC = \(\sqrt{(5+2)^2+(2-1)^2}\) = \(\sqrt{49+1}\) = \(\sqrt{50}\) = \( ... of ΔABC = \(rac{1}{2}\) x base x height = \(rac{1}{2}\) x AB x AC = \(rac{1}{2}\)x 5 x 5 = 12.5 sq. units.

Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Description : Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Last Answer : Let A(1, 2), B(0, -1) and C(2, -1) be the mid-points of the sides PQ, QR and RP of the triangle PQR. Let the co-ordinates of P, Q and R be (x1, y1), (x2, y2) and (x3 , y3) respectively. Then, by the mid- ... ordinates of centroid of ΔPQR = \(\bigg(rac{3+(-1)+1}{3},rac{2+2+(-4)}{3}\bigg)\) = (1, 0).

Find the area of a triangle whose vertices are (1, 3), (2, 4) and (5, 6). -Maths 9th

Description : Find the area of a triangle whose vertices are (1, 3), (2, 4) and (5, 6). -Maths 9th

Last Answer : Let OR = \(x\) units (i) ΔQOR ~ ΔPAR⇒ \(rac{PA}{AR}\) = \(rac{QO}{OR}\) ⇒ \(rac{6}{x+4}\) = \(rac{3}{x}\)⇒ \(rac{x}{x+4}\) = \(rac{3}{6}\) ⇒ \(rac{x}{x+4}\) = \(rac{1}{2}\)⇒ 2\(x\) = \(x\) + 4 ⇒ \(x ... = \(rac{1}{2}\) (OQ + AP) x OA = \(rac{1}{2}\) (3+6) x 4 = \(rac{1}{2}\) x 9 x 4 = 18 sq. units.

The area of a triangle is 5. Two of its vertices are (2, 1) and (3, –2). The third vertex is (x, y) -Maths 9th

Description : The area of a triangle is 5. Two of its vertices are (2, 1) and (3, –2). The third vertex is (x, y) -Maths 9th

Last Answer : Let A(x1, y1) = (3, 4), B(x2, y2) ≡ (0, 5), C(x3, y3) ≡ (2, -1)and D(x4, y4) ≡ (3, -2) be the vertices of quadrilateral ABCD.Area of quad. ABCD = \(rac{1}{2}\) |{(x1 y2 - x2 y1) + (x2y3 - x3y2) + (x3y4 - x4y3) ... ) + (12 + 6)}|= \(rac{1}{2}\) |{15 - 11 + 0 + 18}| = \(rac{1}{2}\)x 22 = 11 sq. units.

Without using Pythagoras’ theorem, show that the points A (0, 4), B(1, 2) and C(3, 3) are the vertices of a right angle triangle. -Maths 9th

Description : Without using Pythagoras’ theorem, show that the points A (0, 4), B(1, 2) and C(3, 3) are the vertices of a right angle triangle. -Maths 9th

Last Answer : Slope (m) = \(rac{(y_2-y_1)}{(x_2-x_1)}\) = \(rac{6-2}{5-1}\) = \(rac{4}{4}\) = 1Also slope (m) = tan θ, where θ is the inclination of the line to the positive direction of the x-axis in the anticlockwise direction. tan θ = 1 ⇒ θ = tan –11 = 45º.

What is the perimeter of the triangle with the vertices A(–4, 2), B(0, –1) and C(3, 3) ? -Maths 9th

Description : What is the perimeter of the triangle with the vertices A(–4, 2), B(0, –1) and C(3, 3) ? -Maths 9th

Last Answer : The two given lines are ax + by + c1 = 0 and ax + by + c2 = 0. Any line parallel to these two lines and midway between them is ax + by + c = 0 ...(i) Putting x = 0, y = \(-rac{c}{b}\) is ... c1 = c - c2 ⇒ c = \(rac{c_1+c_2}{2}\)∴ Required equation is ax + by + \(rac{c_1+c_2}{2}\) = 0.

The coordinates of the circumcentre of the triangle whose vertices are (8, 6), (8, –2) and (2, –2). -Maths 9th

Description : The coordinates of the circumcentre of the triangle whose vertices are (8, 6), (8, –2) and (2, –2). -Maths 9th

Last Answer : (a) bx = ayGiven, AM = BM ⇒ AM2 = BM2 ⇒ [x – (a + b)]2 + [y – (b – a)]2 = [x – (a – b)]2 + (y –(a + b))2

Let PS be the median of the triangle with vertices P(2, 2), Q(6, –1) and R(7, 3). -Maths 9th

Description : Let PS be the median of the triangle with vertices P(2, 2), Q(6, –1) and R(7, 3). -Maths 9th

Last Answer : (b) a = √2b Let D be the mid-point of BC. Then D ≡ \(\bigg(rac{a+0}{2},rac{0}{2}\bigg)\)i.e. \(\bigg(rac{a}{2},0\bigg)\)Let E be the mid-point of AC, thenE = \(\bigg(rac{a+0}{2},rac{0+b}{2}\bigg)\) = \(\bigg ... \(rac{b}{a}.\)∴ From (i), \(rac{-2b}{a}\) x \(rac{b}{a}\) = -1⇒ 2b2 = a2 ⇒ a = √2 .

The medians AD and BE of the triangle with vertices A(0, b), B(0, 0) and C(a, 0) are mutually perpendicular if -Maths 9th

Description : The medians AD and BE of the triangle with vertices A(0, b), B(0, 0) and C(a, 0) are mutually perpendicular if -Maths 9th

Last Answer : (c) \(rac{b+k}{f+h}\)Let the slope of the lin passing through the points (-k, h) and (b, - f) be m1. Then m1 = \(rac{-f-h}{b+k}\) = \(-\bigg(rac{f+h}{b+k}\bigg)\)\(\bigg[Slope = rac{y_2-y_1}{x_2-x_1}\bigg]\) ... \(-rac{1}{m_1}\)= \(rac{-1}{-\big(rac{f+h}{b+k}\big)}\) = \(\bigg(rac{b+k}{f+h}\bigg)\)

The point A(0, 0), B(1, 7) and C(5, 1) are the vertices of a triangle. Find the length of the perpendicular from -Maths 9th

Description : The point A(0, 0), B(1, 7) and C(5, 1) are the vertices of a triangle. Find the length of the perpendicular from -Maths 9th

Last Answer : (b) 3x - y = 0 Given lines are 3x - y - 3 = 0 and 3x - y + 5 = 0. Line parallel to the given lines can be written as 3x - y + c = 0 ...(i) Let us taken a point, say ... 5c + 15 = - 3c + 15 ⇒ 8c = 0 ⇒ c = 0. Substituting c = 0 in (i), the required equation is 3x - y = 0.

The orthocentre of a triangle whose vertices are (0, 0), (3, 0) and (0, 4) is -Maths 9th

Description : The orthocentre of a triangle whose vertices are (0, 0), (3, 0) and (0, 4) is -Maths 9th

Last Answer : (c) 60ºSince p is the length of perpendicular from origin on the straight line ax + by - p = 0.p = \(rac{|a.0+b.0-p|}{\sqrt{a^2+b^2}}\)⇒ 1 = \(\sqrt{a^2+b^2}\) ⇒ 1 ... 60° + y sin 60° = p Hence required angle is 60°, which is the angle between the perpendicular and the positive direction of x-axis.

The two vertices of a triangle are (2, –1), (3, 2) and the third vertex lies on the line x + y = 5. The area of the triangle is 4 units. -Maths 9th

Description : The two vertices of a triangle are (2, –1), (3, 2) and the third vertex lies on the line x + y = 5. The area of the triangle is 4 units. -Maths 9th

Last Answer : (c) (5, 0) or (1, 4) Let the third vertex of the triangle be P(a, b). Since it lies on the line x + y = 5, a + b = 5 ...(i) Also, given area of triangle formed by the points (2, -1), (3, 2) and (a, b) = 4 ... b) - (-3a + b) = 5 + 15⇒ 4a = 20 ⇒ a = 5 ⇒ b = 0. ∴ The points are (1, 4) and (5, 0).

Find the area of triangle ABC whose vertices are A (-5, 7), B (-4, -5) and C (4, 5). -Maths 9th

Description : Find the area of triangle ABC whose vertices are A (-5, 7), B (-4, -5) and C (4, 5). -Maths 9th

Last Answer : the answer is 56.55u because height is 8.7 base is 13 cm

In the figure, arcs and drawn by taking vertices A, B and C of an equilateral triangle of side 10 cm to intersect the sides BC, CA and AB at their respective mid-points D, E and F. Find the area of teh shaded region. [use π = 3.14] -Maths 10th

Description : In the figure, arcs and drawn by taking vertices A, B and C of an equilateral triangle of side 10 cm to intersect the sides BC, CA and AB at their respective mid-points D, E and F. Find the area of teh shaded region. [use π = 3.14] -Maths 10th

Last Answer : Step-by-step explanation: We have been provided that, Triangle ABC is an Equilateral triangle. Side of triangle is = 10 cm The arcs are drawn from each vertices of the triangle. We get three sectors ... portion is, Remaining area = Area of triangle ABC - Area of all the sectors 39.25cm square

what- A triangle is formed by the intersection of the lines y = 0, y = -3x + 3, and y = 3x + 3.Is the triangle equilateral, isosceles, or scalene Graph the lines on grid paper to find the vertices of the triangle?

Description : what- A triangle is formed by the intersection of the lines y = 0, y = -3x + 3, and y = 3x + 3.Is the triangle equilateral, isosceles, or scalene Graph the lines on grid paper to find the vertices of the triangle?

Last Answer : isosceles

what- Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5), I at(-2, 2), and X at (4, -1), where x > 0.What is the value of x?

Description : what- Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5), I at(-2, 2), and X at (4, -1), where x > 0.What is the value of x?

Last Answer : 4

what- A triangle is formed by the intersection of the lines y = 2x + 4, y = -x – 2, and x = 1.Is the triangle equilateral, isosceles, or scalene Graph the lines on grid paper to find the vertices of the triangle?

Description : what- A triangle is formed by the intersection of the lines y = 2x + 4, y = -x – 2, and x = 1.Is the triangle equilateral, isosceles, or scalene Graph the lines on grid paper to find the vertices of the triangle?

Last Answer : scalene

what- a triangle has vertices at?

Description : what- a triangle has vertices at?

Last Answer : isosceles

How many vertices does a triangle have ?

Last Answer : A triangle has 3 vertices.

What are the angles and area of a triangle with vertices at -3 7 and 2 19 and 10 7 on the Cartesian plane?

Description : What are the angles and area of a triangle with vertices at -3 7 and 2 19 and 10 7 on the Cartesian plane?

Last Answer : The vertices (-3, 7) and (2, 19) and (10, 7) will form anisosceles triangle when plotted on the Cartesian plane with anglesof 67.38 degrees, 56.31 degrees and 56.31 degrees all rounded totwo decimal places and the area of the triangle works out as 78square units.

What is the area of a triangle with vertices at -3 7 and 2 19 and 10 7?

Description : What is the area of a triangle with vertices at -3 7 and 2 19 and 10 7?

Last Answer : By plotting the given vertices and then joining them together onthe Cartesian plane the shape of a isosceles triangle will beformed with an area of 78 square units.

What is the area of a triangle with vertices at -3 7 and 2 19 and 10 7?

Description : What is the area of a triangle with vertices at -3 7 and 2 19 and 10 7?

Last Answer : By plotting the given vertices and then joining them together onthe Cartesian plane the shape of a isosceles triangle will beformed with an area of 78 square units.

How do you find the area of a triangle whose vertices have the coordinates ( -1 -1) (-13) and (5 -1)?

Description : How do you find the area of a triangle whose vertices have the coordinates ( -1 -1) (-13) and (5 -1)?

Last Answer : If you mean vertices of: (-1, -1) (-1, 3) and (5, -1) then whenplotted on the Cartesian plane it will form a right angle trianglewith a base of 6 units and a height of 4 units.Area of triangle: 0.5*6*4 = 12 square units

The points (-4, 0), (4, 0), (0, 3) are the vertices of a: (а) Right triangle (b) Isosceles triangle (c) Equilateral triangle (d) Scalene triangle

Description : The points (-4, 0), (4, 0), (0, 3) are the vertices of a: (а) Right triangle (b) Isosceles triangle (c) Equilateral triangle (d) Scalene triangle

Last Answer : (b) Isosceles triangle

The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is: (a) 12 units (b) 11 units (c) 5units (d) (7 + √5)units

Description : The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is: (a) 12 units (b) 11 units (c) 5units (d) (7 + √5)units

Last Answer : (a) 12 units

Find the area of the triangle whose vertices are 4,3 1,4 and 2,3 .

Description : Find the area of the triangle whose vertices are 4,3 1,4 and 2,3 . 

Last Answer : solution:

As a class, we will complete the Frayer Model below for the word “solid” using words, images, or diagrams?

Description : As a class, we will complete the Frayer Model below for the word “solid” using words, images, or diagrams?

Last Answer : yu hav ben anserd

A solid is shown in the figure below. The vertices ABCDEFGH form a 4 cm × 2 cm × 2 cm cuboid. The segments AI and DI are both of length 5 cm, and points ICGFB are coplanar. What is the height (in cm) of point I from the base rectangle EFGH?

Description : A solid is shown in the figure below. The vertices ABCDEFGH form a 4 cm × 2 cm × 2 cm cuboid. The segments AI and DI are both of length 5 cm, and points ICGFB are coplanar. What is the height (in cm) of point I from the base rectangle EFGH? 

Last Answer : 4.80-4.84

“A diagram speaks more than 1000 words” The statement means that the teacher should (A) use diagrams in teaching. (B) speak more and more in the class. (C) use teaching aids in the class. (D) not speak too, much in the class.

Description : “A diagram speaks more than 1000 words” The statement means that the teacher should (A) use diagrams in teaching. (B) speak more and more in the class. (C) use teaching aids in the class. (D) not speak too, much in the class.

Last Answer : (C) use teaching aids in the class.

An ideal gas is heated at constant volume and then expanded isothermally. Show processes on P-V & T-S diagrams.

Description : An ideal gas is heated at constant volume and then expanded isothermally. Show processes on P-V & T-S diagrams.

Last Answer : Process 1-2 : Constant volume process Process 2-3 : Constant temperature process (Isothermal process)

Erratic operation of the devices represented in the diagrams shown in the illustration could be traced to ____________. EL-0092 A. improper contact at 'R' slip rings or 'S' connections B. a low three-phase voltage supply C. improper contact at 'S' slip rings or 'R' connections D. a high three-phase voltage supply

Description : Erratic operation of the devices represented in the diagrams shown in the illustration could be traced to ____________. EL-0092 A. improper contact at 'R' slip rings or 'S' connections B. a low three- ... . improper contact at 'S' slip rings or 'R' connections D. a high three-phase voltage supply

Last Answer : Answer: A

Which statement is true about the number of vertices of any prism?

Description : Which statement is true about the number of vertices of any prism?

Last Answer : They are an even number, greater than or equal to 6.

The figure below shows three steps (A, B, C) of Polymerase Chain Reaction (PCR). Select the option giving correct identification together with what it represents? A. B. C ds DNA 3 5 5 3 5 3 5 3 5 3 5 3 5 5 3 3 5 3 5 3 Region to be amplified . (a) B - denaturation at a temperature of about 98°C separating the two DNA strands (b) A - denaturation at a temperature of about 50°C (c) C - extension in the presence of heat stable DNA polymerase (d) A - annealing with two sets of primers

Description : The figure below shows three steps (A, B, C) of Polymerase Chain Reaction (PCR). Select the option giving correct identification together with what it represents? A. B. C ds DNA 3 5 5 3 ... - extension in the presence of heat stable DNA polymerase (d) A - annealing with two sets of primers

Last Answer : (c) C - extension in the presence of heat stable DNA polymerase