When h has a value of 12 calculate 5h-2?

When h has a value of 12 calculate 5h-2?
by

1 Answer

Answer :

It is then 5 times 12+(-2) = 58
by

Related questions

When h has a value of 12 calculate 5h-2?

Description : When h has a value of 12 calculate 5h-2?

Last Answer : It is then 5 times 12+(-2) = 58

what is 2abx3ab divided by 5h-6ba?

Description : what is 2abx3ab divided by 5h-6ba?

Last Answer : ur mummy

In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Description : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Last Answer : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. ... will A. 10 J B. 15 J C. 25 J D. 40 J

In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Description : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Last Answer : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. ... (2) A` C. `20sqrt(3) A` D. `12sqrt(6) A`

In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Description : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Last Answer : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. ... ` B. `15sqrt(2) A` C. `10 A` D. `20 A`

What is the term of 5h?

Description : What is the term of 5h?

Last Answer : Need answer

What does 0.5H alert mean on 2008 infinity?

Description : What does 0.5H alert mean on 2008 infinity?

Last Answer : what does alert 0.5H mean on a 2008 infinity ex35

The chemical formula for hydrated copper sulphate is – (a) CuSo4.2H 2 O (b) CuSo4.6H 2 O (c) CuSO 4 .4H 2 O (d) CuSO 4 .5H 2 O

Description : The chemical formula for hydrated copper sulphate is – (a) CuSo4.2H 2 O (b) CuSo4.6H 2 O (c) CuSO 4 .4H 2 O (d) CuSO 4 .5H 2 O

Last Answer : (d) CuSO 4 .5H 2 O

The equivalent inductances of two coils 2H and 5H in series aiding flux with mutual inductance of 3H is a) 10 b) 30 c) 1 d) 13

Description : The equivalent inductances of two coils 2H and 5H in series aiding flux with mutual inductance of 3H is a) 10 b) 30 c) 1 d) 13

Last Answer : d) 13

Find the power of an inductor of 5H and current 4.5A after 2 seconds. a) 25.31 b) 50.62 c) 102.4 d) 204.8

Description : Find the power of an inductor of 5H and current 4.5A after 2 seconds. a) 25.31 b) 50.62 c) 102.4 d) 204.8

Last Answer : a) 25.31

A coil of 500 turns is linked with a flux of 25 mwb, when carries a current of 12.5A. Calculate the value of self-inductance.

Description : A coil of 500 turns is linked with a flux of 25 mwb, when carries a current of 12.5A. Calculate the value of self-inductance.

Last Answer : Ans: Self-Inductance: L = NΦ /I = 500 × 25 × 10-3 / 12.5 = 1 H

An electric bulb of 100 W is used for 8 h per day. Calculate the 'units' of energy consumed in one day by the bulb? -Physics 9th

Description : An electric bulb of 100 W is used for 8 h per day. Calculate the 'units' of energy consumed in one day by the bulb? -Physics 9th

Last Answer : Given : t=6 hrs P=0.06 kW Thus energy consumed per day is: E=Pt=0.06×6=0.36 kWh=0.36 units

For a reversible process at T = 300K, the volume is increased from `V_(i)=1L` to `V_(f)=10L`. Calculate `Delta H` if the process is isothermal -

Description : For a reversible process at T = 300K, the volume is increased from `V_(i)=1L` to `V_(f)=10L`. Calculate `Delta H` if the process is isothermal -

Last Answer : For a reversible process at T = 300K, the volume is increased from `V_(i)=1L` to `V_(f)=10L`. Calculate `Delta H ... kJ B. 4.98 kJ C. 0 D. `-11.47 kJ`

The ionisation energy of `H` is `13.6 eV`. Calculate the ionization energy of `Li^(2+)` ions.

Description : The ionisation energy of `H` is `13.6 eV`. Calculate the ionization energy of `Li^(2+)` ions.

Last Answer : The ionisation energy of `H` is `13.6 eV`. Calculate the ionization energy of `Li^(2+)` ions. A. 13.6 eV B. 27.2 eV C. 40 .8 eV D. 122 .4 eV

Calculate the mass loss in the following: `._(1)^(2)H + ._(1)^(3)H to ._(2)^(4)He + ._(0)^(1)n` given the masses: `._(1)^(2)H = 2.014` amu, `._(1)^(3)

Description : Calculate the mass loss in the following: `._(1)^(2)H + ._(1)^(3)H to ._(2)^(4)He + ._(0)^(1)n` given the masses: `._(1)^(2)H = 2.014` amu, `._(1)^(3)

Last Answer : Calculate the mass loss in the following: `._(1)^(2)H + ._(1)^(3)H to ._(2)^(4)He + ._(0)^(1)n` ... amu A. 0.018amu B. 0.18 amu C. 18 amu D. 1.8 amu

calculate the energy released in the nuclear fusion of isotopes of hydrogen (i) `._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n` (ii) `._(1)^(2

Description : calculate the energy released in the nuclear fusion of isotopes of hydrogen (i) `._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n` (ii) `._(1)^(2

Last Answer : calculate the energy released in the nuclear fusion of isotopes of hydrogen (i) `._(1)^(2)H + ._(1)^(2)H rarr . ... ",._(2)^(4)He = 4.00260,am u,):}`

Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Description : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Last Answer : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Calculate the speed of the electron in the first Bohr orbit given that `h=6.6xx10^(-34) Js, m=9.11xx10^(-31) kg` and `e=1.603xx10^(-19) C`.

Description : Calculate the speed of the electron in the first Bohr orbit given that `h=6.6xx10^(-34) Js, m=9.11xx10^(-31) kg` and `e=1.603xx10^(-19) C`.

Last Answer : Calculate the speed of the electron in the first Bohr orbit given that `h=6.6xx10^(-34) Js, m=9.11xx10^(-31) kg` and `e=1.603xx10^(-19) C`.

How is the h fusion used to calculate the mass of a solid that 1 kj of energy will melt?

Description : How is the h fusion used to calculate the mass of a solid that 1 kj of energy will melt?

Last Answer : What is the answer ?

Calculate the recoverable waste heat (Q, in kCal/hour) from flue gases using the followingparameters: V (flow rate of the substance) 2000 m3/hr r (density of the flue gas): 0.9 kg/m3 Cp (specific heat of the substance): 0.20 kCal/kg oC DT (temperature difference): 120 oC h (recovery factor): 50% a. 21600 b. 43200 c. 25600 d. 34000

Description : Calculate the recoverable waste heat (Q, in kCal/hour) from flue gases using the followingparameters: V (flow rate of the substance) 2000 m3/hr r (density of the flue gas): 0.9 kg/m3 Cp (specific heat ... (temperature difference): 120 oC h (recovery factor): 50% a. 21600 b. 43200 c. 25600 d. 34000

Last Answer : 21600

Calculate the power output in horsepower of an 80-kg man that climbs a flight of stairs 3.8 m high in 4.0 s.  a) 744.8 hp  b) 0.998 hp  c) 746 hp  d) 1.998 hp Formula: Power = Fd/t = mgh/t F = W = mg d = h

Description : Calculate the power output in horsepower of an 80-kg man that climbs a flight of stairs 3.8 m high in 4.0 s.  a) 744.8 hp  b) 0.998 hp  c) 746 hp  d) 1.998 hp Formula: Power = Fd/t = mgh/t F = W = mg d = h

Last Answer : 0.998 hp

Saturated steam at 1 atm is discharged from a turbine at 1200 kg/h. Superheated steam at 300 0C and 1 atm is needed as a feed to a heat exchanger. To produce it, the turbine discharge stream is mixed with superheated steam at 400 0C, 1 atm and specific volume of 3.11 m 3 /kg. Calculate the amount of superheated steam at 300 0C produced and the volumetric flow rate of the 400 0C steam.

Description : Saturated steam at 1 atm is discharged from a turbine at 1200 kg/h. Superheated steam at 300 0C  and 1 atm is needed as a feed to a heat exchanger. To produce it, the turbine discharge ... amount of superheated steam at 300 0C produced and the volumetric flow rate of the  400 0C steam.

Last Answer : Solution 1. Mass balance of water 1200 + m1 = m2 ………………………………………… (1) …………………….1 mark 2. Energy balance (1200 kg/h)(2676 kJ/kg) + m1(3278 kJ/kg)

Opening WDV off the block of assets was Rs 15 lakh. During the year, asset was acquired under this block on 15 June 2017 amounting to rupees 10 lakh. One of the assets falling within the block was sold for rupees 5.5 lakh on 14 January 2018. Rate of depreciation of block is 10%. Calculate the amount of depreciation available during the previous year for the block. e. rupees 1.95 lakh f. rupees 2.5 lakh g. rupees 2.25 lakh h. Rs 1.45 lakh

Description : Opening WDV off the block of assets was Rs 15 lakh. During the year, asset was acquired under this block on 15 June 2017 amounting to rupees 10 lakh. One of the assets falling within the block was sold for rupees 5.5 ... . rupees 1.95 lakh f. rupees 2.5 lakh g. rupees 2.25 lakh h. Rs 1.45 lakh

Last Answer : e. rupees 1.95 lakh

In the formula `A=(1)/(2)d(h_(1)+h-(2))`. Find the value of `h_(2)` if `A=12` square units and d=2 square units and `h_(1)=6` units.

Description : In the formula `A=(1)/(2)d(h_(1)+h-(2))`. Find the value of `h_(2)` if `A=12` square units and d=2 square units and `h_(1)=6` units.

Last Answer : In the formula `A=(1)/(2)d(h_(1)+h-(2))`. Find the value of `h_(2)` if `A=12` square units and d=2 square units and `h_(1)=6` units.

Calculate the mass of 12.044 × 1023 carbon atoms -Chemistry 9th

Description : Calculate the mass of 12.044 × 1023 carbon atoms -Chemistry 9th

Last Answer : No. of moles of Carbon atoms = No. of atoms/Avogadro constant = 12.044 × 1023/6.022 × 1023 = 2 mole Mass of carbon atoms = No. of moles × atomic mass = 2 × 12 = 24 g

Calculate the perimeter of a rectangle whose area is 25x2 – 35x + 12. -Maths 9th

Description : Calculate the perimeter of a rectangle whose area is 25x2 – 35x + 12. -Maths 9th

Last Answer : Given, Area of rectangle = 25x2 - 35x + 12 We know, area of rectangle = length breadth So, by factoring 25x2 - 35x + 12, the length and breadth can be obtained. 25x2 - 35x + 12 = 25x2 - 15x - 20x + 12 => 25x2 - 35x + ... )] = 2(5x - 3 + 5x - 4) = 2(10x - 7) = 20x - 14 So, the perimeter = 20x - 14

The first stage of a two-stage amplifier has a voltage gain of 10, a 600 Ω input resistor, a 1600Ω equivalent noise resistance and 27kΩ output resistor. For the second stage, these values are 25, 81kΩ, 19kΩ, and 1MΩ, respectively. Calculate the equivalent input-noise resistance of this two stage amplifier. A. 2,518 kΩ B. 2,518 Ω C. 251.8 Ω D. 12,518 Ω

Description : The first stage of a two-stage amplifier has a voltage gain of 10, a 600 Ω input resistor, a 1600Ω equivalent noise resistance and 27kΩ output resistor. For the second stage, these values are 25, 81kΩ, 19kΩ, and 1MΩ, ... this two stage amplifier. A. 2,518 kΩ B. 2,518 Ω C. 251.8 Ω D. 12,518 Ω

Last Answer : B. 2,518 Ω

If the static deflection is 1.665×10 -3 m, calculate the critical speed of the shaft in rps. Centre of disc at 0.25m away from centre of axis of shaft. A. 8.64 B. 9.64 C. 10.64 D. 12.2

Description : If the static deflection is 1.665×10 -3 m, calculate the critical speed of the shaft in rps. Centre of disc at 0.25m away from centre of axis of shaft. A. 8.64 B. 9.64 C. 10.64 D. 12.2

Last Answer : D. 12.2

Calculate damped natural frequency, if a spring mass damper system is subjected to periodic disturbing force of 30 N. Damping coefficient is equal to 0.76 times of critical damping coefficient and undamped natural frequency is 5 rad/sec A. 3.99 rad/sec B. 2.13 rad/sec C. 4.12 rad/sec D. 3.24 rad/sec

Description : Calculate damped natural frequency, if a spring mass damper system is subjected to periodic disturbing force of 30 N. Damping coefficient is equal to 0.76 times of critical damping coefficient and undamped natural frequency is 5 rad/sec A. 3.99 rad/sec B. 2.13 rad/sec C. 4.12 rad/sec D. 3.24 rad/sec

Last Answer : D. 3.24 rad/sec

Which formula is used to calculate mass moment of inertia (I G ) of a circular rim about the axis through centre of gravity? a. mr 2 /2b. mr 2 /12 c. mr 2 /4 d. mr 2

Description : Which formula is used to calculate mass moment of inertia (I G ) of a circular rim about the axis through centre of gravity? a. mr 2 /2b. mr 2 /12 c. mr 2 /4 d. mr 2

Last Answer : d. mr 2

Calculate the attenuation constant of a conductor of conductivity 200 units, frequency 1M radian/s in air. a) 11.2 b) 1.12 c) 56.23 d) 5.62

Description : Calculate the attenuation constant of a conductor of conductivity 200 units, frequency 1M radian/s in air. a) 11.2 b) 1.12 c) 56.23 d) 5.62

Last Answer : a) 11.2

Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10 8 m/s(in 10 -8 order) a) 0.5 b) 72 c) 4 d) 3

Description : Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10 8 m/s(in 10 -8 order) a) 0.5 b) 72 c) 4 d) 3

Last Answer : c) 4

Calculate the conduction density of a material with resistivity of 0.02 units and electric intensity of 12 units. a) 300 b) 600 c) 50 d) 120

Description : Calculate the conduction density of a material with resistivity of 0.02 units and electric intensity of 12 units. a) 300 b) 600 c) 50 d) 120

Last Answer : b) 600

Calculate the magnetization of a material with susceptibility of 50 and field intensity of 0.25 units. a) 12.5 b) 25 c) 75

Description : Calculate the magnetization of a material with susceptibility of 50 and field intensity of 0.25 units. a) 12.5 b) 25 c) 75 d) 37.5

Last Answer : a) 12.5

Calculate the Larmer angular frequency for a magnetic flux density of 12.34 x 10 -10 . a) 108.36 b) 810.63 c) 368.81 d) 183.36

Description : Calculate the Larmer angular frequency for a magnetic flux density of 12.34 x 10 -10 . a) 108.36 b) 810.63 c) 368.81 d) 183.36

Last Answer : a) 108.36

Calculate the magnetic energy when the magnetic intensity in air is given as 14.2 units(in 10 -4 order) a) 1.26 b) 2.61 c) 6.12 d) 1.62

Description : Calculate the magnetic energy when the magnetic intensity in air is given as 14.2 units(in 10 -4 order) a) 1.26 b) 2.61 c) 6.12 d) 1.62

Last Answer : a) 1.26

Calculate the electric field due to a surface charge of 20 units on a plate in air(in 10 12 order) a) 2.19 b) 1.12 c) 9.21 d) 2.91

Description : Calculate the electric field due to a surface charge of 20 units on a plate in air(in 10 12 order) a) 2.19 b) 1.12 c) 9.21 d) 2.91

Last Answer : b) 1.12

Calculate potential of a metal plate of charge 28C and capacitance 12 mF. a) 3.33 kohm b) 2.33 kohm c) 3.33 Mohm d) 2.33 Mohm

Description : Calculate potential of a metal plate of charge 28C and capacitance 12 mF. a) 3.33 kohm b) 2.33 kohm c) 3.33 Mohm d) 2.33 Mohm

Last Answer : b) 2.33 kohm

Calculate the electric field intensity of a line charge of length 2m and potential 24V. a) 24 b) 12 c) 0.083 d) 12.67

Description : Calculate the electric field intensity of a line charge of length 2m and potential 24V. a) 24 b) 12 c) 0.083 d) 12.67

Last Answer : b) 12

Calculate the potential when a conductor of length 2m is having an electric field of 12.3units. a) 26.4 b) 42.6 c) 64.2 d) 24.6

Description : Calculate the potential when a conductor of length 2m is having an electric field of 12.3units. a) 26.4 b) 42.6 c) 64.2 d) 24.6

Last Answer : d) 24.6

Calculate the polarisation vector in air when the susceptibility is 5 and electric field is 12 units. a) 3 b) 2 c) 60 d) 2.4

Description : Calculate the polarisation vector in air when the susceptibility is 5 and electric field is 12 units. a) 3 b) 2 c) 60 d) 2.4

Last Answer : c) 60

The bound charge density and free charge density are 12 and 6 units respectively. Calculate the susceptibility. a) 1 b) 0 c) 2 d) 72

Description : The bound charge density and free charge density are 12 and 6 units respectively. Calculate the susceptibility. a) 1 b) 0 c) 2 d) 72

Last Answer : c) 2

Calculate the energy in an electric field with flux density 6 units and field intensity of 4 units. a) 12 b) 24 c) 36 d) 48

Description : Calculate the energy in an electric field with flux density 6 units and field intensity of 4 units. a) 12 b) 24 c) 36 d) 48

Last Answer : a) 12

Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

If 2x-y=4 then calculate 6x-3y=? (a)15 (b)12 (c)18 (d)10

Description : If 2x-y=4 then calculate 6x-3y=? (a)15 (b)12 (c)18 (d)10

Last Answer : (b)12

Calculate re-order level from the following: Safety stock: 1000 units Consumption per week: 500 units It takes 12 weeks to reach material from the date of ordering. (a) 1000 units (b) 6000 units (c) 3000 units (d) 7000 units

Description : Calculate re-order level from the following: Safety stock: 1000 units Consumption per week: 500 units It takes 12 weeks to reach material from the date of ordering. (a) 1000 units (b) 6000 units (c) 3000 units (d) 7000 units

Last Answer : (d) 7000 units

Maintain 850 OC for 1 hour (soaking time).  Cool the material to 60 OC in 4 hours. a) Calculate the efficiency of the furnace, if the specific heat of steel is 0.12 kcal/kgOC and fuel oil consumption per batch is 1400 litres.  GCV of fuel oil - 10200 kcal/kg,  Cost of fuel oil - Rs. 46,000/kL,  Sp. gr. of fuel oil - 0.92. b) Due to high cost of oil, the plant management decides to convert to a lower operating cost LPG fired furnace lined on the inside with ceramic fibre insulation and with an operating efficiency of 80%, for same requirement. The investment towards installation of the new furnace is Rs. 50 lakhs. Calculate the Return on Investment, if the plant operates two batches per day and 250 days in a year.  Cost of LPG - Rs. 75/kg,  GCV of LPG - 12500 kcal/kg.

Description : In a heat treatment shop, steel components are heat-treated in batches of 80 Tons. The  heat treatment cycle is as follows;  Increase temperature from 30 OC to 850 OC in 3 hours.  ... efficiency of 80%, for same requirement. The investment towards installation of  the new furnace is Rs. 50

Last Answer : Quantity of steel treated per batch - 80 Tons a. Efficiency of Furnace: Useful heat supplied to steel - 80000 x 0.12 x (850 - 30)   = 7872000 kcal/batch .1 mark Total heat ... = Rs. 64400/batch Efficiency of new LPG furnace - 80% Heat supplied in new LPG furnace - 7872000/0.8

What base year is used to calculate per capita income in India? (a) 2004-05 (b) 2011-12 © 2001-02 (d) 2014-15

Description : What base year is used to calculate per capita income in India? (a) 2004-05 (b) 2011-12 © 2001-02 (d) 2014-15

Last Answer : (b) 2011-12

A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Description : A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Last Answer : Katie earned 84,92,84,75 and 70 on her first 5 tests. What is the minimum grade Katie needs to earn on the next test to have a mean of 84?

Calculate quantity of water to be added for casting cubes in laboratory by 12.5 kg cement if w/c ratio 0.45.

Description : Calculate quantity of water to be added for casting cubes in laboratory by 12.5 kg cement if w/c ratio 0.45. 

Last Answer : As w/c = (weight of water / weight of cement)  w/c = (Ww / Wc)  0.45 = (Ww / 12.5)  Ww = (0.45x12.5)  Ww = 5.625 kg or 5.625 Litres