Is 90 divisible by 5 and 9?

Last Answer : 6 + 4 + 6 = 161 + 6 = 7→ No; 646 is not divisible by 9 (there is a remainder of 7).-----------------------------------------Only if the sum of the ... ifthis single digit is 9 is the original number divisible by 9,otherwise this single digit is the remainder when the originalnumber is divided by 9.

What which of these numbers are divisible by 13 is it a. 52 or b. 9 c. 30 d. 27?

Description : What which of these numbers are divisible by 13 is it a. 52 or b. 9 c. 30 d. 27?

Last Answer : a.

Is 4932 divisible by 9?

Description : Is 4932 divisible by 9?

Last Answer : Yes

What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Description : What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Last Answer : A + b = 0, 9, 18(9,0)(8,1)(7,2)(6,3)(5,4)(4,5)(3,6)(2,7)(1,8)(0,9)(0,0)(9,9)-------------------------------------------To be divisible by 9, the sum 6 + 3 + 1 + 8 + 7 + 2 + A + B = 27+ A ... , 5),(5, 4), (6, 3), (7, 2), (8, 1), (9, 0)Note that (0, 0) must not be forgotten as 27 + 0 + 0 = 27 = 3 9.

What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Description : What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Last Answer : A can be 0 or 9.

Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Description : Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Last Answer : If the sum of digits add up to 9 then the number is divisible by 9 as for example the digits of 450 add up to 9 and so 450/9 = 50-------------------------------------- ... sum is 9, then the original number is divisible by 9, otherwise it is the remainder when the original number is divided by 9.

Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Description : Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Last Answer : If the sum of digits add up to 9 then the number is divisible by 9 as for example the digits of 450 add up to 9 and so 450/9 = 50-------------------------------------- ... sum is 9, then the original number is divisible by 9, otherwise it is the remainder when the original number is divided by 9.

What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Description : What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Last Answer : A can be 0 or 9.

What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Description : What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Last Answer : A + b = 0, 9, 18(9,0)(8,1)(7,2)(6,3)(5,4)(4,5)(3,6)(2,7)(1,8)(0,9)(0,0)(9,9)-------------------------------------------To be divisible by 9, the sum 6 + 3 + 1 + 8 + 7 + 2 + A + B = 27+ A ... , 5),(5, 4), (6, 3), (7, 2), (8, 1), (9, 0)Note that (0, 0) must not be forgotten as 27 + 0 + 0 = 27 = 3 9.

Is 104 divisible by 9?

Description : Is 104 divisible by 9?

Last Answer : No.To check if a number is divisible by 9 add the digits togetherand if the sum is divisible by 9 then so is the original number.The check can be used on the sum so keep summing until a singledigit remains. If ... = 55 is not 9, so 104 is not divisible by 9; it has a remainder of5 when divided by 9

What numbers are divisible by 3 9 6?

Description : What numbers are divisible by 3 9 6?

Last Answer : Any number of the form 18*k where k is an integer.

Is N divisible by 9? (N is a two digit number) I. R(N/3) = 2 II. R(n/7)=1 (a) statement (I) alone is sufficient (b) statement (II) alone is sufficient (c) Both statements (I) and (II) together are not sufficient (d) Both statements (I) and (II) together are necessary

Description : Is N divisible by 9? (N is a two digit number) I. R(N/3) = 2 II. R(n/7)=1 (a) statement (I) alone is sufficient (b) statement (II) alone is sufficient (c) Both statements (I) and (II) together are not sufficient (d) Both statements (I) and (II) together are necessary

Last Answer : (a) statement (I) alone is sufficient

Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Description : Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Last Answer : The two digit numbers can be formed by putting any of 5 digits at the one 's place and also one of the 5 digits at ten's place. So, Total number of 2-digit numbers that can be formed using these 5-digits = 5 5 = ... 52}, i.e, 5 in number. ∴ Required probability = \(rac{5}{25}\) = \(rac{1}{5}.\)

If x^5 – 9x^2 + 12x – 14 is divisible by (x – 3), what is the remainder ? -Maths 9th

Description : If x^5 – 9x^2 + 12x – 14 is divisible by (x – 3), what is the remainder ? -Maths 9th

Last Answer : answer:

If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Description : If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Last Answer : The divisor is x4−1=(x−1)(x+1)(x2+1) By factor theorem, f(1)=f(−1)=0 Thus, 1+p+q−1−1−3=0 and 1+q−1−3=p−1 i.e., p+q=4 and p−q=−2 Adding the two, 2p=2 i.e. p=1 and ∴ q=3. ∴ p2+q2=1+9=10

Which one of the following is divisible by (1 + a + a^5) and (1 + a^4 + a^5) individually ? -Maths 9th

Description : Which one of the following is divisible by (1 + a + a^5) and (1 + a^4 + a^5) individually ? -Maths 9th

Last Answer : answer:

What should be subtracted from 27x^3 – 9x^2 – 6x – 5 to make it exactly divisible by (3x – 1) -Maths 9th

Description : What should be subtracted from 27x^3 – 9x^2 – 6x – 5 to make it exactly divisible by (3x – 1) -Maths 9th

Last Answer : answer:

How many numbers are divisible by 5 from 1 to 100 ?

Description : 20

Last Answer : 20 numbers from 1-100 are divisible by 5.

Is 4095 divisible by 5?

Description : Is 4095 divisible by 5?

Last Answer : Need answer

What is the least number that is divisible by 2 3 5 and ten explain?

Description : What is the least number that is divisible by 2 3 5 and ten explain?

Last Answer : from 2 3 5 10 remove 2 and 5 asthey already go into 10 as 2 x 5 = 10so only leaving 3 and 10 which3 x 10 = 30Check:30 = 2 x 15 = 3 x 10 = 5 x 6 = 10 x 3

Is 313756 divisible by 5?

Description : Is 313756 divisible by 5?

Last Answer : Not evenly because it will have a remainder of 1

What number is divisible by both 5 and 6?

Description : What number is divisible by both 5 and 6?

Last Answer : The lowest common multiple of 5 and 6 is 30, so ALL MULTIPLES of30 are divisible by both 5 and 6, namely:30, 60, 90, 120, 150, 180, 210, 240, 270, 300, 330, 360, 390,420, 450, 480, 510, 540, 570, ... 2550, 2580, 2610, 2640, 2670, 2700, 2730, 2760, 2790,2820, 2850, 2880, 2910, 2940, 2970, 3000, ...

Is 404985 divisible by 5?

Description : Is 404985 divisible by 5?

Last Answer : Yes and the quotient is exactly 80997

What is the smallest number divisible by 2 3 4 5 6 7?

Description : What is the smallest number divisible by 2 3 4 5 6 7?

Last Answer : The lowest common multiple of 2, 3, 4, 5, 6 and 7 is 420.

What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Description : What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Last Answer : Answer- 2 ( 3) Explanation:- On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Description : The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Last Answer : Answer – C (23) Explanation – L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23

Write an algorithm to determine whether a given number is divisible by 5 or not

Description : Write an algorithm to determine whether a given number is divisible by 5 or not

Last Answer : Here's one possible algorithm to determine whether a given number is divisible by 5 or not: Start by taking the input number. Check if the last digit of the number is either 0 or 5. If the ... The above two algorithms are basic ways of checking whether the given number is divisible by 5 or not.

Consider a set A = {1, 2, 3, …….., 1000}. How many members of A shall be divisible by 3 or by 5 or by both 3 and 5 ? (A) 533 (B) 599 (C) 467 (D) 66

Description : Consider a set A = {1, 2, 3, …….., 1000}. How many members of A shall be divisible by 3 or by 5 or by both 3 and 5 ? (A) 533 (B) 599 (C) 467 (D) 66

Last Answer : (C) 467

What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which nothing can be done; which devours every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Description : What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which ... every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Last Answer : Time.

For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : As the given polynomial divisible by x-2 means the polynomial satisfies for the value x=2 So putting x=2 in x²+(4-k)x+2 yields 0 ⇒2²+(4-k)2+2=0 ⇒4+8-2k+2=0 ⇒ 2k=14 ⇒ k= ... ;-3x+2 if factorized yields (x-1)(x-2). Thus is divisible by x-2 as well as divisible by x-1.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : The value of 'k' is 4

An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Description : An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Last Answer : As there are 200 integers, total number of exhaustive, mutually exclusive and equally likely cases, i.e, n(S) = 200 Let A : Event of integer chosen from 1 to 200 being divisible by 6⇒ n(A) = 33 \(\bigg(rac{200}{6}=33rac{1}{3}\ ... (rac{25}{200}\) - \(rac{8}{200}\) = \(rac{50}{200}\) = \(rac{1}{4}\).

A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

Description : A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

Last Answer : Without repetition, a five -digit number can be formed using the five digits in 5! ways (5 4 3 2 1) Out of these 5! numbers, 4! numbers will be starting with digit 0. (0 (fixed) 4 3 2 1) ∴ Total ... + 6 + 6 + 4 + 4 + 4 = 30∴ Required probability = \(rac{30}{96}\) = \(rac{5}{16}.\)

If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Description : If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Last Answer : (c) \(rac{4}{1155}\)Let n(S) = Number of ways of selecting 3 numbers from 100 numbers = 100C3 Let E : Event of selecting three numbers divisible by both 2 and 3 from numbers 1 to 100 = Event of selecting three ... C_3}{^{100}C_3}\) = \(rac{16 imes15 imes14}{100 imes99 imes98}\) = \(rac{4}{1155}\).

For what value of m will the expression 3x^3 + mx^2 + 4x – 4m be divisible by x + 2 ? -Maths 9th

Description : For what value of m will the expression 3x^3 + mx^2 + 4x – 4m be divisible by x + 2 ? -Maths 9th

Last Answer : f(x) = 3x3 + mx2 + 4x – 4m f(x) is divisible by (x + 2) if f(–2) = 0 Now f(–2) = 3(–2)3 + m(–2)2 + 4(–2) – 4m = – 24 + 4m – ... ; 4m = – 32 ≠ 0 ∴ No such value of m exists for which (x + 2) is a factor of the given expression

Without actual division show that 2x^4 – 6x^3 + 3x^2 + 3x – 2 is exactly divisible by x^2 – 3x + 2 -Maths 9th

Description : Without actual division show that 2x^4 – 6x^3 + 3x^2 + 3x – 2 is exactly divisible by x^2 – 3x + 2 -Maths 9th

Last Answer : answer:

Without actual division, show that (x – 1)^2n – x^2n + 2x – 1 is divisible by 2x^3 – 3x^2 + x. -Maths 9th

Description : Without actual division, show that (x – 1)^2n – x^2n + 2x – 1 is divisible by 2x^3 – 3x^2 + x. -Maths 9th

Last Answer : answer:

For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Description : For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Last Answer : Given f(x) = 3x³ - kx² + 4x + 16. Since (x - k/2) is a factor of polynomial. This means x = k/2 is the zero of the given polynomial. ⇒ f(k/2) = 3(k/2)³ - k(k/2)² + 4(k/2) + 16 ⇒ 0 ... - 4k + 32) + 4(k² - 4k + 32) ⇒ 0 = (k + 4)(k² - 4k + 32) ⇒ k = -4.

x^4 + xy^3 + x^3y + xz^3 + y^4 + yz^3 is divisible by : -Maths 9th

Description : x^4 + xy^3 + x^3y + xz^3 + y^4 + yz^3 is divisible by : -Maths 9th

Last Answer : answer:

If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Description : If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Last Answer : Let f(x)=px3+x2−2x−q Since f(x) is divisible by (x−1) and (x+1) so x=1 and −1 must make f(x)=0. Therefore, p+1−2−q=0, i.e., p−q=1; and −p+1+2−q=0, i.e., p+q=3 Thus p=2 and q=1

Is 90 divisible by 5 and 9?

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