What is 0.42 times 10?

What is 0.42 times 10?
by

1 Answer

Answer :

The product is 4.2
by

Related questions

What is 0.42 times 10?

Description : What is 0.42 times 10?

Last Answer : The product is 4.2

For the financial year ended as on March 31, 2013 the figures extracted from the balance sheet of Xerox Limited as under: Opening Stock Rs. 29,000; Purchases Rs. 2,42,000; Sales Rs. 3,20,000; Gross Profit 25% of Sales. Stock Turnover Ratio will be :- (a) 8 times (b) 6 times (c) 9 times (d) 10 times

Description : For the financial year ended as on March 31, 2013 the figures extracted from the balance sheet of Xerox Limited as under: Opening Stock Rs. 29,000; Purchases Rs. 2,42,000; Sales Rs. 3,20,000; Gross Profit 25% of ... Stock Turnover Ratio will be :- (a) 8 times (b) 6 times (c) 9 times (d) 10 times

Last Answer : (a) 8 times

What is 0.42 times 0.2?

Description : What is 0.42 times 0.2?

Last Answer : 0.42 × 0.2 = 0.084

Smoke volatility index is equal to smoke point plus (A) 0.42 × (% distilled at 204°C) (B) 5 mm (C) 0.84 × (% distilled at 204°C) (D) 10 mm approximately

Description : Smoke volatility index is equal to smoke point plus (A) 0.42 × (% distilled at 204°C) (B) 5 mm (C) 0.84 × (% distilled at 204°C) (D) 10 mm approximately

Last Answer : (A) 0.42 × (% distilled at 204°C)

√(4.9 − 0.49) = ? a) 10.42 b) 5.84 c) 12.84 d) 2.1 e) None of these

Description : √(4.9 − 0.49) = ? a) 10.42 b) 5.84 c) 12.84 d) 2.1 e) None of these

Last Answer : Answer: d)

How many times 42 can go into 88?

Description : How many times 42 can go into 88?

Last Answer : 2 R 4

What is 100 times bigger than 42?

Description : What is 100 times bigger than 42?

Last Answer : 4,200four thousand two hundred

How many times can 42 go into 53?

Description : How many times can 42 go into 53?

Last Answer : Once with a remainder of eleven

What times 9 equals 42?

Description : What times 9 equals 42?

Last Answer : 42/9=4.666666666666667

How many times the sixes are their in 42?

Description : How many times the sixes are their in 42?

Last Answer : seven6 + 6 + 6 = 1818 + 18 + 6 = 42

How many times do 42 go in 1596?

Description : How many times do 42 go in 1596?

Last Answer : Exactly 38 times

How many times does 42 go into 124?

Description : How many times does 42 go into 124?

Last Answer : 2 R 40

How many times does 42 go into 78?

Description : How many times does 42 go into 78?

Last Answer : 1.86 times

Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Description : Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Last Answer : C Karthik’s 1 day work : Raghu’s 1 day work = 2:1 (Karthik + Raghu)’s 1 day work = 1/42 Divide 1/42 in the ratio 2:1 Therefore karthick’s 1 day work = 1/42 * 2/3 =1/63 Hence karthik alone can finish the work in 63 days.

The ages of two sisters differ by 32 years. 12 years ago, the elder one was 7 times as old as the younger one. What are their present ages of the elder person a) 46.9 b) 49.3 c) 42.7 d) 45.4

Description : The ages of two sisters differ by 32 years. 12 years ago, the elder one was 7 times as old as the younger one. What are their present ages of the elder person a) 46.9 b) 49.3 c) 42.7 d) 45.4

Last Answer : B Let's take the present age of the elder person = x and the present age of the younger person = x – 32 (x – 12) = 7*(x-32-12) => x – 12 = 7x – 308 => 6x = 296 => x = 49years 3months

One tube can fill a tank five times as fast as another tube. If together the two tubes can fill tank in 42 min, then the slower tube alone will be able to fill the tank in? A) 252 min B) 208 min C) 244 min D) 192 min

Description : One tube can fill a tank five times as fast as another tube. If together the two tubes can fill tank in 42 min, then the slower tube alone will be able to fill the tank in? A) 252 min B) 208 min C) 244 min D) 192 min

Last Answer : A Let the slower tube alone fill the tank in x min. Then, faster tube will fill it in x/5 min. 1/x + 5/x = 1/42 6/x = 1/42 => x = 252min.

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

6. “The refractive index of diamond is 2.42”. What is the meaning of this statement in relation to speed of light? [Delhi] -Chemistry-10

Description : 6. “The refractive index of diamond is 2.42”. What is the meaning of this statement in relation to speed of light? [Delhi] -Chemistry-10

Last Answer : Answer. hope this helps you

5. The refractive index of diamond is 2.42. What is the meaning of this statement? -Physics-10

Description : 5. The refractive index of diamond is 2.42. What is the meaning of this statement? -Physics-10

Last Answer : Diamond has a refractive index of 2.42 which means that the speed of light in diamond will reduce by a factor of 2.42 as compared to its speed in the air. In other words, the speed of light in diamond is 1/2.42 times the speed of light in vacuum.

How many 10 squares can you get in 1 yard of fabric 36 X 42?

Description : How many 10 squares can you get in 1 yard of fabric 36 X 42?

Last Answer : You can get 12.

What is the wavelength of a light of frequency 6.42 x 10 to the 14th power?

Description : What is the wavelength of a light of frequency 6.42 x 10 to the 14th power?

Last Answer : Need answer

convert 1.42 x 10^24 molecules of water into grams?

Description : convert 1.42 x 10^24 molecules of water into grams?

Last Answer : i dont knowww

On Indian Railways standard length of rails for Meter Gauge track, is A. 33 ft (10.06 m) B. 36 ft (10.97 m) C. 39 ft (11.89 m) D. 42 ft (12.8 m)

Description : On Indian Railways standard length of rails for Meter Gauge track, is A. 33 ft (10.06 m) B. 36 ft (10.97 m) C. 39 ft (11.89 m) D. 42 ft (12.8 m)

Last Answer : C [39 ft (11.89 m)]

On Indian Railways standard length of rails for Broad Gauge track, is A. 33 ft (10.06 m) B. 36 ft (10.97 m) C. 39 ft (11.89 m) D. 42 ft (12.8 m)

Description : On Indian Railways standard length of rails for Broad Gauge track, is A. 33 ft (10.06 m) B. 36 ft (10.97 m) C. 39 ft (11.89 m) D. 42 ft (12.8 m)

Last Answer : D [42 ft (12.8 m)] Explanation: Indian Railways is divided into 18 zones. Recently added South Coast Railway zones in Indian Railway (2019).

Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 –3 m 3. Natural frequency of the system = 60 rad/sec A. 100.5 x 10 3 N-s/m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above

Last Answer : C. 42 x 10 3 N-s/m

Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 –3 m 3. Natural frequency of the system = 60 rad/sec a. 100.5 x 10 3 N-s/m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

Last Answer : c. 42 x 10 3 N-s/m

Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his average speed for the entire journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)

Starting from point A, Ajit walks 14 metres towards west, he then turns to his right and walks 14 metres and then turns to his left and walks 10 metres. He again turns to his left and walks 14 metres and reaches to the point E. The shortest distance between A and E is (A) 38 (B) 42 (C) 52 (D) 24

Description : Starting from point A, Ajit walks 14 metres towards west, he then turns to his right and walks 14 metres and then turns to his left and walks 10 metres. He again turns to his left and walks 14 metres and reaches to the point E. The shortest distance between A and E is (A) 38 (B) 42 (C) 52 (D) 24

Last Answer : Answer: D

Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Description : Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Last Answer : A Let sai's 1 day work = x Ram's 1 day work = y Then x+y = 1/10 ===>1 and 2x +2y /3 = 1/6 (6x+2y )/3 = 1/6 6x + 2y =1/2 ====>2 Multiply 1 by 6 =>6x+6y = 6/10 2 = ... /10 - 1/40 = 4-1/10 =3/40 Sai's 1 day work = 3/40 So sai alone could complete the work in 40/3 days.

A mototboat can row to a place 112 km away and come back in 44 hours. The time to row 42 km with the stream is same as the time to row 24 km against the stream. Find the speed of boat in still water. A) 5.5 km/hr B) 7.5km/hr C) 10.5 km/hr D) 3.5 km/hr

Description : A mototboat can row to a place 112 km away and come back in 44 hours. The time to row 42 km with the stream is same as the time to row 24 km against the stream. Find the speed of boat in still water. A) 5.5 km/hr B) 7.5km/hr C) 10.5 km/hr D) 3.5 km/hr 

Last Answer : ANSWER: A Explanation: Downstream speed = 42/x km/hr Upstream speed = 24/x km/hr 112 / (42 / x) + 112 / (24 / x) = 44 112[x /42 + x / 24] = 44 112 / 3 [x / 14 + x / 8] = 44 11x / 56 = 44 * ... = 4 km/hr Speed of boat = 1/2 * (7 + 4) km/hr = 11 /2 speed of boat in still water = 5.5 km/hr

The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000  = (104/100) × (106/100) × (110/100) × 200000  = 1.04×1.06×1.1×200000  = 2,42,528

Convert each of the following decimals into a percentage: (i) 0.6 (ii) 0.42 (iii) 0.07 (iv) 0.005 -Maths

Description : Convert each of the following decimals into a percentage: (i) 0.6 (ii) 0.42 (iii) 0.07 (iv) 0.005 -Maths

Last Answer : answer:

Find the number of significant figures in the following numbers, i. 25.42 ii. 0.004567 iii. 35.320 iv. 91.000

Description : Find the number of significant figures in the following numbers, i. 25.42 ii. 0.004567 iii. 35.320 iv. 91.000

Last Answer : Find the number of significant figures in the following numbers, i. 25.42 ii. 0.004567 iii. 35.320 iv. 91.000

What does 0.42 round to?

Description : What does 0.42 round to?

Last Answer : To the nearest tenth it is 0.4

What is 0.42 repeting as a fraction?

Description : What is 0.42 repeting as a fraction?

Last Answer : It is not possible to answer the question because it isambiguous: the answer depends on what string is repeating. It isnot clear from the question whether the fraction is meant to be0.424242... or 0.4222... .

A trait has two alleles, and their frequencies are represented by p and q. If p=0.42, what is q?

Description : A trait has two alleles, and their frequencies are represented by p and q. If p=0.42, what is q?

Last Answer : 0.58

What is the molecular formula of the compound CH2 with molar mass = 42.0?

Description : What is the molecular formula of the compound CH2 with molar mass = 42.0?

Last Answer : Apex

What is 96.6 divide by 0.42?

Description : What is 96.6 divide by 0.42?

Last Answer : 230

What is actual length in feet of a one-half wavelength of a coax with a velocity factor of 0.59 at 26 MHz? A. 11.16 B. 40.29 C. 42.46 D. 46.28

Description : What is actual length in feet of a one-half wavelength of a coax with a velocity factor of 0.59 at 26 MHz? A. 11.16 B. 40.29 C. 42.46 D. 46.28

Last Answer : A. 11.16

Co-efficient of discharge (Cd ) is defined as actual discharge/theoretical discharge and is equal to Cc . Cv ; where Cc = Co-efficient of contraction and Cv = co-efficient of velocity. Cd of an orifice is usually about (A) 0.42 (B) 0.62 (C) 0.82 (D) 0.98

Description : Co-efficient of discharge (Cd ) is defined as actual discharge/theoretical discharge and is equal to Cc . Cv ; where Cc = Co-efficient of contraction and Cv = co-efficient of velocity. Cd of an orifice is usually about (A) 0.42 (B) 0.62 (C) 0.82 (D) 0.98

Last Answer : (B) 0.62

Co-efficient of discharge (Cd ) is defined as actual discharge/theoretical discharge and is equal to Cc . Cv ; where Cc = Co-efficient of contraction and Cv = co-efficient of velocity. Cd of an orifice is usually about (A) 0.42 (B) 0.62 (C) 0.82 (D) 0.98

Description : Co-efficient of discharge (Cd ) is defined as actual discharge/theoretical discharge and is equal to Cc . Cv ; where Cc = Co-efficient of contraction and Cv = co-efficient of velocity. Cd of an orifice is usually about (A) 0.42 (B) 0.62 (C) 0.82 (D) 0.98

Last Answer : (B) 0.62

The total length of a valley formed by two gradients - 3% and + 2% curve between the two tangent points to provide a rate of change of centrifugal acceleration 0.6 m/sec2 , for a design speed 100 kmph, is (A) 16.0 m (B) 42.3 m (C) 84.6 m (D) None of these

Description : The total length of a valley formed by two gradients - 3% and + 2% curve between the two tangent points to provide a rate of change of centrifugal acceleration 0.6 m/sec2 , for a design speed 100 kmph, is (A) 16.0 m (B) 42.3 m (C) 84.6 m (D) None of these

Last Answer : Answer: Option C

Interior thickness of concrete road slab for design wheel load 6300 kg and permissible flexural stress 21 kg/cm2 , is (A) 17.0 cm (B) 25.5 cm (C) 34.0 cm (D) 42.5 cm

Description : Interior thickness of concrete road slab for design wheel load 6300 kg and permissible flexural stress 21 kg/cm2 , is (A) 17.0 cm (B) 25.5 cm (C) 34.0 cm (D) 42.5 cm

Last Answer : Answer: Option B

The total value of extra widening required at a horizontal curve on a two lane hill road of radius 42 m for a design speed of 50 kmph and for vehicles with wheel base 6 m, is (A) 0.500 m (B) 0.589 m (C) 1.089 m (D) 0.089 m

Description : The total value of extra widening required at a horizontal curve on a two lane hill road of radius 42 m for a design speed of 50 kmph and for vehicles with wheel base 6 m, is (A) 0.500 m (B) 0.589 m (C) 1.089 m (D) 0.089 m

Last Answer : Answer: Option C

If the coefficient of friction on the road surface is 0.15 and a maximum super-elevation 1 in 15 is provided, the maximum speed of the vehicles on a curve of 100 metre radius, is (A) 32.44 km/hour (B) 42.44 kg/hour (C) 52.44 km/hour (D) 62.44 km/hour

Description : If the coefficient of friction on the road surface is 0.15 and a maximum super-elevation 1 in 15 is provided, the maximum speed of the vehicles on a curve of 100 metre radius, is (A) 32.44 km/hour (B) 42.44 kg/hour (C) 52.44 km/hour (D) 62.44 km/hour

Last Answer : Answer: Option C

The total length of a cranked bar through a distance (d) at 45° in case of a beam of effective length L, is (A) L + 0.42 d (B) L + (2 × 0.42 d) (C) L - (0.42 d) (D) L - (2 × 0.4 d)

Description : The total length of a cranked bar through a distance (d) at 45° in case of a beam of effective length L, is (A) L + 0.42 d (B) L + (2 × 0.42 d) (C) L - (0.42 d) (D) L - (2 × 0.4 d)

Last Answer : (B) L + (2 × 0.42 d)

A disk drive has 100 cylinders, numbered 0 to 99. Disk requests come to the disk driver for cyclinders 12, 26, 24, 4, 42, 8 and 50 in that order. The driver is currently serving a request at cyclinder 24. A seek takes 6 msec per cyclinder moved. How much seek time is needed for shortest seek time first (SSTF) algorithm? (A) 0.984 sec (B) 0.396 sec (C) 0.738 sec (D) 0.42 sec

Description : A disk drive has 100 cylinders, numbered 0 to 99. Disk requests come to the disk driver for cyclinders 12, 26, 24, 4, 42, 8 and 50 in that order. The driver is currently serving a request at cyclinder 24. A seek takes ... (SSTF) algorithm? (A) 0.984 sec (B) 0.396 sec (C) 0.738 sec (D) 0.42 sec

Last Answer : C