Description : The population of a town is 378000. It decreases by 16% in the 1st year and increases by 10% in the 2nd year. What is the population in the town at the end of 2 years? a) 182574 b) 482576 c) 282674 d) 283574 e) 349272
Last Answer : Answer: E After 2 years required population is = 378000 (1-16/100) (1+10/100) = 378000 (84/100) (110/100) = 378000 (0.84) (1.1) = 3,49,272
Description : The population of a town is 16200. It decreases annually at the rate of 40% p.a. What was its population 3 years ago? a) 75000 b) 65000 c) 84900 d) 93600
Last Answer : Answer: A (Ago = 100 numerator) Ago 3 years = 16200×(100/60×100/60×100/60) = 75000
Description : In an election three candidates received 2272 , 15272, and 23256 votes respectively. What percentage of the total votes did the winning candidate got? a) 25 b) 41 c) 75 d) 57 e) 93
Last Answer : Answer: D Total number of votes polled = (2272+15272+23256) =40800 Required percentage = 23256/40800 ×100 = 2325600/40800 = 57
Description : The population of a town is 15000. It increases annually at the rate of 20% p.a. What will be its population after 3 years? a) 65439 b) 25920 c) 37193 d) 41093
Last Answer : Answer: B Formula : ( After =100 denominator ) (Ago = 100 numerator) After 3 years = 15000×(1+20/100)^3 = 15000 ×(120/100)^3 = 15000 ×(1.2)^3 = 15000 ×(1.728) = 25920
Description : The value of a machine depreciates at the rate of 20% every year. It was purchased 6 years ago. If its present value is Rs. 17,496, its purchase price was : a) 25023.4 b) 67040.0 c) 34171.8 d) 27337.5
Last Answer : Answer: C Purchase price = 17,496 / (1 -20/ 100)³ = 17,496 × 10/8 × 10/8 ×10/8 = 17496 × 1.25 × 1.25 ×1.25 = 17496 ×1.953 = 34171.8
Description : The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase in population. a) 25 b) 62 c) 6.25 d) 27.5 e) 59.8
Last Answer : Answer: D Population in a small town last year = 50000 Population in a small town after one year = 63750 Increase in population = 63750 - 50000 = 13750 Therefore, percentage increase in population = ... /50000 100 = 1375000/50000 = 27.5% Thus, the increase in population is 27.5%
Description : A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980
Last Answer : Answer: C Original value is percentage = 100 %. Reduce amount in percentage = 10 % Therefore, Percent value in percentage = 100 % - 10 % = 90 %. According to the problem, 90 % of original value ... Therefore, 100 % of original value = 1080/100 90 = 1200. Thus, the original value was 1200.
Description : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Last Answer : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Description : Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years
Last Answer : B We are given that age ratio of tom and ram = 5 : 6 Tom's age = 5x and Ram's age = 6x 3 years ago, their age was 5x and 6x. Hence at present, Tom's age = 5x +3 and Ram's age = 6x +3 After 12years, Tom's ... = 6 / 7 7 (5x + 15) = 6 (6x + 15) X = 15 Ram's present age = (6x + 3) = 93years
Description : A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6
Last Answer : Answer: D Error = 168 – 24 = 144 Therefore, % error = 144/168 [Since, we know decrease% = decrease in value/original value × 100 %] = 144/168 × 100 = 85.7 %
Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98
Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %
Description : Vasavi spends 50% of her monthly income on grocery, clothes and education in the ratio of 8 : 4 : 10 respectively. If the amount spent on clothes is 2770/–, what is Vasavi's monthly income? a) 15235 b) 65000 c) 55400 d) 30470 e) 98700
Last Answer : Answer: D Ratio of Expenses = 8: 4: 10 therefore amount spend on clothes, i.e. 4x = 2770 x = 692.5 Total exp = (8 + 4 + 10)x = 22x. = 22 × 692.5 = 15235 Monthly income be x. 50% of x = 15235 x = 15235 × 100/ 50 X = 30470
Description : To the nearest rupee, what is the net present value of a replacement project whose cash flows are -Rs.104,000; Rs.34,444; Rs.39,877; Rs.25,000; and Rs.52,800 for years 0 through 4, respectively? The firm has decided to ... -free rate is 6%. A. Rs.15,115 B. Rs.26,798 C. Rs.33,346 D. Rs.48,121
Last Answer : C. Rs.33,346
Description : In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989
Last Answer : Answer: B Total marks in the test = (560 + 160) × 100 /25 = 720 ×100/25 = 72000/25 = 2880 Passing marks for girls =2880 × 60/100 = 1728 Required marks = 1728 – 216 = 1512
Description : Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855
Last Answer : Answer: E Increase = 90 % of 450 = 90/100 × 450 = 40500/100 = 405 Therefore, increase value = 450 + 405 = 855
Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price = $37.5 - $ 30 = $ 7.5 Therefore, percentage increase in price = Increase in price/ ... = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %
Description : The Shopkeeper increased the price of a product by 75% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 140% of the required amount. What is the net difference in the ... on that product? a) 12.5 b) 26.0 c) 13.5 d) 17.5 e) 19.8
Last Answer : Answer: D Quantity×Rate=Price 1x1=1 1.4x1.75=2.45 Decrease in price = (0.175/1) × 100 = 17.5%
Description : If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241
Last Answer : Answer: A Fraction is x/y (x + 400/100 x ) / (y + 300/100 y) = 18/35 (500/100) x(35) = (400/100)y (18) (5x) × 35 = 18 × 4 y 175 x = 72 y x/y = 72/175
Description : If weed population is 70/m2 and the crop 140/ m2, weed intensity would be a). 33.3% b). 66.6% c). 50% d). 73.4%
Last Answer : a). 33.3%
Description : In a birthday party, every person shakes hand with every other person. If there was a total of 66 handshakes in the party, how many persons were present in the party? A) 9 B) 8 C) 7 D) 12
Last Answer : Answer: D) Assume that in a party every person shakes hand with every other person Number of hand shake = 66 Total number of hand shake is given by nC2 Let n = the total number of persons ... cannot take negative value of n So, n = 12 Therefore number of persons in the party = 12
Description : Chenna dhal is now being sold at Rs. 70 a kg. Last month, is rate was Rs. 80 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed? a)12.5 b)21.8 c)23 d)18
Last Answer : Answer: A Let a family's monthly consumption of chenna dhal be x kg. To keep the expenditure fixed, their consumption for this month should be 70x/80 = 7x/8. Reduction in consumption = x/8 = 12.5% of x
Description : From the salary of pooja , 40% is deducted as house rent, 20% of rest she spends on children's education and 40% of balance she spends on watching movies. If her savings are Rs.5760/- then hers total salary is: a) 20000 b) 30060 c) 45000 d) 47000 e) 98000
Last Answer : Answer: A Formula: First value = last value×100/(100-p1)×100/(100-p2)× 100/(100-p3) (p=percentage) First value = 5760×100/(100 – 40)×100/(100 – 20)×100/(100 - 40 ) = 5760 × 100/60× 100/80× 100/60 = 5760 × 5/3 × 5/4 × 5/3 = 5760 ×125/36 = 720000/36 = 20000
Description : From the salary of shreya, 15% is deducted as house rent, 15% she spends on children’s education and 20% on watching movies. If her savings are Rs.8450/- then her total salary is: a) 13500 b) 2360 c) 16900 d) 11520 e) 23198
Last Answer : Answer: C She spends = 50% remaining 50% = 8450 Total salary = 8450 × 100 / 50 = 845000 / 50 = 16900
Description : Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1
Last Answer : Answer: E Total cost of the items he purchased = Rs.75 Given that out of this Rs.75, 90 Paise is given as tax => Total tax incurred = 90 Paise = Rs.90/100 Let the cost of the tax free items = x Given that tax rate = ... −0.9 −x) = 90 ⇒ (75 − 0.9 − x) = 5 x = 75 − 0.9 - 5 X=69.1
Description : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be ______. (A) 20% (B) 40% (C) 50% (D) 30%
Last Answer : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be 20%.
Description : One sixth of half of three fourth of a number is 25.What will be 30% of that number? a) 800 b) 120 c) 340 d) 300
Last Answer : Answer: B (1/6) ×(1/2)×(3/4)× x = 25 x/16 =25 x = 25×16 x = 400 30 % of 400 = 30/100 ×400 = 12000/100 = 120
Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41
Last Answer : Answer: A (i) Percentage scored in Mathematics = 120/180 100 = 12000/180 =1200/18 = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100) = (40000/510) = 4000/51 = 78 22/51 %
Description : A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450
Last Answer : Answer: A) Number of ways to choose 10 questions from part A = 12C10 Number of ways to choose 8 questions from part B = 12C8 Total number of ways= 12C10 × 12C8 = 12C2 × 12C4 [∵ nCr = nC(n-r)] ={12×11}/{2×1}X{12×11×10×9} / {4×3×2×1} =66×495 =32670
Description : Calculate workers recruited and joined from the following: Labour turnover rates are 20%, 10% and 6% respectively under Flux method, Replacement method and Separation method. No. of workers replaced during the quarter is 80. (a) 112 (b) 80
Last Answer : (a) 112
Description : Calculate workers left and discharged from the following: Labour turnover rates are 20%, 10% and 6% respectively under Flux method, Replacement method and Separation method. No. of workers replaced during the quarter is 80. (a) 112 (b) 80 (c) 48 (d) 64
Last Answer : (c) 48
Description : Interest rate on 10 year NSC is a) 8.6% b) 8.4% c) 8.5% d) 8.9%
Last Answer : d) 8.9%
Description : If the production of a factory grows at a 16% p.a., what will be its production for the year 2016 if its production in 2014 was 140 lakh tonnes? a) 222.734 b) 149.597 c) 188.384 d) 28 3.812 e) 180.534
Last Answer : Answer: C Required Production=140(1 + 16/100)2 lakh tones =140(1 + 4/25)2 =140((25 + 4) /25)² =140(29/25)² =140(1.16)² =140×1.3456 =188.384 lakh tonnes
Description : In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814
Last Answer : Answer: D Total valid votes = 70% of 7600 = 5320 Number of valid votes to other candidate = 75% of 5320 = 75/100 *5320 = 399000/100 = 3990
Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800
Last Answer : Answer: D Total number of invalid votes = 55 % of 280000 = 55/100 280000 = 15400000/100 = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000 = 40/100 126000 = 5040000/100 = 50400
Description : In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800
Last Answer : Answer: D Total number of votes = 15000 Given that 40% of Percentage votes were invalid => Valid votes = 60% Total valid votes = 15000* 60/100 1st candidate got 45% of the total valid votes. Hence ... votes that 2nd candidate got = total valid votes x 55/100 =15000*60/100*55/100 =4950
Description : Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5
Last Answer : Answer: D Let the number be m. Decrease = 24 % of m = 24/100 × m = 6m /25 Therefore, decrease number = m – 6m/25 = (25m – 6m)/25 = 19m/25 According to the question 19m/25 = 594 19m = 594 × 25 19m = 14850 m = 14850/19 m =781.5
Description : A wooden manufacturing company declares that a wooden is now available for $11200 as against $25200 one year before. Find the percentage reduction in the price of wooden offered by the company. a) 25 1/3 b) 691/3 c) 66 1/3 d) 33 1/3 e) 55 5/9
Last Answer : Answer: E Price of the wooden a year before = $25200 Price of the wooden after a year = $11200 Decrease in price = $(25200 - 11200) = $14000 Therefore, decrease % = 14000/25200 × 100 % = 55 5/9 %
Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98
Last Answer : Answer: E Original cost = $140 Decrease in it = 30% of $140 = 30/100 × 140 = 4200/100 = $42 Therefore, decrease cost = $140 - $42 = $98
Description : By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98
Last Answer : Answer: A Let the number be m Increase in its value = 25 % of m = 25/100 × m = m/4 Therefore, increase value = m + m/4 = (4m + m)/4 = 5m/4 Therefore, the given number must be multiplied by 5/4 to increase the number by 25 %.
Description : In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983
Last Answer : Answer: A Difference = 672-126 = 546 According to the question, 70% of total aggregate = 546 Total aggregate marks = 546 × 100 /70 = 54600/70 = 780
Description : On a test consisting of 500 questions, Dhivya answered 80% of the first 250 questions correctly. What percent of the other 250 questions does she need to answer correctly for her grade on the entire exam to be 60% ? a) 20 b) 60 c) 45 d) 80 e) 40
Last Answer : Answer: E 60% of 500 = 300 80% of 250 = 200 No. of correct answers in remaining 250 questions = 300 – 200 = 100 Percentage = 100 x 100/ 250 = 40%
Description : In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected ... appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800
Last Answer : Answer: C Pondichery and Tamilnadu had an equal number of candidates appeared In Pondicherry, 18% candidates got selected from the total appeared candidates In tamilnadu, 21% candidates ... > total appeared candidates in pondicherry = total appeared candidates in tamilnadu = 24000
Description : In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298
Last Answer : Answer: B The number of students with first division = 56 % of 900 = 56/100 × 900 = 50400/100 = 504 And, the number of students with second division = 27 % of 900 = 27/100 × 900 =24300/100 = 243 Therefore, the number of students who just passed = 900 – (504 + 243) = 900- 747 = 153
Description : In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298
Last Answer : Answer: D Let the maximum marks be x. Aashika’s marks = 32% of x Aashika secured 1328 marks Therefore, 32% of x = 1328 ⇒ 32/100 × x = 1328 x = (1328 × 100)/32 x =132800/32 x = 4150 Therefore, Aashika got 1328 marks out of 4150 marks.
Description : Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989
Last Answer : Answer: C If Gowthaman had scored 26 marks more, he could have scored 25% Therefore, Mike required 424 + 26 = 450 marks Let the maximum marks be x. Then 25 % of x = 450 (25/100) × x = 450 x = (450 × 100)/25 x = 45000/25 x = 1800
Description : A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298
Last Answer : Answer: B Let x be the maximum marks, Then (50% of x)+60 = (75% of x)-40 x/2 +60 = 3x/4 -20 60+20 = 3x/4 – x/ 2 X=320 Hence maximum marks = 320 Minimum pass marks = 320/2 + 60 = 220
Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4
Last Answer : Answer: D Let the marks secured by them be x and (x + 18) Then sum of their marks = x + (x + 18) = 2x + 18 Given that (x + 18) was 72% of the sum of their marks =>(x+18) = 72/100(2x+18) => ... 11x = 126 x = 11.45 Then (x + 18) = 11.45 + 18 = 29.45 Hence their marks are 11.45 and 29.45
Description : Supriya invests 35% of her monthly salary in insurance policies. She spends 45% of her monthly salary in shopping and on household expenses. She saves the remaining amount of `25,750. What is Supriya's monthly income? a) 128750 b) 160050 c) 205200 d) 263400 e) 391800
Last Answer : Answer: A Percentage savings of Supriya = 100 – (35 + 45) = 20% Let her monthly income be x x X 20 /100 = 25750 x = 25750 × 100/20 x = 128750
Description : Two employees X and Y are paid a total of Rs. 4950 per week by their employer. If X is paid 150 percent of the sum paid to Y, how much is Y paid per week? a) 1250 b) 3760 c) 2405 d) 1540 e) 1980
Last Answer : Answer: E Let the amount paid to X per week = x and the amount paid to Y per week = y Then x + y = 4950 But x = 150% of y = 150y/100 = 15y/10 ∴15y/10 + y = 4950 ⇒ y[15/10 + 1] = 4950 ⇒ 25y/10 = 4950 ⇒ 25y = 49500 ⇒ y = 49500/25 y = Rs.1980
Description : mouli had $ 3600 left after spending 40 % of the money he took for shopping. How much money did he take along with him? a) 2500 b) 6000 c) 4500 d) 3000 e) 9800
Last Answer : Answer: B Let the money he took for shopping be x. Money he spent = 40 % of x = 40/100 x = 4/10 x Money left with him = x - 4/10 x = (10x - 4x)/10 = 6x/10 But money left with ... 6x/10 = 3600 x = 3600 10/6 x = 36000/6 x = 6000 Therefore, the money he took for shopping is 6000.