Give the EMPIRICAL formula for the organic compound cyclopentene.

Give the EMPIRICAL formula for the organic compound cyclopentene.
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ANSWER: C5H8 
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Description : Give the empirical formula for the organic compound naphthalene?

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An organic compound (A) has a molecular weight 78 and an empirical formula CH. (A) is resistant to attack by oxidizing agents but undergoes substitution and addition reactions. X-ray analysis shows that the distance between adjacent carbon atoms is 1.39Å (intermediate between single and double bond lengths). The evidence suggests that compound (A) is (a) Benzene (b) Cyclohexane (c) Toluene (d) n-Hexane

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Last Answer : Benzene

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Last Answer : Benzene

Cyclopentanol undergoes oxidation to give : (a) Cyclopentene (b) Cyclopentanone (c) Cyclopentane (d) Cyclopentanal

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Last Answer : ANSWER: OXYGEN ATOMIC NUMBER = 8

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The number of moles of Maganate ion used in oxidation of cyclopentene to cyclopent (1.2) diol is____

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Last Answer : Given: % of iron by mass = 69.9 % % of oxygen by mass = 30.1 % Relative moles of iron in iron oxide: = Percentage of iron by mass/Atomic mass of iron = 69.9/55.85 = 1.25 Relative moles of oxygen in iron ... to oxygen: = 1.25: 1.88 = 1:1.5 = 2:3 ∴ The empirical formula of the iron oxide is Fe2O3.

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What is the empirical formula for hydrogen peroxide?

Description : What is the empirical formula for hydrogen peroxide?

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What is the empirical formula for a molecule containing 46.8 Si and 53 O?

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Description : Which best describes an empirical formula?

Last Answer : Apex

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Empirical formula?

Description : Empirical formula?

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If P is population of a city in thousands and Q is fire demand in litres per minute, for proper estimate of water, the Empirical formula Q = 1135 [(P/5) + 10] is suggested by (A) National Board of fire under-writers (B) Freeman (C) Kuichling (D) None of these

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The fire demand for ascertaining the empirical formula 1136.5 [(P/10) + 10] known as (A) Kuichling's formula (B) Buston's formula (C) Freeman formula (D) Under Writers formula

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For calculating the permissible stress 0 y /[(1 + a(l/r)²]is the empirical formula, known as (A) Straight line formula (B) Parabolic formula (C) Perry's formula (D) Rankine's formula

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For calculating the allowable stress of long columns 0 y/n [1 - a (1/r)²]is the empirical formula, known as (A) Straight line formula (B) Parabolic formula (C) Perry's formula (D) Rankine's formula

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44 g of a sample of organic compound on complet combustion gives 88 g `CO_(2)` and 36 g of `H_(2)O` . The molecular formula of the compound may be :-

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What is the name of the first organic compound prepared from inorganic compounds ?

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What is Free Chain Organic Compound ?

Description : What is Free Chain Organic Compound ?

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(3) prevents freezing of petrol Explanation: Ethylene glycol (IUPAC name: ethane-1,2-diol) is an organic compound widely used as an automotive antifreeze and a precursor to polymers. In its pure form, it is an odorless, colourless, syrupy, sweettasting liquid. Ethylene glycol is toxic, and ingestion can result in death. Due to its low freezing point ethylene glycol resists freezing. A mixture of 60% ethylene glycol and 40% water freezes at -45 degree C (- 49 degree F).

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The first organic compound synthesized in the laboratory was - (1) Urea (2) Uric acid (3) Lactic acid (4) Glucose

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In Dumas’ method for estimation of nitrogen, 0.3g of an organic compound gave 50mL of nitrogen collected at 300K temperature and 715mm pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at 300K=15 mm).

Description : In Dumas’ method for estimation of nitrogen, 0.3g of an organic compound gave 50mL of nitrogen collected at 300K temperature and 715mm pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at 300K=15 mm).

Last Answer : Volume of nitrogen collected at 300K and 715mm pressure is 50 mL Actual pressure = 715-15 =700 mm Volume of Nitrogen at STP=273*700*50/300*760 =41.9 ml 22400 ml of Nitrogen at STP weighs = 28 g 41.9 ml of Nitrogen weighs = 28*41.9/22400 g % of Nitrogen = 28*41.9*100/22400*0.3 = 17.45 %

0.3780g of organic chloro compound gave 0.5740g of silver chloride in carius estimation .Calculate the percentage of chlorine present in the compound.

Description : 0.3780g of organic chloro compound gave 0.5740g of silver chloride in carius estimation .Calculate the percentage of chlorine present in the compound.

Last Answer : % of chlorine = 35.5*mass of AgCl formed * 100/143.5 * mass of the substance = 35.5*0.5740*100/143.5*0.3780 = 19.6 %

In an estimation of sulphur by carius method 0.468 g of an organic compound gave 0.668 g of barium sulphate. Find the percentage of sulphur in the compound.

Description : In an estimation of sulphur by carius method 0.468 g of an organic compound gave 0.668 g of barium sulphate. Find the percentage of sulphur in the compound.

Last Answer : Mass of the compound = 0.468 g Mass of the barium sulphate = 0.668 g % of sulphur = 32 X Mass of barium sulphate X 100/ 233 X Mass of the compound = 32 x 0.668x100/ 233 x0.468 = 19.60 %