Determine the empirical formula of an oxide of iron that has 69.9% iron & 30.1% dioxygen by mass. -General Knowledge

Determine the empirical formula of an oxide of iron that has 69.9% iron & 30.1% dioxygen by mass. -General Knowledge
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Answer :

Given: % of iron by mass = 69.9 % % of oxygen by mass = 30.1 % Relative moles of iron in iron oxide: = Percentage of iron by mass/Atomic mass of iron = 69.9/55.85 = 1.25 Relative moles of oxygen in iron oxide: = Percentage of oxygen by mass/Atomic mass of oxygen = 30.1/16.00 = 1.88 The simplest molar ratio of iron to oxygen: = 1.25: 1.88 = 1:1.5 = 2:3 ∴ The empirical formula of the iron oxide is Fe2O3.
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